Django class based view, save in another model after CreateView - django

I have a create view (Loan_assetCreateView(generic.CreateView)) where I save if an asset is going to be loaned and when it will be returened in a model called Loan_asset(models.Model). Then I have the asset in a diffrent model Asset(model.Model). I would like to once I have saved my data in my Loan_assetCreateView(generic.CreateView) that is set the value in Asset.is_loaned to True. How can I do that?
My models.py:
class Asset(models.Model):
# Relationships
room = models.ForeignKey("asset_app.Room", on_delete=models.SET_NULL, blank=True, null=True)
model_hardware = models.ForeignKey("asset_app.Model_hardware", on_delete=models.SET_NULL, blank=True, null=True)
# Fields
name = models.CharField(max_length=30)
serial = models.CharField(max_length=30, unique=True, blank=True, null=True, default=None)
mac_address = models.CharField(max_length=30, null=True, blank=True)
purchased_date = models.DateField(null=True, blank=True)
may_be_loaned = models.BooleanField(default=False, blank=True, null=True)
is_loaned = models.BooleanField(default=False, blank=True, null=True)
missing = models.BooleanField(default=False, blank=True, null=True)
notes = HTMLField(default="")
ip = models.CharField(max_length=90, null=True, blank=True)
created = models.DateTimeField(auto_now_add=True, editable=False)
last_updated = models.DateTimeField(auto_now=True, editable=False)
class Loan_asset(models.Model):
# Relationships
asset = models.ForeignKey("asset_app.Asset", on_delete=models.SET_NULL, blank=True, null=True)
loaner_type = models.ForeignKey("asset_app.Loaner_type", on_delete=models.SET_NULL, blank=True, null=True)
location = models.ForeignKey("asset_app.Locations", on_delete=models.SET_NULL, blank=True, null=True)
# Fields
loaner_name = models.CharField(max_length=60)
loaner_address = models.TextField(max_length=100, null=True, blank=True)
loaner_telephone_number = models.CharField(max_length=30)
loaner_email = models.EmailField()
loaner_quicklink = models.URLField(null=True, blank=True)
loan_date = models.DateField()
return_date = models.DateField()
notes = HTMLField(default="")
returned = models.BooleanField(default=False, blank=True, null=True)
created = models.DateTimeField(auto_now_add=True, editable=False)
last_updated = models.DateTimeField(auto_now=True, editable=False)
class Meta:
pass
def __str__(self):
return str(self.loaner_name)
def get_absolute_url(self):
return reverse("asset_app_loan_asset_detail", args=(self.pk,))
def get_update_url(self):
return reverse("asset_app_loan_asset_update", args=(self.pk,))
my urls.py
`path("asset_app/loan_asset/create/", views.Loan_assetCreateView.as_view(), name="asset_app_loan_asset_create")`,
my views.py
class Loan_assetCreateView(generic.CreateView):
model = models.Loan_asset
form_class = forms.Loan_assetForm

Here are some options:
override form_valid method that's being called in post method implementation, so that after form will be validated (model instance saved), you'll be able to set the flag through foreign key/by creating Asset instance:
...
def form_valid(self, form):
self.object = form.save()
if self.object.asset:
self.object.asset.is_loaned = True
else:
self.object.asset = Asset.objects.create(is_loaned=True)
return HttpResponseRedirect(self.get_success_url())
use Django signals:
#receiver(post_save, sender=Loan_asset)
def create_transaction(sender, instance, created, **kwargs):
if created:
Asset.objects.create(is_loaned=True)

You can override the post method in your Loan_assetCreateView.
class Loan_assetCreateView(generic.CreateView):
model = models.Loan_asset
form_class = forms.Loan_assetForm
def post(request, *args, **kwargs):
response = super().post(request, *args. **kwargs)
# Do your thing
return response

