SwiftUI Multiple Buttons with Popovers in HStack Behavior - swiftui

When having multiple buttons with popovers in an HStack, I get weird behavior. Whenever you tap one button, the popup shows up correctly. But, when you click on the second item, the first popover quickly closes then reopens. Expected behavior is that it closes the first popover and opens the second. Xcode 12.5.1, iOS 14.5
Here's my code:
struct ContentView: View {
var items = ["item1", "item2", "item3"]
var body: some View {
HStack {
MyGreatItemView(item: items[0])
MyGreatItemView(item: items[1])
MyGreatItemView(item: items[2])
}
.padding(300)
}
struct MyGreatItemView: View {
#State var isPresented = false
var item: String
var body: some View {
Button(action: { isPresented.toggle() }) {
Text(item)
}
.popover(isPresented: $isPresented) {
PopoverView(item: item)
}
}
}
struct PopoverView: View {
#State var item: String
var body: some View {
print("new PopoverView")
return Text("View for \(item)")
}
}
struct ContentView_Previews: PreviewProvider {
static var previews: some View {
ContentView()
}
}
}
Thanks for any help!

Normally you'd use popover(item:content:), but you'll get an error... even the example in the documentation crashes.
*** Terminating app due to uncaught exception 'NSGenericException', reason: 'UIPopoverPresentationController (<UIPopoverPresentationController: 0x14a109890>) should have a non-nil sourceView or barButtonItem set before the presentation occurs.'
What I came up with instead is to use a singular #State presentingItem: Item? in ContentView. This ensures that all the popovers are tied to the same State, so you have full control over which ones are presented and which ones aren't.
But, .popover(isPresented:content:)'s isPresented argument expects a Bool. If this is true it presents, if not, it will dismiss. To convert presentingItem into a Bool, just use a custom Binding.
Binding(
get: { presentingItem == item }, /// present popover when `presentingItem` is equal to this view's `item`
set: { _ in presentingItem = nil } /// remove the current `presentingItem` which will dismiss the popover
)
Then, set presentingItem inside each button's action. This is the part where things get slightly hacky - I've added a 0.5 second delay to ensure the current displaying popover is dismissed first. Otherwise, it won't present.
if presentingItem == nil { /// no popover currently presented
presentingItem = item /// dismiss that immediately, then present this popover
} else { /// another popover is currently presented...
presentingItem = nil /// dismiss it first
DispatchQueue.main.asyncAfter(deadline: .now() + 0.5) {
presentingItem = item /// present this popover after a delay
}
}
Full code:
/// make equatable, for the `popover` presentation logic
struct Item: Equatable {
let id = UUID()
var name: String
}
struct ContentView: View {
#State var presentingItem: Item? /// the current presenting popover
let items = [
Item(name: "item1"),
Item(name: "item2"),
Item(name: "item3")
]
var body: some View {
HStack {
MyGreatItemView(presentingItem: $presentingItem, item: items[0])
MyGreatItemView(presentingItem: $presentingItem, item: items[1])
MyGreatItemView(presentingItem: $presentingItem, item: items[2])
}
.padding(300)
}
}
struct MyGreatItemView: View {
#Binding var presentingItem: Item?
let item: Item /// this view's item
var body: some View {
Button(action: {
if presentingItem == nil { /// no popover currently presented
presentingItem = item /// dismiss that immediately, then present this popover
} else { /// another popover is currently presented...
presentingItem = nil /// dismiss it first
DispatchQueue.main.asyncAfter(deadline: .now() + 0.5) {
if presentingItem == nil { /// extra check to ensure no popover currently presented
presentingItem = item /// present this popover after a delay
}
}
}
}) {
Text(item.name)
}
/// `get`: present popover when `presentingItem` is equal to this view's `item`
/// `set`: remove the current `presentingItem` which will dismiss the popover
.popover(isPresented: Binding(get: { presentingItem == item }, set: { _ in presentingItem = nil }) ) {
PopoverView(item: item)
}
}
}
struct PopoverView: View {
let item: Item /// no need for #State here
var body: some View {
print("new PopoverView")
return Text("View for \(item.name)")
}
}
Result:

