unexpected delay in main thread - c++

Here is a small c++ code to test cyclic call using thread. But it gets failed because of unexpected delay sometimes. The for-loop should be called every 10ms. The runtime of for-loop is just 1ms usually. But sometimes the execution time is longer than 200ms. It looks like other process interrupts this for-loop and return back after 200ms. This is unbelievable, 200ms, so long time is taken. The program runs under GNU Linux 5.10.41 ARM aarch64.
How can I do, so that the main thread can not be preemptive by other process or threads ? Thanks a lot!
while(1)
{
auto start_time = std::chrono::high_resolution_clock::now();
LOG_F(INFO, "cyclic start time");
for(int j = 0; j < 150000; j++); //
auto end_time = std::chrono::high_resolution_clock::now();
auto exec_time = std::chrono::duration_cast<std::chrono::milliseconds>(end_time - start_time);
LOG_F(INFO, "execution time: %dms", exec_time.count());
if (exec_time.count() < 10)
{
LOG_F(INFO, "i = %d", i);
std::this_thread::sleep_for(std::chrono::milliseconds(10 - exec_time.count()));
}
else
{
LOG_F(ERROR, "execution time was higher than 10ms (%dms)", exec_time.count());
break;
}
}

It is working after remove logging statements. Logging is really a mutex hog like #Frebreeze mentioned. Actually the logging statements can be kept in code, just call program with -v ERROR. Thank you very much for the Help !
It looks that the logging is the reason. But why does the logging statements take so long time, but not always, just like a heartbeat ?

Correct answer written in original answer in comments:
Shot in the dark. Logging mutex hog. There likely is a mutex/lock
within your logging system. Another thread may be a resource hog
acquiring the lock and not releasing it quickly. This would cause THIS
thread to wait much longer than expected. Check this behaviour by
disabling all other threads and see if behaviour continues.
Follow up help below:
#Jung Glad you figured it out!
If logging is taking variable amounts of time, look into the data you are passing to the logging system. General things to lookout for would be large data structs passed by value. Yes I know compilers are smart now, but just something to keep an eye out for.
One of the methods I sometimes use to reduce log hogs is to use a dedicated thread for writing log statements to file. This thread uses a std::vector or queue. When vector.size() > 8, then dump it to the file(s). If you have a method of setting priority, you can then also then assign prio. This gets us into RTOS ideas. Can look into that if you need strict timings.
Workflow
Suppose sensor1 thread writes log statement.
Sensor1 thread adds data to std::vec
Suppose sensor2 thread writes log statement
Sensor2 thread adds data to std::vec
....
Once std::vec > 8 fire event to wake up thread
Thread wakes up, and once given CPU time, begins writing to file
This will help minimize the time spent locking mutexs as well as minimize time spent opening files. However, it is at the cost of memory. Play with the queue size to reach your desired goals.

Related

Efficient way to stop a loop after specific number of seconds

I have a loop in C++ that I would like to run for a few seconds. Although the amount of work on every iteration is different, from a few microseconds to seconds, it is ok to stop between iterations. It is high-performance code so I would like to avoid calculating time difference on each iteration:
while (!status.has_value())
{
// do something
// this adds extra delays that I would like to avoid
if (duration_cast<seconds>(system_clock::now() - started).count() >= limit)
status = CompletedBy::duration;
}
What I'm thinking is maybe there is a way to schedule signal and then stop the loop when it happens instead of checking the time difference on every iteration.
BTW, the loop may exit before the signal.
I have done something similar, but in Java. The general idea is to use a separate thread to manage a sentinel value, making your loop look like...
okayToLoop = true;
// code to launch thread that will wait N milliseconds, and then negate okayToLoop
while((!status.hasValue()) AND (okayToLoop)) {
// loop code
}
The "cautionary note" is that many sleep() functions for threads employ "sleep at least" semantics, so if it is really important to only sleep N milliseconds, you'll need to address that in your thread implementation. But, this avoids constantly checking the duration for each iteration of the loop.
