I feel like this should be very simple, and I'm missing a single, important bit.
Example: https://regex101.com/r/lXh5Vj/1
Regex, using /m/g flags:
^GROUPS.*?"(?<name>[^:]+):(?<id>\d+)"
Test string:
GROUPS: ["group1:44343", "group2:23324", "group3:66567"]
USERS: ["user1:44343", "user2:23324", "user3:66567"]
My current regex will only match group1, because only that group is directly preceded by "GROUPS". I interpret this as "Global matching" meaning it will only start to check the string again after the first match. As there is no "GROUPS" between group1 and group2, group2 is not a match. If I alter the test string and add "GROUPS" before group2, this will also match, supporting my suspicion. But I do not know how to alter global matching handling to always consider the start of the line GROUPS.
The Regex should match 3 and 3 in the first line, and none in the second. If I remove the "GROUPS" part from the regex, the groups are matched just fine, but then also match the second line, which I do not want.
If you want to match GROUPS: [" at the start of the string, and the key:value parts in named groups, you can make use of the \G anchor.
(?:^GROUPS:\h*\["(?=[^][]*])|\G(?!^),\h*")(?<name>[^:]+):(?<id>\d+)"
(?: Non capture group
^GROUPS:\h*\[ Start of string, Match GROUPS: optional spaces and [
"(?=[^][]*]) Match " and assert a closing ] at the right
| Or
\G(?!^),\h*" Assert the position at the end of the previous match (to get consecutive groups) and match a comma, optional spaces and "
) Close non capture group
(?<name>[^:]+) Named group name Match 1+ times any char except :
: Match literally
(?<id>\d+) Named group id, match 1+ digits
" Match literally
Regex demo
Related
For example I want to match three values, required text, optional times and id, and the format of id is [id=100000], how can I match data correctly when text contains spaces.
my reg: (?<text>[\s\S]+) (?<times>\d+)? (\[id=(?<id>\d+)])?
example source text: hello world 1 [id=10000]
In this example, all of source text are matched in text
The problem with your pattern is that matches any whitespace and non whitespace one and unlimited times, which captures everything without getting the other desired capture groups. Also, with a little help with the positive lookahead and alternate (|) , we can make the last 2 capture groups desired optional.
The final pattern (?<text>[a-zA-Z ]+)(?=$|(?<times>\d+)? \[id=(?<id>\d+)])
Group text will match any letter and spaces.
The lookahead avoid consuming characters and we should match either the string ended, or have a number and [id=number]
Said that, regex101 with further explanation and some examples
You could use:
:\s*(?<text>[^][:]+?)\s*(?<times>\d+)? \[id=(?<id>\d+)]
Explanation
: Match literally
\s* Match optional whitespace chars
(?<text> Group text
[^][:]+? match 1+ occurrences of any char except [ ] :
) Close group text
\s* Match optional whitespace chars
(?<times>\d+)? Group times, match 1+ digits
\[id= Match [id=
(?<id>\d+) Group id, match 1+ digirs
] Match literally
Regex demo
For example, let's say I have a list of words:
words.txt
accountable
accountant
accountants
accounted
I want to match "accountant\naccountants"
I've tried /(\n\w+){2}s/, but \w+ seems to be perfectly matching different things.
My RegEx also matches the following undesirable texts:
action
actionables
actionable
actions
Am I reaching out too far in what regex can do?
You could for example use a capture group, and match a newline followed by a backreference to the same captured text and an s char.
If the first word can also be at the start of the string, instead of being preceded by a newline, you can use an anchor ^ instead.
^(\w+)\n\1s$
^ Start of string
(\w+) Capture group 1, match 1+ word chars
\n\1s Match a newline, backreference \1 to match the same text as group 1 and an s char
$ End of string
Regex demo
I want to match everything where .com or my\s?example appears in the display name of a From header and where the From email address is not .*#myexample.com.
It's easy when the display name is enclosed by quotation marks, but fails when the quotation marks are absent.
"(.*?(my\s?example|\.com).*?)"(?!\s?\<.*?\#myexample\.com\>)
Please see here:
https://regexr.com/5im6l
Everything works as desired except for the last line in the input field, where the double quotes are missing. I would like it to also match for this.
If an if clause is supported, and you want to capture what is between the double quotes if they are both there or capture the whole string if there are no double quotes at the start and end, you might use:
\bFrom:\s(")?(.*?\b(my\s?example|\.com)\b.*?)(?(1)")\s+<(?!\s?[^\r\n<>]*#myexample\.com>)
The pattern matches:
\bFrom:\s(")? A word boundary, match From: and optionally capture " in group 1
(.*?\b(my\s?example|\.com)\b.*?) Capture group 2, match a part that contains either myexample or .com where the alternatives are in group 3
(?(1)") If clause, if group 1 exists, match " so it is not part of the capture group
\s+< Match 1+ whitespace chars and <
(?! Negative lookahead, assert that what is at the right is not
\s?[^\r\n<>]*#myexample\.com> Match #myexample\.com between the brackets
) Close lookahead
Group 2 contains the whole match, and group 3 contains a part with either Myexample or .com using a case insensitive match.
