How to simplify multiple if else statement using Java - regex

Question

I've use-case where I've to validate two inputs and return success/failed in responses.
Please find my code below, I feel I'm using too many if-else statements - how can we simplify this?
I've to check given string is null or not, then check if matches the pattern - then return success or failure based on below given conditions:
public class Main {
public static void main(String[] args) {
// Scenario 1: -> Return Success
String input1 = "bearer sDjdESddfEsdfdfwere2sEDaa2SmnsSkeew";
String input2 = "bearer kiIkdqAplMNbeieW3dJKidAkdmElsEpsles";
// Scenario 2: -> Return Success
//String input1 = "bearer sDjdESddfEsdfdfwere2sEDaa2SmnsSkeew";
//String input2 = null;
// Scenario 3: -> Return Failed
//String input1 = "bearer sDjdESddfEsdfdfwere2sEDaa2SmnsSkeew";
//String input2 = "bearer ";
// Scenario 4: -> Return Failed
//String input1 = null;
//String input2 = "bearer sDjdESddfEsdfdfwere2sEDaa2SmnsSkeew";
String result = validate(input1, input2);
System.out.println("result: " +result);
}
private static String validate(String input1, String input2) {
Pattern pattern = Pattern.compile("^Bearer (?<token>[a-zA-Z0-9-._~+/]+)=*$", Pattern.CASE_INSENSITIVE);
String status ="failed";
if (input1 != null && input2 != null) {
if (StringUtils.startsWithIgnoreCase(input1, "bearer")
&& StringUtils.startsWithIgnoreCase(input2, "bearer")) {
if (!pattern.matcher(input1).matches() || !pattern.matcher(input2).matches()) {
System.out.println("Pattern not match");
// throw exception here
}
status = "success";
}
} else if (input1 != null) {
if (StringUtils.startsWithIgnoreCase(input1, "bearer")) {
if (!pattern.matcher(input1).matches()) {
System.out.println("Pattern not match");
// throw exception here
}
status = "success";
}
}
return status;
}
}

Answer 1

You can group the ifs related to the same input
if (input1 != null) {
if (StringUtils.startsWithIgnoreCase(input1, "bearer")) {
// INTO
if (input1 != null && StringUtils.startsWithIgnoreCase(input1, "bearer")) {
And include the tests about input2 inside the if for input1
Final code
private static String validate(String input1, String input2) {
Pattern pattern = Pattern.compile("^Bearer (?<token>[a-zA-Z0-9-._~+/]+)=*$", Pattern.CASE_INSENSITIVE);
String status = "failed";
if (input1 != null && StringUtils.startsWithIgnoreCase(input1, "bearer")) {
if ((input2 != null && StringUtils.startsWithIgnoreCase(input2, "bearer") && !pattern.matcher(input2).matches())
|| !pattern.matcher(input1).matches()) {
System.out.println("Pattern not match");
// throw exception here
} else {
status = "success";
}
}
return status;
}