I'm trying to edit an old Abaqus user subroutine for my own project. I am attempting to debug some segmentation faults using print statements (on a university computer and the code requires input from abaqus so using a proper debugger is not possible), however, when I use a print statement it aborts with a message saying: *** buffer overflow detected ***: *path* terminated.
The first few (5 maybe?) times I ran it this morning it actually worked and printed as expected, but then stopped. I've tried using call flush(6) to clear out the buffer but that didn't help. Should I be using a different unit? Or clearing the buffer a different way? Or something else entirely?
I'm new to Fortran and only kind of experienced with programming in general so please any advice on this issue would be appreciated!
Here's the relevant portion of my code:
SUBROUTINE UMAT(STRESS,STATEV,DDSDDE,SSE,SPD,SCD,
1 RPL,DDSDDT,DRPLDE,DRPLDT,STRAN,DSTRAN,TIME,DTIME,
2 TEMP,DTEMP,PREDEF,DPRED,CMNAME,NDI,NSHR,NTENS,
3 NSTATV,PROPS,NPROPS,COORDS,DROT,PNEWDT,CELENT,
4 DFGRD0,DFGRD1,NOEL,NPT,KSPT,KINC)
INCLUDE 'ABA_PARAM.INC'
CHARACTER*80 CMNAME
DIMENSION STRESS(NTENS),STATEV(NSTATV),
1 DDSDDE(NTENS,NTENS),DDSDDT(NTENS),DRPLDE(NTENS),
2 STRAN(NTENS),DSTRAN(NTENS),TIME(2),PREDEF(1),DPRED(1),
3 PROPS(NPROPS),COORDS(3),DROT(3,3),
4 DFGRD0(3,3),DFGRD1(3,3)
dt = DTIME
print *, "TEMP", TEMP
Note: I believe this is using fortran 90 and intel 2020
It turns out that using write(6, *) "TEMP: ", TEMP does what I need without the buffer overflow which is good enough for me
Related
Recently, i've begun learning Fortran programmation language.
I am using CodeBlocks IDE with GNU Fortran Compiler.
I have a problem in simple code that i found in a Fortran Course online that explains how to read and write from a file.
The program is the following:
program main
implicit none
character (len=14) :: c1,c2,c3
integer :: n
real :: T
open(unit=10,file='titi.txt')
read(10,*) c1,n,c2
read(10,*) c3,T
close(10)
open(unit=20,file='toto.txt')
write(20,*) c1,'il est',n,c2
write(20,*)'la',c3,'est de',T,'degres'
close(20)
end
Where the file 'titi.txt' contains:
bonjour 4 heures
temperature 37.2
The error message that appears in the console is the following:
Program received signal SIGSEGV: Segmentation fault - invalid memory
reference.
Backtrace for this error:
#0 ffffffff
I tried using the flag
-g
And than i found using the debugger that the problem is in the first line where 'read' was used
read(10,*) c1,n,c2
I really don't know how to deal with this. The code seems pretty simple to me and i have never seen this error message before, so i don't know what does it mean.
Thanks for your answers in advance.
Thank you all for your responds.
Actually what caused the problem is that i was using an old compiler. So when i downloaded the last version it all worked perfectly without changing any line in the code.
This is not an answer, but it's too much text for a comment.
It's running fine on my computer.
Can you compile it with
gfortran -g -O0 -fbacktrace -Wall -fcheck=all
That way you should get a lot more information. Also, you can add some error checking:
Add the following variables:
integer :: ios
character(len=100) :: iomsg
Then you can add error checking to all io statements like this:
read(10,*) c1,n,c2
becomes:
read(10,*,iostat=ios,iomsg=iomsg) c1,n,c2
if (ios /= 0) then
print*, "Error reading c1, n, c2:"
print*, trim(iomsg)
STOP
end if
That can also give you some hints.
