I am new to regex and having difficulty obtaining values that are caught in between spaces.
I am trying to get the values "field 1" "abc/def try" from the sameple data below just using regex
Currently im using (^.{18}\s+) to skip the first 18 characters, but am at at loss of how to do grab values with spaces between.
A1234567890 field 1 abc/def try
02021051812 12 test test 12 pass
3333G132021 no test test cancel
any help/pointers will be appreciated.
If this text has fixed-width columns, you can match and trim the column values knowing the amount of chars between start of string and the column text.
For example, this regex will work for the text you posted:
^(.*?)\s*(?<=.{19})(.*?)\s*(?<=^.{34})(.*?)\s*(?<=^.{46})
See the regex demo.
So, Column 2 starts at Position 19, Column 3 starts at Position 34 and Column 4 (end of string here) is at Position 46.
However, this regex is not that efficient, and it would be really great if the data format is fixed on the provider's side.
Given the not knowing if the data is always the same length I created the following, which will provide you with a group per column you might want to use:
^((\s{0,1}\S{1,})*)(\s{2,})((\s{0,1}\S{1,})*)(\s{2,})((\s{0,1}\S{1,})*)
Regex demo
Related
I have a small issue, I am trying to get specific characters from a long string using regex but I am having trouble.
Workflow
Prometheus --> Grafana --> Variable (using regex)
I can't use anything other than Regex expressions to achieve this result
I am currently using this expression to grab the long string from some json output:
.*channel_id="(.*?)".*
FROM THIS
{account_id="XXXXXXX-xxxx-xxxx-xxxx-xxxxxxxxxx",account_name="testalpha",channel_id="s0022110430col0901241usa",channel_abbr="s0022109430col}
This returns a string that's ALWAYS 24 characters long:
s0022110430col0901241usa
PROBLEM:
I need to grab the 3 letters 'col' and 'usa' as they are the two teams that are playing, ideally I would be able to pipe the results from the first regex to get these values (the position is key, since the first value will ALWAYS be the 12-14th characters and the second value is the last 3 characters) if I could output these values in uppercase with the string "vs" in between to create a string such as:
COL vs USA
or
ARG vs BRA
I am open to any and every suggestion anyone may have
Thank you!
PS - The uppercase thing is 'nice to have' BUT not needed
I'm still learning RegEx, so this is all I could come up with:
For the col (first team):
(?<=(channel_id=".{11}))\w{3}
For the usa (second team):
(?<=(channel_id=".{21}))\w{3}
Can you define the channel_id?
It begins with 's' and then there are many numbers. If they are always numbers, you can use this regex:
channel_id=".[0-9]+([a-z]+)[0-9]+([a-z]+)
You will get 2 groups, one with "col" and the other with "usa".
Edit:
Or if you just know, that you have always the same size, you can use something like:
channel_id=".{11}([a-z]+).{7}([a-z]+)
I'm having trouble trying to regex extract the 'positions' from the following types of strings:
6 red players position 5, button 2
earn $50 pos3, up to $1,000
earn $50 pos 2, up to $500
table button 4, before Jan 21
I want to get the number that comes after 'pos' or 'position', and if there's no such keyword, get the last number before the first comma. The position value can be a number between 1 and 100. So 'position' for each of the previous rows would be:
Input text
Desired match (position)
6 red players position 5, button 2
5
earn $50 pos3, up to $1,000
3
earn $50 pos 2, up to $500
2
table button 4, before Jan 21
4
I have a big data set (in BigQuery) populated with basically those 4 types of strings.
I've already searched for this type of problem but found no solution or point to start from.
I've tried .+?(?=,) (link) which extracts everything up to the first comma (,), but then I'm not sure how to go about extracting only the numbers from this.
I've tried (?:position|pos)\s?(\d) (link) which extracts what I want for group 1 (by using non-capturing groups), but doesn't solve the 4th type of string.
I feel like there's a way to combine these two, but I just don't know how to get there yet.
And so, after the two things I've tried, I have two questions:
Is this possible with only regex? If so, how?
What would I need to do in SQL to make my life easier at getting these values?
I'd appreciate the help/guidance with this. Thanks a ton!
You can use
^(?:[^,]*[^0-9,])?(\d+),
See the RE2 regex demo. Details:
^ - start of string
(?:[^,]*[^0-9,])? - an optional sequence of:
[^,]* - zero or more chars other than comma
[^0-9,] - a char other than a digit and comma
(\d+) - Group 1: one or more digits
, - a comma
Use look ahead for a comma, with a look behind requiring the previous char to be a space or a letter to prevent matching the “1” in “$1,000”:
(?<=[ a-z])(\d+)(?=,)
See live demo.