Note that this will also allow the current iteration of the loop to finish, before the sentinel value is checked. I have also implemented this approach where the "control thread" actually interrupts the thread on which the loop is executing, interrupting the iteration. When I've done this, I've actually put the loop into a worker thread.
Any form of inter-thread communication is going to be way slower than a simple query of a high performance clock.
Now, steady_clock::now() might be too slow in the loop.
Using OS specific APIs, bind your thread to have ridiculous priority and affinity for a specific CPU. Or use rdtsc, after taking into account everything that can go wrong. Calculate what value you'd expect to get if (a) something went wrong, or (b) you have passed the time threshold.
When that happens, check steady_clock::now(), see if you are close enough to being done, and if so finish. If not, calculate a new high performance clock target and loop again.

Is an un-delayed infinite while loop bad practice? [closed]

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In short: Does an un-delayed while loop consume significant processing power, compared to a similar loop which is slowed down by a delay?
In not-so-short:
I have run into this question more often. I am writing the core part of a program (either microcontroller unit or computer application) and it consists of a semi-infinite while loop to stay alive and look for events.
I will take this example: I have a small application that uses an SDL window and the console. In a while loop I would like to listen to events for this SDL window, but I would also like to break this loop according to the command line input by means of a global variable. Possible solution (pseudo-code):
// Global
bool running = true;
// ...
while (running)
{
if (getEvent() == quit)
{
running = false;
}
}
shutdown();
The core while loop will quit from the listened event or something external. However, this loop is run continuously, maybe even a 1000 times per second. That's a little over-kill, I don't need that response time. Therefore I often add a delaying statement:
while (running)
{
if (getEvent() == quit)
{
running = false;
}
delay(50); // Wait 50 milliseconds
}
This limits the refresh rate to 20 times per second, which is plenty.
So. Is there a real difference between the two? Is it significant? Would it be more significant on the microcontroller unit (where processing power is very limited (but nothing else besides the program needs to run...))?
Well, in fact it's not a question about C++, but rather the answer depends on CPU architecture / Host OS / delay() implementation.
If it's a multi-tasking environment then delay() could (and probably will) help to the OS scheduler to make its job more effectively. However the real difference could be too little to notice (except old cooperative multi-tasking where delay() is a must).
If it's a single-task environment (possibly some microcontroller) then delay() could still be useful if the underlying implementation is able to execute some dedicated low power consumption instructions instead of your ordinary loop. But, of course, there's no guarantee it will, unless your manual explicitly states so.
Considering performance issues, well, it's obvious that you can receive and process an event with a significant delay (or even miss it completely), but if you believe it's not a case then there are no other cons against delay().
You will make your code much harder to read and you are doing asynchronism the old style way: you explicitely wait for something to happen, instead of relying on mechanism that do the job for you.
Also, you delay by 50ms. Is it always optimal? Does it depend on which programs are running?
In C++11 you can use condition_variable. This allows you to wait for an event to happen, without coding the waiting loops.
Documentation here:
http://en.cppreference.com/w/cpp/thread/condition_variable
I have adapted the example to make it simpler to understand. Just waiting for a single event.
Here is an example for you, adapted to your context
// Example program
#include <iostream>
#include <string>
#include <iostream>
#include <string>
#include <thread>
#include <mutex>
#include <chrono>
#include <condition_variable>
std::mutex m;
std::condition_variable cv;
std::string data;
bool ready = false;
bool processed = false;
using namespace std::chrono_literals;
void worker_thread()
{
// Wait until main() sends data
std::unique_lock<std::mutex> lk(m);
std::cout << "Worker thread starts processing data\n";
std::this_thread::sleep_for(10s);//simulates the work
data += " after processing";
// Send data back to main()
processed = true;
std::cout << "Worker thread signals data processing completed"<<std::endl;
std::cout<<"Corresponds to you getEvent()==quit"<<std::endl;
// Manual unlocking is done before notifying, to avoid waking up
// the waiting thread only to block again (see notify_one for details)
lk.unlock();
cv.notify_one();
}
int main()
{
data = "Example data";
std::thread worker(worker_thread);
// wait for the worker
{
std::unique_lock<std::mutex> lk(m);
//this means I wait for the processing to be finished and I will be woken when it is done.
