I have a very basic onboarding for my app where there are few screens in a tabview with the pagetabviewstyle, and I am having trouble getting the keyboard avoidance behavior to work.
If I have have the tabview set with .ignoresSafeArea, then the keyboard doesn't avoid my textfields.
[Tab View With IgnoresSafeArea][1]
[Page With TextField][2]
[Before TextField Pressed][3]
[Keyboard Covers TextField][4]
If I remove the .ignoresSafeArea then the keyboard pushes the pagetabview dot indicators up the screen into the middle of the textfield.
[Keyboard Avoids With Page Dots Pushed Into TextField][5]
My ideal outcome would be to have the entire TabView IgnoreSafeArea without disabling the keyboard avoidance. I've checked online for a while without seeing any information on this issue. Thanks in advance for the help and suggestions!
[1]: https://i.stack.imgur.com/flKCY.png
[2]: https://i.stack.imgur.com/lNSBR.png
[3]: https://i.stack.imgur.com/DWZzN.jpg
[4]: https://i.stack.imgur.com/9ktwz.jpg
[5]: https://i.stack.imgur.com/Wwbwz.png
I had the same issue and solved it by changing the tabViewStyle whenever the keyboard state changes. Publisher code from How to detect if keyboard is present in swiftui :
var keyboardPublisher: AnyPublisher<Bool, Never> =
Publishers.Merge(
NotificationCenter.default
.publisher(for: UIResponder.keyboardWillShowNotification)
.map { _ in true },
NotificationCenter.default
.publisher(for: UIResponder.keyboardWillHideNotification)
.map { _ in false }
)
.eraseToAnyPublisher()
Create a state var in your view:
#State var keyboardShown: Bool
Hook up the publisher:
TabView {
}
.onReceive(vm.keyboardPublisher) { // <-- wherever you put your publisher
self.keyboardShown = $0
}
And modify the tab view style accordingly:
TabView {
}
.tabViewStyle(.page(indexDisplayMode: keyboardShown ? .never : .automatic))
It works surprisingly well.
Related
In my app, I have two tabs. The second tab is shown or hidden based on some condition. I find if there is a sheet being presented in the second tab when the tab is to be hidden, the sheet can't be dismissed.
The issue can be consistently reproduced with the code below. To reproduce it, click tab 2, then click "Present Sheet", then click "Hide Tab 2". You will see the sheet isn't removed, though the tab containing it (that is, tab 2) has been removed (you can drag the sheet down to verify it).
It seems a SwiftUI bug to me. Does anyone know how to work around it? I'm close to finish my app but hit this unexpected issue :( Any help will be much appreciated.
struct ContentView: View {
#State var showTab2: Bool = true
var body: some View {
TabView {
// tab 1
NavigationView {
Text("Tab 1")
}
.tabItem {
Label("Tab 1", systemImage: "1.circle")
}
// tab 2
if showTab2 {
NavigationView {
Tab2(showTab2: $showTab2)
}
.tabItem {
Label("Tab 2", systemImage: "2.circle")
}
}
}
}
}
struct Tab2: View {
#State var showSheet: Bool = false
#Binding var showTab2: Bool
var body: some View {
VStack(spacing: 12) {
Text("Tab 2")
Button("Click to present sheet") {
showSheet = true
}
}
.sheet(isPresented: $showSheet, onDismiss: nil) {
NavigationView {
MySheet(showTab2: $showTab2)
}
}
}
}
struct MySheet: View {
#Environment(\.dismiss) var dismiss
#Binding var showTab2: Bool
var body: some View {
Button("Click to hide tab 2") {
// dismiss() works fine if I comment out this line.
showTab2 = false
dismiss()
}
}
}
I have submitted feedback on this to Apple, but I'm not optimistic for any reply (I have never received one).
Update:
The issue can be reproduced in many other scenarios where no sheet is involved. So, the second approach #Asperi gave is not a general solution.
Well, here we see conflict of actions (due to racing): async sheet closing (due to animation) and sync tab removing.
Here are possible approaches:
delay tab removing after sheet closed (implicit way)
Button("Click to hide tab 2") {
dismiss()
DispatchQueue.main.asyncAfter(deadline: .now() + 0.25) { // << here !!
showTab2 = false
}
}
remove tab after sheet closed (explicit way)
.sheet(isPresented: $showSheet, onDismiss: { showTab2 = false }) { // << here !!
