I finished this code homework assignment tonight. I thought I was done, but I just realized that my "Average" value is coming out wrong with certain values. For example: When my professor entered the values 22, 66, 45.1, and 88 he got an "Average" of 55.27. However, when I enter those values in my program, I get an "Average" of 55.25. I have no idea what I am doing wrong. I was pretty confident in my program until I noticed that flaw. My program is due at midnight, so I am clueless on how to fix it. Any tips will be greatly appreciated!
Code Prompt: "Write a program that dynamically allocates an array large enough to hold a user-defined number of test scores. Once all the scores are entered, the array should be passed to a function that sorts them in ascending order. Another function should be called that calculates the average score. The program should display the sorted list of scores and averages with appropriate headings. Use pointer notation rather than array notation whenever possible."
Professor Notes: The book only states, "Input Validation: Do not accept negative numbers for test scores." We also need to have input validation for the number of scores. If it is negative, including 0, the program halts, we should consider this situation for 'counter' not to be negative while we have a loop to enter numbers. So negative numbers should be rejected for the number of scores and the values of scores.
Here is my code:
#include <iostream>
#include <iomanip>
using namespace std;
void showArray(double* array, int size);
double averageArray(double* array, int size);
void orderArray(double* array, int size);
int main()
{
double* scores = nullptr;
int counter;
double numberOfScores;
cout << "\nHow many test scores will you enter? ";
cin >> numberOfScores;
if (numberOfScores < 0) {
cout << "The number cannot be negative.\n"
<< "Enter another number: ";
cin >> numberOfScores;
}
if (numberOfScores == 0) {
cout << "You must enter a number greater than zero.\n"
<< "Enter another number: ";
cin >> numberOfScores;
}
scores = new double[numberOfScores];
for (counter = 0; counter < numberOfScores; counter++) {
cout << "Enter test score " << (counter + 1) << ": ";
cin >> *(scores + counter);
if (*(scores + counter) < 0) {
cout << "Negative scores are not allowed. " << endl
<< "Enter another score for this test : ";
cin >> *(scores + counter);
}
}
orderArray(scores, counter);
cout << "\nThe test scores in ascending order, and their average, are: " << endl
<< endl;
cout << " Score" << endl;
cout << " -----" << endl
<< endl;
showArray(scores, counter);
cout << "\nAverage Score: "
<< " " << averageArray(scores, counter) << endl
<< endl;
cout << "Press any key to continue...";
delete[] scores;
scores = nullptr;
system("pause>0");
}
void orderArray(double* array, int size)
{
int counterx;
int minIndex;
int minValue;
for (counterx = 0; counterx < (size - 1); counterx++) {
minIndex = counterx;
minValue = *(array + counterx);
for (int index = counterx + 1; index < size; index++) {
if (*(array + index) < minValue) {
minValue = *(array + index);
minIndex = index;
}
}
*(array + minIndex) = *(array + counterx);
*(array + counterx) = minValue;
}
}
double averageArray(double* array, int size)
{
int x;
double total{};
for (x = 0; x < size; x++) {
total += *(array + x);
}
double average = total / size;
return average;
}
void showArray(double* array, int size)
{
for (int i = 0; i < size; i++) {
cout << " " << *(array + i) << endl;
}
}
I try to start my answers with a brief code review:
#include <iostream>
#include <iomanip>
using namespace std; // Bad practice; avoid
void showArray(double* array, int size);
double averageArray(double* array, int size);
void orderArray(double* array, int size);
int main()
{
double* scores = nullptr;
int counter;
double numberOfScores;
cout << "\nHow many test scores will you enter? ";
cin >> numberOfScores;
// This is not input validation, I can enter two consecutive bad values,
// and the second one will be accepted.
if (numberOfScores < 0) {
// Weird formatting, this blank line
cout << "The number cannot be negative.\n"
<< "Enter another number: ";
cin >> numberOfScores;
}
// The homework, as presented, doesn't say you have to treat 0 differently.
if (numberOfScores == 0) {
cout << "You must enter a number greater than zero.\n"
<< "Enter another number: ";
cin >> numberOfScores;
}
scores = new double[numberOfScores];
// Declare your loop counter in the loop
for (counter = 0; counter < numberOfScores; counter++) {
cout << "Enter test score " << (counter + 1) << ": ";
cin >> *(scores + counter);
if (*(scores + counter) < 0) {
cout << "Negative scores are not allowed. " << endl
<< "Enter another score for this test : ";
cin >> *(scores + counter);
}
}
orderArray(scores, counter); // Why not use numberOfScores?
