How to send an array struct into a function using pointers - c++

Question

How to send an array of structs into a function as a parameter?
The employee variable is a struct.
My function:
void arraySort(struct Employee *employee[])
{
bool flag = false;
for (int i = 0; i < 5000; i++)
{
int empID1 = employee[i]->empID;
int empID2 = employee[i + 1]->empID;
flag = Employee().compareEmpID(empID1, empID2);
if (flag == true)
{
Employee swap;
swap = *employee[i + 1];
*employee[i] = *employee[i + 1];
*employee[i + 1] = swap;
}
}
}
Which calls this function:
bool Employee::compareEmpID(int empID1, int empID2)
{
if (empID1 >= empID2)
return true;
return false;
}
I am trying to invoke a call to the arraySorts function from main by using the employee array struct as a pointer:
arraySort(*employee);

Answer 1

The function compareEmpID have to be a static method in struct employee and invoked by calling as Employee::compareEmpID.
There are some issues in for your arraySort method.
You hard code the number 5000, that means your array need to have 5000 elements or more, otherwise you will get error about illegal memory access.
The variable swap should be a pointer and declared outside of the for loop.
Your swap logic is wrong.
I rewrite the program base on your code and tested it.
#include<iostream>
using namespace std;
struct Employee {
int empID;
static bool compareEmpID(int empID1, int empID2) {
return empID1 > empID2;
}
};
void arraySort(Employee *employees[], int size) {
bool flag = false;
Employee *swap;
for(int i=0; i<size-1; i++) {
int empID1 = employees[i]->empID;
int empID2 = employees[i+1]->empID;
flag = Employee::compareEmpID(empID1,empID2);
if(flag) {
swap = employees[i+1];
employees[i+1] = employees[i];
employees[i] = swap;
}
}
}
int main(int argc, char* args[]) {
Employee** employee;
employee = new Employee*[2];
employee[0] = new Employee;
employee[0]->empID = 5;
employee[1] = new Employee;
employee[1]->empID = 1;
arraySort(employee, 2);
cout << "emp[0]: " << employee[0]->empID << endl;
cout << "emp[1]: " << employee[1]->empID << endl;
delete employee[0];
delete employee[1];
delete[] employee;
return 0;
}
Hope this helps you boots your learning progress.