I have some string
022/03/17 05:53:40.376949 1245680 029 DSA- DREP COLS log debug S 1
Need get 1245680 number use regex statement
I use next regular \d+ but many result in output.
First: are you sure that you want to have regex? Wouldn't a string cut operation be better?
First for a fixed amount of 29 characters as this is the prefix length and then search for the next space in the rest of the string to clear the remainder.
If you have to use regex for some other reason (e.g. you don't have the ability to implement a routine where you need it), you can use a regex with a group to extract just the number you want: ^.{29}(\d+).*$
Here you have to use group(1) or any other reference to a group in the language you are using to get the value you want.
As the rest of the line also can contain numbers (and I suppose a variable amount of characters, if this a log entry), my simple attempts to use lookbehind and lookahead combination failed as they also found that other numbers in the line.
If 022/03/17 05:53:40.376949 is always in that format, you can use:
\d{2}:\d{2}:\d{2}.\d{1,6}\s*(\d*)\s*
or more generally:
\d*\/\d*\/\d*\s+.*?\s+(\d*)
These will match the date/time segment, whitespace, the sequence of (captured) digits you desire, and then more whitespace.
Related
I have data like this:
~10~682423~15~Test Data~10~68276127~15~More Data~10~6813~15~Also Data~
I'm trying to use Notepad++ to find and replace the values within tag 10 (682423, 68276127, 6813) with zeroes. I thought the syntax below would work, but it selects the first occurrence of the text I want and the rest of the line, instead of just the text I want (~10~682423~, for example). I also tried dozens of variations from searching online, but they also either did the same thing or wouldn't return any results.
~10~.*~
You can use: (?<=~10~)\d+(?=~) and replace with 0. This uses lookarounds to check that ~10~ precedes the digit sequence and the (?=~) ensures a ~ follows the digit sequence. If any character could be after the ~10~ field, use (?<=~10~)[^~]+(?=~).
The problem with ~10~.*~ is that the * is greedy, so it just slurps away matching any character and ~.
Use
\b10~\d+
Replace with 10~0. See proof. \b10~ will capture 10 as entire number (no match in 210 is allowed) and \d+ will match one or more digits.
Sample input:
___file___name___2000___ed2___1___2___3
DIFFERENT+FILENAME+(2000)+1+2+3+ed10
Desired output (eg, all letters and 4-digit numbers and literal 'ed' followed immediately by a digit of arbitrary length:
file name 2000 ed2
DIFFERENT FILENAME 2000 ed10
I am using:
[A-Za-z]+|[\d]{4}|ed\d+ which only returns:
file name 2000 ed
DIFFERENT FILENAME 2000 ed
I see that there is a related Q+A here:Regular Expression to match specific string followed by number?
eg using ed[0-9]* would match ed#, but unsure why it does not match in the above.
As written, your regex is correct. Remember, however, that regex tries to match its statements from left to right. Your ed\d+ is never going to match, because the ed was already consumed by your [A-Za-z] alternative. Reorder your regex and it'll work just fine:
ed\d+|[a-zA-Z]+|\d{4}
Demo
Nick's answer is right, but because in-order matching can be a less readable "gotcha", the best (order-insensitive) ways to do this kind of search are 1) with specified delimiters, and 2) by making each search term unique.
Jan's answer handles #1 well. But you would have to specify each specific delimiter, including its length (e.g. ___). It sounds like you may have some unusual delimiters, so this may not be ideal.
For #2, then, you can make each search term unique. (That is, you want the thing matching "file" and "name" to be distinct from the thing matching "2000", and both to be distinct from the thing matching "ed2".)
One way to do this is [A-Za-z]+(?![0-9a-zA-Z])|[\d]{4}|ed\d+. This is saying that for the first type of search term, you want an alphabet string which is followed by a non-alphanumeric character. This keeps it distinct from the third search term, which is an alphabet string followed by some digit(s). This also allows you to specify any range of delimiters inside of that negative lookbehind.
demo
You might very well use (just grab the first capturing group):
(?:^|___|[+(]) # delimiter before
([a-zA-Z0-9]{2,}) # the actual content
(?=$|___|[+)]) # delimiter afterwards
See a demo on regex101.com
I am working with government measures and am required to parse a string that contains variable information based on delimiters that come from issuing bodies associated with the fda.
