SAS: proc hpbin function - sas

The data I have is
Year Score
2020 100
2020 45
2020 82
.
.
.
2020 91
2020 14
2020 35
And the output I want is
Score_Ranking Count_Percent Cumulative_count_percent Sum
top100 x y z
101-200
.
.
.
800-900
900-989
The dataset has a total of 989 observations for the same year. I want to divide the whole dataset into 10 bins but set the size to 100. However, if I use the proc hpbin function, my results get divided into 989/10 bins. Is there a way I can determine the bin size?
Also, I want additional rows that show proportion, cumulative proportion, and the sum of the scores. How can I print these next to the bins?
Thank you in advance.

Sort your data
Classify into bins
Use PROC FREQ for #/Cumulative Count
Use PROC FREQ for SUM by using WEIGHT
Merge results
Or do 3-4 in same data step.
I'm not actually sure what the first two columns will tell you as they will all be the same except for the last one.
First generate some fake data to work with, the sort is important!
*generate fake data;
data have;
do score=1 to 998;
output;
end;
run;
proc sort data=have;
by score;
run;
Method #1
Note that I use a view here, not a data set which can help if efficiency may be an issue.
*create bins;
data binned / view=binned;
set have ;
if mod(_n_, 100) = 1 then bin+1;
run;
*calculate counts/percentages;
proc freq data=binned noprint;
table bin / out=binned_counts outcum;
run;
*calculate sums - not addition of WEIGHT;
proc freq data=binned noprint;
table bin / out=binned_sum outcum;
weight score;
run;
*merge results together;
data want_merged;
merge binned_counts binned_sum (keep = bin count rename = count= sum);
by bin;
run;
Method #2
And another method, which requires a single pass of your data rather than multiple as in the PROC FREQ approach:
*manual approach;
data want;
set have
nobs = _nobs /*Total number of observations in data set*/
End=last /*flag for last record*/;
*holds values across rows and sets initial value;
retain bin 1 count cum_count cum_sum 0 percent cum_percent ;
*increments bins and resets count at start of each 100;
if mod(_n_, 100) = 1 and _n_ ne 1 then do;
*output only when end of bin;
output;
bin+1;
count=0;
end;
*increment counters and calculate percents;
count+1;
percent = count / _nobs;
cum_count + 1;
cum_percent = cum_count / _nobs;
cum_sum + score;
*output last record/final stats;
if last then output;
*format percents;
format percent cum_percent percent12.1;
run;

Related

Count the number of times record appears within a variable and apply count in a new variable

SAS - I'd like to count the number of times a record appears within a variable (Ref) and apply a count in a new variable (Count) for these.
Eg.
Ref
Count
1000
1
1001
1
2000
1
3000
1
1000
2
1000
3
What is the best way to do this?
That is what PROC FREQ is for. It will count the number of OBSERVATIONS for each value of a variable (or combination of variables).
proc freq data=have;
tables REF ;
run;
If you want the result in a dataset then use the OUT= option of the TABLES statement.
proc freq data=have;
tables REF / out=want;
run;
Managed to achive the results with the below code.
Please note - Data needs to be sorted with a PROC SORT before running this.
DATA want;
set have;
BY Variable;
IF FIRST.Variable then counter = 1
ELSE counter + 1;
RUN;
If you use the SAS hash object, you can do it with the original order intact
data have;
input Ref $;
datalines;
1000
1001
2000
3000
1000
1000
;
data want;
if _N_ = 1 then do;
dcl hash h();
h.definekey('Ref');
h.definedata('Count');
h.definedone();
end;
set have;
if h.find() ne 0 then Count = 1;
else Count + 1;
h.replace();
run;

