How do I deserialise a const byte * to a structure in cpp? - c++

Question

I have a structure like this
struct foo {
string str1;
uint16_t int1
string str2;
uint32_t int2;
string str3;
};
strings str1, str2 , str3 are of fixed length of 12 bytes, 3 bytes,etc. left padded with spaces.
I have a function
void func(const byte* data, const size_t len) which is supposed to convert the byte * data to structure foo. len is length of data.What are the ways in which I can do this?
Again the data is const pointer of byte type and will not have null characters in between to distinguish different members.
Should I use character array instead of string for str1, str2, str3?

Answer 1

Easiest (but most errorprone) way is to just reinterpret_cast / std::memcpy if the strings have fixed length:
// no padding
#pragma pack(push, 1)
struct foo {
char str1[12];
uint16_t int1;
char str2[3];
uint32_t int2;
char str3[4];
};
#pragma pack(pop)
void func(const byte* data, const size_t len) {
assert(len == sizeof(foo));
// non owning
const foo* reinterpreted = reinterpret_cast<const foo*>(data);
// owning
foo reinterpreted_val = *reinterpret_cast<const foo*>(data);
foo copied;
memcpy(&copied, data, len);
}
Notes:
Make sure that you're allowed to use reinterpret_cast
https://en.cppreference.com/w/cpp/language/reinterpret_cast#Type_aliasing
if you'd try to use strlen or another string operation on any of the strings you most likely will get UB, since the strings are not null terminated.
Slightly better approach:
struct foo {
char str1[13];
uint16_t int1;
char str2[4];
uint32_t int2;
char str3[5];
};
void func(const char* data, const size_t len) {
foo f;
memcpy(f.str1, data, 12);
f.str1[12] = '\0';
data+=12;
memcpy(&f.int1, data, sizeof(uint16_t));
data+=sizeof(uint16_t);
memcpy(f.str2, data, 3);
f.str2[3] = '\0';
data+=3;
memcpy(&f.int2, data, sizeof(uint32_t));
data+=sizeof(uint32_t);
memcpy(f.str3, data, 4);
f.str3[4] = '\0';
data+=4;
}
Notes:
You could combine both approaches to get rid of the pointer arithmetic. That would also account for any padding in your struct you might have.

Answer 2

I think the easiest way to do this is to change the string inside the structure
to the type of char. Then you can easily copy the objects of this
structure according to its size.
you will have to somehow deal with the byte order on machines with different byte
order
struct foo {
char str1[12];
uint16_t int1;
char str2[3];
uint32_t int2;
char str3[5];
};
byte* Encode(foo* p, int Size) {
int FullSize = Size * sizeof(foo);
byte* Returner = new byte[FullSize];
memcpy_s(Returner, FullSize, p, FullSize);
return Returner;
}
foo * func(const byte* data, const size_t len) {
int ArrSize = len/sizeof(foo);
if (!ArrSize || (ArrSize* sizeof(foo)!= len))
return nullptr;
foo* Returner = new foo[ArrSize];
memcpy_s(Returner, len, data, len);
return Returner;
}
int main()
{
const size_t ArrSize = 3;
foo Test[ArrSize] = { {"Test1",1000,"TT",2000,"cccc"},{"Test2",1001,"YY",2001,"vvvv"},{"Test1",1002,"UU",2002,"bbbb"}};
foo* Test1 = nullptr;
byte* Data = Encode(Test, ArrSize);
Test1 = func(Data, ArrSize * sizeof(foo));
if (Test1 == nullptr) {
std::cout << "Error extracting data!" << std::endl;
delete [] Data;
return -1;
}
std::cout << Test1[0].str1 << " " << Test1[1].str1 << " " << Test1[2].str3 << std::endl;
delete [] Data;
delete[] Test1;
return 0;
}
output
Test1 Test2 bbbb