Find UPPERCASE names that end with a colon - regex

Find UPPERCASE names that start with either a letter or digits.
Could include digits, hyphens, periods and spaces with colon at end of name.
MR. SMITH:
- CAPTAIN AMERICA:
ANT-MAN:
2014 NEBULA:
-2012 IRON MAN:
BOY 1:
1
00:00:07,174 --> 00:00:09,837
BARTON: Okay, hold on.
16
00:00:36,411 --> 00:00:37,527
- COOPER: Nice!
- LAURA: Nice throw, kiddo.
Here is my best attempt, but it is also selecting parts of the timecodes.
It's also not filling groups correctly.
Find: ([A-Z0-9])(?:([A-Z0-9\.\-\s]*)*\:+)
regex101
Thanks in Advance !

Try this pattern: ([A-Z0-9][A-Z0-9. -]+)(?=:\B)
See Regex101 Demo

Related

Match first and then all equal occurrences with regex

Lets say we have the string:
one day, when Anne, Lisa and Paul went to the store, then Anne said to Paul: "I love Lisa!". Then Lisa laughed and kissed Anne.
is there a way with regex to match the first name, and then match and all other occurrences of the same name in the string?
Given the name-matching regex /[A-Z][a-z]+ (with /g maybe?), can the regex matcher be made to remember the first match, and then use that match EXACTLY for the rest of the string? Other subsequent matches to the name-matching regex should be ignored (except for Anne in the example).
The result would be (if matches are replaced with "Foo"):
one day, when Foo, Lisa and Paul went to the store, then Foo said to Paul: "I love Lisa!". Then Lisa laughed and kissed Foo.
Please ignore the fact that the sentence start uncapitalized, or add an example that also handles this.
Using a script to get the first match and then using that as input for a second iteration works of course, but that's outside the scope of the question (which is limited to ONE regex expression).
The only way I could think of is with non-fixed width lookbehinds. For example through Pypi's regex module, and maybe Javascript too? Either way, assuming a name is capture through [A-Z][a-z]+ as per your question try:
\b([A-Z][a-z]+)\b(?<=^[^A-Z]*\b\1\b.*)
See an online demo
\b([A-Z][a-z]+)\b - A 1st capture group capturing a name between two word-boundaries;
(?<=^[^A-Z]*\b\1\b.*) - A non-fixed width positive lookbehind to match start of line anchor followed by 0+ characters other than uppercase followed by the content of the 1st capture group and 0+ characters.
Here is a PyPi's example:
import regex as re
s= 'Anne, Lisa and Paul went to the store, then Anne said to Paul: "I love Lisa!". Then Lisa laughed and kissed Anne.'
s_new = re.sub(r'\b([A-Z][a-z]+)\b(?<=^[^A-Z]*\b\1\b.*)', 'Foo', s)
print(s_new)
Prints:
Foo, Lisa and Paul went to the store, then Foo said to Paul: "I love Lisa!". Then Lisa laughed and kissed Foo.

How to use REGEXTRACT to extract certain characters between two strings

I am trying to extract a person's name between different characters. For example, the cells contains this information
PATIENT: 2029985 - COLLINS, JUNIOR .
PATIENT: 1235231-02 - JERRY JR, PATRICK .
PATIENT: 986435--EXP-- - JULIUS, DANIEL .
PATIENT: 2021118-02 - DRED-HARRY, KEVIN .
My goal is to use one REGEXTRACT formula to get the following:
COLLINS, JUNIOR
JERRY JR, PATRICK
JULIUS, DANIEL
LOVE ALSTON, BRENDA
So far, I have come up with the formula:
=ARRAYFORMULA(REGEXEXTRACT(B3:B, "-(.*)\."))
Where B3 contains the first information
Using that formula, I get:
COLLINS, JUNIOR
02 - JERRY JR, PATRICK
02 - LOVE-ALSTON, BRENDA
-EXP-- - JULIUS, DANIEL
02 - DRED-HARRY, KEVIN
I managed to get the first name down but how do I go about extracting the rest.
You can use
=ARRAYFORMULA(REGEXEXTRACT(B3:B, "\s-\s+([^.]*?)\s*\."))
See the regex demo. Details:
\s-\s+ - a whitespace, -, one or more whitespaces
([^.]*?) - Group 1: zero or more chars other than a . as few as possible
\s* - zero or more whitespaces
\. - a . char.
1st solution: With your shown samples, please try following regex.
Online demo for above regex
^PATIENT:.*-\s+([^.]*?)\s*\.
OR try following Google-sheet forumla:
=ARRAYFORMULA(REGEXEXTRACT(B3:B, "^PATIENT:.*-\s+([^.]*?)\s*\."))
Explanation: Checking if line/value starts from PATIENT followed by : till -(using greedy mechanism here), which is followed by spaces(1 or more occurrences). Then creating one and only capturing group which contains everything just before .(dot) in it making it non-greedy, closing capturing group which is followed by spaces(0 or more occurrences) followed by a literal dot.
2nd solution: Using lazy match approach in regex, please try following regex.
.*?\s-\s([^.]*?)\s*\.
Google-sheet formula will be as follows:
=ARRAYFORMULA(REGEXEXTRACT(B3:B, ".*?\s-\s([^.]*?)\s*\."))
Online demo for above regex

