Django - Altering list view based on link that is pressed - django

I have a navbar above my products on my fake e commerce website that I am building. I render this view through list view. In this navbar I have a search area that works fine, and want to add the ability to filter the results based on what is pressed. For example, I have styles: realism, portrait, etc in the navbar. When I click on realism I want the results to change to all realism paintings that are in the DB.
My question is what would be the best way to accomplish this? Could I alter the original list view? Or would I just need to create an entirely new view based on the specific queries I need? Any help is greatly appreciated!
Also attached will be a picture to show you what I mean in case my explanation wasn't the best.
view:
class AllProductView(ListView):
template_name = 'my_site/all_products.html'
model = Product
ordering=['id']
paginate_by = 9
context_object_name = 'products'
product model as requested:
class Product(models.Model):
name = models.CharField(max_length=120)
shortened_name = models.CharField(max_length=50)
date_of_creation = models.CharField(max_length=20, null=True)
history = models.CharField(max_length=255)
price = models.DecimalField(max_digits=9, decimal_places=2)
discount_price = models.FloatField(blank=True, null=True)
style = models.CharField(max_length=50)
artist = models.ForeignKey(Artist, on_delete=models.SET_NULL, null=True)
image = models.ImageField(upload_to='images', null=True)
slug = models.SlugField()

You can filter by overriding the .get_queryset(…) method [Django-doc]:
class AllProductView(ListView):
template_name = 'my_site/all_products.html'
model = Product
ordering=['id']
paginate_by = 9
context_object_name = 'products'
def get_queryset(self, *args, **kwargs):
qs = super().get_queryset(*args, **kwargs)
fltr = self.kwargs['style']
if fltr != 'all':
qs = qs.filter(style=self.kwargs['style'])
return qs
In your urls.py, you can then use a <str:…> path converter to determine the style we want to filter on, so:
path('products/<str:style>/', AllProductView.as_view(), name='products')
In the templates, we can then write URLs with:
Realism
This will than link to a page that only shows Products with style='realism'.

Related

Open listView with foreignkey from another listview with Django

I am working on a product overview page in Django.
For this I have three models: category, brand, product.
I have created a View with ListView of the category. I loop through them to display them. I then want to open another overview of all brands within that category.
How do I do this?
Here are my models:
class Category(models.Model):
category_name = models.CharField(max_length=200)
sub_category = models.CharField(max_length=200,blank=True,null=True)
category_picture = models.ImageField(upload_to='category/', null=True, blank=True)
def __str__(self):
if self.sub_category is None:
return self.category_name
else:
return f" {self.category_name} {self.sub_category}"
class Meta:
ordering = ['category_name']
class Brand(models.Model):
category = models.ForeignKey('Category', on_delete=models.SET_NULL,null=True,blank=True)
brand_name = models.CharField(max_length=200)
brand_owner = models.CharField(max_length=200)
brand_story = models.TextField()
brand_country = models.CharField(max_length=200)
def __str__(self):
return f"{self.brand_name}"
class Bottle(models.Model):
category_name = models.ForeignKey('Category', on_delete=models.SET_NULL,null=True,blank=True)
brand = models.ForeignKey('Brand', on_delete=models.CASCADE)
bottle_name = models.CharField(max_length=255)
bottle_info = models.TextField()
bottle_tasting_notes = models.TextField()
bottle_barcode = models.IntegerField()
bottle_image = models.ImageField(upload_to='bottles/',null=True)
def __str__(self):
return f"{self.brand.brand_name} {self.bottle_name}"
How do I open a listview of all brands within a certain category from a link of the category listview?
First thing is to create another listview that displays all brands within a specific category. We do this by creating a new get_queryset() method.
views.py
class BrandListView(ListView):
model = Brand
def get_queryset(self):
return Brand.objects.filter(category__category_name=self.kwargs['category'])
Next add a url to your URLS.py so it can be accessed. We're using category_name as part of the url so it's human readable
from .views import BrandListView
urlpatterns = [
path('brands/<str:category>/', PublisherBookList.as_view()), name= "brand_list"
]
Then, as you loop through your categories in your template, create a link to the url
{% for category in categories %}
{{category.category_name}} : See brands in category
{% endfor %}
This will work as long as your categories have fairly simple names. If not, you might want to use the ID in the URL instead, or add a slug field to the model and use that.

Object-level permissions in Django

I have a ListView as follows, enabling me to loop over two models (Market and ScenarioMarket) in a template:
class MarketListView(LoginRequiredMixin, ListView):
context_object_name = 'market_list'
template_name = 'market_list.html'
queryset = Market.objects.all()
login_url = 'login'
def get_context_data(self, **kwargs):
context = super(MarketListView, self).get_context_data(**kwargs)
context['scenariomarkets'] = ScenarioMarket.objects.all()
context['markets'] = self.queryset
return context
The two market models are as follows:
class Market(models.Model):
title = models.CharField(max_length=50, default="")
current_price = models.DecimalField(max_digits=5, decimal_places=2, default=0.50)
description = models.TextField(default="")
shares_yes = models.IntegerField(default=0)
shares_no = models.IntegerField(default=0)
b = models.IntegerField(default=100)
cost_function = models.IntegerField(default=0)
open = models.BooleanField(default=True)
def __str__(self):
return self.title[:50]
def get_absolute_url(self):
return reverse('market_detail', args=[str(self.id)])
class ScenarioMarket(models.Model):
title = models.CharField(max_length=50, default="")
description = models.TextField(default="")
b = models.IntegerField(default=100)
cost_function = models.IntegerField(default=0)
most_likely = models.CharField(max_length=50, default="Not defined")
open = models.BooleanField(default=True)
def __str__(self):
return self.title[:50]
def get_absolute_url(self):
return reverse('scenario_market_detail', args=[str(self.id)])
And my user model is as follows:
class CustomUser(AbstractUser):
points = models.DecimalField(
max_digits=20,
decimal_places=2,
default=Decimal('1000.00'),
verbose_name='User points'
)
bets_placed = models.IntegerField(
default=0,
verbose_name='Bets placed'
)
net_gain = models.DecimalField(
max_digits=20,
decimal_places=2,
default=Decimal('0.00'),
verbose_name='Net gain'
)
class Meta:
ordering = ['-net_gain']
What I want happen is that different users see different sets of markets. For example, I want users from company X to only see markets pertaining to X, and same for company Y, Z, and so forth.
Four possibilities so far, and their problems:
I could hardcode this: If each user has a company feature (in addition to username, etc.), I could add a company feature to each market as well, and then use if tags in the template to ensure that the right users see the right markets. Problem: Ideally I'd want to do this through the Admin app: whenever a new market is created there, it would be specified what company can see it.
I could try to use Django's default permissions, which of course would be integrated with Admin. Problem: Setting a view permission (e.g., here) would concern the entire model, not particular instances of it.
From googling around, it seems that something like django-guardian might be what I ultimately have to go with. Problem: As I'm using a CustomUser model, it seems I might run into problems there (see here).
I came across this here on SO, which would enable me to do this without relying on django-guardian. Problem: I'm not clear on how to integrate that into the Admin app, in the manner that django-guardian seems able to.
If anyone has any advice, that would be greatly appreciated!
You can add some relationships between the models:
class Company(models.Model):
market = models.ForeignKey('Market', on_delete=models.CASCADE)
...
class CustomUser(AbstractUser):
company = models.ForeignKey('Company', on_delete=models.CASCADE)
...
then in your view you can simply filter the queryset as appropriate:
class MarketListView(LoginRequiredMixin, ListView):
context_object_name = 'market_list'
template_name = 'market_list.html'
login_url = 'login'
def get_queryset(self):
return Market.objects.filter(company__user=self.request.user)
Note, you don't need the context['markets'] = self.queryset line in your get_context_data; the queryset is already available as market_list, since that's what you set the context_object_name to.

Remove option from generic class view in Django

I just started learning Django this week and I'm trying to figure out how I can remove an option from a select menu being rendered in a class based view. The dropdown is for a Foreign Key field that links to my users table.
The functionality here is that I do not want the current user logged into show up on that list (basically I don't want someone to be able to select themself). How can I go about doing this?
View:
class TransferCreateView(CreateView):
model = Transfer
template_name = 'points/transfer_form.html'
fields = ['receiver', 'message', 'amount']
Model:
class Transfer(models.Model):
receiver = models.ForeignKey(User, null=False,
on_delete=models.CASCADE, related_name='receiver')
sender = models.ForeignKey(User, null=False, on_delete=models.CASCADE, related_name='sender')
amount = models.IntegerField(
validators=[
MinValueValidator(1),
MaxValueValidator(1000)],
null=False)
message = models.CharField(max_length=100)
date_sent = models.DateTimeField(default=timezone.now)
Basically, I don't want the person who is the sender (which i was going to set in the code in a form_valid() function) to be an option for 'receiver' in the template when it renders.
Override the get_form method of the CreateView and change the queryset of that field, something like this:
class TransferCreateView(CreateView):
model = Transfer
template_name = 'points/transfer_form.html'
fields = ['receiver', 'message', 'amount']
def get_form(self, form_class):
form = super().get_form(form_class)
form.fields['receiver'].queryset = User.objects.exclude(id=self.request.user.id)
return form