I am trying to split a string (the string length is uncertain; it could be 500 characters or 1500 characters) into multiple columns, and each column should only contain 5 characters.
For example,
If column A contains the string:
AAGANAB5ARAB7AAAB9AAAC--CAC--1ACMRD
Then, I need Column B to Column H to be:
AAGAN,
AB5AR,
AB7AA,
AB9AA,
AC--C,
AC--1,
ACMRD
Also, the string contains “-“, but it is NOT delimiter. It should also be counted as a part of 5 char strings.
I know RegEx is probably the function I should use, and just by putting "(.....)" in the Regular Expression, Alteryx can extract the first 5 characters. But I don't know how to ask Alteryx to automatically split the entire string (length varies each row) to columns of 5 chars.
In Alteryx, use their RegEx tool (instead of the Formula tool with one of their REGEX expressions). In the config panel of the RegEx tool, and simply enter ..... as the RegEx, and the key is to select "Split to Rows"... this will give you rows with a new field that is the result of the applied RegEx.
I have a huge mongoDB containing documents on which I am using a name as index.
So basically, I had a text file containing 48 000 016 entries. (I use wc -l to obtain that count)
To give more context, the database contains a lot of names that we're extracted from OCR (so a lot of junk) and also names in other languages (Japanese, Russian, etc...).
My MongoDB table statistics tell me I have 48 000 016 which is fine.
The problem happens because I want to query the items on their names (which is a standard string) using this regex :
/^([A-Z]|\W|\s|\d|_)/i
So my checklist :
any letter - check
case insensitive - check
any number - check
underscore - check
\W for anything that is not a number, letter or underscore.
So from what I understand, this regex should get me everything, since I am querying database on string values with this regex. But the problem is that I am missing 5 items.
When I run the count on the result of the query, I have 48 000 011 items.
Any idea where these 5 ones could be ? Because of the nature of my problem I can simply go through all my items using a simple cursor, I know it could be done that way, but I need a regex that can retrieve all my values.
I ran this query on the Database as indicated by the comments.
db.name.aggregate({$group:{_id:"uniqueDocs", count:{$sum:1}}})
Result is :
{ "result" : [ ], "ok" : 1 }
Thanks a lot !
I have seen you are using the anchor ^ to match the beginnig of a line. It could be possible that the line start with an new line \n or carriage return character \r.
Try to include \n and \r to your regex
/^([A-Z]|\W|\s|\d|\r|\n|_)/i
Also check to remove the anchor.
/([A-Z]|\W|\s|\d|\r|\n|_)/i
At last option inverse your regex to see which records are not included. These regex expressions should also math empty strings.
/^(?![.*])/i
I want to thank #Paul Wasilewski for giving me some great solutions. I found my problem which was not related to a regex problem.
My 5 entries we're simply not indexed, their size was more than 1024 bytes in length so MongoDB could not index them.
So that's the reason why they could not be queried by regex.
I am trying to extract a specific text from an Outlook subject line. This is required to calculate turn around time for each order entered in SAP. I have a subject line as below
SO# 3032641559 FW: Attached new PO 4500958640- 13563 TYCO LJ
My final output should be like this: 3032641559
I have been able to do this in MS excel with the formulas like this
=IFERROR(INT(MID([#[Normalized_Subject]],SEARCH(30,[#[Normalized_Subject]]),10)),"Not Found")
in the above formula [#[Normalized_Subject]] is the name of column in which the SO number exists. I have asked to do this in oracle but I am very new to this. Your help on this would be greatly appreciated.
Note: in the above subject line the number 30 is common in every subject line.
The last parameter of REGEXP_SUBSTR() indicates the sub-expression you want to pick. In this case you can't just match 30 then some more numbers as the second set of digits might have a 30. So, it's safer to match the following, where x are more digits.
SO# 30xxxxxx
As a regular expression this becomes:
SO#\s30\d+
where \s indicates a space \d indicates a numeric character and the + that you want to match as many as there are. But, we can use the sub-expression substringing available; in order to do that you need to have sub-expressions; i.e. create groups where you want to split the string:
(SO#\s)(30\d+)
Put this in the function call and you have it:
regexp_substr(str, '(SO#\s)(30\d+)', 1, 1, 'i', 2)
SQL Fiddle