I am using this command line
compare -metric AE -fuzz 5% $OLD_JPG_ProcessFILE $JPG_ProcessFILE /tmp/JPG_PathFullFillName.gif
The command does work and throws me the result as an integer number of different pixels into the next command line of Putty - but I can't assign this integer value to a bash variable ...!
How to do that?
This command
var=$(compare -metric AE -fuzz 5% $OLD_JPG_ProcessFILE $JPG_ProcessFILE /tmp/JPG_PathFullFillName.gif)
does not work, $var remains empty ...!
Thanks in advance and BR
Testing around I have found the answer by appending "null: 2>&1" :
Pixel_Difference=$(compare -metric AE -fuzz 5% $OLD_JPG_ProcessFILE $JPG_ProcessFILE /tmp/JPG_PathFullFillName.gif null: 2>&1)
Works fine!
But why - what is the "magic" behind with "null: 2>&1" ???
Related
I am just learning bash scripting and commands and i need some help with this assignment.
I have txt file that contains the following text and i need to:
Extract guest name ( 1.1.1 ..)
Sum guest result and output the guest name with result.
I used sed with simple regex to extract out the name and the digits but i have no idea about how to summarize the numbers becuase the guest have multiple lines record as you can see in the txt file. Note: i can't use awk for processing
Here is my code:
cat file.txt | sed -E 's/.*([0-9]{1}.[0-9]{1}.[0-9]{1}).*([0-9]{1})/\1 \2/'
And result is:
1.1.1 4
2.2.2 2
1.1.1 1
3.3.3 1
2.2.2 1
Here is the .txt file:
Guest 1.1.1 have "4
Guest 2.2.2 have "2
Guest 1.1.1 have "1
Guest 3.3.3 have "1
Guest 2.2.2 have "1
and the output should be:
1.1.1 = 5
2.2.2 = 3
3.3.3 = 1
Thank you in advance
I know your teacher wont let you use awk but, since beyond this one exercise you're trying to learn how to write shell scripts, FYI here's how you'd really do this job in a shell script:
$ awk -F'[ "]' -v OFS=' = ' '{sum[$2]+=$NF} END{for (id in sum) print id, sum[id]}' file
3.3.3 = 1
2.2.2 = 3
1.1.1 = 5
and here's a bash builtins equivalent which may or may not be what you've covered in class and so may or may not be what your teacher is expecting:
$ cat tst.sh
#!/bin/env bash
declare -A sum
while read -r _ id _ cnt; do
(( sum[$id] += "${cnt#\"}" ))
done < "$1"
for id in "${!sum[#]}"; do
printf '%s = %d\n' "$id" "${sum[$id]}"
done
$ ./tst.sh file
1.1.1 = 5
2.2.2 = 3
3.3.3 = 1
See https://www.artificialworlds.net/blog/2012/10/17/bash-associative-array-examples/ for how I'm using the associative array. It'll be orders of magnitude slower than the awk script and I'm not 100% sure it's bullet-proof (since shell isn't designed to process text there are a LOT of caveats and pitfalls) but it'll work for the input you provided.
OK -- since this is a class assignment, I will tell you how I did it, and let you write the code.
First, I sorted the file. Then, I read the file one line at a time. If the name changed, I printed out the previous name and count, and set the count to be the value on that line. If the name did not change, I added the value to the count.
Second solution used an associative array to hold the counts, using the guest name as the index. Then you just add the new value to the count in the array element indexed on the guest name.
At the end, loop through the array, print out the indexes and values.
It's a lot shorter.
Yet again my unfamiliarity with AWK lets me down, I can't figure out how to match a variable at the end of a line?
This would be fairly trivial with grep etc, but I'm interested in matching integers at the end of a string in a specific field of a tsv, and all the posts suggest (and I believe it to be the case!) that awk is the way to go.
If I want to just match a single one explicity, that's easy:
Here's my example file:
PVClopT_11 PAU_02102 PAU_02064 1pqx 1pqx_A 37.4 13 0.00035 31.4 >1pqx_A Conserved hypothetical protein; ZR18,structure, autostructure,spins,autoassign, northeast structural genomics consortium; NMR {Staphylococcus aureus subsp} SCOP: d.267.1.1 PDB: 2ffm_A 2m6q_A 2m8w_A No DOI found.