Related

Get selected item in SwiftUI list without using a navigation link

I'm writing a SwiftUI Mac app that is similar to a kanban board. The app has three lists: Todo, Doing, and Done. At the bottom of each list is a button to move a task to another list. For example the todo list has a Start Doing button. Selecting a task from the todo list and clicking the button should move the task from the todo list to the doing list.
Every SwiftUI list selection example I have seen uses a navigation link. Selecting a list item takes you to another view. But I don't want to want to navigate to another view when selecting a list item. I want the selected task so I can change its status and move it to the correct list when clicking the button.
Here's the code for one of my lists.
struct TodoList: View {
// The board has an array of tasks.
#Binding var board: KanbanBoard
#State private var selection: Task? = nil
#State private var showAddSheet = false
var body: some View {
VStack {
Text("Todo")
.font(.title)
List(todoTasks, selection: $selection) { task in
Text(task.title)
}
HStack {
Button(action: { showAddSheet = true }, label: {
Label("Add", systemImage: "plus.square")
})
Spacer()
Button(action: { selection?.status = .doing}, label: {
Label("Start Doing", systemImage: "play.circle")
})
}
}
.sheet(isPresented: $showAddSheet) {
AddTaskView(board: $board)
}
}
var todoTasks: [Task] {
// Task conforms to Identifiable.
// A task has a status that is an enum: todo, doing, or done.
return board.tasks.filter { $0.status == .todo}
}
}
When I click on a list item, it is not selected.
How do I get the selected item from the list without using a navigation link?
Workaround
Tamas Sengel's answer led me to a workaround. Give each list item a Start Doing button so I don't have to track the selection.
List(todoTasks, id: \.self) { task in
HStack {
Text(task.title)
Button {
task.status = .doing
} label: {
Text("Start Doing")
}
}
}
The workaround helps for my specific case. But I'm going to keep the question open in hopes of an answer that provides a better alternative to using a button for people who want a way to get the selected list item.
Use a Button in the List and in the action, set a #State variable to the current list item.
#State var currentTask: Task?
List(todoTasks, id: \.self) { task in
Button {
currentTask = task
} label: {
Text(task.title)
}
}
Use .environment(\.editMode, .constant(.active)) to turn on selecting capability.
import SwiftUI
struct ContentView: View {
struct Ocean: Identifiable, Hashable {
let name: String
let id = UUID()
}
private var oceans = [
Ocean(name: "Pacific"),
Ocean(name: "Atlantic"),
Ocean(name: "Indian"),
Ocean(name: "Southern"),
Ocean(name: "Arctic")
]
#State private var multiSelection = Set<UUID>()
var body: some View {
NavigationView {
List(oceans, selection: $multiSelection) {
Text($0.name)
}
.navigationTitle("Oceans")
.environment(\.editMode, .constant(.active))
.onTapGesture {
// This is a walk-around: try how it works without `asyncAfter()`
DispatchQueue.main.asyncAfter(deadline: .now() + 0.05, execute: {
print(multiSelection)
})
}
}
Text("\(multiSelection.count) selections")
}
}
struct ContentView_Previews: PreviewProvider {
static var previews: some View {
ContentView()
}
}
Put your 3 List with same data array but filtering by status on each one something like:
task.filter({ $0.status == .toDo })
Then on your row add the modifier .onTapGesture be sure to cover all the available space.
Inside the code block introduce your logic or func to change the item status. changeTaskStatus(item: task)

SwiftUI NavigationLink with constant binding for isActive

I don't understand why SwiftUI NavigationLink's isActive behaves as if it has it's own state. Even though I pass a constant to it, the back button overrides the value of the binding once pressed.
Code:
import Foundation
import SwiftUI
struct NavigationLinkPlayground: View {
#State
var active = true
var body: some View {
NavigationView {
VStack {
Text("Navigation Link playground")
Button(action: { active.toggle() }) {
Text("Toggle")
}
Spacer()
.frame(height: 40)
FixedNavigator(active: active)
}
}
}
}
fileprivate struct FixedNavigator: View {
var active: Bool = true
var body: some View {
return VStack {
Text("Fixed navigator is active: \(active)" as String)
NavigationLink(
destination: SecondScreen(),
// this is technically a constant!
isActive: Binding(
get: { active },
set: { newActive in print("User is setting to \(newActive), but we don't let them!") }
),
label: { Text("Go to second screen") }
)
}
}
}
fileprivate struct SecondScreen: View {
var body: some View {
Text("Nothing to see here")
}
}
This is a minimum reproducible example, my actual intention is to handle the back button press manually. So when the set inside the Binding is called, I want to be able to decide when to actually proceed. (So like based on some validation or something.)
And I don't understand what is going in and why the back button is able to override a constant binding.
Your use of isActive is wrong. isActive takes a binding boolean and whenever you set that binding boolean to true, the navigation link gets activated and you are navigated to the destination.
isActive does not control whether the navigation link is clickable/disbaled or not.
Here's an example of correct use of isActive. You can manually trigger the navigation to your second view by setting activateNavigationLink to true.
EDIT 1:
In this new sample code, you can disable and enable the back button at will as well:
struct ContentView: View {
#State var activateNavigationLink = false
var body: some View {
NavigationView {
VStack {
// This isn't visible and should take 0 space from the screen!
// Because its `label` is an `EmptyView`
// It'll get programmatically triggered when you set `activateNavigationLink` to `true`.
NavigationLink(
destination: SecondScreen(),
isActive: $activateNavigationLink,
label: EmptyView.init
)
Text("Fixed navigator is active: \(activateNavigationLink)" as String)
Button("Go to second screen") {
activateNavigationLink = true
}
}
}
}
}
fileprivate struct SecondScreen: View {
#State var backButtonActivated = false
var body: some View {
VStack {
Text("Nothing to see here")
Button("Back button is visible: \(backButtonActivated)" as String) {
backButtonActivated.toggle()
}
}
.navigationBarBackButtonHidden(!backButtonActivated)
}
}

