kubectl jsonpath command to list out failed jobs and namespaces - kubectl

Question

The command below give a list of failed jobs
kubectl get jobs -o=jsonpath='{.items[?(#.status.failed==1)].metadata.name}' --all-namespaces
job-3764289372 abc-23145263524 xyz-6745096523
I need to list out the jobs and their namespaces. Is it possible to do this with jsonpath?
Something like below?
NAMESPACE NAME
dev-namespace job-3764289372
namespace-123 abc-23145263524

Answer 1

I think its not possible using plain jsonpath and a post processing(solution-2) is needed. However, if you could use go-template(solution-1), then it can be done with go-template without using any post processing.
k get job
NAME COMPLETIONS DURATION AGE
job1 1/1 2m36s 3h27m
job2 0/1 3h23m 3h23m #failed
job3 0/1 3h23m 3h23m #failed
Solution-1: using go-template:
Below go-template will print the namespace and name of the failed job.
kubectl get job -A -o go-template='{{range $i, $p := .items}}{{range .status.conditions}}{{if (eq .type "Failed")}}{{$p.metadata.namespace}} {{$p.metadata.name}}{{"\n"}}{{end}}{{end}}{{end}}'
default job2
default job3
Solution-2: using jsonpath with awk.
kubectl get job -o jsonpath='{range .items[*]}{.metadata.namespace} {.metadata.name} {.status.conditions[*].type}{"\n"}'|awk 'BEGIN{print "namespace","name"}$NF=="Failed"{print $1,$2}'
namespace name
default job2
default job3