NavigationView {
MySheet(showTab2: $showTab2)
}
}
Note: Actually when view knows/manages something for parent of parent is not very good design, so option 2 (maybe with some additional conditions/callbacks) are more preferable.
#Asperi gave a great answer. But it's not straightforward to apply his approaches in actual app. I'll explain why and how to do it below.
The key idea in Asperi's approaches is that, since the UI changes have race condition, they should be performed in two steps. In both approaches the sheet is dismissed first, then the tab is hidden.
In practice, however, it may not be obvious how to decouple the two steps. For example, my app works this way (I think it's typical):
The sheet contains a form and call data model API to mutate data model when the form is submitted by user.
Since the data model API may fail, the sheet doesn't dismiss itself as soon as user submits the form. Instead it does that only when the API call succeeds (the API call is synchronous).
When the data model is mutated, it may trigger the condition to hide the tab.
Note the item 2 and 3. It means the sheet have to call data model API first, which may hide the tab, and then dismiss itself.
It took me a while to think out the solution - introduce a dedicated state to control show/hide the tab and hence decouple the two steps. Now the issue left is how to synchronize data model change to that state. Since the purpose is to make them to appear as two separate changes to UI, we can't use Combine. It can be messy if not implemented property because data model can be mutated from everywhere (e.g. Form, ActionSheet, or just Button). Fortunately I find a very elegant approach:
.onChange(of: model.showTab2) { value in
// In my experiments async() works fine, but just to be on the safe side...
DispatchQueue.main.asyncAfter(deadline: .now() + 0.1) {
// This is a state outside data model. It hides/shows tab2.
showTab2 = value
}
}
This is another example that there is no problem that can't be solved by adding another layer of abstraction :)
I have a button in a view (inside a NavigationView) that opens a full screen cover - a loading screen while some data is processing. When the cover is dismissed, I want to automatically route to the next view programmatically. I'm using a NavigationLink with a tag and selection binding, and the binding value updates when the cover is dismissed, but the routing doesn't happen unless I tap that same "open modal" button again.
import SwiftUI
struct OpenerView: View {
#EnvironmentObject var viewModel: OpenerViewModel
#State private var selection: Int? = nil
#State private var presentLoadingScreen = false
var body: some View {
VStack {
NavigationLink(destination: SecondScreen(), tag: 1, selection: $selection) { EmptyView() }
Button(action: {
viewModel.frequency = 0
self.presentLoadingScreen.toggle()
}, label: {
Text("Open cover")
}).buttonStyle(PlainButtonStyle())
}
.navigationBarTitle("Nav title", displayMode: .inline)
.fullScreenCover(isPresented: $presentLoadingScreen, onDismiss: {
self.selection = 1
}, content: ModalView.init)
}
}
struct ModalView: View {
#Environment(\.presentationMode) var presentationMode
var body: some View {
Text("Howdy")
.onAppear {
DispatchQueue.main.asyncAfter(deadline: .now() + 2.0) {
presentationMode.wrappedValue.dismiss()
}
}
}
}
The first time I hit the Button, the cover opens. Inside the cover is just a DispatchQueue.main.asyncAfter which dismisses it after 2 seconds. When it's dismissed, the onDismiss fires, but then I have to hit the button again to route to SecondScreen.
Any ideas?
Edit: Added the modal's View
I got it working with some changes to the code, and I'm sharing here along with what I think is happening.
I believe the problem is a race condition using a #State boolean to toggle the cover and the navigation. When the cover is being dismissed, my main OpenerView is being recreated - to be expected with state changes. Because of this, I try to set the #State var selection to trigger the navigation change, but before it can do so, the view is recreated with selection = nil.
There seem to be two ways to solve it in my case:
Move the cover boolean to my view model - this worked, but I didn't want it there because it only applied to this view and it's a shared view model for this user flow. Plus, when the modal is dismissed, you see the current OpenerView for a brief flash and then get routed to the SecondScreen.
Keep the cover boolean in #State, but trigger the navigation change in the button immediately after setting the boolean to open the modal. This worked better for my use case because the modal opens, and when it closes, the user is already on the next screen.
I had a similar problem where I was trying to draw a view after dismissing a fullScreenCover. I kept getting an error that said that the view had been deallocated since it was trying to draw to the fullScreenCover.
