I am trying to add an image to a PDF generated in Reportlab. I am trying to access the image from a Django field, specifying the full path of the file.
When I run the below code I get: "Exception Value: getKeepWithNext".
Any help as to what I am doing wrong would be greatly appreciated.
def holding_pdf(self, course_slug, holding_slug):
buffer = io.BytesIO()
holding = HoldingDetail.objects.get(identifier=holding_slug)
doc = SimpleDocTemplate(buffer,
rightMargin=72,
leftMargin=72,
topMargin=72,
bottomMargin=72,
pagesize=A4,
title=f"Why the {holding.name} is in the portfolio.pdf")
elements = []
styles = getSampleStyleSheet()
elements.append(Paragraph(str(holding.logo.path), styles['Normal']))
elements.append(Image(holding.logo.path))
print(holding.logo.path)
doc.build(elements)
buffer.seek(0)
return FileResponse(buffer, as_attachment=False, filename=f"Why the {holding.name} is in the portfolio.pdf")
I think that you're using an incorrect Image class. Verify the python imports in your file, and sure you use the Image flowable class provides by reportlab.
from reportlab.lib.pagesizes import A4
from reportlab.lib.styles import getSampleStyleSheet
from reportlab.platypus import Paragraph, SimpleDocTemplate, Image
Related
I generate the image using the code below:
source_file = open('/path/to/myimage.jpg', 'rb')
image_generator = Thumbnail(source=source_file)
result = image_generator.generate()
What is the proper method to save the generated "result" back to django ImageField? ie in a model
The generated result seems to be a _io.BytesIO object. And it seems I cannot directly save it to ImageField.
Any help would be appreciated
Assuming you have a SampleModel as below,
class SampleModel(models.Model):
image = models.ImageField(null=True)
then,ContentFile do the magic for you. Follow the snippet,
from django.core.files.base import ContentFile
source_file = open('/path/to/myimage.jpg', 'rb')
image_generator = Thumbnail(source=source_file)
result = image_generator.generate()
# additional snippet
django_file = ContentFile(result.getvalue())
sample = SampleModel.objects.create()
sample.image.save('sample_name.jpg', django_file)
sample.save()
I'm using Django and reportlab to generate a PDF report
I already can generate the pdf, but I Wanted to append a logo.png to it.
these were the lines I added in
views.py:
from reportlab.platypus import Image
logo = Image("/cdss/static/cdss/img/logo.png")
exam.append(logo)
But it isn't working, Am I exporting the Image() method wrong? Or is Path to the file wrong?
Hope you can help me, thanks ;)
This Worked For me....
def PrintImage(request,std_id):
response = HttpResponse(content_type='application/pdf')
doc = SimpleDocTemplate(response,topMargin=2)
doc.pagesize = landscape(A6)
elements = []
I = Image('http://demoschoolzen.educationzen.com/images/tia.png')
I.drawHeight = 0.7*inch
I.drawWidth = 0.7*inch
elements.append(I)
doc.build(elements)
return response
and Call it from your URLs
Hi all reportlab master,
I've search the web and also here in stackoverflow but can't find a similar situation on my problem I'm trying to solve during this Holiday vacation.
In django admin, I'm trying to create an action to view my database to a specific format. If I select one record I can view the report in one page pdf. Which is fine. In case the user try to more record that's where the problem start. For example I select multiple record, I can view the report but all content is still in one page pdf.
Is there a way to show a record per page in pdf? All reportlab master jedi, Please help me how to do this the right way.
Here's my code on what I did.