SwiftUI selection in lists not working on reused cells

Consider the following project with two views. The first view presents the second one:
import SwiftUI
struct ContentView: View {
private let data = 0...1000
#State private var selection: Set<Int> = []
#State private var shouldShowSheet = false
var body: some View {
self.showSheet()
//self.showPush()
}
private func showSheet() -> some View {
Button(action: {
self.shouldShowSheet = true
}, label: {
Text("Selected: \(selection.count) items")
}).sheet(isPresented: self.$shouldShowSheet) {
EditFormView(selection: self.$selection)
}
}
private func showPush() -> some View {
NavigationView {
Button(action: {
self.shouldShowSheet = true
}, label: {
NavigationLink(destination: EditFormView(selection: self.$selection),
isActive: self.$shouldShowSheet,
label: {
Text("Selected: \(selection.count) items")
})
})
}
}
}
struct EditFormView: View {
private let data = 0...1000
#Binding var selection: Set<Int>
#State private var editMode: EditMode = .active
init(selection: Binding<Set<Int>>) {
self._selection = selection
}
var body: some View {
List(selection: self.$selection) {
ForEach(data, id: \.self) { value in
Text("\(value)")
}
}.environment(\.editMode, self.$editMode)
}
}
Steps to reproduce:
Create an app with the above two views
Run the app and present the sheet with the editable list
Select some items at random indexes, for example a handful at index 0-10 and another handful at index 90-100
Close the sheet by swiping down/tapping back button
Open the sheet again
Scroll to indexes 90-100 to view the selection in the reused cells
Expected:
The selected indexes as you had will be in “selected state”
Actual:
The selection you had before is not marked as selected in the UI, even though the binding passed to List contains those indexes.
This occurs both on the “sheet” presentation and the “navigation link” presentation.
If you select an item in the list, the “redraw” causes the original items that were originally not shown as selected to now be shown as selected.
Is there a way around this?
It looks like EditMode bug, worth submitting feedback to Apple. The possible solution is to use custom selection feature.
Here is a demo of approach (modified only part). Tested & worked with Xcode 11.4 / iOS 13.4
struct EditFormView: View {
private let data = 0...1000
#Binding var selection: Set<Int>
init(selection: Binding<Set<Int>>) {
self._selection = selection
}
var body: some View {
List(selection: self.$selection) {
ForEach(data, id: \.self) { value in
self.cell(for: value)
}
}
}
// also below can be separated into standalone view
private func cell(for value: Int) -> some View {
let selected = self.selection.contains(value)
return HStack {
Image(systemName: selected ? "checkmark.circle" : "circle")
.foregroundColor(selected ? Color.blue : nil)
.font(.system(size: 24))
.onTapGesture {
if selected {
self.selection.remove(value)
} else {
self.selection.insert(value)
}
}.padding(.trailing, 8)
Text("\(value)")
}
}
}

Using SwiftUI, we installed a Button in the List. Why does the modal disappear when I tap the button to display the modal and then close it again?

