This question already has answers here:
Why is the Fortran DO loop index larger than the upper bound after the loop?
(2 answers)
Value of Fortran DO loop index after the loop [duplicate]
(2 answers)
Closed 11 months ago.
I'm trying to figure out why did i increased by 1 after the loop has finished.
i have tried to add continue after 'print' but still the same problem.
Do 5 i= 2,3
5 print*, i
Print*,i
End
I have tried another example in this image below
https://i.stack.imgur.com/tHW0w.png
Related
This question already has answers here:
Why aren't variable-length arrays part of the C++ standard?
(10 answers)
How do compilers treat variable length arrays
(4 answers)
Closed 2 years ago.
In the below program, when does the array c gets initialize ?
If is it at compile time then how I got the output as 20 which is the product of n i.e. 5 and size of integer in C++ i.e. 4 ,after I pass the value of n at runtime. And if it got allocated at runtime then, how is it possible ,as for runtime allocation we have to use new operator which is not use in this program.
This question already has answers here:
Calculate rolling / moving average in C++
(11 answers)
Closed 3 years ago.
I am a beginner in C++. I am wondering how can I compute a new list by adding 8 consecutive elements and then divide them by the number of elements added in a list with C++. For example, the new list is re[], and the list we'll be using is a[], it has 200 elements. so re[i] = (a[i-1]+a[i-2]+a[i-3]+a[i-4]+a[i]+a[i+1]+a[i+2]+a[i+3]+a[i+4])/9
for(int i=4;i<196;i++){
re[i] = (a[i-1]+a[i-2]+a[i-3]+a[i-4]+a[i]+a[i+1]+a[i+2]+a[i+3]+a[i+4])/9
}
However the above code is not applicable to the first 4 elements and the last 4 elements in re[], because a[i] in these cases has no 4 consecutive elements either preceding or following a[i].
So I am wondering how can I do the same using for loop for these elements?
Thanks for any help.
I don't really know what you are doing but you might need to use Modulo Symbol so you wont get out of range
For example:
I want to stick with number 7 not get more and not getting less than 0
I will say for example 1 mod 7 and I will get 1
how? because it takes the reminder of the division
To understand more about it go here
To calculate and try go here
in your example
for(int i=0;i<200;i++){
re[i] = (a[(i-1)%200]+a[(i-2)%200]+a[(i-3)%200]+a[(i-4)%200]+a[(i)%200]+a[(i+1)%200]+a[(i+2)%200]+a[(i+3)%200]+a[(i+4)%200])/9
}
This question already has an answer here:
Zero indexed array in Fortran?
(1 answer)
Closed 4 years ago.
I would like to know this example line.
Dimension A(265000, 5:8)
, especially 5:8
I can only know this A is going to be a 2 dimension, but I would like make sure what the 5:8 is.
Is it right to understand like 265000x5, 265000x6, 265000x7, 265000x8?
This is a two dimensional array, and 5:8 means the subscripts for the second dimension have values 5, 6, 7, 8.
This question already has answers here:
Segmentation fault on large array sizes
(7 answers)
Closed 7 years ago.
I define arrays in this way:
double uo[n+2][m+2][n1+2] ,
vo[n+2][m+2][n1+2] ,
wo[n+2][m+2][n1+2] ,
du[n+2][m+2][n1+2] ,
dv[n+2][m+2][n1+2] ,
dw[n+2][m+2][n1+2] ,
w1[n+2][m+2][n1+2] ,
z1[n+2][m+2][n1+2] ,
z[n+2][m+2][n1+2] ;
Once I made it as static double then error removes but it keeps running and does not terminate.
If m or n are to big, you'll get a stackoverflow because you are trying to take to much space in your stack.
Dynamic allocation should be done in the heap using functions such as malloc()
This question already has answers here:
Why do I get the same result with rand() every time I compile and run? [duplicate]
(4 answers)
rand() returns same values when called within a single function
(5 answers)
rand() generating the same number [duplicate]
(3 answers)
Closed 10 years ago.
I'm trying to get random numbers on range from 0 to 3. Using such code:
#include <cstdlib>
int index = rand() % 3;
But always getting the same results: 1 1 0 1.
What I'm doing wrong? Always the same numbers. Results should change their values after each compilation or during runtime?
Your forgot to ad
#include <ctime>
srand(time(NULL))
at the start of your program.
This will generate a new seed everytime you run your program based on the current time.
Results should change their values after each compilation or during runtime?
Actually, no, the results are supposed to be the same for a given seed, and if you do not set the seed explicitly with srand(), then the results will be the same each time you run. To get different results each time, you should set the seed using something derived from something not completely deterministic, like the time (not deterministic in the sense that you don't know the exact time at the moment it gets used to set the seed).