I am trying to retrieve the delimiter and the value after the delimiter. I have searched for hours to find a regex solution to retrieve both the delimiter and the value that follows it and, though there seems to be posts that handle this, the code found in the post haven't worked.
One of the major issues in this task is that the delimiters often have repeated characters. For instance: delimiters are used such as "=", "=,", "/=". In this case I would need to tell the difference between "=" and "=,".
Is there a regex that would handle all of this?
Here is an example of the string :
=/A9999XYZ=>100T0479&,1Blah
Notice the delimiters are:
"=/"
"=>'
"&,1"
Any help would be appreciated.
You can use a regex like this
(=/|=>|&,1)|(\w+)
Working demo
The idea is that the first group contains the delimiters and the 2nd group the content. I assume the content can be word characters (a to z and digits with underscore). You have then to grab the content of every capturing group.
You need to capture both the delimiter and the value as group 1 and 2 respectively.
If your values are all alphanumeric, use this:
(&,1|\W+)(\w+)
See live demo.
If your values can contain non-alphanumeric characters, it get complicated:
(=/|=>|=,|=|&,1)((?:.(?!=/|=>|=,|=|&,1))+.)
See live demo.
Code the delimiters longest first, eg "=," before "=", otherwise the alternation, which matches left to right, will match "=" and the comma will become part of the value.
This uses a negative look ahead to stop matching past the next delimiter.
I want to remove all numbers from a paragraph except from some words.
My attempt is using a negative look-ahead:
gsub('(?!ami.12.0|allo.12)[[:digit:]]+','',
c('0.12','1245','ami.12.0 00','allo.12 1'),perl=TRUE)
But this doesn't work. I get this:
"." "" "ami.. " "allo."
Or my expected output is:
"." "" 'ami.12.0','allo.12'
You can't really use a negative lookahead here, since it will still replace when the cursor is at some point after ami.
What you can do is put back some matches:
(ami.12.0|allo.12)|[[:digit:]]+
gsub('(ami.12.0|allo.12)|[[:digit:]]+',"\\1",
c('0.12','1245','ami.12.0 00','allo.12 1'),perl=TRUE)
I kept the . since I'm not 100% sure what you have, but keep in mind that . is a wildcard and will match any character (except newlines) unless you escape it.
Your regex is actually finding every digit sequence that is not the start of "ami.12.0" or "allo.12". So for example, in your third string, it gets to the 12 in ami.12.0 and looks ahead to see if that 12 is the start of either of the two ignored strings. It is not, so it continues with replacing it. It would be best to generalize this, but in your specific case, you can probably achieve this by instead doing a negative lookbehind for any prefixes of the words (that can be followed by digit sequences) that you want to skip. So, you would use something like this:
gsub('(?<!ami\\.|ami\\.12\\.|allo\\.)[[:digit:]]+','',
c('0.12','1245','ami.12.0 00','allo.12 1'),perl=TRUE)
Rules for the regex in english:
min length = 3
max length = 6
only letters from ASCII table, non-numeric
My initial attempt:
[A-Za-z]{3-6}
A second attempt
\w{3-6}
This regex will be used to validate input strings from a HTML form (i.e. validating an input field).
A modification to your first one would be more appropriate
\b[A-Za-z]{3,6}\b
The \b mark the word boundaries and avoid matching for example 'abcdef' from 'abcdefgh'. Also note the comma between '3' and '6' instead of '-'.
The problem with your second attempt is that it would include numeric characters as well, has no word boundaries again and the hypen between '3' and '6' is incorrect.
Edit: The regex I suggested is helpful if you are trying to match the words from some text. For validation etc if you want to decide if a string matches your criteria you will have to use
^[A-Za-z]{3,6}$
I don't know which regex engine you are using (this would be useful information in your question), but your initial attempt will match all alphabetic strings longer than three characters. You'll want to include word-boundary markers such as \<[A-Za-z]{3,6}\>.
The markers vary from engine to engine, so consult the documentation for your particular engine (or update your question).
First one should be modified as below
([A-Za-z]{3,6})
Second one will allow numbers, which I think you don't want to?
first one should work, second one will include digits as well, but you want to check non-numeric strings.