I am now learning to create a sample code for SwiftUI using the official version of Xcode11.
I wrote a simple code to show and hide modal.
This code adds a button to the list and displays a modal.
Strangely, however, the modal no longer appears when the button is tapped again after closing.
Is there a reason for this or any solution?
Occurs when there is a button in the list, but if you delete only the list from the code, the modal can be displayed as many times as you like.
This is the code that causes the bug.
struct ContentView: View {
#State var show_modal = false
var body: some View {
List {
Button(action: {
print("Button Pushed")
self.show_modal = true
}) {
Text("Show Modal")
}.sheet(isPresented: self.$show_modal, onDismiss: {
print("dismiss")
}) {
ModalView()
}
}
}
}
This is a code that does not cause a bug.
struct ContentView: View {
#State var show_modal = false
var body: some View {
Button(action: {
print("Button Pushed")
self.show_modal = true
}) {
Text("Show Modal")
}.sheet(isPresented: self.$show_modal, onDismiss: {
print("dismiss")
}) {
ModalView()
}
}
}
The only difference is whether or not there is a List.
The ModalView code is below.
struct ModalView: View {
// 1. Add the environment variable
#Environment(\.presentationMode) var presentationMode
var body: some View {
// 2. Embed Text in a VStack
VStack {
// 3. Add a button with the following action
Button(action: {
print("dismisses form")
self.presentationMode.wrappedValue.dismiss()
}) {
Text("Dismiss")
}.padding(.bottom, 50)
Text("This is a modal")
}
}
}
When breakpoint is set, print ("Button Pushed") is called every time, but ModalView of .sheet is not called, and naturally the body of ModalView class is not called.
I think the issue is that your .sheet is not on the List itself but on the Button in your code that causes the bug.
Try this instead:
struct ContentView: View {
#State var show_modal = false
var body: some View {
List {
Button(action: {
print("Button Pushed")
self.show_modal = true
}) {
Text("Show Modal")
}
}.sheet(isPresented: self.$show_modal, onDismiss: {
print("dismiss")
}) {
ModalView()
}
}
}

Is it possible for a NavigationLink to perform an action in addition to navigating to another view?

I'm trying to create a button that not only navigates to another view, but also run a function at the same time. I tried embedding both a NavigationLink and a Button into a Stack, but I'm only able to click on the Button.
ZStack {
NavigationLink(destination: TradeView(trade: trade)) {
TradeButton()
}
Button(action: {
print("Hello world!") //this is the only thing that runs
}) {
TradeButton()
}
}
You can use .simultaneousGesture to do that. The NavigationLink will navigate and at the same time perform an action exactly like you want:
NavigationLink(destination: TradeView(trade: trade)) {
Text("Trade View Link")
}.simultaneousGesture(TapGesture().onEnded{
print("Hello world!")
})
You can use NavigationLink(destination:isActive:label:). Use the setter on the binding to know when the link is tapped. I've noticed that the NavigationLink could be tapped outside of the content area, and this approach captures those taps as well.
struct Sidebar: View {
#State var isTapped = false
var body: some View {
NavigationLink(destination: ViewToPresent(),
isActive: Binding<Bool>(get: { isTapped },
set: { isTapped = $0; print("Tapped") }),
label: { Text("Link") })
}
}
struct ViewToPresent: View {
var body: some View {
print("View Presented")
return Text("View Presented")
}
}
The only thing I notice is that setter fires three times, one of which is after it's presented. Here's the output:
Tapped
Tapped
View Presented
Tapped
NavigationLink + isActive + onChange(of:)
// part 1
#State private var isPushed = false
// part 2
NavigationLink(destination: EmptyView(), isActive: $isPushed, label: {
Text("")
})
// part 3
.onChange(of: isPushed) { (newValue) in
if newValue {
// do what you want
}
}
This works for me atm:
#State private var isActive = false
NavigationLink(destination: MyView(), isActive: $isActive) {
Button {
// run your code
// then set
isActive = true
} label: {
Text("My Link")
}
}
Use NavigationLink(_:destination:tag:selection:) initializer and pass your model's property as a selection parameter. Because it is a two-way binding, you can define didset observer for this property, and call your function there.
struct ContentView: View {
#EnvironmentObject var navigationModel: NavigationModel
var body: some View {
NavigationView {
List(0 ..< 10, id: \.self) { row in
NavigationLink(destination: DetailView(id: row),
tag: row,
selection: self.$navigationModel.linkSelection) {
Text("Link \(row)")
}
}
}
}
}
struct DetailView: View {
var id: Int;
var body: some View {
Text("DetailView\(id)")
}
}
class NavigationModel: ObservableObject {
#Published var linkSelection: Int? = nil {
didSet {
if let linkSelection = linkSelection {
// action
print("selected: \(String(describing: linkSelection))")
}
}
}
}
It this example you need to pass in your model to ContentView as an environment object:
ContentView().environmentObject(NavigationModel())
in the SceneDelegate and SwiftUI Previews.
The model conforms to ObservableObject protocol and the property must have a #Published attribute.
(it works within a List)
I also just used:
NavigationLink(destination: View()....) {
Text("Demo")
}.task { do your stuff here }
iOS 15.3 deployment target.