SwiftUI: How to show some toolbar buttons only for iPhone - swiftui

Question

I have a set of toolbar buttons that should be presented only if the device is iPhone (not iPad).
The following code fails with this error:
Closure containing control flow statement cannot be used with result builder 'ToolbarContentBuilder'
I do understand why it fails, but I am not be able to come up with a solution, which achieves what I need.
import SwiftUI
struct ContentView: View {
var body: some View {
NavigationView {
List {
NavigationLink(
destination: Hello(),
label: {
Text("Hello")
})
}
}
}
}
struct Hello: View {
var body: some View {
Text("Hello World")
.toolbar() {
if UIDevice.current.userInterfaceIdiom == .phone {
ToolbarItem(placement: .navigationBarTrailing) {
Button(action: {
// do something
}, label: {
Text("Button1")
})
}
ToolbarItem(placement: .navigationBarTrailing) {
Button(action: {
// do something
}, label: {
Text("Button2")
})
}
}
ToolbarItem(placement: .navigationBarTrailing) {
Button(action: {
// do something
}, label: {
Text("Button3")
})
}
}
}
}
struct ContentView_Previews: PreviewProvider {
static var previews: some View {
ContentView()
}
}
I'm happy to create a separate function to achieve it. I simply can't figure out how to do it.

Answer 1

Probably you wanted this
struct Hello: View {
var body: some View {
Text("Hello World")
.toolbar() {
ToolbarItemGroup(placement: .navigationBarTrailing) {
if UIDevice.current.userInterfaceIdiom == .phone {
Button(action: {
// do something
}, label: {
Text("Button1")
})
Button(action: {
// do something
}, label: {
Text("Button2")
})
}
Button(action: {
// do something
}, label: {
Text("Button3")
})
}
}
}
}