How to pass a C++ Template instance to a function? - c++

How can I pass any object of an templated class to another function in C++11?
In the snippet below passInObj does not compile because it complains about Printer&. I want to pass in any Printer it does not matter which template T I have used.
How can I do this and why does the solution below not work?
#include <iostream>
#include <vector>
template <typename T>
class Printer {
public:
Printer(const T& tl) : t(tl) {}
void print() const {
for (auto x : t) {
std::cout << x << std::endl;
}
}
const T &t;
};
// THIS LINE DOES NOT COMPILE
void passInObj(const Printer& p) {
p.print();
}
int main() {
std::vector<std::string> vec;
vec.push_back("ABC");
Printer<std::vector<std::string>> printer(vec);
printer.print();
passInObj(p);
return 0;
}

How can I do this
You need to make it into a function template:
template <class T>
void passInObj(const Printer<T>& p) {
p.print();
}
Demo
and why does the solution below not work?
Because Printer is not a type, it's only a template. For passInObj to work with any Printer<T>, you need to make the function into a function template so that it'll be instantiated for every Printer<T> which is used to call it.

While #TedLyngmo's answer should be your go-to by default, you can also do this via a polymorphic interface if you cannot make passInObj() a template for some reason or other.
This is done by adding a base interface class that will be derived by all Printer<> classes:
#include <iostream>
#include <vector>
class IPrinter {
public:
virtual void print() const = 0;
// Either that or public and virtual
protected:
~IPrinter() = default;
};
template <typename T>
class Printer : public IPrinter {
public:
Printer(const T& tl) : t(tl) {}
void print() const override {
for (auto x : t) {
std::cout << x << std::endl;
}
}
const T &t;
};
void passInObj(const IPrinter& p) {
p.print();
}
int main() {
std::vector<std::string> vec;
vec.push_back("ABC");
Printer<std::vector<std::string>> printer(vec);
printer.print();
passInObj(p);
return 0;
}

Related

Specialized inheritance of a templated class causes member function to return templated class type rather than inherited class type

Assume I have a base class like this:
template<typename T>
class Base {
public:
Base& operator()(const T& value) {
this->value = value;
return *this;
}
T value;
};
Now I want to inherit from this class to create type-specific classes
class InheritedFloat : public Base<float> {} inheritedFloat;
Now here I try to catch this inheritance in a functon:
void function(const InheritedFloat& inherited) {
std::cout << inherited.value << '\n';
}
Calling this function like this works fine, of course:
int main() {
function(inheritedFloat); //(inheritedFloat is a global instance)
return 0;
}
But when I try to call it with the operator()(const float& value){...} member function, function(const InheritedFloat& inherited){...} doesn't see it as a InheritedFloat-Type but instead as a Base<float>-Type:
int main() {
function(inheritedFloat(10.f)); //error
return 0;
}
Error:
Error C2664 'void function(const InheritedFloat &)': cannot convert argument 1 from 'Base<float>' to 'const InheritedFloat &'
So how can I make operator()(const T& value){...} return InheritedFloat& instead of Base<float>&?
To clearify further, this is just a simplified example (of course). I have dozens of inheritance cases. So I can't just template-specify function()
template<typename T>
void function(const Base<T>& inherited) {
std::cout << inherited.value << '\n';
}
because each inheritance needs to be treated differently. Types will overlap, so there will be multiple Base<std::size_t> cases, for example.
The whole code:
#include <iostream>
template<typename T>
class Base {
public:
Base& operator()(const T& value) {
this->value = value;
return *this;
}
T value;
};
class InheritedFloat : public Base<float> {} inheritedFloat;
void function(const InheritedFloat& inherited) {
std::cout << inherited.value << '\n';
}
int main() {
function(inheritedFloat(10.f));
return 0;
}
Thanks for reading, I appreciate any help!
You can utilize CRTP here. By supplying extra template parameter you can make base class function return a reference to a derived class:
#include <iostream>
template<typename Derived, typename T>
class Base {
public:
Derived & operator()(const T& value) {
this->value = value;
return *static_cast<Derived *>(this);
}
T value;
};
class InheritedFloat : public Base<InheritedFloat, float> {} inheritedFloat;
void function(const InheritedFloat& inherited) {
std::cout << inherited.value << '\n';
}
int main() {
function(inheritedFloat(10.f));
return 0;
}
online compiler