cout << "\nThe test scores in ascending order, and their average, are: " << endl
<< endl;
cout << " Score" << endl;
cout << " -----" << endl
<< endl;
showArray(scores, counter); // Same as above.
cout << "\nAverage Score: "
<< " " << averageArray(scores, counter) << endl
<< endl;
cout << "Press any key to continue...";
delete[] scores;
scores = nullptr;
system("pause>0"); // Meh, I suppose if you're on VS
}
void orderArray(double* array, int size)
{
int counterx;
int minIndex;
int minValue; // Unnecessary, and also the culprit
// This looks like selection sort
for (counterx = 0; counterx < (size - 1); counterx++) {
minIndex = counterx;
minValue = *(array + counterx);
for (int index = counterx + 1; index < size; index++) {
if (*(array + index) < minValue) {
minValue = *(array + index);
minIndex = index;
}
}
*(array + minIndex) = *(array + counterx);
*(array + counterx) = minValue;
}
}
double averageArray(double* array, int size)
{
int x;
double total{};
for (x = 0; x < size; x++) {
total += *(array + x);
}
double average = total / size;
return average;
}
void showArray(double* array, int size)
{
for (int i = 0; i < size; i++) {
cout << " " << *(array + i) << endl;
}
}
When you are sorting your array, you keep track of the minValue as an int and not a double. That's why your average of the sample input is incorrect. 45.1 is truncated to 45 for your calculations. You don't need to keep track of the minValue at all. Knowing where the minimum is, and where it needs to go is sufficient.
But as I pointed out, there are some other serious problems with your code, namely, your [lack of] input validation. Currently, if I enter two consecutive bad numbers, the second one will be accepted no matter what. You need a loop that will not exit until a good value is entered. It appears that you are allowed to assume that it's always a number at least, and not frisbee or any other non-numeric value.
Below is an example of what your program could look like if your professor decides to teach you C++. It requires that you compile to the C++17 standard. I don't know what compiler you're using, but it appears to be Visual Studio Community. I'm not very familiar with that IDE, but I imagine it's easy enough to set in the project settings.
#include <algorithm>
#include <iomanip>
#include <iostream>
#include <numeric>
#include <string>
#include <vector>
// Assumes a number is always entered
double positive_value_prompt(const std::string& prompt) {
double num;
std::cout << prompt;
do {
std::cin >> num;
if (num <= 0) {
std::cerr << "Value must be positive.\n";
}
} while (num <= 0);
return num;
}
int main() {
// Declare variables when you need them.
double numberOfScores =
positive_value_prompt("How many test scores will you enter? ");
std::vector<double> scores;
for (int counter = 0; counter < numberOfScores; counter++) {
scores.push_back(positive_value_prompt("Enter test score: "));
}
std::sort(scores.begin(), scores.end());
for (const auto& i : scores) {
std::cout << i << ' ';
}
std::cout << '\n';
std::cout << "\nAverage Score: "
<< std::reduce(
scores.begin(), scores.end(), 0.0,
[size = scores.size()](auto mean, const auto& val) mutable {
return mean += val / size;
})
<< '\n';
}
And here's an example of selection sort where you don't have to worry about the minimum value. It requires that you compile to C++20. You can see the code running here.
#include <iostream>
#include <random>
#include <vector>
void selection_sort(std::vector<int>& vec) {
for (int i = 0; i < std::ssize(vec); ++i) {
int minIdx = i;
for (int j = i + 1; j < std::ssize(vec); ++j) {
if (vec[j] < vec[minIdx]) {
minIdx = j;
}
}
int tmp = vec[i];
vec[i] = vec[minIdx];
vec[minIdx] = tmp;
}
}
void print(const std::vector<int>& v) {
for (const auto& i : v) {
std::cout << i << ' ';
}
std::cout << '\n';
}
int main() {
std::mt19937 prng(std::random_device{}());
std::uniform_int_distribution<int> dist(1, 1000);
std::vector<int> v;
for (int i = 0; i < 10; ++i) {
v.push_back(dist(prng));
}
print(v);
selection_sort(v);
print(v);
}
I opted not to give your code the 'light touch' treatment because than I would have done your homework for you, and that's just not something I do. However, the logic shown should still be able to guide you toward a working solution.
Related
(Sorry if this is formatted terribly. I've never posted before.)