//No explicit waiting
cv.wait(lk, []{return processed;});
}
std::cout<<"data processed"<<std::endl;
}
In my experience, you must do something that will relinquish the processor. sleep works OK, and on most windows systems even sleep(1) is adequate to completely unload the processor in a loop.
You can get the best of all worlds, however, if you use something like std::condition_variable. It is possible to come up with constructions using condition variables (similar to 'events' and WaitForSingleObject in Windows API).
One thread can block on a condition variable that is released by another thread. This way, one thread can do condition_varaible.wait(some_time), and it will either wait for the timeout period (without loading the processor), or it will continue execution immediately when another thread releases it.
I use this method where one thread is sending messages to another thread. I want the receiving thread to respond as soon as possible, not after waiting for a sleep(20) to complete. The receiving thread has a condition_variable.wait(20), for example. The sending thread sends a message, and does a corresponding condition_variable.release(). The receiving thread will immediately release and process the message.
This solution gives very fast response to messages, and does not unduly load the processor.
If you don't care about portability, and you happen to be using windows, events and WaitForSingleObject do the same thing.
your loop would look something like:
while(!done)
{
cond_var.wait(std::chrono::milliseconds(20));
// process messages...
msg = dequeue_message();
if(msg == done_message)
done = true;
else
process_message(msg);
}
In another thread...
send_message(string msg)
{
enqueue_message(msg);
cond_var.release();
}
Your message processing loop will spend most if it's time idle, waiting on the condition variable. When a message is sent, and the condition variable is released by the send thread, your receive thread will immediately respond.
This allows your receive thread to loop at a minimum rate set by the wait time, and a maximum rated determined by the sending thread.
What you are asking is how to properly implement an Event Loop. Use OS calls. You ask the OS for event or message. If no message is present, the OS simply sends the process to sleep. In a micro-controller environment you probably don't have an OS. There the concept of interrupts has to be used, which pretty much an "message" (or event) on lower level.
And for microcontrollers you don't have concepts like sleeping or interrupts, so you end with just looping.
In your example, a properly implemented getEvent() should block and do nothing until something actually happens, e.g. a key press.
The best way to determine that is to measure it yourself.
Undelayed loop will result in 100% usage for that specific core the app is running on. With the delay statement, it will be around 0 - 1%.
(counting on immediate response of getEvent function)
Well, that depends on a few factors - if you don't need to run anything else besides that loop in parallel, it makes no performance difference, obviously.
But a problem that might come up is power consumption - depending on how long this loop is, you might save like 90% of the power consumed by the microcontroller in the second variant.
To call it a bad practice overall doesn't seem right to me - it works in a lot of scenarios.
As I know about while loop, the process is still kept in the ram. So its not going to let the processor use its resource while its given delay. The only difference it is making in the second code is the number of executions of while loop in a given amount of time. This helps if the program is running for long time. Else no problem with the first case.

Windows critical sections fairness

I've a question about the fairness of the critical sections on Windows, using EnterCriticalSection and LeaveCriticalSection methods. The MSDN documentation specifies: "There is no guarantee about the order in which threads will obtain ownership of the critical section, however, the system will be fair to all threads."
The problem comes with an application I wrote, which blocks some threads that never enter critical section, even after a long time; so I perfomed some tests with a simple c program, to verify this behaviour, but I noticed strange results when you have many threads an some wait times inside.