Calling parametrised method on list items with different template parameters

I'm trying to store and manipulate a list of template class objects with different parameter types; the template class has two parametrised methods, one returning the parameter type and a void one accepting it as input.
More specifically, I have a template class defined as follows:
template<typename T>
class Test
{
public:
virtual T a() = 0;
virtual void b(T t) = 0;
};
And different specifications of it, such as:
class TestInt : public Test<int>
{
public:
int a() {
return 1;
}
void b(int t) {
std::cout << t << std::endl;
}
};
class TestString : public Test<std::string>
{
public:
std::string a() {
return "test";
}
void b(std::string t) {
std::cout << t << std::endl;
}
};
I'd like to be able to store in one single list different objects of both TestInt and TestString type and loop through it calling one method as input for the other, as in:
for (auto it = list.begin(); it != list.end(); ++it)
(*it)->b((*it)->a());
I've looked into boost::any but I'm unable to cast the iterator to the specific class, because I don't know the specific parameter type of each stored object. Maybe this cannot be done in a statically typed language as C++, but I was wondering whether there could be a way around it.
Just for the sake of completeness, I'll add that my overall aim is to develop a "parametrised observer", namely being able to define an observer (as with the Observer Pattern) with different parameters: the Test class is the observer class, while the list of different types of observers that I'm trying to properly define is stored within the subject class, which notifies them all through the two methods a() and b().
The virtuals have actually no meaning here, since for each T the signatures are distinct.
So it seems you have Yet Another version of the eternal "how can we emulate virtual functions templates" or "how to create an interface without virtual functions":
Generating an interface without virtual functions?
How to achieve "virtual template function" in C++
The first one basically contains an idea that you could employ here.
Here's an idea of what I'd do:
Live On Coliru
#include <algorithm>
#include <iostream>
namespace mytypes {
template <typename T>
struct Test {
T a() const;
void b(T t) { std::cout << t << std::endl; }
};
template <> int Test<int>::a() const { return 1; }
template <> std::string Test<std::string>::a() const { return "test"; }
using TestInt = Test<int>;
using TestString = Test<std::string>;
}
#include <boost/variant.hpp>
namespace mytypes {
using Value = boost::variant<int, std::string>;
namespace detail {
struct a_f : boost::static_visitor<Value> {
template <typename T>
Value operator()(Test<T> const& o) const { return o.a(); }
};
struct b_f : boost::static_visitor<> {
template <typename T>
void operator()(Test<T>& o, T const& v) const { o.b(v); }
template <typename T, typename V>
void operator()(Test<T>&, V const&) const {
throw std::runtime_error(std::string("type mismatch: ") + __PRETTY_FUNCTION__);
}
};
}
template <typename O>
Value a(O const& obj) {
return boost::apply_visitor(detail::a_f{}, obj);
}
template <typename O, typename V>
void b(O& obj, V const& v) {
boost::apply_visitor(detail::b_f{}, obj, v);
}
}
#include <vector>
int main()
{
using namespace mytypes;
using AnyTest = boost::variant<TestInt, TestString>;
std::vector<AnyTest> list{TestInt(), TestString(), TestInt(), TestString()};
for (auto it = list.begin(); it != list.end(); ++it)
b(*it, a(*it));
}
This prints
1
test
1
test
Bonus Points
If you insist, you can wrap the AnyTest variant into a proper class and have a() and b(...) member functions on that:
Live On Coliru
int main()
{
using namespace mytypes;
std::vector<AnyTest> list{AnyTest(TestInt()), AnyTest(TestString()), AnyTest(TestInt()), AnyTest(TestString())};
for (auto it = list.begin(); it != list.end(); ++it)
it->b(it->a());
}
Expanding on my comment above, the simplest what I can currently think of to achieve what you are trying to do - at least as I understood it from your example code - is the following:
/* Interface for your container, better not forget the destructor! */
struct Test {
virtual void operate(void) = 0;
virtual ~Test() {}
};
/* Implementation hiding actual type */
template<typename T>
struct TestImpl : public T, public Test {
void operate(void) {
T::b(T::a());
}
};
/* Actual code as template policies */
struct IntTest {
int a(void) {
return 42;
}
void b(int value) {
std::cout << value << std::endl;
}
};
struct StringTest {
std::string a(void) {
return "Life? Don't talk to me about life.";
}
void b(std::string value) {
std::cout << value << std::endl;
}
};
You would then need to create a container for objects of class Test and fill it with objects of the respective TestImpl<IntTest>, TestImpl<StringTest>, and so on. To avoid object slicing you need reference or pointer semantics, that is std::vector<std::unique_ptr<Test> > for example.
for (auto it = list.begin(); it != list.end(); ++it) {
(*it)->operate();
}