I've been working on a program for class for a few hours and I can't figure out what I need to do to my function to get it to do what I want. The end result should be that addUnique will add unique inputs to a list of its own.
#include <iostream>
using namespace std;
void addUnique(int a[], int u[], int count, int &uCount);
void printInitial(int a[], int count);
void printUnique(int u[], int uCount);
int main() {
//initial input
int a[25];
//unique input
int u[25];
//initial count
int count = 0;
//unique count
int uCount = 0;
//user input
int input;
cout << "Number Reader" << endl;
cout << "Reads back the numbers you enter and tells you the unique entries" << endl;
cout << "Enter 25 positive numbers. Enter '-1' to stop." << endl;
cout << "-------------" << endl;
do {
cout << "Please enter a positive number: ";
cin >> input;
if (input != -1) {
a[count++] = input;
addUnique(a, u, count, uCount);
}
} while (input != -1 && count < 25);
printInitial(a, count);
printUnique(u, uCount);
cout << "You entered " << count << " numbers, " << uCount << " unique." << endl;
cout << "Have a nice day!" << endl;
}
void addUnique(int a[], int u[], int count, int &uCount) {
int index = 0;
for (int i = 0; i < count; i++) {
while (index < count) {
if (u[uCount] != a[i]) {
u[uCount++] = a[i];
}
index++;
}
}
}
void printInitial(int a[], int count) {
int lastNumber = a[count - 1];
cout << "The numbers you entered are: ";
for (int i = 0; i < count - 1; i++) {
cout << a[i] << ", ";
}
cout << lastNumber << "." << endl;
}
void printUnique(int u[], int uCount) {
int lastNumber = u[uCount - 1];
cout << "The unique numbers are: ";
for (int i = 0; i < uCount - 1; i++) {
cout << u[i] << ", ";
}
cout << lastNumber << "." << endl;
}
The problem is my addUnique function. I've written it before as a for loop that looks like this:
for (int i = 0; i < count; i++){
if (u[i] != a[i]{
u[i] = a[i]
uCount++;
}
}
I get why this doesn't work: u is an empty array so comparing a and u at the same spot will always result in the addition of the value at i to u. What I need, is for this function to scan all of a before deciding whether or no it is a unique value that should be added to u.
If someone could point me in the right direction, it would be much appreciated.
Your check for uniqueness is wrong... As is your defintion of addUnique.
void addUnique(int value, int u[], int &uCount)
{
for (int i = 0; i < uCount; i++){
if (u[i] == value)
return; // already there, nothing to do.
}
u[uCount++] = value;
}
So, I'm creating a coin change algorithm that take a Value N and any number of denomination and if it doesn't have a 1, i have to include 1 automatically. I already did this, but there is a flaw now i have 2 matrix and i need to use 1 of them. Is it possible to rewrite S[i] matrix and still increase the size of array.... Also how can i find the max denomination and the second highest and sooo on till the smallest? Should i just sort it out in an highest to lowest to make it easier or is there a simpler way to look for them one after another?
int main()
{
int N,coin;
bool hasOne;
cout << "Enter the value N to produce: " << endl;
cin >> N;
cout << "Enter number of different coins: " << endl;
cin >> coin;
int *S = new int[coin];
cout << "Enter the denominations to use with a space after it" << endl;
cout << "(1 will be added if necessary): " << endl;
for(int i = 0; i < coin; i++)
{
cin >> S[i];
if(S[i] == 1)
{
hasOne = true;
}
cout << S[i] << " ";
}
cout << endl;
if(!hasOne)
{
int *newS = new int[coin];
for(int i = 0; i < coin; i++)
{
newS[i] = S[i];
newS[coin-1] = 1;
cout << newS[i] << " ";
}
cout << endl;
cout << "1 has been included" << endl;
}
//system("PAUSE");
return 0;
}
You could implement it with std::vector, then you only need to use push_back.
std::sort can be used to sort the denominations into descending order, then it's just a matter of checking whether the last is 1 and adding it if it was missing. (There is a lot of error checking missing in this code, for instance, you should probably check that no denomination is >= 0, since you are using signed integers).
