This is the original data, all the data are of two kinds: red and black. And then, I want to study the occurrence of all the blocks. The result will be like this:
It means the first streak of red(from index 1 to 3) has a length of 3, and the second streak which is black(from index 4 to 5) has a length of 2...
I want to find out an elegant way to calculate it but in sheets, it's very hard. COUNTIF and ROWS all can't perfectly resolve this problem.
Do you have an elegant way?
try:
=ARRAYFORMULA(QUERY(REGEXREPLACE(QUERY({TEXT(
VLOOKUP(ROW(B2:B20), QUERY((B2:B20<>B1:B19)*ROW(B2:B20),
"where Col1 <>0"), 1, 1), "000000")&"×"&B2:B20},
"select Col1,count(Col1) group by Col1 label count(Col1)''")&"", "(.+×)", ),
"where Col1 is not null"))
Not sure it's elegant, but you could add two helper columns, the first column checks if the record has changed, and the second counts until the next change using a MATCH. Note you'd need an extra "TRUE" below the last record to catch the last streak. Then you can use FILTER to show the blocks and occurances.
Related
I am trying to see if I am able to get the hours from one column only if it matches a word that is another column.
For example in the sheet link attached, if the word is Operations (Column A) I want to get the sum of all the hours (Column B) that correlate with that word.
https://docs.google.com/spreadsheets/d/1-1QCZsNTZ5xDcDryv8qg0YPtsoY3Erjz7ZNGUXds7HY/edit
Hope this makes sense.
Thanks in advance.
you can use:
=SUM(IFNA(FILTER(B:B,A:A=E1)))
OR
=SUMIF(A:A,E1,B:B)
Cell E1 has the word selection in the sample here
Loc1= FORMAT('Table'[LOC],"000") Any suggestion would be helpful? The original Column LOC is a text field with returns 3 characters with leading Zero's. I need it in numeric form to be able to join and use it in calculated columns.
Found a work around to fix my problem, I came up with a solution to keep Loc column as text and add concatenate column with Business Unit ID and Loc & convert concatenated col to numeric field so I can use for filtering and joining.
I have a column of data in binary values and I would like to split each digit of the number in the column into different cells across a row. How would I go about doing so? I saw the split function, but could not get it to work. https://support.google.com/docs/answer/3094136?
One of my example inputs:
1000111110100101111011110
1000110000100101000010000
try with this (you just change A2 to your cell):
=transpose(arrayformula(mid(A2,row(A1:offset(A1,len(A2),0)),1)))
For some rows (I limited text length with 30 char, you can change it):
=transpose(ARRAYFORMULA(mid(transpose(query(arrayformula(if(isnumber(A1:A)=true ,text(A1:A,"0"),A1:A)),"Select Col1 where Col1<>''")),row(A1:A30),1)))
try:
=ARRAYFORMULA(REGEXEXTRACT(A1:A, REPT("(.)", LEN(A1:A))))
I have a column (Column A) of cells with tracking information. Each cell contains the date shipped and a tracking number. I have another column (Column B) with a bunch of tracking numbers. How can I see if the tracking number in column B match any of the tracking numbers in Column A?
This is what I have tried:
=IF(RegExMatch(A1, TO_TEXT(B:B)),"YES","NO") but that's not working
All of the results are coming back as "YES" even though there is no match. Any thoughts on this?
=ARRAYFORMULA(IF(LEN(B:B), IF(IFERROR(VLOOKUP(""&B:B,
IFERROR(REGEXEXTRACT(A:A, TEXTJOIN("|", 1, B:B))), 1, 0))<>"", "YES", "NO"), ))
I have a list of products in calc (excel), each with an associated IP address. Many of the names have multiple IP addresses, however they are organized one column at a time. I am trying to remove all of the multiples and pull all of the IP addresses under a single name. I have tried nslookup and index match, they do not deal well with multiple outputs though. Right now it looks like this
a| 1
a| 2
a| 3
b| 1
b| 2
b| 3
etc...
I would like it to look like this
a 1,2,3
b 1,2,3
Is there any way to do this without wasting a ton of time, I have a few ways that work but they will take me forever to setup.
