Heading from product filter - bigcartel

I'm using the Foundry theme and on the /products page. I have links to the different categories of products. These take you to /category/______. There is a <h1> heading, which has a default of value Shop. I want the value to represent the current category. I tried the following code, but the heading was just blank.
<h1>
...
{% elsif page.full_url contains "category/" %}
{% for category in categories.all %}
{% if page.full_url contains {{ category.permalink }} %}{{ category.name }}{% endif %}
{% endfor %}
...
</h1>
Examples:
page.full_url returns https://website/category/wall-hangings
category.permalink returns wall-hangings
I also tried a method using:
{{ page.full_url | remove: "https://website/category" | replace: "-" " " | capitalize }}
However, the replace method doesn't insert spaces.

I overcomplicated my original approach. Using {{ page.name }} returns the category name, so using this in the heading tag worked.

Related

What does this html tag mean in django's example?

This is django's polls demo, and most are well documented. However, in this part:
https://docs.djangoproject.com/en/3.0/intro/tutorial04/
<h1>{{ question.question_text }}</h1>
<ul>
{% for choice in question.choice_set.all %}
<li>{{ choice.choice_text }} -- {{ choice.votes }} vote{{ choice.votes|pluralize }}</li>
{% endfor %}
</ul>
Vote again?
The documentation doesn't say anything about this part:
vote{{ choice.votes|pluralize }}
And from the generated html page, I can't see what's the role of this piece?
pluralize is an in-built Django template tag that attempts to convert the word that it is appended to to plural. So you feed it a number, and if the number is 1 then it returns '', but if the number is greater than 1, it returns 's'.
https://docs.djangoproject.com/en/3.0/ref/templates/builtins/#pluralize

Unable to correctly parse URLs using Django template language

I currently am trying to link a researcher's name if they provided a link, otherwise if they provide a blank input or N/A, then I choose not to link their name. I use the information from the researcher object using Django's template language, but when I check the result it ends up linking all of them, and those without input just have href = "" which links back to the homepage.
I've tried using {{r.website_link|length}} instead, but that just creates errors and the page won't load. I'm a newbie to frontend so I'm not sure if my "if" statement is incorrect or if my HTML logic is incorrect.
<div>
{% for r in researcher %}
<div class="researcher">
{% if "{{r.website_link}}" != "N/A" and "{{r.website_link}}" != "" %}
<p><a class="researcherwebname" href="{{ r.website_link }}">{{ r.fullname|title}}</a> | {{ r.institution }} | {{r.position}} | <i>{{ r.des|capfirst }}</i></p>
{% else %}
<p> {{ r.fullname|title}} | {{ r.institution }} | {{r.position}} | <i>{{ r.des|capfirst }}</i></p>
{% endif %}
</div>
{% endfor %}
</div>
I expect it to link researchers with an actual r.website_link input, otherwise the name should be unlinked.
please try
{% if r.website_link %}
{% if r.website_link != "N/A" %}
{# display researcher #}
{% endif %}
{% endif %}

Django template if statement return wrong value

In my home page I have blog, on the right side there is Posts category list like:
Sports
Crime
and etc.. I try to make that when I'm in certain category that active category button will be highlighted.
I'm doing that by setting GET parameter to my home page like: /?category=1
NOW... In index.html template I'm doing this:
{% for category in category_list %}
{{ category.pk }} != {{ request.GET.category }} // This is for debugging. Returns 1==1
{% if category.pk == request.GET.category %}
<li>{{ category }}<span class="pull-right">({{ category.post_set.count }})</span></li>
{% else %}
<li class="active">{{ category }}<span class="pull-right">({{ category.post_set.count }})</span></li>
{% endif %}
{% endfor %}
But this is not working. Any suggestions how to solve this, maybe there is another way?
EDITED:
I figured that category.pk returns int and request.GET.category returns string. Next question. How to convert int<==>string, so I could compare them?
It worked by doing this:
{% if category.pk != request.GET.category|add:"0" %}
apparently |add:"0" converts string to int.