Regex for name with non-latin characters in python [duplicate]

For website validation purposes, I need first name and last name validation.
For the first name, it should only contain letters, can be several words with spaces, and has a minimum of three characters, but a maximum at top 30 characters. An empty string shouldn't be validated (e.g. Jason, jason, jason smith, jason smith, JASON, Jason smith, jason Smith, and jason SMITH).
For the last name, it should be a single word, only letters, with at least three characters, but at most 30 characters. Empty strings shouldn't be validated (e.g. lazslo, Lazslo, and LAZSLO).
Don't forget about names like:
Mathias d'Arras
Martin Luther King, Jr.
Hector Sausage-Hausen
This should do the trick for most things:
/^[a-z ,.'-]+$/i
OR Support international names with super sweet unicode:
/^[a-zA-ZàáâäãåąčćęèéêëėįìíîïłńòóôöõøùúûüųūÿýżźñçčšžÀÁÂÄÃÅĄĆČĖĘÈÉÊËÌÍÎÏĮŁŃÒÓÔÖÕØÙÚÛÜŲŪŸÝŻŹÑßÇŒÆČŠŽ∂ð ,.'-]+$/u
You make false assumptions on the format of first and last name. It is probably better not to validate the name at all, apart from checking that it is empty.
After going through all of these answers I found a way to build a tiny regex that supports most languages and only allows for word characters. It even supports some special characters like hyphens, spaces and apostrophes. I've tested in python and it supports the characters below:
^[\w'\-,.][^0-9_!¡?÷?¿/\\+=##$%ˆ&*(){}|~<>;:[\]]{2,}$
Characters supported:
abcdefghijklmnopqrstwxyz
ABCDEFGHIJKLMNOPQRSTUVWXYZ
áéíóúäëïöüÄ'
陳大文
łŁőŐűŰZàáâäãåąčćęèéêëėįìíîïłńòóôöõøùúûüųū
ÿýżźñçčšžÀÁÂÄÃÅĄĆČĖĘÈÉÊËÌÍÎÏĮŁ
ŃÒÓÔÖÕØÙÚÛÜŲŪŸÝŻŹÑßÇŒÆČŠŽ.-
ñÑâê都道府県Федерации
আবাসযোগ্য জমির걸쳐 있는
I have created a custom regex to deal with names:
I have tried these types of names and found working perfect
John Smith
John D'Largy
John Doe-Smith
John Doe Smith
Hector Sausage-Hausen
Mathias d'Arras
Martin Luther King
Ai Wong
Chao Chang
Alzbeta Bara
My RegEx looks like this:
^([a-zA-Z]{2,}\s[a-zA-Z]{1,}'?-?[a-zA-Z]{2,}\s?([a-zA-Z]{1,})?)
MVC4 Model:
[RegularExpression("^([a-zA-Z]{2,}\\s[a-zA-Z]{1,}'?-?[a-zA-Z]{2,}\\s?([a-zA-Z]{1,})?)", ErrorMessage = "Valid Charactors include (A-Z) (a-z) (' space -)") ]
Please note the double \\ for escape characters
For those of you that are new to RegEx I thought I'd include a explanation.
^ // start of line
[a-zA-Z]{2,} // will except a name with at least two characters
\s // will look for white space between name and surname
[a-zA-Z]{1,} // needs at least 1 Character
\'?-? // possibility of **'** or **-** for double barreled and hyphenated surnames
[a-zA-Z]{2,} // will except a name with at least two characters
\s? // possibility of another whitespace
([a-zA-Z]{1,})? // possibility of a second surname
I have searched and searched and played and played with it and although it is not perfect it may help others making the attempt to validate first and last names that have been provided as one variable.
In my case, that variable is $name.
I used the following code for my PHP:
if (preg_match('/\b([A-Z]{1}[a-z]{1,30}[- ]{0,1}|[A-Z]{1}[- \']{1}[A-Z]{0,1}
[a-z]{1,30}[- ]{0,1}|[a-z]{1,2}[ -\']{1}[A-Z]{1}[a-z]{1,30}){2,5}/', $name)
# there is no space line break between in the above "if statement", any that
# you notice or perceive are only there for formatting purposes.
#
# pass - successful match - do something
} else {
# fail - unsuccessful match - do something
I am learning RegEx myself but I do have the explanation for the code as provided by RegEx buddy.
Here it is:
Assert position at a word boundary «\b»
Match the regular expression below and capture its match into backreference number 1
«([A-Z]{1}[a-z]{1,30}[- ]{0,1}|[A-Z]{1}[- \']{1}[A-Z]{0,1}[a-z]{1,30}[- ]{0,1}|[a-z]{1,2}[ -\']{1}[A-Z]{1}[a-z]{1,30}){2,5}»
