Convert C-Source image dump into original image - c++

Question

I have created with GIMP a C-Source image dump like the following:
/* GIMP RGBA C-Source image dump (example.c) */
static const struct {
guint width;
guint height;
guint bytes_per_pixel; /* 2:RGB16, 3:RGB, 4:RGBA */
guint8 pixel_data[304 * 98 * 2 + 1];
} example= {
304, 98, 2,
"\206\061\206\061..... }
Is there a way to read this in GIMP again in order to get back the original image? because it doesn't seem possible.
Or does it exist a tool that can do this back-conversion?
EDITED
Following some suggestion I tried to write a simple C programme to make the reverse coversion ending up with something very similar to another code found on internet but both dont work:
#include <stdlib.h>
#include <stdio.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include "imgs_press.h"
#include <stdio.h>
#include <unistd.h>
#include <fcntl.h>
using namespace std;
int main(int argc, char** argv) {
int fd;
char *name = "orignal_img.pnm";
fd = open(name, O_WRONLY | O_CREAT, 0644);
if (fd == -1) {
perror("open failed");
exit(1);
}
if (dup2(fd, 1) == -1) {
perror("dup2 failed");
exit(1);
}
// file descriptor 1, i.e. stdout, now points to the file
// "helloworld" which is open for writing
// You can now use printf which writes specifically to stdout
printf("P2\n");
printf("%d %d\n", press_high.width, press_high.height);
for(int x=0; x<press_high.width * press_high.height * 2; x++) {
printf("%d ", press_high.pixel_data[x]);
}
}
As suggested by n-1-8e9-wheres-my-share-m, maybe I need to manipulate the pixels usign the correct decode, but I have no idea how to do that, does anybody have other suggestions?
The image I got is indeed distorted:

Answer 1

Updated Answer
If you want to decode the RGB565 and write a NetPBM format PNM file without using ImageMagick, you can do this:
#include <stdint.h> /* for uint8_t */
#include <stdio.h> /* for printf */
/* tell compiler what those GIMP types are */
typedef int guint;
typedef uint8_t guint8;
#include <YOURGIMPIMAGE>
int main(){
int w = gimp_image.width;
int h = gimp_image.height;
int i;
uint16_t* RGB565p = (uint16_t*)&(gimp_image.pixel_data);
/* Print P3 PNM header on stdout */
printf("P3\n%d %d\n255\n",w, h);
/* Print RGB pixels, ASCII, one RGB pixel per line */
for(i=0;i<w*h;i++){
uint16_t RGB565 = *RGB565p++;
uint8_t r = (RGB565 & 0xf800) >> 8;
uint8_t g = (RGB565 & 0x07e0) >> 3;
uint8_t b = (RGB565 & 0x001f) << 3;
printf("%d %d %d\n", r, g ,b);
}
}
Compile with:
clang example.c
And run with:
./a.out > result.pnm
I have not tested it too extensively beyond your sample image, so you may want to make a test image with some reds, greens, blues and shades of grey to ensure that all my bit-twiddling is correct.
Original Answer
The easiest way to get your image back would be... to let ImageMagick do it.
So, take your C file and add a main() to it that simply writes the 304x98x2 bytes starting at &(example.pixel_data) to stdout:
Compile it with something like:
clang example.c -o program # or with GCC
gcc example.c -o program
Then run it, writing to a file for ImageMagick with:
./program > image.bin
And tell ImageMagick its size, type and where it is and what you want as a result:
magick -size 304x98 RGB565:image.bin result.png
I did a quick, not-too-thorough test of the following code and it worked fine for an image I generated with GIMP. Note it doesn't handle alpha/transparency but that could be added if necessary. Save it as program.c:
#include <unistd.h> /* for write() */
#include <stdint.h> /* for uint8_t */
/* tell compiler what those GIMP types are */
typedef int guint;
typedef uint8_t guint8;
<PASTE YOUR GIMP FILE HERE>
int main(){
/* Work out how many bytes to write */
int nbytes = example.width * example.height * 2;
/* Write on stdout for redirection to a file - may need to reopen in binary mode if on Windows */
write(1, &(example.pixel_data), nbytes);
}
If I run this with the file you provided via Google Drive I get: