How do I implement action={% url '......' %} in django-form - django

Question

I want to know the equivalent using <form action={% url '......' %}> in django-form(i.e. using forms.ModelForm class).
How do I define the action url of my form in djano-form? it can be easily done in HTML using action attribute of form as action={% url....

Answer 1

The form action in views.py will run when you click <button type='submit'> Submit </button> in your <form>. If it's not what you want:
That is how you can trigger a view function from html :
views.py
def YourAction(request, arg):
# do something
return redirect('/anywhere') # you need to return something
urls.py
from .views import YourAction
urlpatterns = [
path('dosomething/<arg>', YourAction, name='action_name'),
]
your html
<form action='{% url 'action_name' arg %}'>
<button type='submit'> Submit! </button>
</form>
You don't have to use form. You can just use <a href='{% url 'action_name' arg %}'> Do Something! </a>

Answer 2

You can change it, also, in View (views.py):
from django.urls import reverse
from .models import YOUR_FORM_MODEL
def myView(request):
if request. Method == 'GET':
form = YOUR_FORM_MODEL()
form.helper.form_action = reverse('appname:testme')
mydata = {'form': form}
return HttpResponse(render(request, 'appname/custom_page.html', context=mydata))
and add in Your urls.py:
from django.urls import path
from . import views
app_name = 'appname'
urlpatterns = [
path('test-my-custom-form-send-path', views.myView, name='testme'),
]
in your template (custom_page.html):
{% extends 'appname/base_html_file.html' %}{% load crispy_forms_tags %}{% load static %}
{% crispy form %}