I have some code that takes multiple images, aligns them, and stacks them together. For some reason, the alignment is off. A simplified version of the code is below
void stackImages(uint8_t **pixels, uint32_t width, uint32_t height, size_t len)
{
cv:: Mat firstImg;
cv::Mat stacked;
for (int i = 0; i < len; i++)
{
// Transformation matrix
cv::Mat1f M = cv::Mat1f(cv::Mat::eye(3, 3, CV_8UC1));
// Convert pixels (4 channel RGBA) to Mat
cv::Mat pixels = cv::Mat(height, width, CV_8UC4, pixels[i]);
cv::Mat gray;
cv::cvtColor(pixels, gray, cv::COLOR_RGBA2GRAY);
// skip the reference image
if(!i) {
firstImg = gray;
stacked = gray;
continue;
}
cv::Mat warped;
// create size struct
cv::Size size;
size.width = width;
size.height = height;
// create the transformation matrix
cv::findTransformECC(firstImg, gray, M, cv::MOTION_HOMOGRAPHY);
// warp the image according ot the transformation matrix
cv::warpPerspective(gray, warped, M, size);
// stack the image
stacked += warped;
}
// write the image
cv::imwrite("stacked.jpg", stacked);
}
I've tested this code with three images taken in rapid succession and the results are below. This is my first foray into image processing, so I'm mostly following online documentation.
Nvidia's cuDNN for deep learning has a rather interesting format for images called CHW. I have a cv::Mat img; that I want to convert to a one-dimensional vector of floats. The problem that I'm having is that the format of the 1D vector for CHW is (RR...R, GG..G,BB..B).
So I'm curious as to how I can extract the channel values for each pixel and order them for this format.
I faced with same problem and and solve it in that way:
#include <opencv2/opencv.hpp>
cv::Mat hwc2chw(const cv::Mat &image){
std::vector<cv::Mat> rgb_images;
cv::split(image, rgb_images);
// Stretch one-channel images to vector
cv::Mat m_flat_r = rgb_images[0].reshape(1,1);
cv::Mat m_flat_g = rgb_images[1].reshape(1,1);
cv::Mat m_flat_b = rgb_images[2].reshape(1,1);
// Now we can rearrange channels if need
cv::Mat matArray[] = { m_flat_r, m_flat_g, m_flat_b};
cv::Mat flat_image;
// Concatenate three vectors to one
cv::hconcat( matArray, 3, flat_image );
return flat_image;
}
P.S. If input image isn't in RGB format, you can change channel order in matArray creation line.
Use cv::dnn::blobFromImage:
cv::Mat bgr_image = cv::imread(imageFileName);
cv::Mat chw_image = cv::dnn::blobFromImage
(
bgr_image,
1.0, // scale factor
cv::Size(), // spatial size for output image
cv::Scalar(), // mean
true, // swapRB: BGR to RGB
false, // crop
CV_32F // Depth of output blob. Choose CV_32F or CV_8U.
);
const float* data = reinterpret_cast<const float*>(chw_image.data);
int data_length = 1 * 3 * bgr_image.rows * bgr_image.cols;
You can either iterate over the image manually and copy the values into the right place, or you can use something like cv::extractChannel to copy the channels one by one like so:
#include <opencv2/opencv.hpp>
int main()
{
//create dummy 3 channel float image
cv::Mat sourceRGB(cv::Size(100,100),CV_32FC3);
auto size = sourceRGB.size();
for (int y = 0; y < size.height; ++y)
{
for (int x = 0; x < size.width; ++x)
{
float* pxl = sourceRGB.ptr<float>(x, y);
*pxl = x / 100.0f;
*(pxl+1) = y / 100.0f;
*(pxl + 2) = (y / 100.0f) * (x / 100.0f);
}
}
cv::imshow("test", sourceRGB);
cv::waitKey(0);
//create single image with all 3 channels one after the other
cv::Size newsize(size.width,size.height*3);
cv::Mat destination(newsize,CV_32FC1);
//copy the channels from the source image to the destination
for (int i = 0; i < sourceRGB.channels(); ++i)
{
cv::extractChannel(
sourceRGB,
cv::Mat(
size.height,
size.width,
CV_32FC1,
&(destination.at<float>(size.height*size.width*i))),
i);
}
cv::imshow("test", destination);
cv::waitKey(0);
return 0;
}
Is there a way to convert from RGB to YUYV (YUY 4:2:2) format? I noted that OpenCV has reverse operation, but not RGB to YUYV for some reason. Maybe someone can point to code which does that (even outside of OpenCV library)?