PVCpnf_18 PAK_3526 PAK_03186 3fxq 3fxq_A 99.7 2.7e-21 7e-26 122.2 >3fxq_A LYSR type regulator of TSAMBCD; transcriptional regulator, LTTR, TSAR, WHTH, DNA- transcription, transcription regulation; 1.85A {Comamonas testosteroni} PDB: 3fxr_A* 3fxu_A* 3fzj_A 3n6t_A 3n6u_A* 10.1111/j.1365-2958.2010.07043.x
PVCunit1_19 PAU_02807 PAU_02793 3kx6 3kx6_A 19.7 45 0.0012 31.3 >3kx6_A Fructose-bisphosphate aldolase; ssgcid, NIH, niaid, SBRI, UW, emerald biostructures, glycolysis, lyase, STRU genomics; HET: CIT; 2.10A {Babesia bovis} No DOI found.
PVClumt_17 PAU_02231 PAU_02190 3lfh 3lfh_A 39.7 12 0.0003 28.9 >3lfh_A Manxa, phosphotransferase system, mannose/fructose-speci component IIA; PTS; 1.80A {Thermoanaerobacter tengcongensis} No DOI found.
PVCcif_11 plu2521 PLT_02558 3h2t 3h2t_A 96.6 2.6e-05 6.7e-10 79.0 >3h2t_A Baseplate structural protein GP6; viral protein, virion; 3.20A {Enterobacteria phage T4} PDB: 3h3w_A 3h3y_A 10.1016/j.str.2009.04.005
PVCpnf_16 PAU_03338 PAU_03377 5jbr 5jbr_A 29.2 22 0.00058 23.9 >5jbr_A Uncharacterized protein BCAV_2135; structural genomics, PSI-biology, midwest center for structu genomics, MCSG, unknown function; 1.65A {Beutenbergia cavernae} No DOI found.
PVCunit1_17 PAK_2892 PAK_02622 1cii 1cii_A 63.2 2.7 6.9e-05 41.7 >1cii_A Colicin IA; bacteriocin, ION channel formation, transmembrane protein; 3.00A {Escherichia coli} SCOP: f.1.1.1 h.4.3.1 10.1038/385461a0
PVCunit1_11 PAK_2886 PAK_02616 3h2t 3h2t_A 96.6 1.9e-05 4.9e-10 79.9 >3h2t_A Baseplate structural protein GP6; viral protein, virion; 3.20A {Enterobacteria phage T4} PDB: 3h3w_A 3h3y_A 10.1016/j.str.2009.04.005
PVCpnf_11 PAU_03343 PAU_03382 3h2t 3h2t_A 97.4 4.4e-07 1.2e-11 89.7 >3h2t_A Baseplate structural protein GP6; viral protein, virion; 3.20A {Enterobacteria phage T4} PDB: 3h3w_A 3h3y_A 10.1016/j.str.2009.04.005
PVCunit1_5 afp5 PAU_02779 4tv4 4tv4_A 63.6 2.6 6.7e-05 30.5 >4tv4_A Uncharacterized protein; unknown function, ssgcid, virulence, structural genomics; 2.10A {Burkholderia pseudomallei} No DOI found.
And I can pull out all the lines which have a "_11" at the end of the first column by running the following on the commandline:
awk '{ if ($1 ~ /_11$/) { print } }' 02052017_HHresults_sorted.tsv
I want to enclose this in a loop to cover all integers from 1 - 5 (for instance), but I'm having trouble passing a variable in to the text match.
I expect it should be something like the following, but $i$ seems like its probably incorrect and by google-fu failed me:
awk 'BEGIN{ for (i=1;i<=5;i++){ if ($1 ~ /_$i$/) { print } } }' 02052017_HHresults_sorted.tsv
There may be other issues I haven't spotted with that awk command too, as I say, I'm not very awk-savvy.
EDIT FOR CLARIFICATION
I want to separate out all the matches, so can't use a character class. i.e. I want all the lines ending in "_1" in one file, then all the ones ending in "_2" in another, and so on (hence the loop).
You can't put variables inside //. Use string concatenation, which is done by simply putting the strings adjacent to each other in awk. You don't need to use a regexp literal when you use the ~ operator, it always treats the second argument as a regexp.
awk '{ for (i = 1; i <= 5; i++) {
if ( $1 ~ ("_" i "$") ) { print; break; }
}' 02052017_HHresults_sorted.tsv
It sounds like you're thinking about this all wrong and what you really need is just (with GNU awk for gensub()):
awk '{ print > ("out" gensub(/.*_/,"",1,$1)) }' 02052017_HHresults_sorted.tsv
or with any awk:
awk '{ n=$1; sub(/.*_/,"",n); print > ("out" n) }' 02052017_HHresults_sorted.tsv
No need to loop, use regex character class [..]:
awk 'match($1,/_([1-5])$/,a){ print >> a[1]".txt" }' 02052017_HHresults_sorted.tsv
New user here, and just started Python a few days ago!