SAS averaging into groups

Ive got 50 columns of data, with 4 different measurements in each, as well as designation tags (groups C, D, and E). Ive averaged the 4 measurements... So every data point now has an average. Now, I am supposed to take the average of all the data points averages of each specific group.
So I want all the data in group C to be averaged, and so on for D and E.... and I dont know how to do that.
avg1=(MEAS1+MEAS2+MEAS3+MEAS4)/4;
avg_score=round(avg1, .1);
run;
proc print;
run;
This is what I have so far.
There are several procedures, and SQL that can average values over a group.
I'll guess you meant to say 50 rows of data.
Example:
Proc MEANS
data have;
call streaminit(314159);
do _n_ = 1 to 50;
group = substr('CDE', rand('integer',3),1);
array v meas1-meas4;
do _i_ = 1 to dim(v);
num + 2;
v(_i_) = num;
end;
output;
end;
drop num;
run;
data rowwise_means;
set have;
avg_meas = mean (of meas:);
run;
* group wise means of row means;
proc means noprint data=rowwise_means nway;
class group;
var avg_meas;
output out=want mean=meas_grandmean;
run;
rowwise_means
want (grandmean, or mean of means)

SAS summary statistic from a dataset

The dataset looks like this:
colx coly colz
0 1 0
0 1 1
0 1 0
Required output:
Colname value count
colx 0 3
coly 1 3
colz 0 2
colz 1 1
The following code works perfectly...
ods output onewayfreqs=outfreq;
proc freq data=final;
tables colx coly colz / nocum nofreq;
run;
data freq;
retain colname column_value;
set outfreq;
colname = scan(tables, 2, ' ');
column_Value = trim(left(vvaluex(colname)));
keep colname column_value frequency percent;
run;
... but I believe that's not efficient. Say I have 1000 columns, running prof freq on all 1000 columns is not efficient. Is there any other efficient way with out using the proc freq that accomplishes my desired output?
One of the most efficient mechanisms for computing frequency counts is through a hash object set up for reference counting via the suminc tag.
The SAS documentation for "Hash Object - Maintaining Key Summaries" demonstrates the technique for a single variable. The following example goes one step further and computes for each variable specified in an array. The suminc:'one' specifies that each use of ref will add the value of one to an internal reference sum. While iterating over the distinct keys for output, the frequency count is extracted via the sum method.
* one million data values;
data have;
array v(1000);
do row = 1 to 1000;
do index = 1 to dim(v);
v(index) = ceil(100*ranuni(123));
end;
output;
end;
keep v:;
format v: 4.;
run;
* compute frequency counts via .ref();
data freak_out(keep=name value count);
length name $32 value 8;
declare hash bins(ordered:'a', suminc:'one');
bins.defineKey('name', 'value');
bins.defineData('name', 'value');
bins.defineDone();
one = 1;
do until (end_of_data);
set have end=end_of_data;
array v v1-v1000;
do index = 1 to dim(v);
name = vname(v(index));
value = v(index);
bins.ref();
end;
end;
declare hiter out('bins');
do while (out.next() = 0);
bins.sum(sum:count);
output;
end;
run;
Note Proc FREQ uses standard grammars, variables can be a mixed of character and numeric, and has lots of additional features that are specified through options.
I think the most time consuming part in your code is generation of the ODS report. You can transpose the data before applying the freq. The below example does the task for 1000 rows with 1000 variables in few seconds. If you do it using ODS it may take much longer.
data dummy;
array colNames [1000] col1-col1000;
do line = 1 to 1000;
do j = 1 to dim(colNames);
colNames[j] = int(rand("uniform")*100);
end;
output;
end;
drop j;
run;
proc transpose
data = dummy
out = dummyTransposed (drop = line rename = (_name_ = colName col1 = value))
;
var col1-col1000;
by line;
run;
proc freq data = dummyTransposed noprint;
tables colName*value / out = result(drop = percent);
run;
Perhaps this statement from the comments is the real problem.
I felt like the odsoutput with proc freq is slowing down and creating
huge logs and outputs. think of 10,000 variables and million records.
I felt there should be another way of accomplishing this and arrays
seems to be a great fit
You can tell ODS not to produce the printed output if you don't want it.
ods exclude all ;
ods output onewayfreqs=outfreq;
proc freq data=final;
tables colx coly colz / nocum nofreq;
run;
ods exclude none ;