UPDATE
I found libyuv library which may work for this purpose by doing BGR to ARGB conversion and then ARGB to YUY2 format (hopefully this is the same as YUYV 4:2:2). But it doesn't seem to work. Do you happen to know what yuyv buffer dimensions/type should look like? What its stride?
To clarify YUYV and YUY2 are the same formats if it helps.
UPDATE 2
Here is my code of using libyuv library:
Mat frame;
// Convert original image im from BGR to BGRA for further use in libyuv
cvtColor(im, frame, CVX_BGR2BGRA);
// Actually libyuv requires ARGB (i.e. reverse of BGRA), so I swap channels here
int from_to[] = { 0,3, 1,2, 2,1, 3,0 };
mixChannels(&frame, 1, &frame, 1, from_to, 4);
// This is the most confusing part. Not sure what argb_stride suppose to be - length of a row in bytes or size of single value in the array?
const uint8_t* argb_data = frame.data;
int argb_stride = 8;
// Also it is not clear what size of yuyv frame should be since we duplicate one Y
Mat yuyv(frame.rows, frame.cols, CVX_8UC2);
uint8_t* yuyv_data = yuyv.data;
int yuyv_stride = 16;
// Do actual conversion
libyuv::ARGBToYUY2(argb_data, argb_stride, yuyv_data, yuyv_stride,
frame.cols, frame.rows);
// Then I feed yuyv_data to video stream buffer and see green or purple image instead of video stream.
UPDATE 3
Mat frame;
cvtColor(im, frame, CVX_BGR2BGRA);
// ARGB
int from_to[] = { 0,3, 1,2, 2,1, 3,0 };
Mat rgba(frame.size(), frame.type());
mixChannels(&frame, 1, &rgba, 1, from_to, 4);
const uint8_t* argb_data = rgba.data;
int argb_stride = rgba.cols*4;
Mat yuyv(rgba.rows, rgba.cols, CVX_8UC2);
uint8_t* yuyv_data = yuyv.data;
int yuyv_stride = width * 2;
int res = libyuv::ARGBToYUY2(argb_data, argb_stride, yuyv_data, yuyv_stride, rgba.cols, rgba.rows);
It appears that although method is called ARGBToYUY2 it requires BGRA order of channels (not reverse).
I have float x, float y, float z values of an image. I want to construct a 16 bit png depth image by copying the z values. The image I am getting as a result has some invalid points. Below is my code.
uint16_t* depthValues = new uint16_t[size];
auto sampleVector(DepthPoints);
for (unsigned int i = 0; i < sampleVector.size(); i++)
{
depthValues[i] = (sampleVector.at(i).z) * 65536;
}
Mat newDepthImage = cv::Mat(var.height, var.width, CV_16UC1,depthValues);
imwrite(Location, CImage);
Can someone tell me, if I can copy the float values into an unsigned char array to create the image?
Is that why my image has invalid points?
auto sampleVector(DepthPoints);
const int size = sampleVector.size();
float* depthValues = new float[size];
for (unsigned int i = 0; i < sampleVector.size(); i++)
{
depthValues[i] = (sampleVector.at(i).z);
}
Mat depthImageOne, depthImageTwo;
Mat depthImageNew = cv::Mat(var.height, var.width, CV_32FC1,depthValues);
normalize(newDepthImageNew, depthImageOne, 1, 0, NORM_MINMAX, CV_32FC1);
depthImageOne.convertTo(depthImageTwo, CV_16UC1, 65536.0,0.0);
imwrite("path", depthImageTwo);
Normalization might cause lose of depth information. I have used normalization for visualization of the images. To preserve the depth information, I used the below code.
Mat depthImageNew = cv::Mat(var.height, var.width, CV_32FC1,depthValues);
depthImageOne.convertTo(depthImageTwo, CV_16UC1, 1000.0,0.0);
I am wondering how would I convert the OpenCV C++ standard cv::Mat type to QImage. I have been searching around, but have no luck. I have found some code that converts the IPlimage to QImage, but that is not what I want. Thanks.
Michal Kottman's answer is valid and give expected result for some images but it'll fail on some cases. Here is a solution i found to that problem.
QImage imgIn= QImage((uchar*) img.data, img.cols, img.rows, img.step, QImage::Format_RGB888);
Difference is adding img.step part. qt won't complain without it but some images won't show properly without it. Hope this will help.
