Unable to overload '[ ]' in here. C++ Noob here - c++

Question

I am trying to implement a linkedlist in C++ and trying to incorporate array like data access using '[]'.
First I declared a Node class as the following.
class Node{
public:
int data;
Node *next, *prev;
Node(int val){
this -> data = val;
this -> next = NULL;
this -> prev = NULL;
}
};
Then I implemented the Linkedlist class as the following where I have overloaded the '[]' operator like the following
class LinkedList{
public:
Node *head;
LinkedList(){
this -> head = NULL;
}
LinkedList(Node *h){
this -> head = h;
}
int operator [] (int index){
if(index < 0 || index >= getsize(this -> head)){
cout << "List out of bounds" << endl;
return -1;
}else{
Node *cur = this -> getnode(index);
return cur -> data;
}
}
Node* getnode(int index){
int count = 0;
Node *cur = this -> head;
while(cur != NULL){
if(count == index)
break;
count++;
cur = cur -> next;
}
return cur;
}
};
In the main function I have tried to print the 'l[0]'. It shows error as
no operator "<<" matches these operandsC/C++(349)
linklist_sort.cpp(173, 10): operand types are: std::ostream << LinkedList
Please help me out. Am I missing some concept here ?
The main function :
int main(){
srand(time(0));
LinkedList *l = new LinkedList();
for(int i = 0; i<10; i++){
int num = rand() % 50 + 1;
l -> head = l -> insert(l->head,num);
}
l->printlist(l->head);
int n1, n2;
cout << "\n";
cin >> n1 >> n2;
l->swap(l->head,n1,n2);
l->printlist(l->head);
cout << "\n";
cout << l[0]; //Error here
return 0;
}
The getsize function :
int getsize(Node *head){
if(head == NULL)
return 0;
else
return 1 + getsize(head->next);
}

Answer 1

Since l is a pointer which is created by
LinkedList *l = new LinkedList();
it needs to be dereferenced to be able to use operator first.
This would solve your problem:
cout << (*l)[0];
But I suggest you to not create LinkedList with new keyword so you can avoid using raw pointers and memory leaks in the application code.
You could use LinkedList l; instead.