Related

Django, i can't put function form inside generic.UpdateView

I am making a app for one kindergarten in my city. I have kids model and payment model.
For updating kid I am using class based view generic UpdateView and for creating a payment i am using form and function view. I have not problems with payment form when I am using a different template but when I try to put it on the same template, payment form is not showing up and it's not working. Is it possible to have payment form on same template as UpdateView class ? I am using UpdateView class as profile page and I would like to have payment form on the same page. Please help. Thanks
models:
class Kids(models.Model):
name = models.CharField(max_length=100, blank=True, null=True)
city_birthday = models.CharField(max_length=100, blank=True, null=True)
custom_id = models.CharField(max_length=100 ,blank=True, null=True)
gender = models.CharField(max_length=100, choices=gender_choices, null=True, blank=True)
address = models.CharField(max_length=250, null=True, blank=True)
contact_phone = models.CharField(max_length=100, blank=True, null=True)
family_size = models.IntegerField(null=True, blank=True)
living_with = models.CharField(max_length=100, choices=living_choices, null=True, blank=True)
number_of_preschool_kids_in_family = models.IntegerField(null=True, blank=True)
kid_already_been_in_kindergarten = models.CharField(max_length=100, choices=preschool_choices,
null=True, blank=True ,default=False)
father_name = models.CharField(max_length=100, blank=True, null=True)
father_education_level = models.CharField(max_length=200, blank=True, null=True)
father_company = models.CharField(max_length=200, blank=True, null=True)
mother_name = models.CharField(max_length=100, blank=True, null=True)
mother_education_level = models.CharField(max_length=200, blank=True, null=True)
mother_company = models.CharField(max_length=200, blank=True, null=True)
parent_notes = models.CharField(max_length=500, blank=True, null=True)
program_choice = models.CharField(max_length=100, choices=kindergarten_program_choice, null=True,
blank=True)
def __str__(self):
return self.name
class Meta:
ordering = ['name']
class Payment(models.Model):
user = models.ForeignKey(Kids, on_delete=models.CASCADE, blank=True, null=True)
bank_paper_id = models.IntegerField(null=True, blank=True)
payment_date = models.CharField(max_length=100, null=True, blank=True)
paid = models.FloatField(null=True, blank=True)
need_to_pay = models.FloatField(null=True, blank=True)
notes = models.CharField(max_length=500, blank=True, null=True)
def __str__(self):
return self.user.name
views:
class UpdateKidView(UpdateView):
model = Kids
fields = '__all__'
template_name = 'vrtic/update_kid.html'
success_url = reverse_lazy('vrtic:kids')
def create_payment(request, pk):
kid = Kids.objects.get(id=pk)
payment_form = PaymentForm()
if request.method == 'POST':
payment_form = PaymentForm(request.POST)
if payment_form.is_valid():
payment = payment_form.save(commit=False)
payment.user = kid
payment_form.save()
return redirect('vrtic:kids')
context = {
'payment_form': payment_form,
'kid': kid
}
return render(request, 'vrtic/update_kid.html', context)
form:
class PaymentForm(forms.ModelForm):
class Meta:
model = Payment
fields = '__all__'
class UpdateKidView(UpdateView):
model = Kids
form_class = KidsForm
second_form_class = PaymentForm
template_name = 'vrtic/update_kid.html'
success_url = reverse_lazy('vrtic:kids')
def get_context_data(self, **kwargs):
context = super(UpdateKidView, self).get_context_data(**kwargs)
context['form'] = self.form_class(instance=self.get_object())
context['second_form'] = self.second_form_class()
return context
def post(self, request, **kwargs):
kids_form = self.form_class(request.POST, request.FILES, instance=self.get_object())
if kids_form.is_valid():
kid = kids_form.save()
payment_form = self.second_form_class(request.POST)
...
Not the happiest solution, but u got the idea, if need more help contact me to explain on Serbian, not sure how are the rules here for languages : )

I wanna create model which Before adding it must be accepted

I would like to create a model which must be accepted by the moderator before adding, after which every change in eg the title in this model must also be accepted
class MangaRequest(models.Model):
title = models.CharField(max_length=191)
type = models.CharField(max_length=30,choices=TYPE, blank=True, default='', null=True)
status= models.CharField(max_length=30, choices=STATUS, blank=True, default='', null=True)
date_start = models.DateField(blank=True, null=True)
data_end = models.DateField(blank=True, null=True)
age_restrictions = models.ForeignKey(OgraniczenieWiekowe, null=True, default='', blank=True)
volumes = models.SmallIntegerField(null=True, blank=True, default=0)
chapter = models.SmallIntegerField(null=True, blank=True, default=0)
is_accept = models.BooleanField(default=False)
delete = models.BooleanField(default=False)
This is my model and I have done it
def save(self, *args, **kwargs):
if self.is_accept == True:
manga = MangaAccept.objects.create(...)
super(MangaRequest, self).delete()
return manga
else:
super(MangaRequest, self).save()
And the same way is about deletes
My question is how can ACCEPT or REJECT for model and everyone field in this model ? Any sugestion ?

Two Foreign keys issue django

Hi I have this python code for django, and basically i am trying to build it so that every tourobject can have many tourbets but also i want to be able to save a certain winning tourbet as current bet but then django complains that it can't find TourBet
class TourObject(models.Model):
tourplace = models.ForeignKey(TourPlace, related_name='tourplace', verbose_name="tourplace", default=1)
title = models.CharField(max_length=155, blank=True)
description = models.TextField(blank=True)
date_created = models.DateTimeField(auto_now_add=True)
status = models.BooleanField(default=False, verbose_name="Status")
end_date = models.DateTimeField(blank=True, default=datetime.now)
current_bet = models.IntegerField(blank=True, default=0)
next_bet = models.IntegerField(blank=True, default=0)
no_auction_price = models.IntegerField(blank=True, default=1)
objects = models.Manager()
def __unicode__(self):
return self.title
def get_absolute_url(self):
return reverse("tourobjects:tourobject", kwargs={"pk": self.pk})
class RelatedTourObject(models.Manager):
def get_queryset(self):
return super(RelatedTourObject, self).get_queryset().select_related('tourobject').all()
class TourBet(models.Model):
user = models.ForeignKey(User, related_name='tourbet', verbose_name='User')
tourobject = models.ForeignKey(TourObject, related_name='tourobjectbet', verbose_name="tourobjectbet", default=1)
date_created = models.DateTimeField(blank=True, default=datetime.now)
bet_amount = models.IntegerField(blank=True, default=1)
objects = models.Manager()
related_tourobject = RelatedTourObject()
def __unicode__(self):
return str(self.bet_amount)
I think you can try this.
class TourObject(models.Model):
winning_bet = models.ForeignKey('TourBet', related_name='winning_bet')

