Django Celery, App import error only on production - django

I have a file structure like this:
myapp
artist_applications
tasks.py
tasks
celery.py
# settings.py
INSTALLED_APPS = [
'myapp.artist_application',
...
# celery.py
import os
from celery import Celery
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'myapp.settings.production')
app = Celery("tasks")
app.config_from_object('django.conf:settings', namespace="CELERY")
app.autodiscover_tasks()
# tasks.py
from tasks.celery import app as celery_myapp
from django.apps import apps
from django.conf import settings
import requests
#celery_esns.task(name='sample_task')
def sample_task():
print('TESTING CELERY')
#celery_esns.task(name='publish_artist_task')
def publish_artist_task(payload, artist_id):
r = requests.post(settings.PUBLISH_URL, json = payload)
if r.status_code == 200:
apps.get_model('artist_application', 'Artist').objects.filter(unique_id=artist_id).update(published=True)
else:
raise Exception("Error publishing artist with id: " + artist_id)
On development all is running fine when I start Celery with:
celery -A myapp.tasks worker -Q celery -l info
But on production I run the command (in a virtualenv) and I get the error:
django.core.exceptions.ImproperlyConfigured: Cannot import 'artist_application'. Check that 'myapp.artist_application.apps.ArtistApplication.name' is correct.
Any ideas where to look? I don't get how 'runserver' is loading the apps differently then wsgi?

I had to put the full dotted path in apps.py
from django.apps import AppConfig
class ArtistApplicationConfig(AppConfig):
name = 'myapp.artist_application'
verbose_name = "Artist Application"

Related

Celery second unregistered task

I have a doubt regarding the implementation of celery with rabbitMQ since only the first function (debug_task()) that I have defined in celery.py is executed.
The problem is that send_user_mail(randomNumber, email) is not working. debug_task is working, so it's registered.
This is the celery console
[2022-10-08 22:28:48,081: ERROR/MainProcess] Received unregistered
task of type 'callservices.celery.send_proveedor_mail_new_orden'. The
message has been ignored and discarded.
Did you remember to import the module containing this task? Or maybe
you are using relative imports?
Why it's unregistered?
celery.py
from __future__ import absolute_import, unicode_literals
import os
from celery import Celery
from django.conf import settings
from django.core.mail import EmailMultiAlternatives, send_mail
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'callservices.settings')
app = Celery('tasks',broker='pyamqp://guest#localhost//')
app.config_from_object('django.conf:settings')
app.autodiscover_tasks(settings.INSTALLED_APPS)
#app.task()
def debug_task():
print("hi all")
#app.task()
def send_user_mail(randomNumber, email):
subject = 'email validation - ServicesYA'
cuerpo="Your number is: "+str(randomNumber)
send_mail(subject, cuerpo ,'xxx.ssmtp#xxx.com', [email],fail_silently = False)
return 1
This is init.py
# This will make sure the app is always imported when
# Django starts so that shared_task will use this app.
from celery import app as celery_app
__all__ = ('celery_app',)
and in settings.py I add this line:
BROKER_URL = "amqp://guest:guest#localhost:5672//"