Regex demo
If \K is supported to forget what is matched so far, and you want as another example a match only:
\bFrom:\s"?\K.*?\b(?:my\s?example|\.com)\b.*?(?="?\s<(?![^<>]*#myexample\.com>))
Regex demo
Note that you don't have to escape \< \> and \#
I have the below string
abc-12d-ef-oy-5678-xyz--**--20190120075439322am--**--ghi-66d-ef-oy-8877-sdf--**--sfdfdsgfg--**--20190120075765487am
It is kind of multi character delimited string, delimited by '--**--' I am trying to extract the first and second words which has the -oy- tag in it. This is a column in a table. I am using the regex_extract method but i am not able extract the string which contains a string and ends with a string.
Here is one pattern that i tried .*(.*oy.*)--
If the -oy- can not be at the start or at the end, you could use this pattern to match the 2 hyphen delimited strings with -oy-:
[a-z0-9]+(?:-[a-z0-9]+)*-oy(?:-[a-z0-9]+)+
Regex details
[a-z0-9]+ Match 1+ times a-z0-9
(?: Non capturing group
-[a-z0-9]+ Match - and 1+ times a-z0-9
)* Close group and repeat 0+ times
-oy Match literally
(?:-[a-z0-9]+)+ Repeat 1+ times a group which will match - and 1+ times a-z0-9
You can extend the character class [A-Za-z0-9] to allow what you want to match like uppercase chars.
Regex demo | Java demo
If the matches should be between delimiters, you could use a positive lookbehind and positive lookahead and an alternation:
(?<=^|--\\*\\*--)[a-z0-9]+(?:-[a-z0-9]+)*-oy(?:-[a-z0-9]+)+(?=--\\*\\*--|$)
See a Java demo
You can use this regex which will match string containing -oy- and capture them in group1 and group2.
^.*?(\w+(?:-\w+)*-oy-\w+(?:-\w+)*).*?(\w+(?:-\w+)*-oy-\w+(?:-\w+)*)
This regex basically matches two strings delimiter separated containing -oy- using this (\w+(?:-\w+)*-oy-\w+(?:-\w+)*) to capture the text.
Demo
Are you able to select values from capture groups?
(?:--\*\*--|^)(.*?-oy-.*?)(?:--\*\*--|$)
?: - Non-capture group, matches the delimiter, begin of line, or end of line but does not create a capture group
*? - Lazy match so you only grab the contents of the field
https://regex101.com/r/aUAvcx/1
--- Second stab at this follows ---
This is convoluted. Hopefully you can use Lookahead and Lookbehind. The last problem I had was the final record was being "Greedy" and sucking up the field before it too. So I had to add an exclusion in the capture group for your delimiter.
See if this works for you.
(?<=--\*\*--|^)((?:(?:(?!--\*\*--).)*)-oy-(?:(?:(?!--\*\*--).)*))(?=--\*\*--|$)
https://regex101.com/r/aUAvcx/3
Basically the (?: are so we are not getting too many capture groups to work with.
There are three parts to this:
The lookbehind - Make sure the field is framed by the delimiter (or start of line)
The capture group - Grab the contents of the field, making sure a delimiter isn't sucked up into it
The lookahead - Make sure the field is framed by the delimiter (or end of line)
As far as the capture group goes, I check the left and right side of the -oy- to make sure the delimiter isn't there.
Can't get why this regex (regex101)
/[\|]?([a-z0-9A-Z]+)(?:[\(]?[,][\)]?)?[\|]?/g
captures all the input, while this (regex101)
/[\|]+([a-z0-9A-Z]+)(?:[\(]?[,][\)]?)?[\|]?/g
captures only |Func
Input string is |Func(param1, param2, param32, param54, param293, par13am, param)|
Also how can i match repeated capturing group in normal way? E.g. i have regex
/\(\(\s*([a-z\_]+){1}(?:\s+\,\s+(\d+)*)*\s*\)\)/gui
And input string is (( string , 1 , 2 )).
Regex101 says "a repeated capturing group will only capture the last iteration. Put a capturing group around the repeated group to capture all iterations...". I've tried to follow this tip, but it didn't helped me.
Your /[\|]+([a-z0-9A-Z]+)(?:[\(]?[,][\)]?)?[\|]?/g regex does not match because you did not define a pattern to match the words inside parentheses. You might fix it as \|+([a-z0-9A-Z]+)(?:\(?(\w+(?:\s*,\s*\w+)*)\)?)?\|?, but all the values inside parentheses would be matched into one single group that you would have to split later.
It is not possible to get an arbitrary number of captures with a PCRE regex, as in case of repeated captures only the last captured value is stored in the group buffer.
What you may do is get mutliple matches with preg_match_all capturing the initial delimiter.
So, to match the second string, you may use
(?:\G(?!\A)\s*,\s*|\|+([a-z0-9A-Z]+)\()\K\w+
See the regex demo.
Details:
(?:\G(?!\A)\s*,\s*|\|+([a-z0-9A-Z]+)\() - either the end of the previous match (\G(?!\A)) and a comma enclosed with 0+ whitespaces (\s*,\s*), or 1+ | symbols (\|+), followed with 1+ alphanumeric chars (captured into Group 1, ([a-z0-9A-Z]+)) and a ( symbol (\()
\K - omit the text matched so far
\w+ - 1+ word chars.