To convert from cv::Mat to QImage, you could try to use the QImage(uchar * data, int width, int height, Format format) constructor as follows (mat is a cv::Mat) :
QImage img((uchar*)mat.data, mat.cols, mat.rows, QImage::Format_RGB32);
It is more efficient than manually converting the pixels to the QImage, but you have to keep the original cv::Mat image in memory. It can be easily converted to a QPixmap and displayed using a QLabel:
QPixmap pixmap = QPixmap::fromImage(img);
myLabel.setPixmap(pixmap);
Update
Because OpenCV uses BGR order by default, you should first use cvtColor(src, dst, CV_BGR2RGB) to get an image layout that Qt understands.
Update 2:
If the image you are trying to show has nonstandard stride (when it is non-continuous, submatrix), the image may appeard distorted. In this case, it is better to explicitly specify the stride using cv::Mat::step1():
QImage img((uchar*)mat.data, mat.cols, mat.rows, mat.step1(), QImage::Format_RGB32);
Here is code for 24bit RGB and grayscale floating point. Easily adjustable for other types. It is as efficient as it gets.
QImage Mat2QImage(const cv::Mat3b &src) {
QImage dest(src.cols, src.rows, QImage::Format_ARGB32);
for (int y = 0; y < src.rows; ++y) {
const cv::Vec3b *srcrow = src[y];
QRgb *destrow = (QRgb*)dest.scanLine(y);
for (int x = 0; x < src.cols; ++x) {
destrow[x] = qRgba(srcrow[x][2], srcrow[x][1], srcrow[x][0], 255);
}
}
return dest;
}
QImage Mat2QImage(const cv::Mat_<double> &src)
{
double scale = 255.0;
QImage dest(src.cols, src.rows, QImage::Format_ARGB32);
for (int y = 0; y < src.rows; ++y) {
const double *srcrow = src[y];
QRgb *destrow = (QRgb*)dest.scanLine(y);
for (int x = 0; x < src.cols; ++x) {
unsigned int color = srcrow[x] * scale;
destrow[x] = qRgba(color, color, color, 255);
}
}
return dest;
}
OpenCV loads images into a Mat in Blue-Green-Red (BGR) format by default, while QImage expects RGB. This means that if you convert a Mat to QImage, the blue and red channels will be swapped. To fix this, before constructing the QImage, you need to change the BRG format of your Mat to RGB, via the cvtColor method using argument CV_BGR2RGB, like so:
Mat mat = imread("path/to/image.jpg");
cvtColor(mat, mat, CV_BGR2RGB);
QImage image(mat.data, mat.cols, mat.rows, QImage::Format_RGB888);
Alternatively, use rgbSwapped() on the QImage
QImage image = QImage(mat.data, mat.cols, mat.rows, QImage::Format_RGB888).rgbSwapped());
Mat opencv_image = imread("fruits.jpg", CV_LOAD_IMAGE_COLOR);
Mat dest;
cvtColor(opencv_image, dest,CV_BGR2RGB);
QImage image((uchar*)dest.data, dest.cols, dest.rows,QImage::Format_RGB888);
This is what worked for me. I modified Michal Kottman's code above.
I have the same problem as you too, so I develop four functions to alleviate my pain, they are
QImage mat_to_qimage_cpy(cv::Mat const &mat, bool swap = true);
QImage mat_to_qimage_ref(cv::Mat &mat, bool swap = true);
cv::Mat qimage_to_mat_cpy(QImage const &img, bool swap = true);
cv::Mat qimage_to_mat_ref(QImage &img, bool swap = true);
These functions can handle the images with 1, 3, 4 channels, every pixel must occupy one byte only(CV_8U->Format_Indexed8, CV_8UC3->QImage::Format_RGB888, CV_8UC4->QImage::Format_ARGB32), I do not deal with other types yet(QImage::Format_RGB16, QImage::Format_RGB666 and so on). The codes are located
at github.
