XSLT: for-each-group select with condition - not(contains()) - xslt

Question

I would like to get help with my problem in creating an xslt transform.
I need to get select from xsl:for-each-group with some conditions.
I need to get all elements, which sub-element have text in sub-element "Zkrat" not same as text in this array
<xsl:variable name="zkratky">
<zkratka>1</zkratka>
<zkratka>2</zkratka>
<zkratka>5</zkratka>
<zkratka>6</zkratka>
</xsl:variable>
<xsl:variable name="lookup" select="document('')//xsl:variable[#name='zkratky']"/>
My XML file input is:
<MoneyData>
<SeznamObjPrij>
<ObjPrij>
<Polozka>
<KmKarta>
<Popis>Main title</Popis>
<TypKarty>komplet</TypKarty>
<Slozeni>
<Komponenta>
<KmKarta>
<Popis>Subtitle Item1</Popis>
<Zkrat>2</Zkrat>
<Katalog>1111</Katalog>
</KmKarta>
<PocMj>1</PocMj>
</Komponenta>
<Komponenta>
<KmKarta>
<Popis>Subtitle Item2</Popis>
<Zkrat>1</Zkrat>
<Katalog>22222</Katalog>
</KmKarta>
<PocMj>4</PocMj>
</Komponenta>
<Komponenta>
<KmKarta>
<Popis>Subtitle Item3</Popis>
<Zkrat>3</Zkrat>
<Katalog>1111</Katalog>
</KmKarta>
<PocMj>1</PocMj>
</Komponenta>
</Slozeni>
</KmKarta>
</Polozka>
<Polozka>
<KmKarta>
<Popis>Test</Popis>
<TypKarty>jednoducha</TypKarty>
</KmKarta>
</Polozka>
<Polozka>
<KmKarta>
<Popis>Main title</Popis>
<TypKarty>komplet</TypKarty>
<Slozeni>
<Komponenta>
<KmKarta>
<Popis>Subtitle Item1</Popis>
<Zkrat>2</Zkrat>
<Katalog>1111</Katalog>
</KmKarta>
<PocMj>10</PocMj>
</Komponenta>
<Komponenta>
<KmKarta>
<Popis>Subtitle Item2</Popis>
<Zkrat>2</Zkrat>
<Katalog>33333</Katalog>
</KmKarta>
<PocMj>1</PocMj>
</Komponenta>
<Komponenta>
<KmKarta>
<Popis>Subtitle Item3</Popis>
<Zkrat>1</Zkrat>
<Katalog>1111</Katalog>
</KmKarta>
<PocMj>2</PocMj>
</Komponenta>
<Komponenta>
<KmKarta>
<Popis>Subtitle Item4</Popis>
<Zkrat>3</Zkrat>
<Katalog>4444</Katalog>
</KmKarta>
<PocMj>1</PocMj>
</Komponenta>
</Slozeni>
</KmKarta>
</Polozka>
</ObjPrij>
</SeznamObjPrij>
</MoneyData>
My xslt transform:
<xsl:for-each-group select="Polozka/KmKarta/Slozeni/Komponenta[$lookup[not(contains(., KmKarta/Zkrat))]]" group-by="KmKarta/Katalog">
<xsl:sort select="KmKarta/Popis"/>
<tr>
<td><xsl:value-of select="KmKarta/Popis"/></td>
<td><xsl:value-of select="current-grouping-key()"/></td>
<td><xsl:value-of select="KmKarta/Zkrat"/></td>
<td><xsl:value-of select="sum(current-group()/PocMJ)"/></td>
</tr>
</xsl:for-each-group>
I always get all elements or none. Or this message:
Wrong occurrence to match required sequence type
Error location: xsl:stylesheet / xsl:template / div / table / tbody / xsl:for-each-group / #select
Details
XPTY0004: The parameter value ('4' item(s)) at position '1' of the 'contains' function has the wrong occurrence to match the sequence type xs:string ('zero or one')
Please, help me.
Thank you very much :)

Answer 1

All sorts of things wrong here.
Firstly, if you're using for-each-group then you're using XSLT 2.0+ which means you don't need the contortion of having the stylesheet read its own global variables using document('').
There are several problems in this expression
Komponenta[$lookup[not(contains(., KmKarta/Zkrat))]]
As written, the context item for evaluating KmKarta/Zkrat is an element in $lookup, which isn't what you want.
And I don't think you need contains() here - you need "=" which makes it much simpler.
So I think you just want Komponenta[not(KmLarta/Zkrat = $zkratky/zkratka)].

Answer 2

I would just use
<xsl:variable name="zkratky">
<zkratka>1</zkratka>
<zkratka>2</zkratka>
<zkratka>5</zkratka>
<zkratka>6</zkratka>
</xsl:variable>
plus
<xsl:for-each-group select="Polozka/KmKarta/Slozeni/Komponenta[not($zkratky/zkratka = KmKarta/Zkrat)]" group-by="KmKarta/Katalog">