I have implemented quick sort in c++. Following is my code .
#include <iostream>
using namespace std;
template <typename T>
void swap(T *a, T *b)
{
T temp;
temp = *a;
*a = *b;
*b = temp;
}
template <typename T>
void PrintArray(T arr[], int n)
{
cout << "---------- Array ----------" << endl;
for (int i=0; i<n ; i++)
{
cout << arr[i] <<'\t';
}
cout << endl;
}
template <typename T>
int partition(T arr[], int low, int high)
{
T pivot = arr[low];
int i = low+1, j = high;
do
{
while (pivot >= arr[i])
{
i += 1;
}
while (pivot < arr[j])
{
j -= 1;
}
if (i<j)
{
swap<T>(arr[i], arr[j]);
}
}while( i < j);
swap<T>(arr[low], arr[j]);
return j;
}
template <typename T>
void quick_sort(T arr[], int low, int high)
{
if (low < high)
{
int parition_index;
parition_index = partition<T>(arr, low, high);
quick_sort<T>(arr, low, parition_index-1);
quick_sort<T>(arr, parition_index+1, high);
}
}
int main()
{
// Array creation
int n = 8;
int a[] ={4, 3,2, 1, 18, -1, 89, -200};
// Array sorting
quick_sort<int>(a,0, n);
PrintArray<int>(a, n);
return 0;
}
It gives sorted array i.e -200, -1, 1, 2, 3, 4, 18, 89 most of the times. However, re-running the code may gives garbage values at some indices (for ex: -968225408, -200, -1, 1, 2, 3, 4, 18). To check, I replaced all the functions in the code above with the functions from blocks in the post https://www.geeksforgeeks.org/quick-sort/ . Nonetheless, the problem persists.
What could be the problem with the code and what is the solution to the problem.
#FrançoisAndrieux comments were very useful in finding out the problem.
As he pointed out that j is taking 8 as value which is out of bounds.
To solve the problem
step 1: quick_sort<int>(a,0, n-1); in the int main().
steps 2: knock off the custom swap function
Related
I'm currently trying to learn Quick Sort, and here is my code:
#include<iostream>
#include<vector>
#include<cmath>
using namespace std;
void swap(int *a, int *b)
{
int t = *a;
*a = *b;
*b = t;
}
int partition(vector<int> &A, int low, int high)
{
int pivot = A[low];
int i = low;
int j = high;
while(i < j){
do
{
i++;
}while(A[i]>=pivot);
do
{
j--;
}while(A[j]<pivot);
if(i < j)
{
swap(A[i], A[j]);
}
}
swap(A[low], A[j]);
return j;
}
void QuickSort(vector<int> &A, int low, int high)
{
int j = partition(A, low, high);
QuickSort(A, low, j);
QuickSort(A, j+1, high);
}
int main()
{
vector<int> A{-7, 11, -3, 3, 2};
QuickSort(A, 0, A.size()-1);
for(int i:A)
{
cout << i << endl;
}
}
after the code ran, I keep getting Segmentation fault (core dumped), how do I fix this error.
also, could any one recommend a good c++ debugger. thank you so much
You have infinite recursion in your QuickSort function. Whenever it gets called, it'll call itself and there is no condition there to break the cycle.
Also, your swap function does not work. As it is written, the values in the A bins will be supplied to the function and interpreted as addresses. That should not compile. The only reason why it does compile is that you don't use that function in your program. You are using std::swap because you've done using namespace std;, so don't do that.
Your swap function should take the arguments by reference and you need to add a condition in the QuickSort function.
I wasn't sure exactly which partitioning scheme you tried implementing so I made some changes to make it work in accordance with the Hoare partition scheme.