Between 2 and 5 times, as many times as possible, giving back as needed (greedy) «{2,5}»
* I NEED SOME HELP HERE WITH UNDERSTANDING THE RAMIFICATIONS OF THIS NOTE *
Note: I repeated the capturing group itself. The group will capture only the last iteration. Put a capturing group around the repeated group to capture all iterations. «{2,5}»
Match either the regular expression below (attempting the next alternative only if this one fails) «[A-Z]{1}[a-z]{1,30}[- ]{0,1}»
Match a single character in the range between “A” and “Z” «[A-Z]{1}»
Exactly 1 times «{1}»
Match a single character in the range between “a” and “z” «[a-z]{1,30}»
Between one and 30 times, as many times as possible, giving back as needed (greedy) «{1,30}»
Match a single character present in the list “- ” «[- ]{0,1}»
Between zero and one times, as many times as possible, giving back as needed (greedy) «{0,1}»
Or match regular expression number 2 below (attempting the next alternative only if this one fails) «[A-Z]{1}[- \']{1}[A-Z]{0,1}[a-z]{1,30}[- ]{0,1}»
Match a single character in the range between “A” and “Z” «[A-Z]{1}»
Exactly 1 times «{1}»
Match a single character present in the list below «[- \']{1}»
Exactly 1 times «{1}»
One of the characters “- ” «- » A ' character «\'»
Match a single character in the range between “A” and “Z” «[A-Z]{0,1}»
Between zero and one times, as many times as possible, giving back as needed (greedy) «{0,1}»
Match a single character in the range between “a” and “z” «[a-z]{1,30}»
Between one and 30 times, as many times as possible, giving back as needed (greedy) «{1,30}»
Match a single character present in the list “- ” «[- ]{0,1}»
Between zero and one times, as many times as possible, giving back as needed (greedy) «{0,1}»
Or match regular expression number 3 below (the entire group fails if this one fails to match) «[a-z]{1,2}[ -\']{1}[A-Z]{1}[a-z]{1,30}»
Match a single character in the range between “a” and “z” «[a-z]{1,2}»
Between one and 2 times, as many times as possible, giving back as needed (greedy) «{1,2}»
Match a single character in the range between “ ” and “'” «[ -\']{1}»
Exactly 1 times «{1}»
Match a single character in the range between “A” and “Z” «[A-Z]{1}»
Exactly 1 times «{1}»
Match a single character in the range between “a” and “z” «[a-z]{1,30}»
Between one and 30 times, as many times as possible, giving back as needed (greedy) «{1,30}»
I know this validation totally assumes that every person filling out the form has a western name and that may eliminates the vast majority of folks in the world. However, I feel like this is a step in the proper direction. Perhaps this regular expression is too basic for the gurus to address simplistically or maybe there is some other reason that I was unable to find the above code in my searches. I spent way too long trying to figure this bit out, you will probably notice just how foggy my mind is on all this if you look at my test names below.
I tested the code on the following names and the results are in parentheses to the right of each name.
STEVE SMITH (fail)
Stev3 Smith (fail)
STeve Smith (fail)
Steve SMith (fail)
Steve Sm1th (passed on the Steve Sm)
d'Are to Beaware (passed on the Are to Beaware)
Jo Blow (passed)
Hyoung Kyoung Wu (passed)
Mike O'Neal (passed)
Steve Johnson-Smith (passed)
Jozef-Schmozev Hiemdel (passed)
O Henry Smith (passed)
Mathais d'Arras (passed)
Martin Luther King Jr (passed)
Downtown-James Brown (passed)
Darren McCarty (passed)
George De FunkMaster (passed)
Kurtis B-Ball Basketball (passed)
Ahmad el Jeffe (passed)
If you have basic names, there must be more than one up to five for the above code to work, that are similar to those that I used during testing, this code might be for you.
If you have any improvements, please let me know. I am just in the early stages (first few months of figuring out RegEx.
