storing different rows of two lists in new list - list

Question

I am trying to create a new object by comparing two list. If the rows are matching the row should be removed form the splitted row_list or appended to a new list containing only the differences between both lists.
Sample data: basically the data is structured in a way that splitted_row_list has all the rows all_rows has, but contains additional rows, which are different, aswell(btw also meaning there is an unequal amount of rows between both lists) . I am amining to do put these additional rows into a new object.
all_rows[0]:'1390', '139080', '13980', '1380', '139080', '13080'
splitted_row_list[0]:'35335','53527','353529','242424','5222','444'
results = []
for row in splitted_row_list:
print(row)
for row1 in all_rows:
if row1 == row:
splitted_row_list.remove(row)
else:
results.append(row)
print(results)
However, this code just returns all the rows. Does anyone have a suggestion?

Answer 1

The two lists are distict, therefore you get every item in one list because if row1 == row is never true, then you wont remove anything.
There are no differences.
EDIT:
You can simply
nonunique = []
for row in splitted_row_list:
print(row)
for row1 in all_rows:
if row1 == row:
nonunique.append(splitted_row_list.remove(row))
result = splitted_row_list #the nonunique have been removed
if you want the non unique from all_rows, just add a all_rows.remove(row).
For the complete sets, just concatenate them after the loop.
all = nonunique +splitted_row_list+all_rows

Answer 2

Thanks I have 'solved' this problem in this particular context by just appending a string and then later sorting based on whether they contain the string or not..not very elegant but it works..
def append_mark2(splitted_row_list):
for row in splitted_row_list:
for row1 in all_rows:
if row1 == row:
row.append('jaja')
print(row)
return splitted_row_list
def sort_on_appendix(splitted_row_list_appended_mark):
next_row_list3=[]
for row in splitted_row_list_appended_mark:
if 'jaja' not in row:
print(row)
next_row_list3.append(row)
print('next_row_list3:',next_row_list3)
return next_row_list3