How to display a QChartView inside a QStackedWidget? - c++

Question

I want my form to have a QStackedWidget with 2 (at least) pages and each of them has a QChartView.
In the form editor, through the 'promote' menu, I made a QChartView from QGraphicView. (screenshoot (so far there is only 1 QChartView on it - so that i can see which page is open)).
From the main window, when one of the buttons is pressed, I want to open the above windows in a loop:
void Widget::ShowStudioCharts() noexcept
{
for(auto & e : this->userInfoVector){
Form *pForm = new Form();
pForm->provideStudioData(&e.studiosStats, e.nickname);
pForm->processStudioStats();
pForm->show();
}
}
I tried to do it like this:
Form.h
#ifndef FORM_H
#define FORM_H
#include <QWidget>
#include <QPieSeries>
#include <QChart>
#include <QChartView>
#include <QGridLayout>
#include <vector>
#include <map>
#include <QStackedWidget>
#include <QtGlobal>
#include <QRectF>
#include <QRect>
#include <QPushButton>
namespace Ui {
class Form;
}
class Form : public QWidget
{
Q_OBJECT
public:
explicit Form(QWidget *parent = nullptr);
~Form();
void provideStudioData(std::map<std::string, std::size_t> *studiosStats, const std::string &nickname) noexcept;
void processStudioStats() noexcept;
private slots:
void on_pushButton_2_clicked();
private:
std::vector<std::map<std::string, size_t>*> stats;
std::vector<std::string> nicknames;
Ui::Form *ui;
};
#endif // FORM_H
Form.cpp
#include "form.h"
#include "ui_form.h"
#include <QPieSeries>
#include <QPieSlice>
#include <QChart>
using namespace QtCharts;
Form::Form(QWidget *parent) :
QWidget(parent),
ui(new Ui::Form)
{
ui->setupUi(this);
}
Form::~Form()
{
delete ui;
}
void Form::provideStudioData(std::map<std::string, size_t> *studiosStats, const std::string &nickname) noexcept
{
this->stats.push_back(studiosStats);
this->nicknames.push_back(nickname);
}
void Form::processStudioStats() noexcept
{
srand(time(0));
QPieSeries *series = new QPieSeries();
// for (const auto & e : this->stats ){
// //QBarSet *set0 = new QBarSet("1");
// for ( const auto & a : *e){
// //*set0 << a.second;
// qDebug( (a.first + " " + std::to_string(a.second)).c_str());
// }
// }
for ( const auto & a : *this->stats[0]){
QPieSlice * slice = new QPieSlice();
slice->setColor(QColor(rand()%255, rand()%255, rand()%255));
slice->setValue(a.second);
slice->setLabel(a.first.c_str());
series->append(slice);
}
QChart *chart = new QChart();
chart->setAnimationOptions(QChart::AnimationOption::AllAnimations);
chart->addSeries(series);
//chart->setPlotArea(QRectF(200,0,1400,1100));
//chart->legend()->detachFromChart();
chart->legend()->setBackgroundVisible(true);
chart->legend()->setBrush(QBrush(QColor(128, 128, 128, 128)));
chart->legend()->setPen(QPen(QColor(192, 192, 192, 192)));
//chart->legend()->setGeometry(QRectF(20,20,200,1000));
chart->setTitle(QString::fromStdString(this->nicknames[0]));
this->setWindowTitle(QString::fromStdString(this->nicknames[0]));
chart->legend()->setAlignment(Qt::AlignLeft);
ui->graphicsView = new QChartView(chart);
ui->graphicsView->show();
//ui->stackedWidget->show();
}
void Form::on_pushButton_2_clicked()
{
if(0 == this->ui->stackedWidget->currentIndex())
this->ui->stackedWidget->setCurrentIndex(1);
else if(1 == this->ui->stackedWidget->currentIndex())
this->ui->stackedWidget->setCurrentIndex(0);
}
The code is compiled, windows are opened. But the problem is that my chart is displayed in another window above the opened one.
This is obviously the result of
ui->graphicsView->show();
But if i remove this line, then the graph is not visible at all.
Help please, thanks in advance.

Answer 1

Doing ui->graphicsView = new QChartView(chart); does not replace the QChartView, you are just assigning the pointer. The solution is to reuse the existing QChartView so it changes to: ui->graphicsView->setChart(chart);.