I'm looking to make a basic regex pattern for a url that will exclude any subdomains for soe basic mocking (I know there are some weaknesses in the regex for something more serious)
so for example this works
http:\/\/.*\/accounts\/.+
it matches my urls so for example
http://localhost:8080/accounts/mynewaccount
but what I would like it to do is not pickup the 'sub endpoints' so for example I would like it not to match
http://localhost:8080/accounts/mynewaccount/address
I've tried doing this by adding ^[/] to the end or by adding a surrounding ^ and $ but I don't seem to quite get it ? Can anyone help ? The less sophisticated the better really as it is just for mocking end points in a basic set of unit tests
Related
I'm looking for a regex function to implement in a goal for Google Analytics.
Consider this URL: /dagje-uit/....variable part..../contact/vpv/bedankt
Regex should work when beginning of URL matches /dagje-uit/ and end part contains /contact/vpv/bedankt Everything in the middle can be variable.
Without result i've tried
(?=^/dagje-uit/.*)(?=.*/bedankt$).*
(?=^dagje-uit.*)(?=.*bedankt$).*
Thanks in advance!
Regards,
Pim
Forgive me if Google Analytics has some regex standards which I am overlooking but is it possible that your regex is failing because it does not account for the start of the whole of the URL? Adding .* to either end of your regex may help.
It also looks like your regex is over-complex for the conditions you have described. Could a simpler match be :
.*/dagje-uit/.*/contact/vpv/bedankt.*
or
http(s)?://.*/dagje-uit/.*/contact/vpv/bedankt.*
if you want to be a little more confident that it is a valid URL.
I'm setting up URL Rewrite on an IIS and i need to match the following URLs using regex.
http://sub.mysite.com
sub.mysite.com
sub.mysite.com/
sub.mysite.com/Site1
sub.mysite.com/Site1/admin
but not:
sub.mysite.com/admin
sub.mysite.com/admin/somethingelse
sub.mysite.com/admin/admin
The site it self (sub.mysite.com) should not be "hardcoded" in the expression. Instead, it should be matched by something like .*.
I'm really blank on this one. I did find solutions to match the different URLs but once i try to combine them either none of them match or all of them do.
I hope someone can help me.
For your specific case, assuming you are matching the part after the domain (REQUEST_URI):
(?!/admin).*
(?!...) is a negative lookahead. I am not sure if it is supported in the IIS URL Rewrite engine. If not, a better approach would be to check for a complementary approach:
Or as #kirilloid said, just match /admin/? and discard (pay attention to slashes).
BTW. if you want to quickly test RegExps with a "visual" feedback, I highly recommend http://gskinner.com/RegExr/
([A-Za-z0-9]+.)+.com(?!/admin)/?([A-Za-z0-9]+/?)*
this should do the trick
I'm using CodeIgniter to write an app where a user will be allowed to register an account and is assigned a URL (URL slug) of their choosing (ex. domain.com/user-name). CodeIgniter has a URL routing feature that allows the utilization of regular expressions (link).
User's are only allowed to register URL's that contain alphanumeric characters, dashes (-), and under scores (_). This is the regex I'm using to verify the validity of the URL slug: ^[A-Za-z0-9][A-Za-z0-9_-]{2,254}$
I am using the url routing feature to route a few url's to features on my site (ex. /home -> /pages/index, /activity -> /user/activity) so those particular URL's obviously cannot be registered by a user.
I'm largely inexperienced with regular expressions but have attempted to write an expression that would match any URL slugs with alphanumerics/dash/underscore except if they are any of the following:
default_controller
404_override
home
activity
Here is the code I'm using to try to match the words with that specific criteria:
$route['(?!default_controller|404_override|home|activity)[A-Za-z0-9][A-Za-z0-9_-]{2,254}'] = 'view/slug/$1';
but it isn't routing properly. Can someone help? (side question: is it necessary to have ^ or $ in the regex when trying to match with URL's?)
Alright, let's pick this apart.
Ignore CodeIgniter's reserved routes.
The default_controller and 404_override portions of your route are unnecessary. Routes are compared to the requested URI to see if there's a match. It is highly unlikely that those two items will ever be in your URI, since they are special reserved routes for CodeIgniter. So let's forget about them.
$route['(?!home|activity)[A-Za-z0-9][A-Za-z0-9_-]{2,254}'] = 'view/slug/$1';
Capture everything!
With regular expressions, a group is created using parentheses (). This group can then be retrieved with a back reference - in our case, the $1, $2, etc. located in the second part of the route. You only had a group around the first set of items you were trying to exclude, so it would not properly capture the entire wild card. You found this out yourself already, and added a group around the entire item (good!).
$route['((?!home|activity)[A-Za-z0-9][A-Za-z0-9_-]{2,254})'] = 'view/slug/$1';
Look-ahead?!
On that subject, the first group around home|activity is not actually a traditional group, due to the use of ?! at the beginning. This is called a negative look-ahead, and it's a complicated regular expression feature. And it's being used incorrectly:
Negative lookahead is indispensable if you want to match something not followed by something else.
There's a LOT more I could go into with this, but basically we don't really want or need it in the first place, so I'll let you explore if you'd like.
In order to make your life easier, I'd suggest separating the home, activity, and other existing controllers in the routes. CodeIgniter will look through the list of routes from top to bottom, and once something matches, it stops checking. So if you specify your existing controllers before the wild card, they will match, and your wild card regular expression can be greatly simplified.