#include <iostream>
#include <vector>
void swap(int& a, int& b) { // take arguments by reference
int t = a;
a = b;
b = t;
}
size_t partition(std::vector<int>& A, size_t low, size_t high) {
int pivot = A[(high + low) / 2];
size_t i = low;
size_t j = high;
while(true) {
while(A[i] < pivot) ++i;
while(A[j] > pivot) --j;
if(i >= j) return j;
swap(A[i], A[j]);
++i;
--j;
}
}
void QuickSort(std::vector<int>& A, size_t low, size_t high) {
if(low < high) { // added condition
size_t j = partition(A, low, high);
QuickSort(A, low, j);
QuickSort(A, j + 1, high);
}
}
int main() {
std::vector<int> A{-7, 11, -3, 3, 2};
QuickSort(A, 0, A.size() - 1);
for(int i : A) {
std::cout << i << '\n';
}
}
Like the title says, I am trying to write a code for QuickSort, but I am trying to do this following a psuedocode given to us in the lecture. This isn't an assignment that's due it's just me trying to figure it out on my own. I've found a sample of QuickSort online, but it looks different than what our psuedocode says. The QuickSort code i found online uses pointers, i don't think pointers are mentioned in the given psuedocode. In other words, could someone check if im on the right path and maybe point out where I messed up. Thank you!
My code
#include <iostream>
using namespace std;
int Partition(int arr[], int p, int r)
{
int x = arr[r];
int i = p - 1;
for (int j = p; j < r - 1; j++)
{
if (arr[j] <= x)
{
i = i + 1;
swap(arr[i], arr[j]);
}
swap(arr[i + 1], arr[r]);
}
return i + 1;
}
void Quicksort(int arr[], int p, int r)
{
if (p < r)
{
int k = Partition(arr, p, r);
Quicksort(arr, p, k - 1);
Quicksort(arr, k + 1, r);
}
}
void print(int arr[], int n)
{
int i;
for (i = 0; i < n; i++)
{
cout << arr[i] << " ";
}
}
int main()
{
int arr[] = { 5, 3, 4, 9, 10 };
int n = sizeof(arr) / sizeof(arr[0]);
Quicksort(arr, 0, n);
print(arr, n);
//I get an error here "Stack around the variable 'arr' was corrupted"
}
This is the psuedocode for my QuickSort function
Picture number two is the given psuedocode for my Partition function
In Partition(), if i is never incremented, then a swap(arr[p-1], ...) is done, probably the cause of the stack error. Normally, quick sort parameters are first and last index, as opposed to first and end (= last+1) index, in this case, Quicksort(arr, 0, n-1). The inner loop is looking for values < pivot (not <= pivot). The final swap needs to be done after the for loop. Fixes noted in comments.
#include <iostream>
using namespace std;
int Partition(int arr[], int p, int r)
{
int x = arr[r];
int i = p; // fix
for (int j = p; j < r; j++) // fix
{
if (arr[j] < x) // fix
{
swap(arr[i], arr[j]);
i = i + 1; // fix
}
}
swap(arr[i], arr[r]); // fix
return i; // fix
}
void Quicksort(int arr[], int p, int r)
{
if (p < r)
{
int k = Partition(arr, p, r);
Quicksort(arr, p, k - 1);
Quicksort(arr, k + 1, r);
}
}
void print(int arr[], int n)
{
int i;
for (i = 0; i < n; i++)
{
cout << arr[i] << " ";
}
}
int main()
{
int arr[] = { 5, 3, 4, 9, 10 };
int n = sizeof(arr) / sizeof(arr[0]);
Quicksort(arr, 0, n-1); // fix
print(arr, n);
return 0; // fix
}
I have written a quick sort code and logic seem pretty correct but there is no output on the console.
when only index function runs the output is correct and also the output loop is correct but when quicSort function is added then there is no output.
