Rectangular shape with characters inside it placed with a certain width - c++

Question

I am trying to replicate this:
Type the height and width of the rectangle: 10 13
+-------------+
| w w w |
| w w w |
| w w w |
|w w w w|
| w w w |
| w w w |
| w w w |
|w w w w|
| w w w |
| w w w |
+-------------+
Type the height and width of the rectangle: 0 0
+-+
+-+
Type the height and width of the rectangle: 4 1
+-+
| |
| |
| |
|w|
+-+
I succesfully made a subprogram that printed out the rectangle (though it is messy and there's obvious duplications of code). How can I, in the same subprogram (or maybe in a different one) print out the 'w' and the empty spaces filled with spaces? The width of each 'w' is 4 spaces. I kind of have an idea. That we do cout << setfill(' ') << setw(4) << 'w' and then an if-statement that if the setw exceeds <= width it will do a '\n'
However this is my code and I would much appreciate how my code could be improven and how to implement a character with width 4 inside the rectangle.
#include <iostream>
#include <iomanip>
using namespace std;
void print_rectangle (int const width,
int const height)
{
cout << '+' << '-';
for (int i {1}; i < width; ++i)
{
cout << '-';
}
cout << '+' << endl;
for (int j {}; j < height; ++j)
{
cout << '|' << setw(width + 1) << '|' << endl;
}
cout << '+' << '-';
for (int i {1}; i < width; ++i)
{
cout << '-';
}
cout << '+' << endl;
}
int main()
{
int width {};
int height {};
cout << "Enter the height and width of the rectangle: ";
cin >> height;
cin >> width;
print_rectangle(width,height);
return 0;
}

Answer 1

Well the solution for the second part which will print the 'w' and the spaces is as follows:
#include <iostream>
#include <iomanip>
using namespace std;
void print_rectangle (int const width,
int const height)
{
int counter=1;
int remainder= (width+1) % height;
cout << '+' << '-';
for (int i = 1; i < width; ++i)
{
cout << '-';
}
cout << '+' << endl;
for (int j =0 ; j < height; ++j)
{
if(j == 0 || j == height )
cout << '|' << setw(width + 1) << '|' << endl;
else
{
cout << '|';
for (int i = 0; i <width ; i++)
{
if(counter % remainder == 0)
cout<<"w";
else
cout<<" ";
counter++;
}
cout << '|'<<endl;
}
}
cout << '+' << '-';
for (int i =1 ; i < width; ++i)
{
cout << '-';
}
cout << '+' << endl;
}
int main()
{
int width =0;
int height =0;
cout << "Enter the height and width of the rectangle: ";
cin >> height;
cin >> width;
print_rectangle(width,height);
return 0;
}
I have tested the given input cases on it as well and it gives the right output. What's happening here is that the remainder of height and width+1 gives us a remainder and with the help of that remainder we are going to print w's. A counter is incremented in the loop and whenever that counter is a multiple of that remainder w will be printed otherwise space.
Here is the output of the test case input 4 and 1 output
And here is the output of test case input 10 and 13

Answer 2

Please learn split problem to smaller pieces which are a small functions.
Take a look on this:
using std::setw;
void print_ending(std::ostream& out, int const width) {
out << '+' << std::string(width, '-') << '+' << '\n';
}
void print_row(std::ostream& out,
int const width,
int const period,
int offset) {
out << '|' << std::string(std::min(width, offset), ' ');
if (offset < width) {
out << 'w';
auto remainin_width = width - offset - 1;
for (int i = remainin_width / period; i > 0; --i) {
out << setw(period) << 'w';
}
out << std::string(remainin_width % period, ' ');
}
out << "|\n";
}
void print_rectangle(std::ostream& out,
int const width,
int const height,
int period = 4) {
print_ending(out, width);
for (int j{}; j < height; ++j) {
print_row(out, width, period, (height - j) % period);
}
print_ending(out, width);
}
Live demo