How to use different functoids within an array or vector

I have written a small piece of code where I am able to call setter and getter functions packed within a functoid using mem_fun templates.
I now would like to use this approach on top of a class hierarchy where every class might have getter and setter which can be registered as pair within a vector or array to be able to call the getter and setter if needed. GUIObject and GUICompositeObject are example classes out of the described class hierarchy.
The bound_mem_fun_t for the objects have unfortunately different types and thats the reason I don't know how to integrate them into an array/vector of pointers to the functors.
In c++11 I would use std::function. Is there a way to emulate this in c++98?
Because our compiler support only c++98 I cannot use the new features of c++11 or c++14. Also boost is not allowed.
#include <functional>
class GUIObject
{
int m_Alpha;
public:
void SetAlpha(int a) { m_Alpha = a;};
int GetAlpha() {return m_Alpha;};
};
class GUICompositeObject: public GUIObject
{
int m_NumOfChilds;
public:
void SetNumOfChilds(int NumOfChilds) { m_NumOfChilds = NumOfChilds;};
int GetNumOfChilds() {return m_NumOfChilds;};
};
template<typename T>
struct bound_mem_fun_t
{
bound_mem_fun_t(std::mem_fun_t<int, T> GetFunc, std::mem_fun1_t<void, T, int> SetFunc, T* o) :
m_GetFunc(GetFunc), m_SetFunc(SetFunc), obj(o) { } ;
int operator()() { return m_GetFunc(obj); } ;
void operator()(int i) { m_SetFunc(obj, i); } ;
std::mem_fun_t<int, T> m_GetFunc;
std::mem_fun1_t<void, T, int> m_SetFunc;
T* obj;
};
int main()
{
GUIObject kGUIObject;
GUICompositeObject kCompObj;
bound_mem_fun_t<GUIObject> GUIObjectFunc(std::mem_fun(&GUIObject::GetAlpha), std::mem_fun(&GUIObject::SetAlpha), &kGUIObject);
GUIObjectFunc(17);
int ii = GUIObjectFunc();
bound_mem_fun_t<GUICompositeObject> GUICompObjectFunc(std::mem_fun(&GUICompositeObject::GetNumOfChilds), std::mem_fun(&GUICompositeObject::SetNumOfChilds), &kCompObj);
GUICompObjectFunc(17);
int iChilds = GUICompObjectFunc();
return 0;
}
Here is the complete solution after #filmors answer:
#include <functional>
#include <vector>
#include <iostream>
class GUIObject
{
int m_Alpha;
public:
void SetAlpha(int a) { m_Alpha = a;};
int GetAlpha() {return m_Alpha;};
};
class GUICompositeObject: public GUIObject
{
int m_NumOfChilds;
public:
void SetNumOfChilds(int NumOfChilds) { m_NumOfChilds = NumOfChilds;};
int GetNumOfChilds() {return m_NumOfChilds;};
};
struct bound_mem_fun_base
{
virtual int operator()() =0;
virtual void operator()(int) =0;
};
template<typename T>
struct bound_mem_fun_t : public bound_mem_fun_base
{
bound_mem_fun_t(std::mem_fun_t<int, T> GetFunc, std::mem_fun1_t<void, T, int> SetFunc, T* o) :
m_GetFunc(GetFunc), m_SetFunc(SetFunc), obj(o) { } ;
virtual int operator()() { return m_GetFunc(obj); } ;
virtual void operator()(int i) { m_SetFunc(obj, i); } ;
std::mem_fun_t<int, T> m_GetFunc;
std::mem_fun1_t<void, T, int> m_SetFunc;
T* obj;
};
template<typename T> bound_mem_fun_t<T>* make_setter(std::mem_fun_t<int, T> GetFunc, std::mem_fun1_t<void, T, int> SetFunc, T* o)
{
return new bound_mem_fun_t<T> (GetFunc, SetFunc, o);
}
int main()
{
GUIObject kGUIObject;
GUICompositeObject kCompObj;
std::vector<bound_mem_fun_base*> kBoundVector;
kBoundVector.push_back(new bound_mem_fun_t<GUIObject> (std::mem_fun(&GUIObject::GetAlpha), std::mem_fun(&GUIObject::SetAlpha), &kGUIObject));
kBoundVector.push_back(new bound_mem_fun_t<GUICompositeObject> (std::mem_fun(&GUICompositeObject::GetNumOfChilds), std::mem_fun(&GUICompositeObject::SetNumOfChilds), &kCompObj));
kBoundVector.push_back(make_setter<GUIObject> (std::mem_fun(&GUIObject::GetAlpha), std::mem_fun(&GUIObject::SetAlpha), &kGUIObject));
kBoundVector.push_back(make_setter<GUICompositeObject> (std::mem_fun(&GUICompositeObject::GetNumOfChilds), std::mem_fun(&GUICompositeObject::SetNumOfChilds), &kCompObj));
for (int i = 0; i < 4 ; i++)
{
(*kBoundVector[i])(i*10);
int res = (*kBoundVector[i])();
std::cout << "Getter result " << res << "\n";
}
return 0;
}
Unfortunately the make_setter function does not really shorten the creation of the functor. Any ideas will be welcome.
Just give your bound_mem_fun_t<T> a common base class and use dynamic dispatch to solve your problem:
struct bound_mem_fun_base {
virtual int operator()() = 0;
virtual void operator()(int) = 0;
};
template <typename T>
struct bound_mem_fun_t : bound_mem_fun_t ...
Then you can keep pointers to bound_mem_fun_base in your vector and call the elements as (*v[0])().
Also, TR1 does contain std::tr1::function, is that available?
First a remark on std::function from c++11: That will not solve your problem, because you need an already bounded function pointer. This pointer must be bound to your object. I believe what you need is an own implementation to std::bind.
I started only a very! small Binder class which is hopefully a starting point for your needs. If you need to have template parameter lists in older c++ versions, take a look for loki. http://loki-lib.sourceforge.net/
As a hint I can give you a short example of what i did:
class A
{
private:
int val;
public:
A(int i): val(i) {}
void Do(int i) { std::cout << "A " << val<< " " << i << std::endl; }
};
class B
{
private:
int val;
public:
B(int i): val(i){}
void Go(int i) { std::cout << "B " << val << " " << i << std::endl; }
};
class Base
{
public:
virtual void operator()(int i)=0;
};
template <typename T>
class Binder: public Base
{
void (T::*fnct)(int);
T* obj;
public:
Binder( void(T::*_fnct)(int), T*_obj):fnct(_fnct),obj(_obj){}
void operator()(int i)
{
(obj->*fnct)(i);
}
};
int main()
{
A a(100);
B b(200);
// c++11 usage for this example
//std::function<void(int)> af= std::bind( &A::Do, &a, std::placeholders::_1);
//af(1);
// hand crafted solution
Base* actions[2];
actions[0]= new Binder<A>( &A::Do, &a);
actions[1]= new Binder<B>( &B::Go, &b);
actions[0]->operator()(55);
actions[1]->operator()(77);
}