How to sum a variable and record the total in the last row using SAS

I have a dataset looks like the following:
Name Number
a 1
b 2
c 9
d 6
e 5.5
Total ???
I want to calculate the sum of variable Number and record the sum in the last row (corresponding with Name = 'total'). I know I can do this using proc means then merge the output backto this file. But this seems not very efficient. Can anyone tell me whether there is any better way please.
you can do the following in a dataset:
data test2;
drop sum;
set test end = last;
retain sum;
if _n_ = 1 then sum = 0;
sum = sum + number;
output;
if last then do;
NAME = 'TOTAL';
number = sum;
output;
end;
run;
it takes just one pass through the dataset
It is easy to get by report procedure.
data have;
input Name $ Number ;
cards;
a 1
b 2
c 9
d 6
e 5.5
;
proc report data=have out=want(drop=_:);
rbreak after/ summarize ;
compute after;
name='Total';
endcomp;
run;
The following code uses the DOW-Loop (DO-Whitlock) to achieve the result by reading through the observations once, outputting each one, then lastly outputting the total:
data want(drop=tot);
do until(lastrec);
set have end=lastrec;
tot+number;
output;
end;
name='Total';
number=tot;
output;
run;
For all of the data step solutions offered, it is important to keep in mind the 'Length' factor. Make sure it will accommodate both 'Total' and original values.
proc sql;
select max(5,length) into :len trimmed from dictionary.columns WHERE LIBNAME='WORK' AND MEMNAME='TEST' AND UPCASE(NAME)='NAME';
QUIT;
data test2;
length name $ &len;
set test end=last;
...
run;

Summing vertically across rows under conditions (sas)

County...AgeGrp...Population
A.............1..........200
A.............2..........100
A.............3..........100
A............All.........400
B.............1..........200
So, I have a list of counties and I'd like to find the under 18 population as a percent of the population for each county, so as an example from the table above I'd like to add only the population of agegrp 1 and 2 and divide by the 'all' population. In this case it would be 300/400. I'm wondering if this can be done for every county.
Let's call your SAS data set "HAVE" and say it has two character variables (County and AgeGrp) and one numeric variable (Population). And let's say you always have one observation in your data set for a each County with AgeGrp='All' on which the value of Population is the total for the county.
To be safe, let's sort the data set by County and process it in another data step to, creating a new data set named "WANT" with new variables for the county population (TOT_POP), the sum of the two Age Group values you want (TOT_GRP) and calculate the proportion (AgeGrpPct):
proc sort data=HAVE;
by County;
run;
data WANT;
retain TOT_POP TOT_GRP 0;
set HAVE;
by County;
if first.County then do;
TOT_POP = 0;
TOT_GRP = 0;
end;
if AgeGrp in ('1','2') then TOT_GRP + Population;
else if AgeGrp = 'All' then TOT_POP = Population;
if last.County;
AgeGrpPct = TOT_GRP / TOT_POP;
keep County TOT_POP TOT_GRP AgeGrpPct;
output;
run;
Notice that the observation containing AgeGrp='All' is not really needed; you could just as well have created another variable to collect a running total for all age groups.
If you want a procedural approach, create a format for the under 18's, then use PROC FREQ to calculate the percentage. It is necessary to exclude the 'All' values from the dataset with this method (it's generally bad practice to include summary rows in the source data).
PROC TABULATE could also be used for this.
data have;
input County $ AgeGrp $ Population;
datalines;
A 1 200
A 2 100
A 3 100
A All 400
B 1 200
B 2 300
B 3 500
B All 1000
;
run;
proc format;
value $age_fmt '1','2' = '<18'
other = '18+';
run;
proc sort data=have;
by county;
run;
proc freq data=have (where=(agegrp ne 'All')) noprint;
by county;
table agegrp / out=want (drop=COUNT where=(agegrp in ('1','2')));
format agegrp $age_fmt.;
weight population;
run;