Counting rows per record - list

Question

I'm trying count the total number of invoices where record is concurent.

Answer 1

I am unsure about what it is you exactly want. I'm going to base my expectations on your code.
There are a three errors in the code:
Function arguments should a variable name.
def count_consecutive_invoice (df, invoiceNumber):
retlist = []
for i in range(len(df[InvoiceNumber]) - 1):
Notice the removal of quotes around invoiceNumber. You set, what it's equal to later, when calling the function.
You are trying to call the function instead of accessing a variable:
if count_consecutive_invoice[i] + 1 == count_consecutive_invoice[i
+ 1]:
Should be
if df[InvoiceNumber][i] + 1 == df[InvoiceNumber][i + 1]:
You need to declare all variables, including count.
To do this, just add count = 1 after retlist = [].
This code should work:
df = pd.read_excel(r'MYPath\Book1.xlsx')
def count_consecutive_invoice (df, invoiceNumber):
retlist = []
count = 1
for i in range(len(df[ivoiceNumber]) - 1):
# Check if the next number is consecutive
if df[invoiceNumber][i] + 1 == df[invoiceNumber][i+1]:
count += 1
elif count > 1:
# If it is not and count > 1 append the count and restart counting
retlist.append(count)
count = 1
# Since we stopped the loop one early append the last count
retlist.append(count)
return retlist
output = count_consecutive_invoice(df, 'Invoice Number')
print(output)
output:
[4]

Answer 2

Here is my commented solution.
It does recreate a panda frame, you need to pass the rows name for the id and the one on which we count the invoicing.
def count_consecutive_invoice(table, invoice_row_name, id_row_name):
invoiced_table = {} # the output
for row in table:
if row != invoice_row_name:
invoiced_table[row] = []
invoiced_table['Cont of Consecutive Invoices'] = []
streak = False # keep track of streaking invoices cause on first invoice we need to add 2, not 1
for line in range(len(table[invoice_row_name]) - 1):
id = table[id_row_name][line]
if not id in invoiced_table[id_row_name]:
for row in table:
if row != invoice_row_name:
invoiced_table[row].append(table[row][line])
invoiced_table['Cont of Consecutive Invoices'].append(0)
if id == table[id_row_name][line+1]: #check the vendor id so if you get the invoicing for each
if table[invoice_row_name][line]+1 == table[invoice_row_name][line+1]: # check the actual invoicing
itable_line = invoiced_table[id_row_name].index(id)
invoiced_table['Cont of Consecutive Invoices'][itable_line] += 1 + int(not streak) #otherwise we add 1 or 2 depending on the streak status
streak = True
continue
streak = False
return invoiced_table
invoiced = count_consecutive_invoice(df, "Invoice ID", "Vendor ID")
print(pd.DataFrame.from_dict(invoiced))