unique_ptr is calling destructor twice - c++

Question

I have a block of code where I am using unique_ptr.
class Abc {
public:
std::string msg;
Abc(std::string m) {
msg = m;
std::cout << "Constructor: " << msg << std::endl;
}
~Abc() {
std::cout << "Destructor: " << msg << std::endl;
}
};
int main() {
auto p = std::make_unique<Abc>(Abc(__func__));
}
But the destructor is called two times. Is there a way I can make it call the destructor only one time?

Answer 1

You're constructing a temporary Abc (i.e. Abc(__func__)) firstly, then pass it to std::make_unique, which constructs the underlying Abc from the temporary (via the move constructor of Abc); i.e. two Abc objects are constructed, then destructor are called twice too.
You can pass __func__ to std::make_unique directly, i.e. needn't to construct the temporary Abc from the beginning.
auto p = std::make_unique<Abc>(__func__); // constructs Abc via Abc::Abc(std::string) directly

Answer 2

You create two objects and see both of them destructed. Abc(__func__) is a temporary that gets destroyed at the end of the line in main.
Add a user defined move constructor to see how make_unique move constructs the object:
#include <string>
#include <memory>
#include <iostream>
class Abc {
public:
std::string msg;
Abc(std::string m) {
msg = m;
std::cout << "Constructor: " << msg << std::endl;
}
Abc(Abc&& other){
msg = other.msg + " moved";
std::cout << "Move Constructor: " << msg << "\n";
}
~Abc() {
std::cout << "Destructor: " << msg << std::endl;
}
};
int main() {
auto p = std::make_unique<Abc>(Abc(__func__));
}
Output:
Constructor: main
Move Constructor: main moved
Destructor: main
Destructor: main moved