int main() {
int x;
const int Maxword = 5;
std::string Guess[Maxword];
std::string words[Maxword] = {
"Hello",
"World",
"Shift",
"Green",
"Seven"
};
srand(time(NULL));
int iSecret = rand() % 4 + 1;
std::string Cool(words[iSecret]);
for (int i = 0; i < 5; i++) {
std::cout << Cool[i] << std::endl;
}
for (int i = 0; i < 5; i++) {
std::cout << ("Please enter the letters you would like to guess") << std::endl;
std::cin >> Guess[i];
std::cout << Guess[i] << std::endl;
}
for (int i = 0; i < 5; i++) {
if (Guess[i] == Cool[i]) {
std::cout << Guess[i] << "Is in the word";
}
}
For this statement here at the Bottom for statement within the if statement it has a no operator dont mind the actual code it is just a rough draft before I make the actual code but i dont see the problem.
Cool is a string. Cool[i] is a character. Guess is an array of strings. Guess[i] is a string. You're trying to compare a character to a string. You probably mean if (guess[i] == Cool)
Related
int main() {
int x;
const int Maxword = 5;
char Guess[Maxword] {};
std::string words[Maxword] = {
"Hello",
"World",
"Shift",
"Green",
"Seven"
};
srand(time(NULL));
int iSecret = rand() % Maxword;
std::string Word(words[iSecret]);
for (int i = 0; i < 5; i++) {
std::cout << Word[i] << std::endl;
}
for (int i = 0; i < 5; i++) {
std::cout << ("Please enter the letters you would like to guess") << std::endl;
std::cin >> Guess[i];
std::cout << Guess[i] << std::endl;
}
for (int i = 0; i < 5; i++) {
if (Guess[i] == Word[i]) {
std::cout << Guess[i] << "\t" << "Is in the right place" << std::endl;
} else if (Guess[i] != Word[i]) {
std::cout << Guess[i] << "\t" << "Isnt in the right place" << std::endl;
} else {
}
}
void InTheWord() {
for (int i = 0; i < 5; i++) {
}
}
I want to use elements of arrays Guess[] and Word[] how would I access them from the other function. So like I want to check if a letter from Guess[] is in the array of Word[] so id have to pass down each letter and check guess against every letter in word then return to the other function to then print out whether the letter that the person guessed was in the word that the program generated.
I'm having issues with this c++ code. It is supposed to print a hollow right isosceles triangle, but instead just prints asterisks over and over, so the for loops seem to be stuck.
#include "pch.h"
#include <string>
#include <iostream>
int main() {
int row;
std::string s = " ";
std::string a = " *";
int rows = 10;
for (int i = 0; i < rows; i++) {
if (i = 0) {
std::cout << a << std::endl;
}
while (i > 2 && i < rows) {
std::cout << a;
for (int pos = 0; pos < i; pos++) {
std::cout << s;
}
std::cout << a << std::endl;
}
std::cout << a << a << a << a << a << a << a << a << a << std::endl;
}
}
your while loop condition will never become false, AND you need to use comparison (==) instead of assignment in this line:
if (i = 0) {
Supposing that what you want to print is something of the following form:
Eg. for rows = 5
*
**
* *
* *
*****
Your code should have the following structure:
for (int i = 1; i <= rows; ++i)
{
//special case for the first line
if (i == 1)
std::cout << asterisk << std::endl;
//for each of the other lines print 2 asterisks and the rest spaces
if (i > 1 && i <= rows - 1)
{
//one at the start of the line
std::cout << asterisk;
//print line - 2 spaces
for (int j = 0; j < i - 2; ++j)
std::cout << space;
//one at the end of the line
std::cout << asterisk << std::endl;
}
//special case for the last line
if (i == rows)
{
for (int j = 1; j <= i; ++j )
std::cout << asterisk;
std::cout << endl;
}
}
https://ideone.com/peGRUG
Your while loop condition is the issue here, also you should use == instead of = inside if condition. Anyways,Here is a small fix in your solution..