from django.contrib import admin
from models import LatestRsl
from io import BytesIO
from reportlab.pdfgen import canvas
from django.http import HttpResponse
try:
from cStringIO import StringIO
except ImportError:
from StringIO import StringIO
from reportlab.lib.units import inch
from reportlab.lib.styles import getSampleStyleSheet, ParagraphStyle
from reportlab.platypus import BaseDocTemplate, PageTemplate, Paragraph, Frame
from reportlab.lib.pagesizes import letter
def go(modeladmin, request, queryset):
response = HttpResponse(mimetype='application/pdf')
response['Content-Disposition'] = 'filename = testframe.pdf'
buffer = StringIO()
c = canvas.Canvas(buffer)
doc = BaseDocTemplate(buffer, showBoundary=1, leftMargin= 0.1*inch, rightMargin= 0.1*inch,
topMargin= 0.1*inch, bottomMargin= 0.1*inch)
signfr = Frame(5.1*inch, 1.2*inch, 2.8*inch, 0.44*inch, showBoundary=1)
modelfr = Frame(3.6*inch, 4.6*inch, 2.8*inch, 0.44*inch, showBoundary=1)
doc.addPageTemplates([PageTemplate(id= 'rsl_frame', frames=[signfr, modelfr]),
PageTemplate(id= 'rsl_frame2', frames=[signfr, modelfr])])
story = []
styles=getSampleStyleSheet()
styles.add(ParagraphStyle(name='Verdana9', fontName= 'Verdana', fontSize= 9))
styles.add(ParagraphStyle(name='VerdanaB10', fontName= 'VerdanaB', fontSize= 10))
for obj in queryset:
#1st frame
model = Paragraph(obj.make,styles["Verdana9"])
story.append(model)
modelfr.addFromList(story,c)
#2nd frame
signatory = Paragraph(obj.signatory,styles["VerdanaB10"])
story.append(signatory)
signfr.addFromList(story,c)
doc.build(story)
c.showPage()
c.save()
pdf = buffer.getvalue()
buffer.close()
response.write(pdf)
return response
Assuming your queryset variable contains all the records you need, you could insert a PageBreak object. Just add from reportlab.platypus import PageBreak to the top of your file, then append a PageBreak object to your document's elements.
If you want to change the template for each page, you can also append a NextPageTemplate and pass the id of your PageTemplate. You'll need to add from reportlab.platypus import NextPageTemplate to the top of your file as well.
for obj in queryset:
#1st frame
model = Paragraph(obj.make,styles["Verdana9"])
story.append(model)
modelfr.addFromList(story,c)
#2nd frame
signatory = Paragraph(obj.signatory,styles["VerdanaB10"])
story.append(signatory)
signfr.addFromList(story,c)
# Force the report to use a different PageTemplate on the next page
story.append(NextPageTemplate('rsl_frame2'))
# Start a new page for the next object in the query
story.append(PageBreak())
You could move the PageBreak wherever you need it, but it's a simple "function" flowable. NextPageTemplate can take the id of any valid PageTemplate object that you've added via addPageTemplates.
I am having error after error trying to upload and resize images to s3 with pil and botos3 and the django default_storage. I am trying to do this on save in the admin.
here is the code:
from django.db import models
from django.forms import CheckboxSelectMultiple
import tempfile
from django.conf import settings
from django.core.files.base import ContentFile
from django.core.files.storage import default_storage as s3_storage
from django.core.cache import cache
from datetime import datetime
import Image, os
import PIL.Image as PIL
import re, os, sys, urlparse
class screenshot(models.Model):
title = models.CharField(max_length=200)
slug = models.SlugField(max_length=200)
image = models.ImageField(upload_to='screenshots')
thumbnail = models.ImageField(upload_to='screenshots-thumbs', blank=True, null=True, editable=False)
def save(self):
super(screenshot, self).save() # Call the "real" save() method
if self.image:
thumb = Image.open(self.image.path)
thumb.thumbnail(100, 100)
filename = str(self.slug)
temp_image = open(os.path.join('tmp',filename), 'w')
thumb.save(temp_image, 'JPEG')
from django.core.files import File
thumb_data = open(os.path.join('/tmp',filename), 'r')
thumb_file = File(thumb_data)
new_file.thumb.save(str(self.slug) + '.jpg', thumb_file)
def __str__(self):
return self.title
This is just one of the many ways I have tried to get it working, and I either get (2, 'No such file or directory') or some other error.