I recommend setting up your formulas in multiple "helper" cells before getting to the final "result cell". This breaks down the problem into smaller steps that are more easily formulated and, if needed in the future, updated. Once the setup is complete you can hide the helper columns by right-clicking on the column letter and choosing "Hide".
The first column to set up is the list of distinct product names. For the formula below to work, the product/IP list will need to be sorted in ascending order. If the list is not already sorted, to sort it first highlight the entire list, including headers. Then choose Data→Sort; select sort by "Product", make sure the radio button "Ascending" is selected, and press OK.
For purposes of this example, I'll assume product names are in column A, starting on row 2 and IPs are in column B starting on row 2 (with row 1 being the header labels). In the column where you want to list the distinct product names (I used column D), enter in the top cell =A2. In the cell below enter
=INDEX($A$2:$A$13;MATCH(D2;$A$2:$A$13;1)+1)
The match formula has a 1 as the third variable, meaning the range is sorted ascending and MATCH will return the position of the last matching cell. We add 1 to the position of the last matching cell, and this will be the position of the first cell with a new product name. That position is fed into the INDEX function to show the next product name.
Copy and paste that cell down as far as you need to show all the product names.
Now we'll set up a series of cells to display each IP address. I used columns F to I to show up to 4 addresses:
=IF(MATCH(D2;$A$2:$A$13;0)<=MATCH($D2;$A$2:$A$13;1);INDEX($B$2:$B$13;MATCH($D2;$A$2:$A$13;0));"")
=IF(MATCH(D2;$A$2:$A$13;0)+1<=MATCH(D2;$A$2:$A$13;1);INDEX($B$2:$B$13;MATCH(D2;$A$2:$A$13;0)+1);"")
=IF(MATCH(D2;$A$2:$A$13;0)+2<=MATCH(D2;$A$2:$A$13;1);INDEX($B$2:$B$13;MATCH(D2;$A$2:$A$13;0)+2);"")
=IF(MATCH(D2;$A$2:$A$13;0)+3<=MATCH(D2;$A$2:$A$13;1);INDEX($B$2:$B$13;MATCH(D2;$A$2:$A$13;0)+3);"")
MATCH with the third variable of 1 returns the position of the last matching cell; MATCH with the third variable of 0 returns the position of the first matching cell.
The IF statement checks if the position of the first matching cell (in the first lookup column) or the cell below that (in the second lookup column) or the cell two below the first match (in the third lookup column), etc. is less than or equal to the position of the last matching cell. If yes, then it looks up the relevant IP address. If no, it displays a blank.
In the formulas above you would need to manually enter the formula in the top row of each column. If you have some products with a large number of IP addresses, you may want to set up the formula so you can copy and paste between columns as well as down the rows. This would work if you were starting in column F:
=IF(MATCH($D2;$A$2:$A$13;0)+COLUMN()-6<=MATCH($D2;$A$2:$A$13;1);INDEX($B$2:$B$13;MATCH($D2;$A$2:$A$13;0)+COLUMN()-6);"")
Once you have your top row set up as you want, copy and paste down however many rows you need.
If you want to combine all the IPs into a single cell separated by commas, you can use a formula like this:
=CONCATENATE(F2;IF(G2<>"";","&G2;"");IF(H2<>"";","&H2;"");IF(I2<>"";","&I2;""))
Each IF statement will add a comma separator followed by the cell contents if the checked cell is not empty, otherwise it returns a blank string. You will need to manually adjust to add additional IF statements for however many maximum columns you want to concatenate. Again, once you have the top row set up, copy and paste down however far you need.
Assuming you have two columns (A and B), that these are labelled and sorted as shown, then enter in C2:
=IF(A1<>A2;B2;C1&","&B2)
and in D1:
=A1<>A2
Copy both down to suit, select ColumnC and Copy, Paste Special... with each Selection ticked other than Paste all and Formulas, click OK.
Select ColumnsA:D, Data > Filter > AutoFilter, click Yes and select 1 for ColumnD and all visible range.
Copy and paste into a new sheet, move B1 to C1 and delete Columns B and D.