django with celery error:No result backend is configured

my version:
Django==3.2
celery==5.1.2
my settings.local:
CELERY_RESULT_BACKEND = 'redis://#127.0.0.1:6379/1'
celery.py:
from __future__ import absolute_import, unicode_literals
import os
from celery import Celery
from django.conf import settings
# # 设置环境变量
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'cmdb.settings.local')
# 实例化
# app = Celery('celeryPro', include=['message.tasks'])
app = Celery('celeryPro', backend='redis://127.0.0.1:6379/1')
# app = Celery('cmdb')
# namespace='CELERY'作用是允许你在Django配置文件中对Celery进行配置
# 但所有Celery配置项必须以CELERY开头,防止冲突
app.config_from_object('django.conf:settings', namespace='CELERY')
# app.config_from_object(config, namespace='CELERY')
# 自动从Django的已注册app中发现任务
app.autodiscover_tasks(lambda: settings.INSTALLED_APPS)
#app.task(bind=True)
def debug_task(self):
print('Request:{0!r}'.format(self.request))
always get the error
Your setup is incorrect in two ways.
You are adding the backend only when creating the instance of celery and also calling the config_from_object, as per the docs, any previous configuration is reset.
You are passing the incorrect config file to the config_from_object method. You need to send the file that Celery should use and not the one
that Django uses. You can find more info in the configuration docs.
As an example, you can have your celery.py file configured as below:
from __future__ import absolute_import, unicode_literals
import os
from celery import Celery
from django.conf import settings
# # 设置环境变量
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'cmdb.settings.local')
# 实例化
# app = Celery('celeryPro', include=['message.tasks'])
# app = Celery('celeryPro', backend='redis://127.0.0.1:6379/1')
app = Celery('cmdb')
# namespace='CELERY'作用是允许你在Django配置文件中对Celery进行配置
# 但所有Celery配置项必须以CELERY开头,防止冲突
app.config_from_object('celery_config', namespace='CELERY')
# app.config_from_object(config, namespace='CELERY')
# 自动从Django的已注册app中发现任务
app.autodiscover_tasks(lambda: settings.INSTALLED_APPS)
#app.task(bind=True)
def debug_task(self):
print('Request:{0!r}'.format(self.request))
and your celery_config.py file could be something like below:
broker_url = 'redis://localhost:6379/1'
result_backend = 'redis://localhost:6379/1'
Having your configuration for celery in a different file allows for more flexibility when you want to extend the configuration.
NOTE - you should keep the celery_config.py file in the root directory of the project i.e., in the same location as the manage.py file.

celery .delay freezes for this task but runs for others

I am trying to send notifications using celery.
#shared_task(name='send_notifis')
def send_notifs(device_ids, title, message):
from pills_reminder.models import UserNotifications, UserDevice
devices = UserDevice.objects.filter(id__in=device_ids)
print(devices)
device_tokens = []
for device in devices:
UserNotifications.objects.create(
uid=device.device_id,
title=title,
message=message,
)
print(UserNotifications)
device_tokens.append(device.registration_token)
if len(device_tokens) > 1:
device_tokens = ["".join(token.split()) for token in device_tokens]
response = push_service.notify_multiple_devices(registration_ids=device_tokens,
message_title=title,
message_body=message)
elif len(device_tokens) == 1:
registration_id = "".join(device_tokens[0].split())
response = push_service.notify_single_device(registration_id=registration_id,
message_title=title,
message_body=message)
else:
pass
print(response)
return True
this works without .delay() and when running using
python manage.py shell
>>> send_notifs.delay(devices, title='title', message='message')
<AsyncResult: f54188f8-cec6-42dd-a840-b097abffd7f4>
but it freezes when i call using Django Model post_save signal.
#receiver(post_save, sender=Notification)
def Notification_post_save_handler(sender, instance, **kwargs):
print('hello from post_save signal')
devices = instance.get_devices()
# send_notifs(devices)
if len(devices)>0:
send_notifs.delay(devices,
title=instance.title,
message=instance.message)
This above code freezes execution, but without .delay. it works fine.
UPADATE:1
the above task with .delay is running from python manage.py shell not from runserver . so the problem is with celery and Django settings. Hence i dig deep and found out
while running from shell i get,
>>> add.app.conf #(add is a async task here)
{'broker_url': 'redis://localhost:6379/1'}, ...
but running from runserver gives:
`{'broker_url': None}`
Now i am looking for how to set the settings properly ? I am using django-configurations with celery.py as
from __future__ import absolute_import, unicode_literals
import os
from celery import Celery
# set the default Django settings module for the 'celery' program.
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'core.settings')
os.environ.setdefault('DJANGO_CONFIGURATION', 'Development')
import configurations
configurations.setup()
app = Celery('core')
app.config_from_object('django.conf:settings', namespace='CELERY')
app.autodiscover_tasks()
#app.task(bind=True)
def debug_task(self):
print('Request: {0!r}'.format(self.request))
Any help is appreciated. Thank you for your time and patience.
use this
from configurations import importer
importer.install()
in place of
import configurations
configurations.setup()
Turns out the settings sepecified in django-configuration docs for including celery was causing the problem. Modified celery.py, and now it is working fine.
from __future__ import absolute_import, unicode_literals
import os
from celery import Celery
# set the default Django settings module for the 'celery' program.
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'core.settings')
os.environ.setdefault('DJANGO_CONFIGURATION', 'Development')
from configurations import importer
importer.install()
# import configurations
# configurations.setup()
app = Celery('core')
app.config_from_object('django.conf:settings', namespace='CELERY')
app.autodiscover_tasks()
#app.task(bind=True)
def debug_task(self):
print('Request: {0!r}'.format(self.request))

