How to display one models data in another model django admin panel - django

Question

I have two models: 1) SchoolProfile & 2) Content
I want to show content data in schoolprofile, But data should be display as per user foreignkey.
User foreignkey common for both the models.
School Profile Model
class SchoolProfile(models.Model):
id=models.AutoField(primary_key=True)
user=models.ForeignKey(User,on_delete=models.CASCADE,unique=True)
school_name = models.CharField(max_length=255)
school_logo=models.FileField(upload_to='media/', blank=True)
incharge_name = models.CharField(max_length=255, blank=True)
email = models.EmailField(max_length=255, blank=True)
phone_num = models.CharField(max_length=255, blank=True)
num_of_alu = models.CharField(max_length=255, blank=True)
num_of_student = models.CharField(max_length=255, blank=True)
num_of_cal_student = models.CharField(max_length=255, blank=True)
def __str__(self):
return self.school_name
Content Model
class Content(models.Model):
id=models.AutoField(primary_key=True)
user=models.ForeignKey(User,on_delete=models.CASCADE)
content_type = models.CharField(max_length=255, blank=True, null=True)
show=models.ForeignKey(Show,on_delete=models.CASCADE, blank=True, null=True)
sponsor_link=models.CharField(max_length=255, blank=True, null=True)
status=models.BooleanField(default=False, blank=True, null=True)
added_on=models.DateTimeField(auto_now_add=True)
content_file=models.FileField(upload_to='media/', blank=True, null=True)
title = models.CharField(max_length=255)
subtitle = models.CharField(max_length=255, blank=True, null=True)
description = models.CharField(max_length=500, blank=True, null=True)
draft = models.BooleanField(default=False)
publish_now = models.CharField(max_length=255, blank=True, null=True)
schedule_release = models.DateField(null=True, blank=True)
expiration = models.DateField(null=True, blank=True)
tag = models.ManyToManyField(Tag, null=True, blank=True)
topic = models.ManyToManyField(Topic, null=True, blank=True)
category = models.ManyToManyField(Categorie, null=True, blank=True)
def __str__(self):
return self.title
I have used Inline but it's show below error:
<class 'colorcast_app.admin.SchoolProfileInline'>: (admin.E202) 'colorcast_app.SchoolProfile' has no ForeignKey to 'colorcast_app.SchoolProfile'.
My admin.py
class SchoolProfileInline(InlineActionsMixin, admin.TabularInline):
model = SchoolProfile
inline_actions = []
def has_add_permission(self, request, obj=None):
return False
class SchoolProfileAdmin(InlineActionsModelAdminMixin,
admin.ModelAdmin):
inlines = [SchoolProfileInline]
list_display = ('school_name',)
admin.site.register(SchoolProfile, SchoolProfileAdmin)

Answer 1

Using the StackedInline to link two models is straight forward and a much clean practice, so basically this is my solution below:
class ContentInlineAdmin(admin.StackedInline):
model = Content
#admin.register(SchoolProfile)
class SchoolProfileAdmin(admin.ModelAdmin):
list_display = ('school_name',)
inlines = [ContentInlineAdmin]