Add a condtion for specfic row length in a script - if-statement

Question

I want to modify the following script:
awk 'NR>242 && $1 =='$t' {print $4, "\t" '$t'}' test.txt > file
I want to add a condition for the first "1 to 121" data (corresponding to the first 121 points) and then for the "122 to 242" data (which corresponds to the other 121 points).
so it becomes:
when NR>242 take the corresponding values of rows form 1 to 121 print them to file1
when NR>242 take the corresponding values of rows form 121 to 242 print them to file2
Thanks!

Answer 1

Generic solution: Adding more generic solution here, where you could give all line numbers inside lines variable of awk program. Once line number matches with values it will increase counter of file with 1 eg: from file1 to file2 OR file2 to file3 and so on...
awk -v val="$t" -v lines="121,242" -v count=1'
BEGIN{
num=split(lines,arr,",")
for(i=1;i<=num;i++){
line[arr[i]]
outputfile="file"count
}
}
FNR in arr[i]{
close(outputfile)
outputfile="file"++count
}
($1 == val){
print $4 "\t" val > (outputfile)
}
' Input_file
With your shown samples, please try following. This will print all lines from 1st line to 242nd line to file1 and 243 line onwards it will print output to file2. Also program has a shell variable named t passed into awk program's variable named val here.
awk -v val="$t" '
FNR==1{
outputfile="file1"
}
FNR==243{
outputfile="file2"
}
($1 == val){
print $4 "\t" val > (outputfile)
}
' Input_file

Answer 2

$ awk -v val="$t" '{c=int((NR-1)%242/121)+1}
$1==val {print $4 "\t" $1 > (output"c")}' file
this should take the first, third, etc blocks of 121 records to output1 and second, fourth, etc blocks of 121 records to output2 if they satisfy the condition.
If you want to skip first two blocks (first 242 records) just add && NR>242 condition to the existing one.