$route['home'] = 'pages';
$route['activity'] = 'user/activity';
$route['([A-Za-z0-9][A-Za-z0-9_-]{2,254})'] = 'view/slug/$1';
Remember to list your routes in order from most specific to least. Wild card matches are less specific than exact matches (like home and activity), so they should come after (below).
Now, that's all the complicated stuff. A little more FYI.
Remember that dashes - have a special meaning when in between [] brackets. You should escape them if you want to match a literal dash.
$route['([A-Za-z0-9][A-Za-z0-9_\-]{2,254})'] = 'view/slug/$1';
Note that your character repetition min/max {2,254} only applies to the second set of characters, so your user names must be 3 characters at minimum, and 255 at maximum. Just an FYI if you didn't realize that already.
I saw your own answer to this problem, and it's just ugly. Sorry. The ^ and $ symbols are used improperly throughout the lookahead (which still shouldn't be there in the first place). It may "work" for a few use cases that you're testing it with, but it will just give you problems and headaches in the future.
Hopefully now you know more about regular expressions and how they're matched in the routing process.
And to answer your question, no, you should not use ^ and $ at the beginning and end of your regex -- CodeIgniter will add that for you.
Use the 404, Luke...
At this point your routes are improved and should be functional. I will throw it out there, though, that you might want to consider using the controller/method defined as the 404_override to handle your wild cards. The main benefit of this is that you don't need ANY routes to direct a wild card, or to prevent your wild card from goofing up existing controllers. You only need:
$route['404_override'] = 'view/slug';
Then, your View::slug() method would check the URI, and see if it's a valid pattern, then check if it exists as a user (same as your slug method does now, no doubt). If it does, then you're good to go. If it doesn't, then you throw a 404 error.
It may not seem that graceful, but it works great. Give it a shot if it sounds better for you.
I'm not familiar with codeIgniter specifically, but most frameworks routing operate based on precedence. In other words, the default controller, 404, etc routes should be defined first. Then you can simplify your regex to only match the slugs.
Ok answering my own question
I've seem to come up with a different expression that works:
$route['(^(?!default_controller$|404_override$|home$|activity$)[A-Za-z0-9][A-Za-z0-9_-]{2,254}$)'] = 'view/slug/$1';
I added parenthesis around the whole expression (I think that's what CodeIgniter matches with $1 on the right) and added a start of line identifier: ^ and a bunch of end of line identifiers: $
Hope this helps someone who may run into this problem later.
I have a regex pattern for URL's that I use to check for links in a body of text. The only problem is that the pattern will match this link
stackoverflow.com
And this sentence
I'm a sentence.Next Sentence.
Obviously this would make sense because my pattern doesn't strong check .com, .co.uk, .com.au etc
I want it to match stackoverflow.com and not the latter.
As I'm no Regex expert, does anyone know of any good Regex patterns for checking for all types of URL's in a body text, while not matching the sentences like above?
If I have to strong check the domain extension, I suppose I'll have to settle.
Here's my pattern, but i don't think it help.
(([\w]+:)?\/\/)?(([\d\w]|%[a-fA-f\d]{2,2})+(:([\d\w]|%[a-fA-f\d]{2,2})+)?#)?([\d\w][-\d\w]{0,253}[\d\w]\.)+[\w]{2,4}(:[\d]+)?(\/([-+_~.\d\w]|%[a-fA-f\d]{2,2})*)*(\?(&?([-+_~.\d\w]|%[a-fA-f\d]{2,2})=?)*)?(#([-+_~.\d\w]|%[a-fA-f\d]{2,2})*)?
I would definitely suggest finding a working regex that someone else has made (which would probably include a strong check on the domain extension), but here is one possible way to just modify your existing regex.
It requires that you make the assumption that usually links will not mix case in the domain extension, for example you might see .COM or .com but probably not .Com, if you only match domain extensions that don't mix case then you would avoid matching most sentences.
In the middle of your regex you have [\w]{2,4}, try changing this to ([A-Z]{2,4}|[a-z]{2,4}) (or (?:[A-Z]{2,4}|[a-z]{2,4}) if you don't want a new captured group).
I found an updated version of John Gruber's regex for url matching in this post by user GianPac, which states it's been adapted to recognize url without protocol or the www part:
(?i)\b((?:[a-z][\w-]+:(?:/{1,3}|[a-z0-9%])|www\d{0,3}[.]|[a-z0-9.-]+[.][a-z]{2,4}/?)(?:[^\s()<>]+|(([^\s()<>]+|(([^\s()<>]+)))))(?:(([^\s()<>]+|(([^\s()<>]+))))|[^\s`!()[]{};:'\".,<>?«»“”‘’]))
Whilst this works in most cases, I found it does not match "google.com". It does match "google.comm" and "google.co.uk", so this must be a small oversight.
The trouble is, I literally hate regex. It's the bane of my life. I just want to try and tweak this one more time to allow for "google.com" - can anyone throw me a pointer? I (think) it's something to do with this part of the code:
+[.][a-z]{2,4}/?)
?
Change it from {2,4} to {1,4} and it will match.
(?i)\b((?:[a-z][\w-]+:(?:/{1,3}|[a-z0-9%])|www\d{0,3}[.]|[a-z0-9.-]+[.][a-z]{1,4}/?)(?:[^\s()<>]+|(([^\s()<>]+|(([^\s()<>]+)))))(?:(([^\s()<>]+|(([^\s()<>]+))))|[^\s`!()[]{};:'\".,<>?«»“”‘’]))
It's still completely incomprehensible though, and I'm not sure I'd trust a regex url checker that doesn't match google.com to begin with! Most languages have something built in for parsing URLs, that's a better option if possible anyway.