This is the code of the test program:
CRITICAL_SECTION CriticalSection;
DWORD WINAPI ThreadFunc(void* data) {
int me;
int i,c = 0;;
me = *(int *) data;
printf(" %d started\n",me);
for (i=0; i < 10000; i++) {
EnterCriticalSection(&CriticalSection);
printf(" %d Trying to connect (%d)\n",me,c);
if(i!=3 && i!=4 && i!=5)
Sleep(500);
else
Sleep(10);
LeaveCriticalSection(&CriticalSection);
c++;
Sleep(500);
}
return 0;
}
int main() {
int i;
int a[20];
HANDLE thread[20];
InitializeCriticalSection(&CriticalSection);
for (i=0; i<20; i++) {
a[i] = i;
thread[i] = CreateThread(NULL, 0, ThreadFunc, (LPVOID) &a[i], 0, NULL);
}
}
The results of this is that some threads are blocked for many many cycles, and some others enter critical section very often. I also noticed if you change the faster Sleep (the 10 ms one), everything might returns to be fair, but I didn't find any link between sleep times and fairness.
However, this test example works much better than my real application code, which is much more complicated, and shows actually starvation for some threads. To be sure that starved threads are alive and working, I made a test (in my application) in which I kill threads after entering 5 times in critical section: the result is that, at the end, every thread enters, so I'm sure all of them are alive and blocked on the mutex.
Do I have to assume that Windows is really NOT fair with threads?
Do you know any solution for this problem?
EDIT: The same code in linux with pthreads, works as expected (no thread starves).
EDIT2: I found a working solution, forcing fairness, using a CONDITION_VARIABLE.
It can be inferred from this post (link), with the required modifications.
You're going to encounter starvation issues here anyway since the critical section is held for so long.
I think MSDN is probably suggesting that the scheduler is fair about waking up threads but since there is no lock acquisition order then it may not actually be 'fair' in the way that you expect.
Have you tried using a mutex instead of a critical section? Also, have you tried adjusting the spin count?
If you can avoid locking the critical section for extended periods of time then that is probably a better way to deal with this.
For example, you could restructure your code to have a single thread that deals with your long running operation and the other threads queue requests to that thread, blocking on a completion event. You only need to lock the critical section for short periods of time when managing the queue. Of course if these operations must also be mutually exclusive to other operations then you would need to be careful with that. If all of this stuff can't operate concurrently then you may as well serialize that via the queue too.
Alternatively, perhaps take a look at using boost asio. You could use a threadpool and strands to prevent multiple async handlers from running concurrently where synchronization would otherwise be an issue.
I think you should review a few things:
in 9997 of 10000 cases you branch to Sleep(500). Each thread holds the citical section for as much as 500 ms on almost every successful attempt to acquire the critical section.
The threads do another Sleep(500) after releasing the critical section. As a result a single thread occupies almost 50 % (49.985 %) of the availble time by holding the critical section - no matter what!
Behind the scenes: Joe Duffy: The wait lists for mutually exclusive locks are kept in FIFO order, and the OS always wakes the thread at the front of such wait queues.
Assuming you did that on purpose to show the behavior: Starting 20 of those threads may result in a minimum wait time of 10 seconds for the last thread to get access to the critical section on a single logical processor when the processor is completely available for this test.
For how long dif you do the test / What CPU? And what Windows version? You should be able to write down some more facts: A histogram of thread active vs. thread id could tell a lot about fairness.
Critical sections shall be acquired for short periods of time. In most cases shared resources can be dealt with much quicker. A Sleep inside a critical section almost certainly points to a design flaw.
Hint: Reduce the time spent inside the critical section or investigate Semaphore Objects.

C++11 Thread waiting behaviour: std::this_thread::yield() vs. std::this_thread::sleep_for( std::chrono::milliseconds(1) )

I was told when writing Microsoft specific C++ code that writing Sleep(1) is much better than Sleep(0) for spinlocking, due to the fact that Sleep(0) will use more of the CPU time, moreover, it only yields if there is another equal-priority thread waiting to run.