Adding a template typename to two template classes

I have learned this code like inheritance by using template technique on C++. This code works.
#include <iostream>
using namespace std;
template < typename T >
class Base {
public:
explicit Base(const T& policy = T()) : m_policy(policy) {}
void doSomething()
{
m_policy.doA();
m_policy.doB();
}
private:
T m_policy;
};
class Implemented {
public:
void doA() { cout << "A"; };
void doB() { cout << "B"; };
};
int main() {
Base<Implemented> x;
x.doSomething();
return 0;
}
However, is it possible to add arguments with new typename S in doA and doB? For example, this code doesn't work by type/value mismatch errors.
#include <iostream>
using namespace std;
template < typename T, typename S >
class Base {
public:
explicit Base(const T& policy = T()) : m_policy(policy) {}
void doSomething()
{
m_policy.doA(m_s);
m_policy.doB(m_s);
}
private:
T m_policy;
S m_s;
};
template < typename S >
class Implemented {
public:
void doA(S& s) { cout << "A" << s; };
void doB(S& s) { cout << "B" << s; };
};
int main() {
Base<Implemented, int> x;
x.doSomething();
return 0;
}
I guess I must let both class Base and Implemented know about an actual type of S at main(). How can I fix this issue? Thank you for your help in advance.
In this line:
Base<Implemented, int> x;
Implemented is no longer a type, now you made it a template. But Base still expects a type - so give it one:
Base<Implemented<int>, int> x;
When Implemented was a class, you used a template parameter T. Now that Implmented is a template class, you need to use a so called template template parameter, like so:
#include <iostream>
using namespace std;
template < template <class TS> class T, typename S >
class Base {
public:
explicit Base(const T<S>& policy = T<S>()) : m_policy(policy) {}
void doSomething()
{
m_policy.doA(m_s);
m_policy.doB(m_s);
}
private:
T<S> m_policy;
S m_s;
};
template < typename S >
class Implemented {
public:
void doA(S& s) { cout << "A" << s; };
void doB(S& s) { cout << "B" << s; };
};
int main() {
Base<Implemented, int> x;
x.doSomething();
return 0;
}

Callback in C++, template member?