Please can someone help me to get it working. I want it to use the django backend to get the image uploaded to be resized and saved as the thumbnail and then saved. Let me know if you need to know any information. I would be happy to use the django snippet - http://djangosnippets.org/snippets/224/ but I don't know what data to feed it. I get the same IOErrors and 'no such path/filename' even though the main image is uploading to s3 fine. I have also tried things like:
myimage = open(settings.MEDIA_URL + str(self.image))
myimage_io = StringIO.StringIO()
imageresize = myimage.resize((100,100), Image.ANTIALIAS)
imageresize.save('resize_100_100_aa.jpg', 'JPEG', quality=75)
It's been 3 days of looking now so I am starting to go spare! Thanks
I had a similar problem, but in my case using sorl-thumbnail was not an option. I found that I can open an Image directly from S3BotoStorage by passing in a file descriptor instead of a path.
So instead of
thumb = Image.open(self.image.path)
use
thumb = Image.open(s3_storage.open(self.image.name))
Then you can process and save the new file locally as you were doing before.
Why don't you try sorl-thumbnail. It has the exact same interface as the default ImageField django provides and it seems like it would be a lot nicer to work with than the roll-your-own support.
Storage support
Pluggable Engine support (PIL, pgmagick)
Pluggable Key Value Store support (redis, cached db)
Pluggable Backend support
Admin integration with possibility to delete
Dummy generation
Flexible, simple syntax, generates no html
ImageField for model that deletes thumbnails
CSS style cropping options
Margin calculation for vertical positioning
I'm trying to upload and save a resized image in a db.BlobProperty field on Google App Engine using Django.
the relevant part of my view that process the request looks like this:
image = images.resize(request.POST.get('image'), 100, 100)
recipe.large_image = db.Blob(image)
recipe.put()
Which seems like it would be the logical django equivalent of the example in the docs:
from google.appengine.api import images
class Guestbook(webapp.RequestHandler):
def post(self):
greeting = Greeting()
if users.get_current_user():
greeting.author = users.get_current_user()
greeting.content = self.request.get("content")
avatar = images.resize(self.request.get("img"), 32, 32)
greeting.avatar = db.Blob(avatar)
greeting.put()
self.redirect('/')
(source: http://code.google.com/appengine/docs/python/images/usingimages.html#Transform)
But, I keep getting an error that says: NotImageError / Empty image data.
and refers to this line:
image = images.resize(request.POST.get('image'), 100, 100)
I'm having trouble getting to the image data. Seems like it's not being uploaded but I can't figure out why. My form has the enctype="multipart/form-data" and all that. I think something's wrong with how I'm referring to the image data. "request.POST.get('image')" but I can't figure out how else to reference it. Any ideas?
Thanks in advance.
After some guidance from "hcalves" I figured out the problem. First of all, the default version of Django that comes bundled with App Engine is version 0.96 and how the framework handles uploaded files has changed since then. However in order to maintain compatibility with older apps you have to explicitly tell App Engine to use Django 1.1 like this:
from google.appengine.dist import use_library
use_library('django', '1.1')
You can read more about that in the app engine docs.
Ok, so here's the solution:
from google.appengine.api import images
image = request.FILES['large_image'].read()
recipe.large_image = db.Blob(images.resize(image, 480))
recipe.put()
Then, to serve the dynamic images back again from the datastore, build a handler for images like this:
from django.http import HttpResponse, HttpResponseRedirect
def recipe_image(request,key_name):
recipe = Recipe.get_by_key_name(key_name)
if recipe.large_image:
image = recipe.large_image
else:
return HttpResponseRedirect("/static/image_not_found.png")
#build your response
response = HttpResponse(image)
# set the content type to png because that's what the Google images api
# stores modified images as by default
response['Content-Type'] = 'image/png'
# set some reasonable cache headers unless you want the image pulled on every request
response['Cache-Control'] = 'max-age=7200'
return response
You access uploaded data via request.FILES['field_name'].
http://docs.djangoproject.com/en/dev/topics/http/file-uploads/
Reading more about Google's Image API, seems to me you should be doing something like this:
from google.appengine.api import images
image = Image(request.FILES['image'].read())
image = image.resize(100, 100)
recipe.large_image = db.Blob(image)
recipe.put()
request.FILES['image'].read() should work because it's supposed to be a Django's UploadedFile instance.