how to use regex variable in zsh? - regex

Question

How can I use a regex variable in zsh the same way it works in bash? I can only get zsh to work with an inline regex. I am just trying to test a string only contains alphanumerics, underscores or periods, but no dashes. As you can see, the inline regex and the regex variable work as expected in bash, but zsh only matches the inline regex.
Bash
#!/bin/bash
RE='[0-9A-Za-z_\.]'
for test in $#; do
echo -e "bash test: $test"
if [[ "${test//[0-9A-Za-z_\.]/}" = "" ]]; then
echo -e '\tmatch inline'
fi
if [[ "${test//$RE/}" = "" ]]; then
echo -e '\tmatch var'
fi
done
❯./bash-regex-test.sh foo_bar foo-bar
output:
bash test: foo_bar
match inline
match var
bash test: foo-bar
Zsh
#!/bin/zsh
RE='[0-9A-Za-z_\.]'
for test in $#; do
echo "zsh test: $test"
if [[ "${test//[0-9A-Za-z_\.]/}" = "" ]]; then
echo '\tmatch inline'
fi
if [[ "${test//$RE/}" = "" ]]; then
echo '\tmatch var'
fi
done
❯./zsh-regex-test.zsh foo_bar foo-bar
output:
zsh test: foo_bar
match inline
zsh test: foo-bar

Answer 1

With zsh you need to use ${~RE} instead of $RE so the variable $RE
is treated as a pattern, not the literal string. Then change the line as:
if [[ "${test//${~RE}/}" = "" ]]; then
BTW your usage of $RE is not the regex but the pattern as in
pathname expansion.
In order to use it as a regex, you'll need to use =~ operator as:
#!/bin/zsh
RE='^[0-9A-Za-z_\.]+$'
for test in "$#"; do
echo "zsh test: $test"
if [[ $test =~ ^[0-9A-Za-z_\.]+$ ]]; then
echo '\tmatch inline'
fi
if [[ $test =~ $RE ]]; then
echo '\tmatch var'
fi
done