Thanks and good luck,
Steve
I've tried almost everything on this page, then I decided to modify the most voted answer which ended up working best. Simply matches all languages and includes .,-' characters.
Here it is:
/^[\p{L} ,.'-]+$/u
First name would be
"([a-zA-Z]{3,30}\s*)+"
If you need the whole first name part to be shorter than 30 letters, you need to check that seperately, I think. The expression ".{3,30}" should do that.
Your last name requirements would translate into
"[a-zA-Z]{3,30}"
but you should check these. There are plenty of last names containing spaces.
As maček said:
Don't forget about names like:
Mathias d'Arras
Martin Luther King, Jr.
Hector Sausage-Hausen
and to remove cases like:
..Mathias
Martin king, Jr.-
This will cover more cases:
^([a-z]+[,.]?[ ]?|[a-z]+['-]?)+$
This regex work for me (was using in Angular 8) :
([a-zA-Z',.-]+( [a-zA-Z',.-]+)*){2,30}
It will be invalid if there is:-
Any whitespace start or end of the name
Got symbols e.g. #
Less than 2 or more than 30
Example invalid First Name (whitespace)
Example valid First Name :
I'm working on the app that validates International Passports (ICAO). We support only english characters. While most foreign national characters can be represented by a character in the Latin alphabet e.g. è by e, there are several national characters that require an extra letter to represent them such as the German umlaut which requires an ‘e’ to be added to the letter e.g. ä by ae.
This is the JavaScript Regex for the first and last names we use:
/^[a-zA-Z '.-]*$/
The max number of characters on the international passport is up to 31.
We use maxlength="31" to better word error messages instead of including it in the regex.
Here is a snippet from our code in AngularJS 1.6 with form and error handling:
class PassportController {
constructor() {
this.details = {};
// English letters, spaces and the following symbols ' - . are allowed
// Max length determined by ng-maxlength for better error messaging
this.nameRegex = /^[a-zA-Z '.-]*$/;
}
}
angular.module('akyc', ['ngMessages'])
.controller('PassportController', PassportController);
.has-error p[ng-message] {
color: #bc111e;
}
.tip {
color: #535f67;
}
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.6/angular.min.js"></script>
<script src="https://code.angularjs.org/1.6.6/angular-messages.min.js"></script>
<main ng-app="akyc" ng-controller="PassportController as $ctrl">
<form name="$ctrl.form">
<div name="lastName" ng-class="{ 'has-error': $ctrl.form.lastName.$invalid} ">
<label for="pp-last-name">Surname</label>
<div class="tip">Exactly as it appears on your passport</div>
<div ng-messages="$ctrl.form.lastName.$error" ng-if="$ctrl.form.$submitted" id="last-name-error">
<p ng-message="required">Please enter your last name</p>
<p ng-message="maxlength">This field can be at most 31 characters long</p>
<p ng-message="pattern">Only English letters, spaces and the following symbols ' - . are allowed</p>
</div>
<input type="text" id="pp-last-name" ng-model="$ctrl.details.lastName" name="lastName"
class="form-control" required ng-pattern="$ctrl.nameRegex" ng-maxlength="31" aria-describedby="last-name-error" />
</div>
<button type="submit" class="btn btn-primary">Test</button>
</form>
</main>
Read almost all highly voted posts (only some are good). After understanding the problem in detail & doing research, here are the tight regexes:
1). ^[A-Z][a-z]*(([,.] |[ '-])[A-Za-z][a-z]*)*(\.?)$
name Z is allowed contrary to the assumption made by some in the thread.
No leading or trailing spaces are allowed, empty string is NOT allowed, string containing only spaces is NOT allowed
Supports English alphabets only