However, with the C++11 thread library, there isn't much documentation (at least that I've been able to find) about the effects of std::this_thread::yield() vs. std::this_thread::sleep_for( std::chrono::milliseconds(1) ); the second is certainly more verbose, but are they both equally efficient for a spinlock, or does it suffer from potentially the same gotchas that affected Sleep(0) vs. Sleep(1)?
An example loop where either std::this_thread::yield() or std::this_thread::sleep_for( std::chrono::milliseconds(1) ) would be acceptable:
void SpinLock( const bool& bSomeCondition )
{
// Wait for some condition to be satisfied
while( !bSomeCondition )
{
/*Either std::this_thread::yield() or
std::this_thread::sleep_for( std::chrono::milliseconds(1) )
is acceptable here.*/
}
// Do something!
}
The Standard is somewhat fuzzy here, as a concrete implementation will largely be influenced by the scheduling capabilities of the underlying operating system.
That being said, you can safely assume a few things on any modern OS:
yield will give up the current timeslice and re-insert the thread into the scheduling queue. The amount of time that expires until the thread is executed again is usually entirely dependent upon the scheduler. Note that the Standard speaks of yield as an opportunity for rescheduling. So an implementation is completely free to return from a yield immediately if it desires. A yield will never mark a thread as inactive, so a thread spinning on a yield will always produce a 100% load on one core. If no other threads are ready, you are likely to lose at most the remainder of the current timeslice before you get scheduled again.
sleep_* will block the thread for at least the requested amount of time. An implementation may turn a sleep_for(0) into a yield. The sleep_for(1) on the other hand will send your thread into suspension. Instead of going back to the scheduling queue, the thread goes to a different queue of sleeping threads first. Only after the requested amount of time has passed will the scheduler consider re-inserting the thread into the scheduling queue. The load produced by a small sleep will still be very high. If the requested sleep time is smaller than a system timeslice, you can expect that the thread will only skip one timeslice (that is, one yield to release the active timeslice and then skipping the one afterwards), which will still lead to a cpu load close or even equal to 100% on one core.
A few words about which is better for spin-locking. Spin-locking is a tool of choice when expecting little to no contention on the lock. If in the vast majority of cases you expect the lock to be available, spin-locks are a cheap and valuable solution. However, as soon as you do have contention, spin-locks will cost you. If you are worrying about whether yield or sleep is the better solution here spin-locks are the wrong tool for the job. You should use a mutex instead.
For a spin-lock, the case that you actually have to wait for the lock should be considered exceptional. Therefore it is perfectly fine to just yield here - it expresses the intent clearly and wasting CPU time should never be a concern in the first place.
I just did a test with Visual Studio 2013 on Windows 7, 2.8GHz Intel i7, default release mode optimizations.
sleep_for(nonzero) appears sleep for a minimium of around one millisecond and takes no CPU resources in a loop like:
for (int k = 0; k < 1000; ++k)
std::this_thread::sleep_for(std::chrono::nanoseconds(1));
This loop of 1,000 sleeps takes about 1 second if you use 1 nanosecond, 1 microsecond, or 1 millisecond. On the other hand, yield() takes about 0.25 microseconds each but will spin the CPU to 100% for the thread:
for (int k = 0; k < 4,000,000; ++k) (commas added for clarity)
std::this_thread::yield();
std::this_thread::sleep_for((std::chrono::nanoseconds(0)) seems to be about the the same as yield() (test not shown here).
In comparison, locking an atomic_flag for a spinlock takes about 5 nanoseconds. This loop is 1 second:
std::atomic_flag f = ATOMIC_FLAG_INIT;
for (int k = 0; k < 200,000,000; ++k)
f.test_and_set();
Also, a mutex takes about 50 nanoseconds, 1 second for this loop:
for (int k = 0; k < 20,000,000; ++k)
std::lock_guard<std::mutex> lock(g_mutex);
Based on this, I probably wouldn't hesitate to put a yield in the spinlock, but I would almost certainly wouldn't use sleep_for. If you think your locks will be spinning a lot and are worried about cpu consumption, I would switch to std::mutex if that's practical in your application. Hopefully, the days of really bad performance on std::mutex in Windows are behind us.
