folder_1-> parent folder
which has data
file.txt
file2.txt
in this folder has another folder name is folder_2
folder_2 has data
file3.txt
file4.txt
impor os
cwd = os.getcwd()
new_folder = "\folder2"
new_path = cwd + new_folder
now how to go inside and reach file3.txt and open it and then file4.
txt
Related
search the same file in multiple folders
I have tried with os.walk(path) but I am not getting the nested folders traversing
for current_root, folders, file_names in os.walk(self.path, topdown=True):
for i in folders:
print i
for filename in file_names:
count+= 1
file_path = os.path.join(current_root + '\\' + filename)
#print file_path
self.location_dictionary[file_path] = filename
in my code, it will print all folders but it will not enter to the nested folders recursively
ex: I have subdir,subdir1,subdir2 and in subdir I have another dir called abc
in subdir and abc both contain same file name I want to read that file
os.walk does not work that way.
for each current_root it traverses, it provides the list of directories and files directly under it.
You're nesting the loops, which does ... well I don't know...
Here you don't need the folder (so just mute the argument). current_root already contains that info for your files:
for current_root, _, file_names in os.walk(self.path, topdown=True):
for filename in file_names:
count+= 1
file_path = os.path.join(current_root,filename)
#print file_path
self.location_dictionary[file_path] = filename
aside: creating a dictionary with full file as key and filename as value looks, well, not what you want (the same information could be stored in a set or list and os.path.basename could be used to compute the filename. Maybe it's reverse (filename => full path), provided that there are no duplicate filenames.
I want to open and read all csv file in a specific folder.
I'm on OS X El Capitan version 10.11.6, and I'm using Python 2.7.10.
I have the following function in phyton file:
def open_csv_files(dir):
for root,dirs,files in os.walk(dir):
for file in files:
if file.endswith(".csv"):
f= open(file)
print "FILE OPEN, AND DO SOMETHING... "
f.close
return
I call open_csv_file(./dati/esempi)
This procedure return
IOError: [Errno 2] No such file or directory: 'sensorfile_1.csv'
I try to call the procedure with absolute path /Users/Claudia/Desktop/Thesis/dati/esempi/ but I have the same error.
Moreover I define another procedure that print all filename in folder, this procedure print correctly all filenames in folder.
Thanks for the help.
You need to build absolute path to file based on values of root (base dir) and file name.
import os
def open_csv_files(directory):
for root, dirs, files in os.walk(directory):
for file_name in files:
if file_name.endswith(".csv"):
full_file_path = os.path.join(root, file_name)
with open(full_file_path) as fh:
print "Do something with", full_file_path
import os
myDir = "C:\\temp\\a"
for root, dirs, files in os.walk(myDir):
for file in files:
# fname = os.path.join(root, file) # this works fine, yeah!
fname = os.path.join(myDir, file)
print ("%r" % (fname))
src = os.path.isfile(fname)
if src == False:
print ("%r :Fail" % (fname))
f = open(fname,"r")
f.close()
I expected the two versions of fname to be the same, but I've found out the hard way that the above code doesn't work. I just want to know why, that's all.
The problem is that os.walk(myDir) walks all the subdirectories, recursively! When walk descends into a subdirectory, root will be that directory, while myDir is still the root directory the search started in.
Let's say you have a file C:\temp\a\b\c\foo.txt. When os.walk descends into c, myDir is still C:\temp\a and root is C:\temp\a\b\c. Then os.path.join(root, file) will yield C:\temp\a\b\c\foo.txt, while os.path.join(myDir, file) gives C:\temp\a\foo.txt.
You might want to rename your myDir variable to root, and root to current, respectively, so it's less confusing.
I am trying to set up a program to put my minecraft server world into a zip and place it into another directory on another drive (/media/500gb/MinecraftWorldBackups)
But I keep getting this error
Although the folder doesn't contain a folder or file called 'h'
What do I need to do to fix this I believe it is due to file and folder?
#!/usr/bin/env python
import time, zipfile
while True:
FileName = 'MinecraftBackup_' + str(int(time.time()))
Path = '/home/bertie/Desktop/FeedTheBeastServer/world/'
print(FileName)
Zip = zipfile.ZipFile('/media/500gb/MinecraftWorldBackups/'+FileName+'.zip','w')
for each in Path:
print(each)
try: Zip.write(Path + each)
except IOError: None
Zip.Close()
print('Done')
time.sleep(60)
My problem is to read '.csv' files in catalogs and do some calculations on them.
I have calculations working but my for loop seem not to work as I want to.
d = 'F:\MArcin\Experiments\csvCollection\'
for dirname, dirs, files in os.walk(d):
for i in files:
if i.endswith('.csv'):
data1 = pd.read_csv(i, sep=",")
data = data1['x'][:, np.newaxis]
target = data1['y']
The error Iam getting is:
IOError: File 1.csv does not exist
files is list of all '.csv' files inside dirname
i is str of size 1 and contains 1.csv (that is first of the files in catalog)
Any ideas why this is not working?
Thanks for any help.
Because 1.csv is somewhere on the filesystem and when you call read_csv() it opens file relative to current directory.
Just open it using absolute path:
data1 = pd.read_csv(os.path.join(dirname, i), sep=",")
dirname in os.walk represents actual directory where file 1.csv is located.