Supports hyphens (Some-Foobarbaz-name, Some foobarbaz-Name), apostrophes (David D'Costa, David D'costa, David D'costa R'Costa p'costa), periods (Dr. L. John, Robert Downey Jr., Md. K. P. Asif) and commas (Martin Luther, Jr.).
First alphabet of only the first word of a name MUST be capital.
NOT Allowed: John sTeWaRT, JOHN STEWART, Md. KP Asif, John Stewart PhD
Allowed: John Stewart, John stewart, Md. K P Asif
you can easily modify this condition.
If you also want to allow names like Queen Elizabeth 2 or Henry IV:
2). ^[A-Z][a-z]*(([,.] |[ '-])[A-Za-z][a-z]*)*([.]?| (-----)| [1-9][0-9]*)$
replace ----- with roman numeral's regex (which itself is long) OR you can use this alternative regex which is based on KISS philosophy [IVXLCDM]+ (here I, V, X, ... in ANY random order will satisfy the regex).
I personally suggest to use this regex:
3). ^[A-Z][a-z]*(([,.] |[ '-])[A-Za-z][a-z]*)*(\.?)( [IVXLCDM]+)?$
Feel free to try this regex HERE & make any modifications of your choice.
I have provided with tight regex which covers every possible name I found on my research with no bug. Modify these regexes to relax some of the unwanted constraints.
[UPDATE - March, 2022]
Here are 4 more regexes:
^[A-Za-z]+(([,.] |[ '-])[A-Za-z]+)*([.,'-]?)$
^((([,.'-]| )(?<!( {2}|[,.'-]{2})))*[A-Za-z]+)+[,.'-]?$
^( ([A-Za-z,.'-]+|$))+|([A-Za-z,.'-]+( |$))+$
^(([ ,.'-](?<!( {2}|[,.'-]{2})))*[A-Za-z])+[ ,.'-]?$
It's been a while since I looked back at these 4 regexes so I forgot their specifications. These 4 regexes are not tight, unlike the previous ones but do the job very well. These regexes distinguish 3 parts of a name: English alphabet, space and special character. Which one you need out of these 4 depends on your answer (Yes/No) to these questions:
have at least 1 alphabet?
can start with a space or a special character?
can end with a space or a special character?
are 2 consecutive spaces allowed?
are 2 consecutive special characters allowed?
Note: name validation should ONLY serve as a warning NOT a necessity a name should fulfill because there is no fixed naming pattern, if there is one it can change overnight and thus, any tight regex you come across will become obsolete somewhere in future.
There is one issue with the top voted answer here which recommends this regex:
/^[a-z ,.'-]+$/i
It takes spaces only as a valid name!
The best solution in my opinion is to add a negative look forward to the beginning:
^(?!\s)([a-z ,.'-]+)$/i
I use:
/^(?:[\u00c0-\u01ffa-zA-Z'-]){2,}(?:\s[\u00c0-\u01ffa-zA-Z'-]{2,})+$/i
And test for maxlength using some other means
I didn't find any answer helpful for me simply because users can pick a non-english name and simple regex are not helpful. In fact it's actually very hard to find the right expression that works for all languages.
Instead, I picked a different approach and negated all characters that should not be in the name for the valid match. Below pattern negates numerical, special characters, control characters and '\', '/'
Final regex
without punctuations: ["] ['] [,] [.], etc. :
^([^\p{N}\p{S}\p{C}\p{P}]{2,20})$
with punctuations:
^([^\p{N}\p{S}\p{C}\\\/]{2,20})$
With this, all these names are valid:
alex junior
沐宸
Nick
Sarah's Jane ---> with punctuation support
ביממה
حقیقت
Виктория
And following names become invalid:
🤣 Maria
k
١١١١١
123John
This means all names that don't have numerical characters, emojis, \ and are between 2-20 characters are allowed. You can edit the above regex if you want to add more characters to exclusion list.
To get more information about available patterns to include / exclude checkout this:
https://www.regular-expressions.info/unicode.html#prop
^\p{L}{2,}$
^ asserts position at start of a line.
\p{L} matches any kind of letter from any language
{2,} Quantifier — Matches between 2 and unlimited times, as many times as possible, giving back as needed (greedy)
$ asserts position at the end of a line
