Reversing a linked list using recursion - c++

Question

I don't know where I'm going wrong. Output shows 1 upon inputting 1 2 3 -1 (-1 to terminate insertion of nodes). Help is appreciated!
I can't seem to find the error in my code that is resulting in wrong output upon different test cases.
Other approaches to the same problem are also welcome.
Any tips so that i won't commit such errors in the future, along with some fundamentals(generally tips) of linked lists
#include <iostream>
using namespace std;
class Node
{
public:
int data;
Node *next;
Node(int data)
{
this->data = data;
next = NULL;
}
};
Node *insert()
{
int data;
cin >> data;
Node *head = NULL;
Node *tail = NULL;
while (data != -1)
{
Node *n = new Node(data);
if (head == NULL)
{
head = n;
tail = n;
}
else
{
tail->next = n;
tail = tail->next;
}
cin >> data;
}
return head;
}
void print(Node *head)
{
Node *temp = head;
while (temp != NULL)
{
cout << temp->data << " ";
temp = temp->next;
}
}
Node *rev_LL(Node *head)
{
if (head == NULL || head->next == NULL)
{
return head;
}
Node *smallAns = rev_LL(head->next);
Node *temp = smallAns;
while (temp->next != NULL)
{
temp = temp->next;
}
temp->next = head;
head->next = NULL;
return smallAns;
}
int main()
{
Node *head = insert();
print(head);
cout << endl;
cout << "After reversing the Linked list : " << endl;
rev_LL(head);
print(head);
cout << endl;
return 0;
}

Answer 1

You have to assign the return value of rev_LL to head instead of just ignoring that.
int main()
{
Node *head = insert();
print(head);
cout << endl;
cout << "After reversing the Linked list : " << endl;
//rev_LL(head);
head = rev_LL(head); // assign the result
print(head);
cout << endl;
return 0;
}