What you want is probably a condition variable. A condition variable with a conditional wake up function is typically implemented like what you are writing, with the sleep or yield inside the loop a wait on the condition.
Your code would look like:
std::unique_lock<std::mutex> lck(mtx)
while(!bSomeCondition) {
cv.wait(lck);
}
Or
std::unique_lock<std::mutex> lck(mtx)
cv.wait(lck, [bSomeCondition](){ return !bSomeCondition; })
All you need to do is notify the condition variable on another thread when the data is ready. However, you cannot avoid a lock there if you want to use condition variable.
if you are interested in cpu load while using yield - it's very bad, except one case-(only your application is running, and you are aware that it will basically eat all your resources)
here is more explanation:
running yield in loop will ensure that cpu will release execution of thread, still, if system try to come back to thread it will just repeat yield operation. This can make thread use full 100% load of cpu core.
running sleep() or sleep_for() is also a mistake, this will block thread execution but you will have something like wait time on cpu. Don't be mistaken, this IS working cpu but on lowest possible priority. While somehow working for simple usage examples ( fully loaded cpu on sleep() is half that bad as fully loaded working processor ), if you want to ensure application responsibility, you would like something like third example:
combining! :
std::chrono::milliseconds duration(1);
while (true)
{
if(!mutex.try_lock())
{
std::this_thread::yield();
std::this_thread::sleep_for(duration);
continue;
}
return;
}
something like this will ensure, cpu will yield as fast as this operation will be executed, and also sleep_for() will ensure that cpu will wait some time before even trying to execute next iteration. This time can be of course dynamicaly (or staticaly) adjusted to suits your needs
cheers :)

Overhead due to use of Events

I have a custom thread pool class, that creates some threads that each wait on their own event (signal). When a new job is added to the thread pool, it wakes the first free thread so that it executes the job.
The problem is the following : I have around 1000 loops of each around 10'000 iterations do to. These loops must be executed sequentially, but I have 4 CPUs available. What I try to do is to split the 10'000 iteration loops into 4 2'500 iterations loops, ie one per thread. But I have to wait for the 4 small loops to finish before going to the next "big" iteration. This means that I can't bundle the jobs.
My problem is that using the thread pool and 4 threads is much slower than doing the jobs sequentially (having one loop executed by a separate thread is much slower than executing it directly in the main thread sequentially).
I'm on Windows, so I create events with CreateEvent() and then wait on one of them using WaitForMultipleObjects(2, handles, false, INFINITE) until the main thread calls SetEvent().
It appears that this whole event thing (along with the synchronization between the threads using critical sections) is pretty expensive !
My question is : is it normal that using events takes "a lot of" time ? If so, is there another mechanism that I could use and that would be less time-expensive ?
Here is some code to illustrate (some relevant parts copied from my thread pool class) :
// thread function
unsigned __stdcall ThreadPool::threadFunction(void* params) {
// some housekeeping
HANDLE signals[2];
signals[0] = waitSignal;
signals[1] = endSignal;
do {
// wait for one of the signals
waitResult = WaitForMultipleObjects(2, signals, false, INFINITE);
// try to get the next job parameters;
if (tp->getNextJob(threadId, data)) {
// execute job
void* output = jobFunc(data.params);
// tell thread pool that we're done and collect output
tp->collectOutput(data.ID, output);
}
tp->threadDone(threadId);
}
while (waitResult - WAIT_OBJECT_0 == 0);
// if we reach this point, endSignal was sent, so we are done !