So it should be a name in any language containing at least 2 letters(or symbols) without numbers or other characters.
If you are searching a simplest way, just check almost 2 words.
/^[^\s]+( [^\s]+)+$/
Valid names
John Doe
pedro alberto ch
Ar. Gen
Mathias d'Arras
Martin Luther King, Jr.
No valid names
John
陳大文
For simplicities sake, you can use:
(.*)\s(.*)
The thing I like about this is that the last name is always after the first name, so if you're going to enter this matched groups into a database, and the name is John M. Smith, the 1st group will be
John M., and the 2nd group will be Smith.
So, with customer we create this crazy regex:
(^$)|(^([^\-!#\$%&\(\)\*,\./:;\?#\[\\\]_\{\|\}¨ˇ“”€\+<=>§°\d\s¤®™©]| )+$)
For first and last names theres are really only 2 things you should be looking for:
Length
Content
Here is my regular expression:
var regex = /^[A-Za-z-,]{3,20}?=.*\d)/
1. Length
Here the {3,20} constrains the length of the string to be between 3 and 20 characters.
2. Content
The information between the square brackets [A-Za-z] allows uppercase and lowercase characters. All subsequent symbols (-,.) are also allowed.
The following expression will work on any language supported by UTF-16 and will ensure that there's a minimum of two components to the name (i.e. first + last), but will also allow any number of middle names.
/^(\S+ )+\S+$/u
At the time of this writing it seems none of the other answers meet all of that criteria. Even ^\p{L}{2,}$, which is the closest, falls short because it will also match "invisible" characters, such as U+FEFF (Zero Width No-Break Space).
Try these solutions, for maximum compatibility, as I have already posted here:
JavaScript:
var nm_re = /^(?:((([^0-9_!¡?÷?¿/\\+=##$%ˆ&*(){}|~<>;:[\]'’,\-.\s])){1,}(['’,\-\.]){0,1}){2,}(([^0-9_!¡?÷?¿/\\+=##$%ˆ&*(){}|~<>;:[\]'’,\-. ]))*(([ ]+){0,1}(((([^0-9_!¡?÷?¿/\\+=##$%ˆ&*(){}|~<>;:[\]'’,\-\.\s])){1,})(['’\-,\.]){0,1}){2,}((([^0-9_!¡?÷?¿/\\+=##$%ˆ&*(){}|~<>;:[\]'’,\-\.\s])){2,})?)*)$/;
HTML5:
<input type="text" name="full_name" id="full_name" pattern="^(?:((([^0-9_!¡?÷?¿/\\+=##$%ˆ&*(){}|~<>;:[\]'’,\-.\s])){1,}(['’,\-\.]){0,1}){2,}(([^0-9_!¡?÷?¿/\\+=##$%ˆ&*(){}|~<>;:[\]'’,\-. ]))*(([ ]+){0,1}(((([^0-9_!¡?÷?¿/\\+=##$%ˆ&*(){}|~<>;:[\]'’,\-\.\s])){1,})(['’\-,\.]){0,1}){2,}((([^0-9_!¡?÷?¿/\\+=##$%ˆ&*(){}|~<>;:[\]'’,\-\.\s])){2,})?)*)$" required>
This is what I use.
This regex accepts only names with minimum characters, from A-Z a-z ,space and -.
Names example:
Ionut Ionete, Ionut-Ionete Cantemir, Ionete Ionut-Cantemirm Ionut-Cantemir Ionete-Second
The limit of name's character is 3. If you want to change this, modify {3,} to {6,}
([a-zA-Z\-]+){3,}\s+([a-zA-Z\-]+){3,}
This seems to do the job for me:
[\S]{2,} [\S]{2,}( [\S]{2,})*
I usually write:
return /^[a-zA-Z\-\s\.\'\`\u00E0-\u00FC]+$/.test(firstName);
Fullname with only one whitespace:
^[a-zA-Z'\-\pL]+(?:(?! {2})[a-zA-Z'\-\pL ])*[a-zA-Z'\-\pL]+$
A simple function using preg_match in php
<?php
function name_validation($name) {
if (!preg_match("/^[a-zA-Z ]*$/", $name) === false) {
echo "$name is a valid name";
} else {
echo "$name is not a valid name";
}
}
//Test
name_validation('89name');
?>
If you want the whole first name to be between 3 and 30 characters with no restrictions on individual words, try this :
[a-zA-Z ]{3,30}
Beware that it excludes all foreign letters as é,è,à,ï.
If you want the limit of 3 to 30 characters to apply to each individual word, Jens regexp will do the job.
var name = document.getElementById('login_name').value;
if ( name.length < 4 && name.length > 30 )
{
alert ( 'Name length is mismatch ' ) ;
}
var pattern = new RegExp("^[a-z\.0-9 ]+$");
var return_value = var pattern.exec(name);
if ( return_value == null )
{
alert ( "Please give valid Name");
return false;
}

