Retrieve multiple ArrayFire subarrays from min/max data points - c++

I have an array with sections of touching values in it. For example:
0 0 1 0 0 0 0 0 0 0
0 1 1 1 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 2 2 2 0 0
0 0 0 0 0 0 0 2 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 3 0 0 0 0 0 0 0
0 0 3 0 0 0 0 0 0 0
0 0 3 0 0 0 0 0 0 0
from this, I created a set of af::arrays: minX, maxX, minY, maxY. These define the box that encloses each group.
so for this example:
minX would be: [1,5,2] // 1 for label(1), 5 for label(2) and 2 for label(3)
maxX would be: [3,7,2] // 3 for label(1), 7 for label(2) and 2 for label(3)
minY would be: [0,3,7] // 0 for label(1), 3 for label(2) and 7 for label(3)
maxY would be: [1,4,9] // 1 for label(1), 4 for label(2) and 9 for label(3)
So if you take the i'th element from each of those arrays, you can get the upperleft/lowerright bounds of a box that encloses the corresponding label.
I would like use these values to pull out subarrays from this larger array. My goal is to put these values enclosed in the boxes into a flat list. In GPU memory, I also have calculated how many entries I would need for each box using the max/min X/Y values. So in this example - the result of the flat list should be:
result=[0 1 0 1 1 1 2 2 2 0 0 2 3 3 3]
where the first 6 entries are from the box
______
|0 1 0 |
|1 1 1 |
------
the second 6 entries are from the box
______
|2 2 2 |
|0 0 2 |
------
and the final three entries are from the box
___
| 3 |
| 3 |
| 3 |
---
I cannot figure out how to index into this af::array with min/max values in memory that resides on the GPU (and do not want to transfer them to the CPU). I was trying to see if gfor/seq would work for me, but it appears that af::seq cannot use array data, and everything I have tried with using af::index i could not get to work for me either.
I am able to change how I represent min/max (I could store indices for upper left/lower right) but my main goal is to do this efficiently on the GPU without moving data back and forth between the GPU and CPU.
How can this be achieved efficiently with ArrayFire?
Thank you for your help

How did you get there so far? which language are you using?
I guess you could be tiling the results to 3rd dimensions to handle each regions separately and end up with min/max vectors in GPU memory.

Related

What is the 5x5 equivalent of the 3x3 emboss kernel?

-2 -1 0
-1 1 1
0 1 2
This is 3x3 emboss kernel. How should I write this in 5x5?
As I understand, these filters take directional differences (see the wikipidea page).
We can decompose you filter into directions
0 -1 0 0 0 0 -2 0 0
0 0 0 -1 0 1 0 0 0
0 1 0 0 0 0 0 0 2
So, I think you can expand it over these 3 directions giving emphasis
0 0 -1 0 0 0 0 0 0 0 -2 0 0 0 0
0 0 -1 0 0 0 0 0 0 0 0 -2 0 0 0
0 0 0 0 0 -1 -1 0 1 1 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0 0 0 2 0
0 0 1 0 0 0 0 0 0 0 0 0 0 0 2
So, the final kernel would be
-2 0 -1 0 0
0 -2 -1 0 0
-1 -1 1 1 1
0 0 1 2 0
0 0 1 0 2
May be you can also try interpolating filter coefficients marked as x
-2 x -1 0 0
x -2 -1 0 0
-1 -1 1 1 1
0 0 1 2 x
0 0 1 x 2
The simple solution to fitting any lower-dimensional convolution kernel into a higher-dimensional matrix of the same rank is to surround it by zero weights. This is especially true when you're dealing with a concept like embossing, which is arguably more interested in immediate vector of change than the rate at which it is changing. That is, for this embossing matrix,
You could equivalently use this in 5 x 5:
Granted, this will get you a different visual effect than anything with any part of the matrix filled in; but sometimes, especially with edge-detection, immediate clarity is more important. We aren't always displaying it. If this were something like a Guassian blur kernel, having a greater range could improve the effect, but embossing isn't that different conceptually from Sobel-Feldman and it may be better to keep it tight.

Notepad++ regex - search only in certain column all numbers between two numbers?

i have now 250 million lines of text from a database.
I want to highlight only certain values, that are only in the third column.
I use this \b1011(3[1-9]\d[1-9]|[4]\d\d\d|5[0-8][0-3][0-6])\b for highlight all values between 10113101 to 10115836.
Can one exclude the numbers from column 4?
Edit: a column means for me the text between the spaces
1 2 3 4 5 ..... columns
307607 1317011864 10113101 -25 13135611 2700 0 0 0 12 0 0 0 walk029h.rwx
2264 910115836 10114632 -15 20111192 900 0 0 0 11 0 0 0 walk029.rwx
326169 1010523891 10115836 -1 20911192 0 0 0 0 11 0 0 0 walk12h.rwx
38718 826265392 10113628 0 10114603 2700 0 0 0 11 0 0 0 street2.rwx
241512 1317011864 636346 0 10113987 900 0 0 0 12 0 0 0 walk029h.rwx
38718 826266129 10113448 0 10114310 900 0 0 0 10 0 0 0 tree5m.rwx
38718 826266243 10113898 0 10114810 900 0 0 0 10 0 0 0 tree9m.rwx
This pattern will capture the numbers you want in the third column only. Refer to capture group 1 for their values.
^(?:\S+\s){2}\b(1011(?:3[1-9]\d{2}|4\d{3}|5[0-8][0-3][0-6]))\b.*
All I did was modify yours to add the prefix and removed some redundancy.