#include <iostream>
using namespace std;
int index(int* a, int s, int e) {
int i, j, start, piv, temp;
start = s;
piv = a[e];
for (i = start; i <= e; i++) {
if (a[i] <= piv) {
temp = a[i];
a[i] = a[start];
a[start] = temp;
start++;
}
}
return start;
}
void quickSort(int* a, int s, int e) {
int pivot;
if (s < e) {
pivot = index(a, s, e);
quickSort(a, s, pivot - 1);
quickSort(a, pivot + 1, e);
}
}
int main() {
int A[] = {2, 5, 8, 3, 6, 9, 1, 4};
quickSort(A, 0, 7);
for (int i = 0; i < 8; i++) {
cout << A[i];
}
return 0;
}
the output should be sorted array
Code needs two fixes. Changes noted in comments:
#include <iostream>
using namespace std;
int index(int* a, int s, int e) {
int i, start, piv; // j, temp not used
start = s;
piv = a[e];
for (i = start; i <= e; i++) {
if (a[i] < piv) { // fix (not <=)
swap(a[i], a[start]); // simplify
start++;
}
}
swap(a[start], a[e]); // fix (swap pivot into place)
return start;
}
void quickSort(int* a, int s, int e) {
int pivot;
if (s < e) {
pivot = index(a, s, e);
quickSort(a, s, pivot - 1);
quickSort(a, pivot + 1, e);
}
}
int main() {
int A[] = {2, 5, 8, 3, 6, 9, 1, 4};
quickSort(A, 0, 7);
for (int i = 0; i < 8; i++) {
cout << A[i] << " "; // put space beteen numbers
}
cout << endl;
return 0;
}
I think you get confused by bubblesort when creating your quicksort program.
The quicksort ideia is to break the vector in smaller vectors one with the numbers bigger than the pivot e another with the numbers smaller than the pivot.
You should round up your code in C++ data structures like vectors.
One example is, with c++11:
#include <stdio.h>
#include <stdlib.h>
#include <iostream>
#include <numeric>
#include <vector>
using namespace std;
vector<int> quicksort(vector<int> data) {
if (data.size() == 1) return data;
vector<int> small_numbers;
vector<int> big_numbers;
vector<int> ret;
float pivot = accumulate(data.begin(), data.end(), 0.0) / data.size();
for (int value : data) {
if (value < pivot) {
small_numbers.push_back(value);
} else {
big_numbers.push_back(value);
}
}
if (small_numbers.empty()) return big_numbers;
small_numbers = quicksort(small_numbers);
big_numbers = quicksort(big_numbers);
ret.insert(ret.end(), small_numbers.begin(), small_numbers.end());
ret.insert(ret.end(), big_numbers.begin(), big_numbers.end());
return ret;
}
int main() {
vector<int> A({2, 5, 8, 3, 6, 9, 1, 4});
A = quicksort(A);
for (int value : A) cout << value << endl;
return 0;
}
This example break the the vector into two vectors, the pivot is the mean value of the values of vector. It calls the function recursively until it calls a vector with the size of 1 element.
Hope it push you to a less complicated way of see quicksort.
I have a small program below:
#include <iostream>
#include <time.h>
using namespace std;
void changeArray(int *a, int n)
{
swap(a[rand() % n], a[rand() % n]);
}
void Try(int* a, int n, int step)
{
if (step > n)
return;
changeArray(a, n);
Try(a, n, step + 1);
//Do something to recovery previous array data?
}
void printArr(int *a, int n)
{
for (int i = 0; i < n; ++i)
cout << a[i] << " ";
cout << endl;
}
int main()
{
srand(time(NULL));
int a[] = { 1, 2, 3, 4, 5 };
int step = 0;
int n = sizeof(a) / sizeof(int);
printArr(a, n); //Before
Try(a, n, 0);
printArr(a, n); //After recursion
// Expected array is : 1,2,3,4,5
return 0;
}
The problem is a as follows: can I recover previously created data? Line 17 will recover an array after Try() function is run on line 16.
The resulting, line 36, array will be 1,2,3,4,5.
Any ideas would be really appreciated! Thank you!
How do I sort an array without using a loop in C++? I think it might use recursion, but I do not know how to implement it.