void printTriangle() {
int row;
std::string s = " ";
std::string a = " *";
int rows = 10;
for (int i = 1; i < rows-1; i++) {
for (int j = 1; j <= i; ++j)
{
if (j == 1 || j == i)
std::cout << a;
else
std::cout << s;
}
std::cout << std::endl;
}
for (int i = 1; i < rows; ++i)
std::cout << a;
}
What is the simple way to get numbers from given string pattern using regular expressions?
the string pattern is like,
${type:1234} ${type:2345}
I want the numbers, in that case, 1234, 2345.
the string patten can also contain spaces,
${(WS)*type(WS)*:(WS)*1234(WS)*} , ... (more like this)
I need also to check that the string is valid pattern and if it is, to extract the numbers.
I know it can be easily done using tokenizer but I think it will be better to use regular expressions.
you use some magic to achieve what you want using loops:
#include <iostream>
#include <string>
int main()
{
std::string str("${type:1234} ${type:2345}");
int n = 0;
for(int i(0); i < str.length(); i++)
{
if(isdigit(str[i]))
{
n++;
while(isdigit(str[i]))
i++;
}
}
std::cout << "There are: " << n << std::endl;
std::string* strTmp = new std::string[n];
int j = 0;
for(int i = 0; i < str.length(); i++)
{
if(isdigit(str[i]))
{
while(isdigit(str[i]))
{
strTmp[j] += str[i];
i++;
}
j++;
}
}
for(int i = 0; i < n; i++)
std::cout << strTmp[i] << std::endl;
// now you have strTmo holding numbers as strings you can convert them to integer:
int *pInt = new int[n];
for(int i = 0; i < n; i++)
pInt[i] = atoi(strTmp[i].c_str());
for(int i = 0; i < n; i++)
std::cout << "value " << i+1 << ": " << pInt[i] << std::endl;
delete[] strTmp;
strTmp = NULL;
delete[] pInt;
pInt = NULL;
std::cout << std::endl;
return 0;
}
will you please tell me what will be the procedure to find alphabet occur in all strings(char string lists) in c++
the output will only return matched values(alphabet numbers)
i m trying this
#include <vector>
#include <iostream>
#include <cstdio>
int main()
{
//setup
std::vector<int> alphabetCount;
for (int i = 0; i < 26; ++i)
{
alphabetCount.push_back(0);
}
//now the interactive bit
std::cout << "Enter a line of text\n";
std::string line;
std::getline(std::cin, line);
for (size_t i = 0; i < line.size(); ++i)
{
char currentChar = tolower(line[i]);
if (isalpha(currentChar))
{
++alphabetCount[currentChar - 'a']; //subtract a, so if currentChar = a, 'a' - 'a' = 0, so its index 0
}
}
for (size_t i = 0; i < alphabetCount.size(); ++i)
{
std::cout << "there were " << alphabetCount[i] << " occurences of " << static_cast<char>(i + 'a') << "\n"; //add 'a' for the same reason as above, though we have to cast it to a char.
}
system("pause");
return 0;
}
but it only returns values from single string i want result from all string
The reason why it is taking one string at a time is because you are taking one as input, you should make a vector of string and take input in it.
You have not read the string more than once in program. below is sample program, which is very naive to demonstrate the process. The loop terminating condition can be much better than mine though.
int main()
{
//setup
std::vector<int> alphabetCount;
for (int i = 0; i < 26; ++i)
{
alphabetCount.push_back(0);
}
//now the interactive bit
std::cout << "Enter a line of text\n";
std::string line;
do{
std::getline(std::cin, line);
for (size_t i = 0; i < line.size(); ++i)
{
char currentChar = tolower(line[i]);
if (isalpha(currentChar))
{
++alphabetCount[currentChar - 'a']; //subtract a, so if currentChar = a, 'a' - 'a' = 0, so its index 0
}
}
}while(line != "exit");
--alphabetCount['e' - 'a'];
--alphabetCount['x' - 'a'];
--alphabetCount['i' - 'a'];
--alphabetCount['t' - 'a'];
for (size_t i = 0; i < alphabetCount.size(); ++i)
{
std::cout << "there were " << alphabetCount[i] << " occurences of " << static_cast<char>(i + 'a') << "\n"; //add 'a' for the same reason as above, though we have to cast it to a char.