Following code does NOT work, but it expresses well what I wish to do. There is a problem with the template struct container, which I think SHOULD work because it's size is known for any template argument.
class callback {
public:
// constructs a callback to a method in the context of a given object
template<class C>
callback(C& object, void (C::*method)())
: ptr.o(object), ptr.m(method) {}
// calls the method
void operator()() {
(&ptr.o ->* ptr.m) ();
}
private:
// container for the pointer to method
template<class C>
struct {
C& o;
void (C::*m)();
} ptr;
};
Is there any way to do such a thing? I mean have a non-template class callback which wraps any pointer to method?
Thanks C++ gurus!
Edit:
Please see this:
Callback in C++, template member? (2)
This is a complete working example that does what I think you're trying to do:
#include <iostream>
#include <memory>
// INTERNAL CLASSES
class CallbackSpecBase
{
public:
virtual ~CallbackSpecBase() {}
virtual void operator()() const = 0;
};
template<class C>
class CallbackSpec : public CallbackSpecBase
{
public:
CallbackSpec(C& o, void (C::*m)()) : obj(o), method(m) {}
void operator()() const { (&obj->*method)(); }
private:
C& obj;
void (C::*method)();
};
// PUBLIC API
class Callback
{
public:
Callback() {}
void operator()() { (*spec)(); }
template<class C>
void set(C& o, void (C::*m)()) { spec.reset(new CallbackSpec<C>(o, m)); }
private:
std::auto_ptr<CallbackSpecBase> spec;
};
// TEST CODE
class Test
{
public:
void foo() { std::cout << "Working" << std::endl; }
void bar() { std::cout << "Like a charm" << std::endl; }
};
int main()
{
Test t;
Callback c;
c.set(t, &Test::foo);
c();
c.set(t, &Test::bar);
c();
}
I recently implemented this:
#define UNKOWN_ITEM 0xFFFFFFFF
template <typename TArg>
class DelegateI
{
public:
virtual void operator()(TArg& a)=0;
virtual bool equals(DelegateI<TArg>* d)=0;
};
template <class TArg>
class Event
{
public:
Event()
{
}
~Event()
{
for (size_t x=0; x<m_vDelegates.size(); x++)
delete m_vDelegates[x];
}
void operator()(TArg& a)
{
for (size_t x=0; x<m_vDelegates.size(); x++)
{
m_vDelegates[x]->operator()(a);
}
}
void operator+=(DelegateI<TArg>* d)
{
if (findInfo(d) != UNKOWN_ITEM)
{
delete d;
return;
}
m_vDelegates.push_back(d);
}
void operator-=(DelegateI<TArg>* d)
{
uint32 index = findInfo(d);
delete d;
if (index == UNKOWN_ITEM)
return;
m_vDelegates.erase(m_vDelegates.begin()+index);
}
protected:
int findInfo(DelegateI<TArg>* d)
{
for (size_t x=0; x<m_vDelegates.size(); x++)
{
if (m_vDelegates[x]->equals(d))
return (int)x;
}
return UNKOWN_ITEM;
}
private:
std::vector<DelegateI<TArg>*> m_vDelegates;
};
template <class TObj, typename TArg>
class ObjDelegate : public DelegateI<TArg>
{
public:
typedef void (TObj::*TFunct)(TArg&);
ObjDelegate(TObj* t, TFunct f)
{
m_pObj = t;
m_pFunct = f;
}
virtual bool equals(DelegateI<TArg>* di)
{
ObjDelegate<TObj,TArg> *d = dynamic_cast<ObjDelegate<TObj,TArg>*>(di);
if (!d)
return false;
return ((m_pObj == d->m_pObj) && (m_pFunct == d->m_pFunct));
}
virtual void operator()(TArg& a)
{
if (m_pObj && m_pFunct)
{
(*m_pObj.*m_pFunct)(a);
}
}
TFunct m_pFunct; // pointer to member function
TObj* m_pObj; // pointer to object
};
template <typename TArg>
class FunctDelegate : public DelegateI<TArg>
{
public:
typedef void (*TFunct)(TArg&);
FunctDelegate(TFunct f)
{
m_pFunct = f;
}
virtual bool equals(DelegateI<TArg>* di)
{
FunctDelegate<TArg> *d = dynamic_cast<FunctDelegate<TArg>*>(di);
if (!d)
return false;
return (m_pFunct == d->m_pFunct);
}
virtual void operator()(TArg& a)
{
if (m_pFunct)
{
(*m_pFunct)(a);
}
}
