I want to combine the list and find(), but I don't know how to merge them - c++

Question

Please see the part where the find() function is called. (I ran it in Visual Studio.)
Code:
using namespace std;
int main(void) {
//Implementing the find()
/*
bool Find(const Stu & a); {
return (*it).name;
}
*/
list<Astu>::iterator that;
//that = astu.begin();
//that = find(astu.begin(), astu.end(), (*it).name);
for (it = stu.begin(); it != stu.end(); it++) {
that = find_if(astu.begin(), astu.end(), (*it).name);
if (that != astu.end()) {
all = astu.erase(all);
all++;
}
else
all++;
}
/*
//Filter absenteeism from the total student roster
for (it = stu.begin(); it != stu.end(); it++) {
for (all = astu.begin(); all != astu.end();) {
if (!strcmp((*all).name, (*it).name)) {
//Delete attendees and latecomers from the list
all = astu.erase(all);
}
else
all++;
}
}
*/
cout << "---------------------\n결석자: " << endl;
//이름순으로 정렬
astu.sort(SizeComp2);
//결석자들 출력
for (all = astu.begin(); all != astu.end(); all++) {
cout << "이름: " << (*all).name << endl;
}
return 0;
}
Output:
C2064 error occurred: Term does not evaluate to a function that takes
1 argument.
Even with find_if() in this code, there is a problem. The bool() part in the comment was used for the find_if object, but it doesn't seem to be used well here.
I deleted the part where there was no problem as a result of debugging. You must use an unconditional list, not a vector.
Where should I fix it?

Answer 1

The third argument to std::find_if is a function.
You could use a lambda as the function:
auto that = find_if(astu.begin(), astu.end(), [it](Astu const& astu)
{
return astu.name == it->name;
});
[This assumes that Astu::name is a std::string]