}
system("pause");
return 0;
}
I was writing some code challenge from reddit about encrypting strings and I came up with something like this:
#include <iostream>
#include <string>
using namespace std;
string encrypt(string sentence);
int main()
{
string sentence;
int i = 0;
cout << "Welcome. Enter a sentence: ";
getline(cin, sentence);
cout << sentence << endl;
encrypt(sentence);
cout << endl << endl;
system("pause");
return 0;
}
string encrypt(string sentence)
{
int i = 0;
int x = (sentence.size());
string *encrypted_sentence = new string[sentence.size()];
int *wsk = new int[sentence.size()];
for (i = 0; i < x; i++)
{
wsk[i] = sentence[i];
}
for (i = 0; i < x; i++)
{
if (wsk[i] == ' ')
continue;
else if (islower(wsk[i]))
{
if (wsk[i] <= 99)
wsk[i] = (wsk[i] + 23);
else
wsk[i] = (wsk[i] - 3);
}
else
{
if (wsk[i] <= 67)
wsk[i] = (wsk[i] + 23);
else
wsk[i] = (wsk[i] - 3);
}
}
for (i = 0; i < x; i++)
{
//cout << static_cast <char> (wsk[i]);
encrypted_sentence[i] = wsk[i];
}
return *encrypted_sentence;
}
My problem is, that there is nothing that gets returned. After I run the program I get nothing in return. Can anybody point me in the right direction with this? What have I missed?
First main() returns an int always. void main() is not standard. Secondly:
string encrypted_sentence = new string[sentence.size()];
Will not even compile. encrypted_sentence is of type std::string but you are trying to assign to it a std::string *. Third you should avoid using using namespace std;
Update:
I believe you are trying to output the encrypted string at:
cout << endl << endl;
But all this is doing is outputting 2 newlines and flushing the output twice. If you want to display the encrypted string then you either need to capture the return of the encrypt() function and display it or encrypt() can take the string in by reference. IF you change encrypt() to take a reference then it would become:
void encrypt(string & sentence)
{
string *encrypted_sentence = new string[sentence.size()]; // get rid of this line as it is not needed.
//...
for (i = 0; i < x; i++)
{
sentence[i] = wsk[i];
}
}
And then you would output the string with:
cout << sentence << endl;
In case anyone would seek an answer to this question, I've come up with this, and I'm pretty sure it finally works how I wanted it to:
#include <iostream>
#include <string>
std::string encrypt(std::string to_encrypt);
int main()
{
std::string sentence;
std::string result;
std::cout << "Welcome. Please enter a sentence: ";
getline(std::cin, sentence);
result = encrypt(sentence);
std::cout << "Result: " << result << std::endl;
system("pause");
return 0;
}
std::string encrypt(std::string to_encrypt)
{
int i = 0;
int x = (to_encrypt.size());
std::cout << std::endl << "x = " << x << std::endl;
int *temp = new int[to_encrypt.size()];
for (i = 0; i < x; i++)
{
temp[i] = to_encrypt[i];
}
for (i=0; i < x; i++)
{
if (temp[i] == ' ')
continue;
else if (islower(temp[i]))
{
if (temp[i] <= 99)
temp[i] = temp[i] + 23;
else
temp[i] = temp[i] - 3;
}
else
{
if (temp[i] <= 67)
temp[i] = temp[i] + 23;
else
temp[i] = temp[i] - 3;
}
}
std::string encrypted;
for (i = 0; i < x; i++)
{
encrypted += (static_cast <char> (temp[i]));
}
return encrypted;
}
The code is obviously wrong. string *encrypted_sentence = new string[sentence.size()]; allocates an ARRAY of strings! Not a single string. Judging from that, you can see how your code is wrong.