Celery doesn't see tasks

Here is my celery config:
config.celery.py
from __future__ import absolute_import, unicode_literals
import os
from celery import Celery
import sys
from django.conf import settings
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'config.settings')
app = Celery('config',
backend=os.getenv('REDIS_URL', ),
broker=os.getenv('CLOUDAMQP_URL')
)
app.conf.update(BROKER_URL=os.getenv('CLOUDAMQP_URL', 'redis://localhost'),
CELERY_RESULT_BACKEND=os.getenv('REDIS_URL',
'redis://localhost'))
app.config_from_object('django.conf:settings', namespace='CELERY')
sys.path.append(os.path.join(os.getcwd(), "applications"))
app.autodiscover_tasks()
TASK_SERIALIZER = 'json'
Celery can't find tasks in following structure
project_name/
apps/
users/
tasks.py
config/
celery.py
All my apps are registered in INSTALLED APPS and I'm using app registration via apps.py files.
According to Celery's documentation, your file config/__init__.py should have something similar to this:
from __future__ import absolute_import, unicode_literals
# This will make sure the app is always imported when
# Django starts so that shared_task will use this app.
from .celery import app as celery_app
__all__ = ('celery_app',)

Django - Celery with RabbitMQ: task always remains in PENDING

I have to use Celery 4.0.2 with RabbitMQ 3.6.10 to handle an async task. Then, I have followed this tutorial: https://www.codementor.io/uditagarwal/asynchronous-tasks-using-celery-with-django-du1087f5k
However, I have a slight problem with my task because it's impossible to have a result. My task always remains in "PENDING" state.
My question is what i have to do to get a result ?
Thank you in advance for your answer.
Here my code:
Here my __init_.py:
from __future__ import absolute_import, unicode_literals
# This will make sure the app is always imported when
# Django starts so that shared_task will use this app.
from .celery import app as celery_app
__all__ = ['celery_app']
Here a part of my setting.py:
BROKER_URL = 'amqp://guest:guest#localhost//'
CELERY_ACCEPT_CONTENT = ['json']
CELERY_TASK_SERIALIZER = 'json'
CELERY_RESULT_SERIALIZER = 'json'
Here my celery.py:
from __future__ import absolute_import, unicode_literals
import os
from celery import Celery
# set the default Django settings module for the 'celery' program.
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'mysite.settings')
app = Celery('mysite',
backend='amqp',
broker='amqp://guest#localhost//')
# Using a string here means the worker don't have to serialize
# the configuration object to child processes.
# - namespace='CELERY' means all celery-related configuration keys
# should have a `CELERY_` prefix.
app.config_from_object('django.conf:settings', namespace='CELERY')
# Load task modules from all registered Django app configs.
app.autodiscover_tasks()
#app.task(bind=True)
def debug_task(self):
print('Request: {0!r}'.format(self.request))
And my tasks.py
# Create your tasks here
from __future__ import absolute_import, unicode_literals
from celery import shared_task
#shared_task
def add(x, y):
test = "ok"
current_task.update_state(state='PROGRESS',
meta={'test': ok})
return x + y
And here my Django Shell:
>>> from blog.tasks import *
>>> job = add.delay(2,3)
>>> job.state
'PENDING'
>>> job.result
>>>
With a picture of my RabbitMQ interface:
You need to start a worker that will process the tasks you add to queue. From your virtualenv run:
celery worker -A blog -l info