TFunct m_pFunct; // pointer to member function
};
template <typename TArg>
class ProxieDelegate : public DelegateI<TArg>
{
public:
ProxieDelegate(Event<TArg>* e)
{
m_pEvent = e;
}
virtual bool equals(DelegateI<TArg>* di)
{
ProxieDelegate<TArg> *d = dynamic_cast<ProxieDelegate<TArg>*>(di);
if (!d)
return false;
return (m_pEvent == d->m_pEvent);
}
virtual void operator()(TArg& a)
{
if (m_pEvent)
{
(*m_pEvent)(a);
}
}
Event<TArg>* m_pEvent; // pointer to member function
};
template <class TObj, class TArg>
DelegateI<TArg>* delegate(TObj* pObj, void (TObj::*NotifyMethod)(TArg&))
{
return new ObjDelegate<TObj, TArg>(pObj, NotifyMethod);
}
template <class TArg>
DelegateI<TArg>* delegate(void (*NotifyMethod)(TArg&))
{
return new FunctDelegate<TArg>(NotifyMethod);
}
template <class TArg>
DelegateI<TArg>* delegate(Event<TArg>* e)
{
return new ProxieDelegate<TArg>(e);
}
use it like so:
define:
Event<SomeClass> someEvent;
enlist callbacks:
someEvent += delegate(&someFunction);
someEvent += delegate(classPtr, &class::classFunction);
someEvent += delegate(&someOtherEvent);
trigger:
someEvent(someClassObj);
You can also make your own delegates and overide what they do. I made a couple of others with one being able to make sure the event triggers the function in the gui thread instead of the thread it was called.
You need to use polymorphism. Use an abstract base class with a virtual invocation method (operator() if you please), with a templated descendant that implements the virtual method using the correct type signature.
The way you have it now, the data holding the type is templated, but the code meant to invoke the method and pass the object isn't. That won't work; the template type parameters need to flow through both construction and invocation.
#Barry Kelly
#include <iostream>
class callback {
public:
virtual void operator()() {};
};
template<class C>
class callback_specialization : public callback {
public:
callback_specialization(C& object, void (C::*method)())
: o(object), m(method) {}
void operator()() {
(&o ->* m) ();
}
private:
C& o;
void (C::*m)();
};
class X {
public:
void y() { std::cout << "ok\n"; }
};
int main() {
X x;
callback c(callback_specialization<X>(x, &X::y));
c();
return 0;
}
I tried this, but it does not work (print "ok")... why?
Edit:
As Neil Butterworth mentioned, polymorphism works through pointers and references,
X x;
callback& c = callback_specialization<X>(x, &X::y);
c();
Edit:
With this code, I get an error:
invalid initialization of non-const reference of type ‘callback&’
from a temporary of type ‘callback_specialization<X>’
Now, I don't understand that error, but if I replace callback& c with const callback& c and virtual void operator()() with virtual void operator()() const, it works.
You didn't say what errors you found, but I found that this worked:
template<typename C>
class callback {
public:
// constructs a callback to a method in the context of a given object
callback(C& object, void (C::*method)())
: ptr(object,method) {}
// calls the method
void operator()() {
(&ptr.o ->* ptr.m) ();
}
private:
// container for the pointer to method
// template<class C>
struct Ptr{
Ptr(C& object, void (C::*method)()): o(object), m(method) {}
C& o;
void (C::*m)();
} ptr;
};
Note that Ptr needs a constructor as it has a reference member.
You could do without struct Ptr and have the raw members.
Tested with VS2008 express.
Improving the OP's answer:
int main() {
X x;
callback_specialization<X> c(x, &X::y);
callback& ref(c);
c();
return 0;
}
This prints "ok".
Tested on VS2008 express.
Please see this
Callback in C++, template member? (2)