Show django form in a designed page - django

Question

How are you?
I m totally new in Django.I designed a page and I wanted to show a django form(edit or create) in a well designed HTML page. but i do not know how.
This is my owner method:
class OwnerUpdateView(LoginRequiredMixin, UpdateView):
"""
queryset to the requesting user.
"""
def get_queryset(self):
print('update get_queryset called')
""" Limit a User to only modifying their own data. """
qs = super(OwnerUpdateView, self).get_queryset()
return qs.filter(user=self.request.user)
class OwnerCreateView(LoginRequiredMixin, CreateView):
"""
Sub-class of the CreateView to automatically pass the Request to the Form
and add the owner to the saved object.
"""
# Saves the form instance, sets the current object for the view, and redirects to get_success_url().
def form_valid(self, form):
print('form_valid called')
object = form.save(commit=False)
object.user = self.request.user
object.save()
return super(OwnerCreateView, self).form_valid(form)
This is my views.py
class TaskUpdateView(OwnerUpdateView):
model = Task
fields = ["title", "text", "endDate"]
class TaskCreateView(OwnerCreateView):
model = Task
fields = ["title","text","status","endDate"]
This is my urls.py:
app_name='task'
urlpatterns = [
path('', views.TaskListView.as_view(), name='all'),
path('task/<int:pk>/', views.TaskDetailView.as_view(), name='detail'),
path('task/create', views.TaskCreateView.as_view(success_url=reverse_lazy('task:all')), name='task_create'),
path('task/update/<int:pk>', views.TaskUpdateView.as_view(success_url=reverse_lazy('task:all')),
name='task_update'),
path('task/delete/<int:pk>', views.TaskDeleteView.as_view(success_url=reverse_lazy('task:all')),
name='task_delete'),
path("accounts/login/", views.login, name='login'),
path("accounts/logout/", views.logout, name='logout'),
]
And this is the models.py:
class Task(models.Model):
title=models.CharField(max_length=250)
text=models.TextField()
user=models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE, null=False)
status=models.ForeignKey('Status',on_delete=models.SET_NULL,null=True)
startDate=models.DateTimeField(auto_now_add=True)
endDate=models.DateField(null=True)
def __str__(self):
return self.title
class Status(models.Model):
name=models.CharField(max_length=250)
def __str__(self):
return self.name
And this is where these both function work:
{%extends 'base.html'%}
{% block content %}
<form action="" method="post">
{% csrf_token %}
<table>{{ form.as_table }}</table>
<input type="submit" value="Submit">
{# <input type="submit" onclick="window.location='{% url 'project:all' %}' ; return false;" value="Cancel">#}
</form>
{% endblock %}
How can i separate each element of this form and put it in a better designed page?
Thanks

Answer 1

There are two ways:
Option 1:
Loop over the form fields and render them individually:
{% for field in form %}
<div class="form-group">
{{ field.errors }}
{{ field.label_tag }} {{ field }}
{% if field.help_text %}
<span class="form-text">{{ field.help_text|safe }}</span>
{% endif %}
</div>
{% endfor %}
See docs for more.
Option 2:
You can manually create form inputs and give them the correct field name attribute. This gives you more control but also requires more work:
<div class="form-group"
<input
type="text"
name="title"
value="{{ form.title.value }}"
class="form-control {% if form.title.errors %}is-invalid{% endif %}"
>
{% if form.title.help_text%}
<span class="form-text">{{ form.title.help_text|safe }}</span>
{% endif %}
<div class="invalid-feedback">{{ form.title.errors }}</div>
</div>
<!-- now do the same for other fields -->