Try to join a OneToOne relationship in Django

I need some help doing a join using Django, which seems like it should be easy. I have looked at the documentation but it seems like it won't join for some reason.
I am trying to get in my view, the model.Photo and model.PhotoExtended with both joined and then displayed in the view. Currently I am just trying to get the model.Photo displayed but with a join which finds the request.user and filters it based on that.
They are in different apps.
models.py for model.Photo
class Photo(ImageModel):
title = models.CharField(_('title'),
max_length=60,
unique=True)
slug = models.SlugField(_('slug'),
unique=True,
help_text=_('A "slug" is a unique URL-friendly title for an object.'))
models.py for model.PhotoExtended
class PhotoExtended(models.Model):
Photo = models.OneToOneField(Photo, related_name='extended', help_text='Photo required', null=True)
user = models.ForeignKey(User, on_delete=models.CASCADE, null=True, help_text='User that uploaded the photo')
views.py
class PhotoExtendedUserView(ListView):
template_name = 'photo_user_list.html'
def get_queryset(self):
user = get_object_or_404(User, username=self.request.user)
return Photo.objects.filter(photoextended__user=user)
You set the related_name on Photo (which shouldn't be capitalized by the way) to extended so you need to filter like so:
class PhotoExtendedUserView(ListView):
template_name = 'photo_user_list.html'
def get_queryset(self):
user = get_object_or_404(User, username=self.request.user)
# 'extended' vs. 'photoextended'
return Photo.objects.filter(extended__user=user)

search query result in django

Here is my model
class News(models.Model):
title = models.CharField(max_length=500)
published_date = models.CharField(max_length=100)
description = models.TextField()
details = models.TextField()
status = models.BooleanField(default=False)
crawler = models.ForeignKey('Crawler')
category = models.ForeignKey('Category')
And the view for the news is
class DisplayNewsView(TemplateView):
template_name = "news_listing.html"
#paginate_by = 10
def get_context_data(self, **kwargs):
context = super(DisplayNewsView, self).get_context_data(**kwargs)
categories_list = Category.objects.all().filter(created_by=self.request.user)
context['news_list'] = []
for categories in categories_list:
print(categories)
for crawler in categories.crawlers.get_queryset():
#print(categories)
print(crawler)
crawler_list = News.objects.filter(
Q(category=categories),
Q(crawler=crawler) | Q(crawler=crawler))
#print(crawler_list)
context['news_list'].append(crawler_list)
return context
I have displayed the news in template.
I want to search the news according to time. I mean the news from "date" to "date" as per the published date in news model.
My model for category is
class Category(models.Model):
category = models.CharField(max_length=50)
identifier = models.CharField(max_length=50, unique=True)
level_1_words = models.TextField()
level_2_words = models.TextField()
created_by = models.ForeignKey(User,null=True)
crawlers = models.ManyToManyField('Crawler',related_name='crawler_name')
class Meta:
verbose_name_plural = "Categories"
def __unicode__(self): # Python 3: def __str__(self):
return self.category
Can anyone plz help to to search the news according to publish date.
I want it to be done like from "date" to "date" submit.
When user click the submit button I want the news to be filtered..
It would be great help if someone tell me how to download the searched news in csv too. thanx in advance
You first need to make that field of the date a DateField instead of CharField
This is how to query date range in django
News.objects.filter(pub_date__lte=datetime(2014, 5, 30), pub_date__gte=datetime(2014, 1, 30))
Another example would be
News.objects.filter(pub_date__lte=datetime(2014, 5, 30), pub_date__gte=datetime(2014, 1, 30)).exclude(datetime.date.today())
for more information on django queries check out the docs # Making queries in Django