I'm trying to read some data from a file, and the endfile record detection is important to stop reading. However, depending of the array dimensions of the array used to read data, I cannot detect properly the endfile record and my Fortran program stops.
The program is below:
!integer, dimension(3) :: x ! line 1.1
!integer, dimension(3,10) :: x ! line 1.2
integer, dimension(10,3) :: ! line 1.3
integer :: status,i=1
character(len=100) :: error
open( 30, file='data.dat', status='old' )
do
print *,i
!read( 30, *, iostat=status, iomsg=error ) x ! line 2.1
!read( 30, *, iostat=status, iomsg=error ) x(:,i) ! line 2.2
read( 30, *, iostat=status, iomsg=error ) x(i,:) ! line 2.3
if ( status < 0 ) then print *,'EOF'
print *,'total of ',i-1,' lines read.'
exit
else if ( status > 0 ) then
print *,'error cod: ',status
print *,'error message: ', error
stop
else if ( status == 0 ) then
print *,'reading ok.'
i = i + 1
end if
end do
With 'data.dat' file been:
10 20 30
30 40 50
When lines 1.3 and 2.3 are uncommented the mentioned error appears:
error cod: 5008
error message: Read past ENDFILE record
However, using lines 1.1 and 2.1, or 1.2 and 2.2, the program works, detecting endfile record.
So, I would like some help on understanding why I cannot use lines 1.3 and 2.3 to read properly this file, since I'm giving the correct number of array elements for read command.
I'm using gfortran compiler, version 6.3.0.
EDIT: simpler example
the following produces a 5008 "Read past ENDFILE record" error:
implicit none
integer x(2,2),s
open(20,file='noexist')
read(20,*,iostat=s)x
write(*,*)s
end
if we make x a scalar or a one-d array ( any size ) we get the expected -1 EOF flag. It doesn't matter if the file actually doesn't exist or is empty. If the file contains some, but not enough, data its hard to make sense of which return value you might get.
I am not sure if I am expressing myself correctly but it has to do with the way fortran is reading and storing 2d-arrays. When you are using this notation: x(:,i), the column i is virtually expanded in-line and the items are read using this one line of code. In the other case where x(i,:) is used, the row i is read as if you called read multiple times.
You may use implied loops if you want to stick with a specific shape and size. For example you could use something like that:read( 30, *, iostat=status, iomsg=error ) (x(i,j), j=1,3)
In any case you should check that your data are stored properly (as expected at least) in variable x.
Please note this is only a guess. Remember that Fortran stores arrays in column major order. When gfortran compiles read() x(:,i), the 3 memory locations are next to each other so in the executable, it produces a single call to the operating system to read in 3 values from the file.
Now when read() x(i,:) is compiled, the three data elements x(i,1), x(i,2) and x(i,3) are not in contiguous memory. So I am guessing the executable actually has 3 read calls to the operating system. The first one would trap the EOF but the 2nd one gives you the read past end of file error.
UPDATE: I have confirmed that this does not occur with Intel's ifort. gfortran seems to have had a similar problem before: Bad IOSTAT values when readings NAMELISTs past EOF. Whether this is a bug or not is debatable. The code certainly looks like it should trap an EOF.
I am quite new in Fortran, and just got the program from a PhD. It is used to count the number of beads in certain histograms. Here is the code:
program xrdf
implicit none
include 'currentconf.fi'
real drdf,rdf12(200)
real xni12, Zface
integer ibead,iconf,ii,io,i,j,k,linecount
integer mchains, iendbead, nstart
logical ifend
Zface=1.5
mchains=49
drdf=0.1
xni12=0.
io=10
nstart=12636
open(file='pcushion.tr.xmol',unit=io)
do i=1,200
rdf12(i)=0.0
end do
ifend=.false.