#include <iostream> // for std::cout/std::cin
#include <vector> // for std::vector
#include <algorithm> // for std::sort
int main()
{
std::cout << "Enter the value N to produce:\n";
int N;
std::cin >> N;
std::cout << "Enter the number of different denominations:\n";
size_t denomCount;
std::cin >> denomCount;
std::vector<int> denominations(denomCount);
for (size_t i = 0; i < denomCount; ++i) {
std::cout << "Enter denomination #" << (i + 1) << ":\n";
std::cin >> denominations[i];
}
// sort into descending order.
std::sort(denominations.begin(), denominations.end(),
[](int lhs, int rhs) { return lhs > rhs; });
// if the lowest denom isn't 1... add 1.
if (denominations.back() != 1)
denominations.push_back(1);
for (int coin: denominations) {
int numCoins = N / coin;
N %= coin;
if (numCoins > 0)
std::cout << numCoins << " x " << coin << '\n';
}
return 0;
}
Live demo: http://ideone.com/h2SIHs
So I'm trying to create an array that contains some user inputted names, and then associate those names with letter grades from tests (ex: A, B, C, D, F). My question is, how would I use an array to accept the user inputted names?
EDIT:
Sorry this is a bit long, I don't know what part to put that would help out. Totally new to C++ and I can't seem to find anything online regarding the matter, lol.
Here is some code. This program currently asks the user for test scores, then displays and drops the lowest test score, and finally, calculates the average of the scores without the lowest one. The end goal is to ask the user for 5 students names, and 4 scores for each student, then dropping the lowest score for each student and calculating the averages of ALL scores inputted regardless of student.
#include <iostream>
#include <string>
using namespace std;
void getScore(int &);
int findLowest(int [], int);
void calcAverage(int [], int);
int main () {
const int NUM_SCORES = 5;
int scores[NUM_SCORES];
cout << "Welcome to test averages." << endl;
cout << "Please enter scores for " << NUM_SCORES << " students." << endl;
cout << endl;
for (int i = 0; i < NUM_SCORES; i++) {
getScore(scores[i]);
}
for (int i = 0; i < NUM_SCORES; i++) {
cout << "Score " << (i + 1) << ": " << scores[i] << endl;
}
cout << endl;
cout << "The lowest of these scores is " << findLowest(scores, NUM_SCORES) << endl;
calcAverage(scores, NUM_SCORES);
return 0;
}
void getScore(int & s) {
s = -1;
cout << "Please enter a test score: ";
cin >> s;
while (s < 0 || s > 100) {
cout << "Score range must be from 0-100" << endl;
cout << "Please re-enter a score: ";
cin >> s;
}
}
int findLowest(int theArray [], int theArraySize) {
int lowest = theArray[0];
for (int i = 1; i < theArraySize; i++) {
if (theArray[i] < lowest) {
lowest = theArray[i];
}
}
return lowest;
}
void calcAverage(int theArray [], int theArraySize) {
int sum = 0;
for (int i = 0; i < theArraySize; i++) {
sum += theArray[i];
}
double average = (sum - findLowest(theArray, theArraySize)) / (theArraySize - 1.0);
cout << "The average is " << average << endl;
}
Try getline from #include <string>
std::string names[5];
for (int i = 0; i < 5; ++i){
getline(std::cin, names[i]);
}
I'm a relatively new learner to C++ and I've been having some trouble. If you guys read the title, this is a homework problem (just letting you guys know out there) and I'm not really sure as to where my error is. Using GIT Bash, I can't see why this isn't compiling (or maybe i just don't know how to read it). I feel like i've touched upon all the bases and would appreciate a quick look over to see if my mistake is blaringly obvious. I've done a couple looks through stackoverflow and so the inputting values into a vector was used from another post but i've modified it a bit. In addition, I added in a sort for the vector from smallest to largest.
Also, how can I change the for statement to allow for variable #'s in the vector?
#include <iostream>
#include <vector>
using namespace std;
double showMedian(const vector<int> & vecmedian, int size)
{
int middle;
double average, median;
middle = size / 2.0;
if (size % 2 == 0)
{
median = (vecmedian[middle] + vecmedian[middle + 1]) / 2.0;
cout << "The median is: " << average << endl;
}
else
{
median = vecmedian[middle + 0] / 1.0;
cout << "The median is: " << median << endl;
}
return median;
}
int main()
{
int n,input, i;
vector<int> vecmedian;
vector<int>::iterator itr;
cout << "Enter the amount of numbers: ";
cin >> n;
cout << "Enter your numbers to be evaluated: " << endl;
while (vecmedian.size() < n && cin >> input){
vecmedian.push_back(input);
}
for(i = 1; i < 10; ++i){
for(itr = vecmedian.begin(); itr != vecmedian.end(); ++itr){
if(vecmedian[i] < *itr){
vecmedian.insert(itr, vecmedian[i]);
break;
}
}
if(itr == vecmedian.end())
vecmedian.push_back(vecmedian[i]);
}
showMedian();
return 0;
}
Point 1
When making function prototypes, you need to keep them consistent with the actual definition of the function.