I used Joe's hints above to make this work. Specifically:
DispatchQueue.main.asyncAfter(deadline: .now() + 0.1) {
viewToShow()
}
I had previously tried onChange, onDisappear, onAppear - but none of those fit the use case I needed.
I’m having trouble using an arrow key as a .keyboardShortcut in SwiftUI. Sample iOS app:
struct ContentView: View {
#State var time: Date = Date()
var body: some View {
VStack {
Button("Press Me") {
time = Date()
}
.keyboardShortcut(KeyEquivalent.rightArrow, modifiers: [])
Text("\(time)")
}
}
}
This puts up a button that, when pressed, changes the time displayed in the text. I should be able to use the right arrow key on the keyboard and get it to work as well, but it doesn’t. If I change the keyboardShortcut line to, say, this:
.keyboardShortcut(KeyEquivalent(“a”), modifiers: [])
everything works as expected. You can press the “a” key and the time changes. If you hold down the command key, you get the system-provided HUD that shows the “a" shortcut. Change it to .rightAarrow and it shows the HUD but there’s an enclosed “?” for the shortcut, and the shortcut doesn’t fire when the arrow key is pressed.
(I’m aware I could do this using UIKit. Trying to understand why the SwiftUI version doesn’t work.)
I am attempting to accomplish the same objective in my MacOS SwiftUI app. Using your code as an example, I inserted the .keyboardShortcut(KeyEquivalent.rightArrow, modifiers: []) after my Button{} and it works fine. I then pasted your entire code into my ContentView and again it works fine. I do not know why it works in my MacOS app but not in your iOS app.
Copying my answer from this post. I wasn't able to use SwiftUI's commands to get this to work on iOS/iPadOS. However I found some luck using view controllers, and if you're using SwiftUI views then this will work with a hosting controller.
In your view controller, add the code below. The important bit is setting wantsPriorityOverSystemBehavior to true:
override var keyCommands: [UIKeyCommand]? {
let upArrow = UIKeyCommand(input: UIKeyCommand.inputUpArrow, modifierFlags: [], action: #selector(test))
upArrow.wantsPriorityOverSystemBehavior = true
return [upArrow]
}
#objc func test(_ sender: UIKeyCommand) {
print(">>> test was pressed")
}
I have referred to this Stack Overflow thread SwiftUI How to Pop to root view.
However it doesn't work for my case, of course no answer fits each persons use case perfectly so one always has to modify the answer slightly but of course keeping to the overall outline of the solution.
I have looked at this thread How to popup multiple view off navigation stack, but I am not sure resetting the scene is the best option? There has got to be a "normal" way?
The solution I went with is use an ObservableObject and set it as an EnvironmentObject of the root view.
The navigation stack grows by 4 views:
RootView().environmentObject(AppSettings.shared)
FirstView()
SecondView()
ThirdView()
FourthView()
The NavigationLink isActive state for the FirstView is defined in AppSettings.shared, all the other states are found in the subsequent view and not in AppSettings.
For example:
FirstView -> SecondView the SecondView isActive state is defined in the ViewModel of the FirstView, and so on and so forth.
What I am trying to achieve is to pop to RootView from the FourthView. So on the FourthView there is an environmentObject variable of type AppSettings (passed down as an EnvironmentObject from RootView) and on button press, toggle RootView -> FirstView isActive state to false.
It toggles but there's no navigation.
However, in the debug console this is the error
Trying to pop to a missing destination at /Library/Caches/com.apple.xbs/Sources/Monoceros/Monoceros-42.24.100/Shared/NavigationBridge_PhoneTV.swift:205
From my understanding toggling that state to false should trigger a navigation back, but in the Stack Overflow thread there was a post to use #State variable from RootView -> FirstView and in the EnvironmentObject have a variable moveToDashbord. Then on the RootView add a .onReceive modifier to listen to moveToDashboard publisher and then trigger #State variable. But again that also results in the same debug console message.
In short all solutions result in a missing destination console message. Is this because the navigation is too deep?
This is an iPad only project, and the navigationView style is set to StackedNavigationStyle.