do iconf=1,1000000
! reading current frame
ii=iconf
call readconf(io,ii,linecount,ifend)
write(*,*)' conf ',iconf,' N=',n
if (ifend) go to 777
! if trajectory ended, exit loop
ibead=0
do i=1,mchains
iendbead=nstart+i*45
dz=abs(Zface-z(iendbead))
ii=int(dz/drdf)+1
rdf12(ii)=rdf12(ii)+1
xni12=xni12+1.0
end do
end do !iconf
777 write(*,*)' total ',iconf-1,' frames '
write(*,*)' r rho(z) '
do i=1,200
write(*,'(f10.4,e15.7)')(i-0.5)*drdf,rdf12(i)/xni12
end do
close(io)
stop
end
Because I really do not know which part is wrong, so I just past all the code here. When I compile this program, there comes an error:
i=int(dz/drdf)+1
1
Error: Incompatible ranks 0 and 1 in assignment at (1)
How can I edit the program to fix it?
I was able to reproduce your compiler error using a simple program. It seems likely that in
ii=int(dz/drdf)+1
you are trying to assign an array (maybe dz?) to an integer (ii).
integer ibead,iconf,ii,io,i,j,k,linecount
Compare the dimensions of ii (dimension is 1) with the dimensions of dz and drdf.
This is my program (compiled it using gfortran):
PROGRAM TEST
implicit none
integer dz(10),ii
real dy
dz=3
dy=2.0
ii=int(dz/dy)+1
END PROGRAM TEST
Using ifort the error message is more revealing:
error #6366: The shapes of the array expressions do not conform
Hey so I am trying to learn Fortran basics so that I can use it for a basic physics project. I am having trouble with getting input properly. My code is:
program main
write(*, *) "Enter n:"
read(*, *) n
print *, "Number is ", n
end program main
It is quite simple. Except that when I compile and run it, nothing happens until I enter the input in which it looks like this
gfortran num.f90 -o num
./num
(nothing happens until I type) 3
Enter n:
Number is: 3
Is there a problem with my memory allocation? Or could it be my compiler? I honestly have no clue.
Your program is fine, on my machine it prints the Enter n: before reading the variable. If you do not see the message until you enter a value (and hit Enter), it could have to do with the buffering of your command window you use. For checking this, you could just open an xterminal (type xterm in your command window), and run the program there.
I'm currently porting an application from Fortran to C and need to output some variables to compare results. I'm very new to Fortran, and although i understand the code and have now ported several thousand lines, I'm a noob at writing Fortran code myself.
This code:
write(6,'(A,I3,A,E12.8,A,E12.8,A,E12.8,A,E12.8,A,E12.8)') 'iHyd:',
& ih,'; dzdr: ',dzdr,'; tauray:', tauRay,'; zRay: ',
& zray,'; ampRay: ',realpart(aray),'+j*',
& imagpart(aray),'; qRay: ',qray,'; width :',w
Compiles fine, but when run, the program exits with:
At line 296 of file calcpr.for (unit = 6, file = 'stdout')
Fortran runtime error: Expected INTEGER for item 15 in formatted transfer, got REAL
(A,I3,A,E12.8,A,E12.8,A,E12.8,A,E12.8,A,E12.8)
^
q0: 1432.3944878270595
nArrayR: 501 nArrayZ: 201
iHyd: 1; dzdr: ************; tauray:************; zRay: ************; ampRay: NaN+j* NaN
; qRay:
Besides being really ugly, it doesn't make much sense to me, as ìh is declared as integer*8 and not as real.
So how can i solve this?
I'm counting 6 character&variable specifications in the format statement, but you're printing 8 of them.
edit:
a nicer use of the format statement would be '(A,I3,7(A,E12.8))'
Fortran "recycles" the format if there are more things to be printed than specified in the format statement. If a write statement gives results you don't understand, to diagonose the problem it may be helpful to remove the things printed one at a time until the error goes away.
It says "item 15", which I would take to be down near the end of your list, not ih at the beginning. It's clear that both "w" and "qray" are being printed as REAL; is either one of them an INTEGER? You may need to change the format specifier then.