Eigen: Zero matrix with smaller matrix as the "diagonals"

Is it possible to create a 9x9 matrix where the "diagonal" is another matrix and the rest are zeroes, like this:
5 5 5 0 0 0 0 0 0
5 5 5 0 0 0 0 0 0
5 5 5 0 0 0 0 0 0
0 0 0 5 5 5 0 0 0
0 0 0 5 5 5 0 0 0
0 0 0 5 5 5 0 0 0
0 0 0 0 0 0 5 5 5
0 0 0 0 0 0 5 5 5
0 0 0 0 0 0 5 5 5
from a smaller 3x3 matrix repeated:
5 5 5
5 5 5
5 5 5
I am aware of the Replicate function but that repeats it everywhere in the matrix and doesn't maintain the zeroes. Is there a builtin way of achieving what I'm after?
One way of doing this is by using blocks where .block<3,3>(0,0) is a 3x3 block starting at 0,0. (Note: Your IDE might flag this line as an error but it will compile and run)
for (int x=0, x<3, x++){
zero_matrix.block<3,3>(x*3,x*3) = five_matrix;
}
You can use the (unsupported) KroneckerProduct module for that:
#include <unsupported/Eigen/KroneckerProduct>
int main()
{
Eigen::MatrixXd A = Eigen::kroneckerProduct(Eigen::Matrix3d::Identity(), Eigen::Matrix3d::Constant(5));
std::cout << A << '\n';
}

Regex command to insert character into column

I have a text file organized into columns that looks like this:
# v Col 50
EE84 1484.74 1364.99 62.5 2 1 0 1
EE85 505.23 841.63 60. 2 1 0 1
EE86 945.95 913.39 100. 1 0 0 0
P3 972.44 1126.12 100. 1 0 0 0
P28 980.0 1119.0 100. 1 0 0 0
P100 964.03 1125.93 100. 1 0 0 0
P102 963.49 1133.71 100. 1 0 0 0
P106 974.06 1150.73 100. 1 0 0 0
P108 1017.36 1062.47 100. 1 0 0 0
P109 965.31 1151.14 100. 1 0 0 0
composed of several hundreds lines.
I need to add a value, say 0 in column 50 for each of the lines in the file, so it will look like this:
# v Col 50
EE84 1484.74 1364.99 62.5 0 2 1 0 1
EE85 505.23 841.63 60. 0 2 1 0 1
EE86 945.95 913.39 100. 0 1 0 0 0
P3 972.44 1126.12 100. 0 1 0 0 0
P28 980.0 1119.0 100. 0 1 0 0 0
P100 964.03 1125.93 100. 0 1 0 0 0
P102 963.49 1133.71 100. 0 1 0 0 0
P106 974.06 1150.73 100. 0 1 0 0 0
P108 1017.36 1062.47 100. 0 1 0 0 0
P109 965.31 1151.14 100. 0 1 0 0 0
I could paste the file into LibreOffice Calc, add the column and then paste it back, but that messes with the columns alignment.
I'm using Sublime Text 3 as my text editor, which enables the user to apply regex commands.
Which regex command could I use to do this?
Use Ctrl + H to open the Search and Replace, enable Regular Expression.
Find What: ^[^#].{48}\K
Replace With: 0
Demo
You can search using this regex:
/^((?:\S+\s+){49})/gm
Replace with this expression:
"${1}0 "
RegEx Demo

Matlab: how to work with sparse keys to access sparse data?

I am trying to access the sparse mlf with the keys such as BEpos and BEneg where one key per line. Now the problem is that most commands are not meant to deal with too large input: bin2dec requires clean binary numbers without spaces but the regexp hack fails to too many rows -- and so on.
How to work with sparse keys to access sparse data?
Example
K>> mlf=sparse([],[],[],2^31,1);
BEpos=Cg(pos,:)
BEpos =
(1,1) 1
(2,3) 1
(2,4) 1
K>> mlf(bin2dec(num2str(BEpos)))=1
Error using bin2dec (line 36)
Binary string must be 52 bits or less.
K>> num2str(BEpos)
ans =
1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
K>> bin2dec(num2str('1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0'))
Error using bin2dec (line 36)
Binary string must be 52 bits or less.
K>> regexprep(num2str(BEpos),'[^\w'']','')
Error using regexprep
The 'STRING' input must be a one-dimensional array
of char or cell arrays of strings.
Manually works
K>> mlf(bin2dec('1000000000000000000000000000000'))
ans =
All zero sparse: 1-by-1
Consider a different approach using manual binary to decimal conversions:
pows = pow2(size(BEpos,2)-1 : -1 : 0);
inds = uint32(BEpos*pows.')
I haven't benchmarked this, but it might work faster than bin2dec and cell arrays.
How it works
This is pretty simple: the powers of 2 are calculated and stored in pows (assuming the MSB is in the leftmost position). Then they are multiplied by the bits in the matching positions and summed to produce the corresponding decimal values.
Try to index with this:
inds = uint32( bin2dec(cellstr(num2str(BEpos,'%d'))) );