Use std::sort defined in algorithm header file
#include <iostream>
#include <algorithm>
using namespace std;
int main()
{
int a[]={5,3,4,1,2};
sort(a,a+5);
for(int i=0;i<5;i++)
cout<<a[i]<<" "; // 1 2 3 4 5
return 0;
}
//C++
void bubblesort(vector<int> &arr, int iteration) {
if(iteration == 0)
return;
bubbleswap(arr, 0, 1, iteration);
bubblesort(arr, iteration-1);
}
void bubbleswap(vector<int> &arr, int i, int j, int n) {
if(j>=n)
return ;
if(arr[i] < arr[j]){
swap(arr[i], arr[j]);
}
bubbleswap(arr, i+1, j+1, n);
}
void sort(vector<int> &arr) {
int n = arr.size();
if(n<=1)
return ;
bubblesort(arr, n);
}
Recursive Selection Sort
#include <iostream>
#include <vector>
using namespace std;
//----------------------------------------------------------
int recursive_min(vector<int>& a, size_t first) {
//base case
if (first + 1 >= a.size()) {
return first;
}
else {
size_t min_index {first};
int temp_index {recursive_min(a, first + 1)};
if (a[min_index] > a[temp_index]) {
min_index = temp_index;
}
return min_index;
}
}
//----------------------------------------------------------
void selectionSort(vector<int>& a, size_t step = 0) {
//base case
if (step + 1 >= a.size()) {
return;
}
else {
int temp_index {recursive_min(a, step + 1)};
if (a[step] > a[temp_index]) {
swap(a[step], a[temp_index]);
}
selectionSort(a, step + 1);
}
}
//---------------------------------------------------------
int main() {
vector<int> vec {11, 23, 2, 50, 3, 8, 1, 4, 5};
selectionSort(vec);
for (int i : vec) {
cout << i << " ";
}
}
Recursive Insertion Sort
#include <iostream>
#include <vector>
using namespace std;
int recursive_insert(vector<int>& a, int key, int i) {
//base case
if (i <= -1 || a[i] <= key) {
return i;
}
else {
a[i + 1] = a[i];
return recursive_insert(a, key, i - 1);
}
}
//-----------------------------------------------------------------------------
void insertion_sort(vector<int>& a, size_t j = 1) {
//base case
if (j >= a.size()) {
return;
}
else {
int key = a[j];
int i = recursive_insert(a, a[j], j - 1);
a[i + 1] = key;
insertion_sort(a, j + 1);
}
}
//-----------------------------------------------------------------------------
int main() {
vector<int> vec {11, 23, 2, 50, 3, 8, 1, 4, 5};
insertion_sort(vec);
for (int i : vec) {
cout << i << " ";
}
}
#include<stdio.h>
int * sort(int *p,int i,int j,int size)
{
if(i<size)
{
if(j<size-i-1)
{
if(p[j]>p[j+1])
{
int temp = p[j];
p[j] = p[j+1];
p[j+1] = temp;
}
}
else
{
j=-1;
++i;
}
p = sort(p,i,++j,size);
}
return p;
}
Below is how to use it
int main()
{
int array[] ={1,5,2,7,3};
int len = sizeof(array)/sizeof(int);
int *a = sort(array,0,0,len);
for(int i=0;i<len;i++)
{
printf("\n array[%d]->%d",i,a[i]);
}
}
I think you are looking for the Quicksort Algorithm
There are more ways to sort an array.
If you are trying to implement a loop recursively, you can check out a wikipedia article. It is well explained under "Recursion computer science".
Otherwise you can try to implement different sorting algorithms. The well known are Quicksort and Mergesort.
There are many sorting algorithms
Well, I'm writing a Python interpreter and didn't write loop yet. I got the codebase from some website and rewrite the loop by some recursion. It works. :D
def quickSort(arr, low, high):
def jLoop(low, high, pivot, i, j):
if j >= high:
temp = arr[high]
arr[high] = arr[i+1]
arr[i+1] = temp
return (i+1)
else:
if arr[j] <= pivot:
i = i+1
temp = arr[i]
arr[i] = arr[j]
arr[j] = temp
return jLoop(low, high, pivot, i, j+1)
def partition(low, high):
i = (low - 1)
pivot = arr[high]
return jLoop(low, high, pivot, i, low)
def quick(low, high):
if low < high:
pi = partition(low, high)
quick(low, pi-1)
quick(pi+1, high)
quick(low, high)
return arr
my_list = [0, 6, 3, 1, 2, 4, 7, 5]
length = 8
print quickSort(my_list, 0, 7)
my_list = [9, 0, 8, 1, 7, 2, 6, 3, 5, 4]
length = 10
print quickSort(my_list, 0, 9)