The key concepts of **transform mat to Qimage ** are
/**
* #brief copy QImage into cv::Mat
*/
struct mat_to_qimage_cpy_policy
{
static QImage start(cv::Mat const &mat, QImage::Format format)
{
//The fourth parameters--mat.step is crucial, because
//opencv may do padding on every row, you need to tell
//the qimage how many bytes per row
//The last thing is if you want to copy the buffer of cv::Mat
//to the qimage, you need to call copy(), else the qimage
//will share the buffer of cv::Mat
return QImage(mat.data, mat.cols, mat.rows, mat.step, format).copy();
}
};
struct mat_to_qimage_ref_policy
{
static QImage start(cv::Mat &mat, QImage::Format format)
{
//every thing are same as copy policy, but this one share
//the buffer of cv::Mat but not copy
return QImage(mat.data, mat.cols, mat.rows, mat.step, format);
}
};
The key concepts of transform cv::Mat to Qimage are
/**
* #brief copy QImage into cv::Mat
*/
struct qimage_to_mat_cpy_policy
{
static cv::Mat start(QImage const &img, int format)
{
//same as convert mat to qimage, the fifth parameter bytesPerLine()
//indicate how many bytes per row
//If you want to copy the data you need to call clone(), else QImage
//cv::Mat will share the buffer
return cv::Mat(img.height(), img.width(), format,
const_cast<uchar*>(img.bits()), img.bytesPerLine()).clone();
}
};
/**
* #brief make Qimage and cv::Mat share the same buffer, the resource
* of the cv::Mat must not deleted before the QImage finish
* the jobs.
*/
struct qimage_to_mat_ref_policy
{
static cv::Mat start(QImage &img, int format)
{
//same as copy policy, but this one will share the buffer
return cv::Mat(img.height(), img.width(), format,
img.bits(), img.bytesPerLine());
}
};
If would be good if some one can extend these functions and make them support more types, please inform me if there are any bugs.
cv::Mat has a conversion operator to IplImage, so if you have something that converts the IplImage to a QImage, just use that (or make the - probably minor - adjustments to take the cv::Mat directly, the memory layout is the same, it's "just" the header that is different.)
This post shows how to convert a QImage to OpenCV's IplImage and vise-versa.
After that, if you need help to convert between IplImage* to cv::Mat:
// Assume data is stored by:
// IplImage* image;
cv::Mat mat(image, true); // Copies the data from image
cv::Mat mat(image, false); // Doesn't copy the data!
It's a hack, but will get the job done.
Use the static function convert16uc1 for the depth image:
QPixmap Viewer::convert16uc1(const cv::Mat& source)
{
quint16* pSource = (quint16*) source.data;
int pixelCounts = source.cols * source.rows;
QImage dest(source.cols, source.rows, QImage::Format_RGB32);
char* pDest = (char*) dest.bits();
for (int i = 0; i < pixelCounts; i++)
{
quint8 value = (quint8) ((*(pSource)) >> 8);
*(pDest++) = value; // B
*(pDest++) = value; // G
*(pDest++) = value; // R
*(pDest++) = 0; // Alpha
pSource++;
}
return QPixmap::fromImage(dest);
}
QPixmap Viewer::convert8uc3(const cv::Mat& source)
{
quint8* pSource = source.data;
int pixelCounts = source.cols * source.rows;
QImage dest(source.cols, source.rows, QImage::Format_RGB32);
char* pDest = (char*) dest.bits();
for (int i = 0; i < pixelCounts; i++)
{
*(pDest++) = *(pSource+2); // B
*(pDest++) = *(pSource+1); // G
*(pDest++) = *(pSource+0); // R
*(pDest++) = 0; // Alpha
pSource+=3;
}
return QPixmap::fromImage(dest);
}
QPixmap Viewer::convert16uc3(const cv::Mat& source)
{
quint16* pSource = (quint16*) source.data;
int pixelCounts = source.cols * source.rows;
QImage dest(source.cols, source.rows, QImage::Format_RGB32);
char* pDest = (char*) dest.bits();
for (int i = 0; i < pixelCounts; i++)
{
*(pDest++) = *(pSource+2); // B
*(pDest++) = *(pSource+1); // G
*(pDest++) = *(pSource+0); // R
*(pDest++) = 0; // Alpha
pSource+=3;
}
return QPixmap::fromImage(dest);
}
This did the trick for me. It's a little dodgy, has terrible performance (as pointed out in the comments), but works with all color formats I have thrown at it so far, and it is also very simple to do.
The procedure is as follows:
cv::Mat image = //...some image you want to display
// 1. Save the cv::Mat to some temporary file
cv::imwrite("../Images/tmp.jpg",image);
// 2. Load the image you just saved as a QImage
QImage img;
img.load("../Images/tmp.jpg");
Done!
If you, say, want to display it in a QLabel, then continue with:
// Set QImage as content of MyImageQLabel
ui-> MyImageQLabel->setPixmap(QPixmap::fromImage(img, Qt::AutoColor));
I personally use this for a simple image editor.