return 0;
}
// create all threads
for (int i = 0; i < nbThreads; ++i) {
threadData data;
unsigned int threadId = 0;
char eventName[20];
sprintf_s(eventName, 20, "WaitSignal_%d", i);
data.handle = (HANDLE) _beginthreadex(NULL, 0, ThreadPool::threadFunction,
this, CREATE_SUSPENDED, &threadId);
data.threadId = threadId;
data.busy = false;
data.waitSignal = CreateEvent(NULL, true, false, eventName);
this->threads[threadId] = data;
// start thread
ResumeThread(data.handle);
}
// add job
void ThreadPool::addJob(int jobId, void* params) {
// housekeeping
EnterCriticalSection(&(this->mutex));
// first, insert parameters in the list
this->jobs.push_back(job);
// then, find the first free thread and wake it
for (it = this->threads.begin(); it != this->threads.end(); ++it) {
thread = (threadData) it->second;
if (!thread.busy) {
this->threads[thread.threadId].busy = true;
++(this->nbActiveThreads);
// wake thread such that it gets the next params and runs them
SetEvent(thread.waitSignal);
break;
}
}
LeaveCriticalSection(&(this->mutex));
}
This looks to me as a producer consumer pattern, which can be implented with two semaphores, one guarding the queue overflow, the other the empty queue.
You can find some details here.
Yes, WaitForMultipleObjects is pretty expensive. If your jobs are small, the synchronization overhead will start to overwhelm the cost of actually doing the job, as you're seeing.
One way to fix this is bundle multiple jobs into one: if you get a "small" job (however you evaluate such things), store it someplace until you have enough small jobs together to make one reasonably-sized job. Then send all of them to a worker thread for processing.
Alternately, instead of using signaling you could use a multiple-reader single-writer queue to store your jobs. In this model, each worker thread tries to grab jobs off the queue. When it finds one, it does the job; if it doesn't, it sleeps for a short period, then wakes up and tries again. This will lower your per-task overhead, but your threads will take up CPU even when there's no work to be done. It all depends on the exact nature of the problem.
Watch out, you are still asking for a next job after the endSignal is emitted.
for( ;; ) {
// wait for one of the signals
waitResult = WaitForMultipleObjects(2, signals, false, INFINITE);
if( waitResult - WAIT_OBJECT_0 != 0 )
return;
//....
}
Since you say that it is much slower in parallel than sequential execution, I assume that your processing time for your internal 2500 loop iterations is tiny (in the few micro seconds range). Then there is not much you can do except review your algorithm to split larger chunks of precessing; OpenMP won't help and every other synchronization techniques won't help either because they fundamentally all rely on events (spin loops do not qualify).
On the other hand, if your processing time of the 2500 loop iterations is larger than 100 micro seconds (on current PCs), you might be running into limitations of the hardware. If your processing uses a lot of memory bandwidth, splitting it to four processors will not give you more bandwidth, it will actually give you less because of collisions. You could also be running into problems of cache cycling where each of your top 1000 iteration will flush and reload the cache of the 4 cores. Then there is no one solution, and depending on your target hardware, there may be none.
If you are just parallelizing loops and using vs 2008, I'd suggest looking at OpenMP. If you're using visual studio 2010 beta 1, I'd suggesting looking at the parallel pattern library, particularly the "parallel for" / "parallel for each"
apis or the "task group class because these will likely do what you're attempting to do, only with less code.
Regarding your question about performance, here it really depends. You'll need to look at how much work you're scheduling during your iterations and what the costs are. WaitForMultipleObjects can be quite expensive if you hit it a lot and your work is small which is why I suggest using an implementation already built. You also need to ensure that you aren't running in debug mode, under a debugger and that the tasks themselves aren't blocking on a lock, I/O or memory allocation, and you aren't hitting false sharing. Each of these has the potential to destroy scalability.
I'd suggest looking at this under a profiler like xperf the f1 profiler in visual studio 2010 beta 1 (it has 2 new concurrency modes which help see contention) or Intel's vtune.