regex return everything up to the first space after nth character

I have a list of product names and I want to shorten them (Short Name). I need a regex that will return the first word if it is more than 5 characters and the first two words if it is 5 characters or less.
Product Name Short Name
BABY WIPES MIS /ALOE BABY WIPES
PKU GEL PAK PKU GEL
CA ASCORBATE TAB 500MG CA ASCORBATE
SOD SUL/SULF CRE 10-2% SOD SUL/SULF
ASPIRIN TAB 81MG EC ASPIRIN
IRON TAB 325MG IRON TAB
PEDA PEDA
I initially used:
^([^ \t]+).*
but it only returns the first word so BABY WIPES MIS /ALOE would be BABY. I then tried:
.....([^ \t]+)
But this appears to not work for names less than 5 characters. Any help would be greatly appreciated.
Brief
Your try is close, however, since you negated spaces and tabs, you were unable to move past the first word.
Code
See code in use here
^(\S{1,5}[ \t]*?\S+).*$
Note: The link uses the following shortened regex. \h may not work in your flavour of regex, which is why the code above is posted as well.
^(\S{1,5}\h*?\S+).*$
Super-simplified it becomes ^\S{1,5}\h*?\S+ (without capture groups and .*$ as the OP initially used.)
Results
Input
BABY WIPES MIS /ALOE
PKU GEL PAK
CA ASCORBATE TAB 500MG
SOD SUL/SULF CRE 10-2%
ASPIRIN TAB 81MG EC
IRON TAB
PEDA
Output
BABY WIPES
PKU GEL
CA ASCORBATE
SOD SUL/SULF
ASPIRIN
IRON TAB
PEDA
Explanation
^ Assert position at the start of a line
(\S{1,5}[ \t]*?\S+) Capture group doing the following
\S{1,5} Match any non-whitespace character between 1 and 5 times
[ \t]*? Match space or tab characters any number of times, but as few as possible (note in PCRE regex, this can be replaced with \h*? to make it shorter)
\S+ Match any non-whitespace character between one and unlimited times
.* Match any character (except newline character assuming s modifier is off - it should be for this problem)
$ Assert position at the end of a line
You can use a regex like this:
^\S{1,5} \S+|^\S+
or
^\S{1,5} ?\S*
Working demo
By the way, if you want to replace a full line with the shortened version, then you can use this regex instead:
(^\S{1,5} \S+|^\S+).*
or
(^\S{1,5} ?\S*).*
With the replacement string $1 or \1 depending on your regex engine.
Working demo

Regex: Match all, but ignore a specific word

Sample 1 String:
Aquaman Figure, XL DC Comics
Sample 2 String:
Rocket Raccoon, Mini Marvel
Regex:
/(DC Comics|Marvel)/
Match Sample 1:
DC Comics
Match Sample 2:
Marvel
Works perfectly in Regex101
How do I reverse this?
I want to match Aquaman Figure, XL and Rocket Raccoon, Mini only.
Edit:
/(.+)(?=Marvel)/ seems to do the job. It excludes Marvel from Rocket Raccon! How do I make this also work with DC comics?
/(.+)(?=Marvel)/ (or /(.+)(?=DC Comics|Marvel)/ for both) isn't going to work for something like:
John Marvel Bob
For which I presume you want the result to be:
John Bob
You'll only get John in the first match, and you'll get Marvel Bob in the second match (since look-ahead doesn't consume the looked-ahead characters).
Or something that doesn't contain either of the strings (since you require that the next characters match some given characters to get a match).
The easiest solution is probably just replacing the two desired sub-strings with empty strings. Replace:
DC Comics|Marvel
with:
(empty string)
Or you can repeatedly search for:
/(.*?)(DC Comics|Marvel|$)/
And just extract the first group (which will correspond to what matches .*, which is everything starting from the end of the last match up to just before "DC Comics", "Marvel" or the end of the string).
The reluctant quantifier ? is needed to prevent the .* from matching John Marvel Bob, rather than just John in John Marvel Bob Marvel.
re.findall(r"(.*)(?=Marvel|Comics)",input)
This does exactly what you are looking for.Its in python.input will be your string.