System Details:
Xcode 11.6
iOS/ PadOS Target 13.0 (so not using SwiftUI 2.0, if that is a thing)
Code examples:
This is the SceneDelegate which sets the AppSettings as system wide EnvironmentObject.
func scene(_ scene: UIScene, willConnectTo session: UISceneSession, options connectionOptions: UIScene.ConnectionOptions) {
let contentView = LoginView().environmentObject(AppSettings.shared)
if let windowScene = scene as? UIWindowScene {
let window = UIWindow(windowScene: windowScene)
window.rootViewController = UIHostingController(rootView: contentView)
self.window = window
window.makeKeyAndVisible()
}
}
This is an example of the navigationLink to the RootView
NavigationLink(destination: RootView().navigationBarBackButtonHidden(true), isActive: self.$loginViewModel.loginSuccess) {
EmptyView()
}
This is an example of navigationLink from RootView -> FirstView:
NavigationLink(destination: FirstView().environmentObject(FirstViewModel()), isActive: self.$appSettings.firstView) {
EmptyView()
}.isDetailLink(false)
Note. I had to change the actual names of the Views for clarification sake.
I found the issue, on one of the views there was a UIViewControllerRepresentable wrapped UIAlertController. It was structured as a view modifier with provision for content.
This basically wrapped over the original view which ended up breaking the navigation stack.
The solution was to rather wrap a UIViewController which is presented by the View and in that ViewController resides the UIAlertController.
This solution for the UIAlertController was used and adapted SwiftUI - UIAlertController
I am creating an App where the login / register part is inside a modal, which is shown if the user is not logged in.
The problem is, that the user can dismiss the modal by swiping it down...
Is it possible to prevent this?
var body: some View {
TabView(selection: $selection) {
App()
}.sheet(isPresented: self.$showSheet) { // This needs to be non-dismissible
LoginRegister()
}
}
Second example:
I am using a modal to ask for information. The user should not be able to quit this process except by dismissing the modal with save button. The user has to input information before the button works. Unfortunately the modal can be dismissed by swiping it down.
Is it possible to prevent this?
iOS 15 and later:
Use .interactiveDismissDisabled(true) on the sheet, that's all.
Prev iOS 15:
You can try to do this by using a highPriorityGesture. Of course the blue Rectangle is only for demonstration but you would have to use a view which is covering the whole screen.
struct ModalViewNoClose : View {
#Environment(\.presentationMode) var presentationMode
let gesture = DragGesture()
var body: some View {
Rectangle()
.fill(Color.blue)
.frame(width: 300, height: 600)
.highPriorityGesture(gesture)
.overlay(
VStack{
Button("Close") {
self.presentationMode.value.dismiss()
}.accentColor(.white)
Text("Modal")
.highPriorityGesture(gesture)
TextField("as", text: .constant("sdf"))
.highPriorityGesture(gesture)
} .highPriorityGesture(gesture)
)
.border(Color.green)
}
}
This is a common problem and a "code smell"... well not really code but a "design pattern smell" anyway.
The problem is that you are making your login process part of the rest of the app.
Instead of presenting the LoginRegister over the App you should really be showing either App or LoginRegister.
i.e. you should have some state object like userLoggedIn: Bool or something and depending on that value you should show either App or LoginRegister.
Just don't have both in the view hierarchy at the same time. That way your user won't be able to dismiss the view.
If you dont mind using Introspect:
import Introspect
#available(iOS 13, *)
extension View {
/// A Boolean value indicating whether the view controller enforces a modal behavior.
///
/// The default value of this property is `false`. When you set it to `true`, UIKit ignores events
/// outside the view controller's bounds and prevents the interactive dismissal of the
/// view controller while it is onscreen.
public func isModalInPresentation(_ value: Bool) -> some View {
introspectViewController {
$0.isModalInPresentation = value
}
}
}
Usage:
.sheet {
VStack {
...
}.isModalInPresentation(true)
}
iOS 15+
Starting from iOS 15 you can use interactiveDismissDisabled.
You just need to attach it to the sheet:
var body: some View {
TabView(selection: $selection) {
App()
}.sheet(isPresented: self.$showSheet) {
LoginRegister()
.interactiveDismissDisabled(true)
}
}
Regarding your second example, you can pass a variable to control when the sheet is disabled:
.interactiveDismissDisabled(!isAllInformationProvided)
You can find more information in the documentation.
theoretically this may help you (I didn't tryed it)
private var isDisplayedBind: Binding<Bool>{ Binding(get: { true }, set: { _ = $0 }) }
and usage:
content
.sheet(isPresented: isDisplayedBind) { some sheet }