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My "num = -num" line inside of my "if (num<0)" line still affects results, even if my input is greater than 0.
#include <iostream>
int main()
{
std::cout << "Enter a positive number: ";
int num{};
std::cin >> num;
if (num < 0)
std::cout << "Negative number entered. Making positive.\n";
num = -num;
std::cout << "You entered: " << num;
return 0;
}
To have multiple statements inside an if, you must use brackets.
And at this point of learning the language, I would recommend just always using brackets.
if (num < 0) {
std::cout << "Negative number entered. Making positive.\n";
num = -num;
}
Unlike languages like python, leading whitespace is not meaningful to the compiler in C++.
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I'm currently getting into subroutines/subprograms or whatever you call them in english and in this specific assignment that i'm trying to solve I have to calculate the average length of two words.
void Length(string const text_1,
string const text_2,
int & total_length,
double & mean_length)
{
total_length = text_1.length() + text_2.length();
mean_length = static_cast<double>(total_length) / 2;
}
void Length_Program(int val)
{
string text_1;
string text_2;
int total_length{};
double mean_length{};
cout << "Mata in två ord: ";
cin >> text_1 >> text_2;
cout << "Totallängd: ";
Length(text_1, text_2, total_length, mean_length);
cout << total_length << endl;
cout << "Medellängd: " << fixed << setprecision(1) << mean_length;
}
I have set the precision to setprecision(1) and I assume it will only write one decimal but I keep getting two decimals.
my example is: abcd E
it should say that it is an average of 2.5 words but it says 2.51 for some reason. Can someone help me understand what i'm doing wrong?
Your problem is that you forgot << endl on your last output line. The return code shown by the OS is appended to your output. The setprecision is working just fine.
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ok so i writ this little code in c++. keep in mind i just started learning c++ so this problem confused me a lot
when i run this code in code blocks (
using namespace std;
int Answer;
int main()
{
cout << "yo, are u male?"<< endl;
cin >>Answer;
if (Answer = 1){
cout << "ur male"<< endl;
} else {
cout <<"ur female"<< endl;
}
cout <<Answer;
}
)
the answer value is always set to one even if i type 0
i tried coding another if statement for the answer value if it was 0 but that didn't work either
In C++, = operator is an assignment operator and it sets value of left operand to value of right operand. Therefore the value of Answer becomes 1 thanks to Answer = 1.
You should use == operator to check equality.
Use the == operator in your code, as = operators does the job of assigning values.
using namespace std;
int Answer;
int main()
{
cout << "yo, are u male?"<< endl;
cin >>Answer;
if (Answer == 1){
cout << "ur male"<< endl;
} else {
cout <<"ur female"<< endl;
}
cout <<Answer;
}
)
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My while loop is not working. The code runs correctly on the Codecademy website compiler. I then compile it with Visual Studio, run it from the Command prompt and input a number. The program stops prematurely even if the number is the correct one.
#include <cstdlib>
#include <iostream>
int main() {
int answer = 8;
int guess;
int tries;
std::cout << "I have a number between 1-10.\n";
std::cout << "Please guess it: ";
std::cin >> guess;
while (guess != 8 && tries < 50) {
std::cout << "Wrong guess, try again: ";
std::cin >> guess;
tries++;
}
if (guess == 8) {
std::cout << "You got it!\n";
}
}
As #rsjaffe and #Ken White have said in the comments, the tries variable is unitiailized, meaning that the location in memory that the variable is pointing to is "junk" (left over memory). Try to give it an initial value, like this:
int tries = 0;
which will instantiate and initialize the tries variable.
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I am a newbie in C++, I started to learn coding in C++ two weeks ago. Why does my code below always give me result 0 when I build and run? Please help
# include <iostream>
# include <string>
using namespace std;
int main ()
{
int input = 1;
cout << "input your number : \n";
cin >> input;
int faktorial = 1;
for(int i=1;i<=input;i++)
{
faktorial = faktorial * i;
}
cout << "factorial value from number " << input << " is " << faktorial << endl;
}
Your code works: https://ideone.com/CYFaxo
I suspect your problem is, you are looking at program exit code. When you don't return any value from main, program exit code is 0 (this is special case, and only non-void function where you may leave the return statement out), which conventionally means success (non-zero exit code usually indicates some kind of error, by convention).
Try to find the program output from your IDE, it should have the correct printout.
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I am trying to get only the alphabetic characters from an array of characters entered by the user. Here is a snippet:
const int SIZE(100);
int main()
{
char* entryTextArray = new char[SIZE];
char* adjustedTextArray= new char[SIZE];
int i, j;
cout << "Enter text, and I will tell you if it is a palindrome!" << endl;
cin.get(entryTextArray, SIZE);
cout << "Length of char array is " << strlen(entryTextArray) << endl;
for(i=0, j=0; i <= (strlen(entryTextArray)); i++) {
if(isalpha(entryTextArray[i]) && (entryTextArray[i] != '\0')) {
adjustedTextArray[j] = entryTextArray[i];
cout << adjustedTextArray[j] << endl;
j++;
}
}
cout << adjustedTextArray << endl;
}
When I compile, the cout of the adjustedTextArray displays the proper individual entrys, but the cout outside of the loop is the entry text, followed by garbage. I have no idea what is wrong! Help?!
You have the condition:
if (something && (entryTextArray[i] != '\0'))
so you are explicitly avoiding to copy the NUL terminating value from entryTextArray to adjustedTextArray. So you need to place it manually.
But since you are working in C++ using std::string just makes more sense.