Variable subtraction in django templates

It is able to write {{ myval.add:5 }}, {{ myval|add:value }} and even {{ myval|add:-5 }}.
However, I can't find out what I should type to add value * -1 like {{ myval|add:-value }}. This doesn't work, sadly.
You need to use double quotes:
{{ myval|add:"-5" }}
This subtracts five from myval.
The built-in Django template tags/filters aren't all-encompassing, but it's super easy to write your own custom template tags: https://docs.djangoproject.com/en/dev/howto/custom-template-tags/
You could make your own subtract template tag pretty easily:
#register.filter
def subtract(value, arg):
return value - arg
Use django-mathfilters from PyPI: https://pypi.python.org/pypi/django-mathfilters
To install :
$ pip install django-mathfilters
Then add mathfilters in your INSTALLED_APPS.
In template:
{% load mathfilters %}
<ul>
<li>8 + 3 = {{ 8|add:3 }}</li>
<li>13 - 17 = {{ 13|sub:17 }}</li>
{% with answer=42 %}
<li>42 * 0.5 = {{ answer|mul:0.5 }}</li>
{% endwith %}
{% with numerator=12 denominator=3 %}
<li>12 / 3 = {{ numerator|div:denominator }}</li>
{% endwith %}
<li>|-13| = {{ -13|abs }}</li>
</ul>
I recently started working with Django and stumbled upon this one as well: I needed a very simple template loop that stops printing after n times and shows a "more" link to toggle the rest of the items.
With great interest I read the struggle of people trying to understand why this is not being added to the Django default filters (since before 2013). I didn't feel like creating a custom template tag and I kind of found a way to subtract 2 variables using strings and add in combination with with and stringformat
Let's say I have a list of items where I want to print the first 2 and hide the rest, showing how many hidden items are there, eg.
John, Anna and 5 others like this (when given a list of 7 items)
As long as the number of visible items is harcoded in the template (eg. 2), it's possible to add the negative 2 |add:"-2", but I wanted the number of visible items to be a variable as well. The Math-filter library as suggested above doesn't seem up to date (I haven't tested it with Django 2.x).
The trick seems to be to use the add helper to concat the strings "-" with the integer as string, so it can be coerced back to a negative integer in a any consecutive calls to the add helper. This doesn't work however if the value is not a string, so that's where the stringformat helper comes in.
With string value
template posts.html (note how visible is explicitely passed as string - alternative below)
{% for post in posts %}
<h4>{{ post.title }}</h4>
...
{% include 'show_likes.html' with likes=post.likes visible="3" %}
{% endfor %}
template show_likes.html (note the add:0 to make the boolean operator work)
{% with show=visible|default:"2" %}
{% for like in likes %}
{% if forloop.counter <= show|add:0 %}
{% if not forloop.first %},{% endif %}
{{ like.username }}
{% endif %}
{% endfor %}
{% if likes|length > show|add:0 %}
{% with rest="-"|add:show %}
and {{ likes|length|add:rest }} more
{% endwith %}
{% endif %}
like this
{% endwith %}
Alternative with integer
You could just convert your integer to a string in the calling template using |stringformat:"d"
If however the number of visible items you want to show is an integer, you'll have to add a call to stringformat:"d" to have it converted to string
template posts.html
{% for post in posts %}
<h4>{{ post.title }}</h4>
...
{% include 'show_likes.html' with likes=post.likes visible=3 %}
{% endfor %}
template show_likes.html
{% with show=visible|default:2 %}
{% with show_str=show|stringformat:"d" %}
{% for like in likes %}
{% if forloop.counter <= show %}
{% if not forloop.first %},{% endif %}
{{ like.username }}
{% endif %}
{% endfor %}
{% if likes|length > show|add:0 %}
{% with rest="-"|add:show_str %}
and {{ likes|length|add:rest }} more
{% endwith %}
{% endif %}
{% endwith %}
{% endwith %}
Since I'm a very beginner with Django and Python, I'm pretty sure this approach is far worse than actually creating a custom helper! So I'm not suggesting anyone should be using this. This was just my attempt on trying to solve this with the available template helpers and without any custom stuff.
Hope this helps
Lo primero es multiplicar por -1 para convertirlo en una valor negativo y guardarlo en una variable y posterior a usar la suma
The first thing is to multiply by -1 to turn it into a negative value
and save it in a variable and then use the add
{% widthratio val2 1 -1 as result %}
{{result|add:val1}}
After search I found that I can make {% with var=value %} with filters to make the arithmetic operations "with other variables or not"
For example: I have x = 5 and y = 3 and need to add the y's value to x value, all what I need is these steps:
1- Create variable x : {% with x=5 %}
2- Create variable y : {% with y=3 %}
3- In my HTML tags, say <h1>, write that : <h1>{{ x|add:y }}</h1>
4- Close the y's with : {% endwith %}
5- Close the x's with : {% endwith %}
Hope it works with you, it worked with me.
{% with i=3 %}
{% with x=1 %}
<h1>{{i|add:x}}</h1> <!-- result is 4 -->
{% endwith %}
{% endwith %}

Django template vars and list indices

I have a strange problem.
I use paginator to display some data in each page, however, I do not see any possibility to add other attributes I need to the model, so I have created another list of dicts with additional data.
In template:
{% for x in p.object_list %}
{% with c=forloop.counter0 %}
{{ info.c }} <!-- prints nothing, while {{ info }} prints all the list of dicts and {{ c }} prints 0, for example. {{ info.0 }} prints everything as intended too. -->
{% endwith %}
{% endfor %}
{{ info.c }} accesses info['c'], info.c, etc. You want the slice filter instead.