QuerySet Raised: Related Field got invalid lookup: icontains

Am learning Django and I used ForeignKey to link my models.
icontains work in field that are not ForeignKeys.
I want to filter the Items in my model to show me only fields that match the queryset.
But queryset raised: Related Field got invalid lookup: icontains
Please help. Below is My model and View
My Model
class Category(models.Model):
category = models.CharField(max_length=200, default='', blank=True, null=True)
def __unicode__(self):
return self.category
class StoreItems(models.Model):
item_name = models.CharField(max_length=200, default='', blank=True, null=True)
def __unicode__(self):
return self.item_name
class Supplier(models.Model):
supplier_name = models.CharField(max_length=200, default='', blank=True, null=True)
def __unicode__(self):
return self.supplier_name
class Unit(models.Model):
unit = models.CharField(max_length=200, default='', blank=True, null=True)
def __unicode__(self):
return self.unit
class Store(models.Model):
category = models.ForeignKey(Category, blank=True, null=True)
item_name = models.ForeignKey(StoreItems, blank=True, null=True)
quantity = models.IntegerField(default='', blank=True, null=False)
receive_amount = models.IntegerField(blank=True, null=True)
receive_by = models.CharField(max_length=120, default='', blank=True, null=False)
issue_amount = models.IntegerField(blank=True, null=True)
issue_by = models.CharField(max_length=120, default='', blank=True, null=True)
issue_to = models.CharField(max_length=120, default='', blank=True, null=True)
supplier_name = models.ForeignKey(Supplier, blank=True, null=True)
created_by = models.CharField(max_length=15, default='', blank=True, null=True)
unit = models.ForeignKey(Unit, blank=True, null=True)
reorder_level = models.IntegerField(default='0', blank=True, null=False)
export_to_CSV = models.BooleanField(default=False)
last_updated = models.DateTimeField(auto_now_add=False, auto_now=True)
My View
def store_list(request):
label = 'STORE'
title = 'Select the item you want to filter'
heading = 'SEARCH ITEMS'
if request.user.is_authenticated():
form = StoreSearchForm(request.POST or None)
context = {
"title": title,
"form": form,
"heading": heading,
}
if request.method == 'POST':
queryset = Store.objects.all().order_by('item_name').filter(category__icontains=form['category'].value(), item_name__icontains=form['item_name'].value())
context = {
"queryset": queryset,
"form": form,
}
return render(request, "store.html", context)
Yep, you can't directly use icontains on a foreign key but ...
Store.objects.all().order_by('item_name'
).filter(category__category__icontains=form['category'].value(), item_name__icontains=form['item_name'].value())
Your category model contains a field also called category. That can be accessed as category__category which means you can use a query such as the one given above.

post save operation if a filed is null or blank in django models?

here is my code :
class Invitation(models.Model):
#other fields here
Code = models.CharField(max_length=128, null=True, blank=True)
Tags = models.ManyToManyField("CategorieInvitation", null=True, blank=True)
Tags = models.ManyToManyField("Usage", null=True, blank=True)
Note = models.CharField(max_length=128, null=True, blank=True)
Used = models.BooleanField(default=False, blank=True)
SendTo = models.EmailField(null=True, blank=True)
# a revoir
def post_save(self, model_instance, add):
if self.Code.__len__() == 0 :
self.Code = generate_invitation(1)[0]
self.save()
how to replace Code with the result of generate_invitation if Code is blank or null even if created in django-admin interface ?
regards
Bussiere
For what you are trying to do it's probably easier and more efficient to override the save method.
class Invitation(models.Model):
#other fields here
code = models.CharField(max_length=128, null=True, blank=True)
tags = models.ManyToManyField("CategorieInvitation", null=True, blank=True)
tags2 = models.ManyToManyField("Usage", null=True, blank=True)
note = models.CharField(max_length=128, null=True, blank=True)
used = models.BooleanField(default=False, blank=True)
send_to = models.EmailField(null=True, blank=True)
# a revoir
def save(self, *args, **kwargs):
if not self.code:
self.code = generate_invitation(1)[0]
super(Invitation, self).save(*args, **kwargs)
By the way post_save is not something that should be a model instance method.
See: https://docs.djangoproject.com/en/1.4/ref/signals/#signals