Getting error in merging two arrays in c++? - c++

Question

I am trying to merge two dynamic arrays but I am getting an error in my merge function that
"data': is not a member of 'List<T>"
I know that the error is ocuring because the given parameter in the merge(const List& other) is list but I am confused how to access my ArrayList2 which has been passed in merge function in the main
my code is:
#include <iostream>
using namespace std;
template<class T>
class List {
public:
// return the capacity of the list
virtual size_t capacity() const = 0;
// return the number of elements in the list
virtual size_t size() const = 0;
// inserts an element to the beginning
virtual void push_front(const T& value) = 0;
// adds an element to the end
virtual void push_back(const T& value) = 0;
// removes the last element
virtual void pop_back() = 0;
// removes the first element
virtual void pop_front() = 0;
// remove the first occurrence of an element with the given value
virtual void remove(const T& val) = 0;
// merges two sorted lists
virtual void merge(const List<T>& other) = 0;
virtual ~List() {}
};
template<class T>
class ArrayList : public List<T>
{
private:
T* data;
size_t max_capacity;
size_t num_of_element;
public:
ArrayList() = delete; // disable default constructor
// constructor
ArrayList(size_t capacity) : max_capacity(capacity), num_of_element(0) {
data = new T[capacity];
}
// copy constructor
ArrayList(const ArrayList<T>& other_list) : max_capacity(other_list.max_capacity),
num_of_element(other_list.num_of_element) {
data = new T[max_capacity];
for (size_t i = 0; i < other_list.num_of_element; i++) {
data[i] = other_list.data[i];
}
}
// destructor
virtual ~ArrayList() {
delete[]data;
}
size_t capacity() const override {
return max_capacity;
}
size_t size() const override {
return num_of_element;
}
T& operator[](int index) {
return data[index];
}
bool operator==(const ArrayList<T>& other_list) {
// not comparing capacity as eventually array list can be made capacity irrelevant using dynamic allocation
if (num_of_element != other_list.num_of_element) {
return false;
}
for (int i = 0; i < num_of_element; i++) {
if (data[i] != other_list.data[i]) {
return false;
}
}
return true;
}
void push_front(const T& value)
{
}
void push_back(const T& value)
{
if (max_capacity > num_of_element)
{
num_of_element++;
data[num_of_element - 1] = value;
}
}
void pop_back()
{
}
void pop_front()
{
}
void remove(const T& val)
{
int i = 0, j;
while (i < max_capacity)
{
if (data[i] == val)
{
for (int j = i; j < num_of_element-1; j++)
data[j] = data[j + 1];
if (data[i] == val && (i + 1) > num_of_element - 1)
{
data[i] = {};
num_of_element--;
break;
}
num_of_element--;
}
else
i++;
}
}
void merge(const List<T>& other)
{
int i;
int newsize = size() + other.size();
T* temp = new T[newsize];
for (i = 0; i < num_of_element; i++)
temp[i] = data[i];
for (int j = 0; j < other.size(); j++)
{
temp[i] = other.data[j]; //I am getting error on this line
i++;
}
}
private:
void shift_left_to(size_t start) {
for (size_t i = start; i < num_of_element - 1; i++) {
data[i] = data[i + 1];
}
}
};
int main() {
ArrayList<int> list1(3);
list1.push_back(3);
list1.push_back(1);
list1.push_back(1);
ArrayList<int> list2(2);
list2.push_back(1);
list2.push_back(8);
list1.merge(list2);
/* for (size_t i = 0; i < list1.size(); i++)
cout<<list1[i]<<" ";
cout<<"Size:"<<list1.size()<<" Capacity:"<<list1.capacity();*/
system("pause");
return 0;
}

Answer 1

Presumably, all of your concrete List<T> classes (e.g. ArrayList<T>) will have some kind of accessors to the elements. You can make those accessors part of the List<T> interface and call them in the implementation of void merge(List<T> const&). As an example:
template <class T>
class List {
public:
// ...
virtual T& operator[](int index) = 0;
virtual T const& operator[](int index) const = 0;
};
template <class T>
class ArrayList : public List<T> {
private:
T* data;
size_t max_capacity;
size_t num_of_element;
public:
// ...
T& operator[](int index) override { return data[index]; }
T const& operator[](int index) const override { return data[index]; }
// ...
void merge(const List<T>& other) {
int i;
int newsize = size() + other.size();
T* temp = new T[newsize];
for (i = 0; i < num_of_element; i++) temp[i] = data[i];
for (int j = 0; j < other.size(); j++) {
temp[i] = other[j]; // < Use your List<T>::operator[] here
i++;
}
}
// ...
};

Answer 2

I'd say the message is quite descriptive: List does not have a member called data. You should use the [] operator instead to access the list elements in the merge function. [] operator is implemented by descendants of List.
temp[i] = other[j]