You have:
void showMedian();
As a function-prototype but you have:
double showMedian(int *vecmedian, int size)
As the actual definition. They both need to be consistent.
Since you have not declared an array, maybe change the parameters of showMedian to:
double showMedian(const vector<int> & vecmedian, int size)
Point 2
if(nums[i] < *itr)
Where is nums declared?
Point 3
If you want to use the definition of showMedian, then use the parameters that it uses assuming you made the changes above (and assuming n is size).
showMedian(vecmedian, n);
Edit
With all the consulting in the comment section and the new updated OP Question, here is a fairly solid program which finds the median in a vector:
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
double showMedian(const vector<double> & vecmedian, int num);
int main()
{
unsigned int n;
double input;
vector<double> vecmedian;
// cout << "Enter the amount of numbers: ";
do {
cout << "Enter the amount of numbers: ";
while(!(cin >> n)){
cout << "Wrong input" << endl;
cout << "Enter the amount of numbers: ";
cin.clear();
cin.ignore(numeric_limits<streamsize>::max(), '\n');
}
if (n == 0)
{
cout << "Invalid, size must be greater than 0" << endl;
}
} while (n == 0);
// cout << "Enter your numbers to be evaluated: " << endl;
for (int i = 1; i <= n; ++i)
{
cout << "Enter number here (" << ((n + 1) - i) << " number/s remaining): ";
while(!(cin >> input)){
cout << "Wrong input" << endl;
cout << "Enter number here (" << ((n + 1) - i) << " number/s remaining): ";
cin.clear();
cin.ignore(numeric_limits<streamsize>::max(), '\n');
}
vecmedian.push_back(input);
}
// while (vecmedian.size() < n && cin >> input){
// vecmedian.push_back(input);
// }
sort(vecmedian.begin(), vecmedian.end());
showMedian(vecmedian, vecmedian.size());
return 0;
}
double showMedian(const vector<double> & vecmedian, int num)
{
int middle;
double median;
middle = (num / 2);
if (num % 2)
median = vecmedian[middle];
else
median = (vecmedian[middle - 1] + vecmedian[middle]) / 2.0;
cout << "The median is: " << median << endl;
return median;
}
#include <iostream>
#include <iomanip>
using namespace std;
// Function Prototype
void sortArray(int array[], int size);
void showArray(const int arr[], int size);
void average(int testScores[], int size);
int main()
{
int *testScores;
int numGrades,count;
cout << "How many grades? " << endl;
cin >> numGrades;
testScores = new int[numGrades];
cout << "Please enter the scores below." << endl;
for (count = 0; count < numGrades; count++)
{
cin >> testScores[count];
}
sortArray(testScores, numGrades);
showArray(testScores, numGrades);
average(testScores, numGrades);
delete[] testScores;
testScores = 0;
system("pause");
return (0);
}
//function for ascending order
int * testScores[];
void sortArray(int array[], int size)
{
bool swap;
int temp;
do
{
swap = false;
for (int count = 0; count < (size - 1); count++)
{
if (array[count]> array[count + 1])
{
temp = array[count];
array[count] = array[count + 1];
array[count + 1] = temp;
swap = true;
}
}
} while (swap);
}
// display array function
void showArray(const int arr[], int size)
{
cout << " Scores in ascending order." << endl;
for (int count = 0; count < size; count++)
{
cout << " " << arr[count] << "";
}
cout << endl;
cout << endl;
}
// function to get average of the array
void average(int testScores[], int numGrades)
{
float total = 0.0;
for (int count = 0; count < numGrades; count++)
{
total += testScores[count];
}
float average = total / numGrades;
cout << " This is the average of the scores entered." << endl;
cout << endl;
cout << fixed << showpoint << setprecision(2);
cout << " *** " << average << " ***" << endl;
}
So this program was made to allow students to enter as many test scores as they want and the program will show them in ascending order and then will calculate the average of all test scores. It works wonderful until you enter a negative test score and then it throws the averaging process off. I can't seem to be able to make the program not accept the negative numbers. Any clues or hints would work wonders! Please and Thank You.
You are doing this:-
cin >> testScores[count];
This would accept all integers positive as well as negative. One way is to check the number, if it's positive then insert it into array.