You could also share the code that you're running in the tasks, so folks could get a better idea of what you're doing, because the answer I always get with performance issues is first "it depends" and second, "have you profiled it."
Good Luck
-Rick
It shouldn't be that expensive, but if your job takes hardly any time at all, then the overhead of the threads and sync objects will become significant. Thread pools like this work much better for longer-processing jobs or for those that use a lot of IO instead of CPU resources. If you are CPU-bound when processing a job, ensure you only have 1 thread per CPU.
There may be other issues, how does getNextJob get its data to process? If there's a large amount of data copying, then you've increased your overhead significantly again.
I would optimise it by letting each thread keep pulling jobs off the queue until the queue is empty. that way, you can pass a hundred jobs to the thread pool and the sync objects will be used just the once to kick off the thread. I'd also store the jobs in a queue and pass a pointer, reference or iterator to them to the thread instead of copying the data.
The context switching between threads can be expensive too. It is interesting in some cases to develop a framework you can use to process your jobs sequentially with one thread or with multiple threads. This way you can have the best of the two worlds.
By the way, what is your question exactly ? I will be able to answer more precisely with a more precise question :)
EDIT:
The events part can consume more than your processing in some cases, but should not be that expensive, unless your processing is really fast to achieve. In this case, switching between thredas is expensive too, hence my answer first part on doing things sequencially ...
You should look for inter-threads synchronisation bottlenecks. You can trace threads waiting times to begin with ...
EDIT: After more hints ...
If I guess correctly, your problem is to efficiently use all your computer cores/processors to parralellize some processing essencialy sequential.
Take that your have 4 cores and 10000 loops to compute as in your example (in a comment). You said that you need to wait for the 4 threads to end before going on. Then you can simplify your synchronisation process. You just need to give your four threads thr nth, nth+1, nth+2, nth+3 loops, wait for the four threads to complete then going on. You should use a rendezvous or barrier (a synchronization mechanism that wait for n threads to complete). Boost has such a mechanism. You can look the windows implementation for efficiency. Your thread pool is not really suited to the task. The search for an available thread in a critical section is what is killing your CPU time. Not the event part.
It appears that this whole event thing
(along with the synchronization
between the threads using critical
sections) is pretty expensive !
"Expensive" is a relative term. Are jets expensive? Are cars? or bicycles... shoes...?
In this case, the question is: are events "expensive" relative to the time taken for JobFunction to execute? It would help to publish some absolute figures: How long does the process take when "unthreaded"? Is it months, or a few femtoseconds?
What happens to the time as you increase the threadpool size? Try a pool size of 1, then 2 then 4, etc.
Also, as you've had some issues with threadpools here in the past, I'd suggest some debug
to count the number of times that your threadfunction is actually invoked... does it match what you expect?
Picking a figure out of the air (without knowing anything about your target system, and assuming you're not doing anything 'huge' in code you haven't shown), I'd expect the "event overhead" of each "job" to be measured in microseconds. Maybe a hundred or so. If the time taken to perform the algorithm in JobFunction is not significantly MORE than this time, then your threads are likely to cost you time rather than save it.
As mentioned previously, the amount of overhead added by threading depends on the relative amount of time taken to do the "jobs" that you defined. So it is important to find a balance in the size of the work chunks that minimizes the number of pieces but does not leave processors idle waiting for the last group of computations to complete.
Your coding approach has increased the amount of overhead work by actively looking for an idle thread to supply with new work. The operating system is already keeping track of that and doing it a lot more efficiently. Also, your function ThreadPool::addJob() may find that all of the threads are in use and be unable to delegate the work. But it does not provide any return code related to that issue. If you are not checking for this condition in some way and are not noticing errors in the results, it means that there are idle processors always. I would suggest reorganizing the code so that addJob() does what it is named -- adds a job ONLY (without finding or even caring who does the job) while each worker thread actively gets new work when it is done with its existing work.