My question is:
I need to write a Python stub to print names of image files and whether they are blurry or not. They are considered blurry if the value is > 0.3. There are 5 bits of information in each line, the second bit (index 1) is the number in question. In total there are 1868 lines.
Here is a sample of the data:
['out04-32-44-03.tif,0.295554,536047.6051,5281850.4252,19.8091\n',
'out04-32-44-15.tif,0.337232,536047.2831,5281850.5974,19.8256\n',
'out04-32-44-27.tif,0.2984,536046.9611,5281850.7696,19.8420\n',
'out04-32-44-39.tif,0.311989,536046.6392,5281850.9418,19.8584\n',
'out04-32-44-51.tif,0.346901,536046.3172,5281851.1140,19.8749\n',
'out04-32-44-63.tif,0.358519,536045.9953,5281851.2862,19.8913\n',
'out04-32-44-75.tif,0.342837,536045.6733,5281851.4584,19.9078\n',
'out04-32-44-87.tif,0.32909,536045.3513,5281851.6306,19.9242\n',
'out04-32-44-99.tif,0.294824,536045.0294,5281851.8028,19.9406\n']
Any suggestions greatly appreciated :-)
Based on the code you have written in the comments. This is for python 2.7
fin = open('E:\KGG 375 - GIS Advanced\Assignment 2 - Python\TIR043109gpxpos.txt')
for line in fin: # no need to read these into a list first
info = line.split(',')
blurry = float(info[1])
print info[0],
if blurry > 0.3:
print ' is blurry'
else:
print ' is not blurry'
Explanation:
There is no need to read the lines of a file to a list, you can just iterate over a file and it will read line by line
To be able to compare against a float, you need to convert the 2nd element (info[1]) into a float.
print info[0], will print the filename and the comma will prevent a line break so " is blurry" will print out to the same line. HOX! This is python2.7 syntax so it will not work with python 3.x
Below gives the list in a file (unsorted-file) that needs to be sorted in Linux, preferably in a single line linux command.
03123456789abcd
02987654321pqrs
02123456789mnop
03987654321stuv
04123456789ghjk
01000000000
99000000000
97000000000
98000000000
Required sorted file output:
01000000000
02123456789mnop
03123456789abcd
04123456789ghjk
02987654321pqrs
03987654321stuv
97000000000
98000000000
99000000000
Requirement:
If first two char is 01 then it is the header
If first two char is greater than 90 then they are trailers
Sort order: position 3 - 11 and then position 1 - 2
I tried a simple sort command like
$sort unsorted-file > sorted-file.
The requirement 3 failed. Then I tried
$sort -k 1.3, 1.11 -k 1.2 unsorted-file > sorted-file
The trailer records made it to the top of the file because of all zeros from position 3.
The other options that I know is to strip out the headers and trailers; sort the file and merge the header and trailer files back. Is there a way to do in one linux (complex) command itself?
Thanks for your time.
-R-
( grep '^01' unsorted-file
grep -E -v '^(01|9)' unsorted-file | sort -k 1.3,1.11 -k 1.1
grep '^9' unsorted-file ) > sorted-file
On "Linux Mint 16 Petra" i type this command :
zenity --list --column "test" a b c
I select the item 'a', then the returnning value is randomly
a or a|a
How do you explain this ? is it a zenity bug ?
How to get only 'a' ?
Regards.
It is a pretty annoying bug. Not the first one this year too.
open=$(find "${#}" -iname "$string" | zenity --list --title "Search results" --text "Please select file or directory to open:" --width 800 --height 600 --column "Files")
work-around:
opens=$(echo $open | cut -d "|" -f2)
When you select "a" with mouse double click (or with the enter key on keyboard), the value is "a|a". When you select it and press "Ok", the value is "a".
I don't know exactly why.
A simple workaround could be :
TMP=$(zenity --list --column "test" a b c) # Save the returned value in TMP
VAL=${TMP:0:1} # Keep the first character of TMP and put it in VAL
echo $VAL # VAL = "a", "b" or "c"
Print every value in a | separated list : zenity --list --print-column=ALL (...) and get the whole selected row.