C++ Checking while condition with user input array - c++

Question

I'm student in high school and I wanna to make simple game with guessing random number and I had problem with user inputed array while I need to check the condition.
When it comes to checking condition it says there wasn't declared i.
Below I leave code.
#include <iostream>
#include <stdlib.h>
#include <time.h>
using namespace std;
int main()
{
int PlayerAns[200];
int iNumSecret, iNumGuess;
int iWrongAns = 0;
srand(time(NULL));
int iNumMax = 100;
iNumSecret = rand() % iNumMax + 1;
cout << "========== Simple Game =========== "
<< "\n";
do
{
for (int i = 0; i < 100; i++)
{
cout << "Guess the number od 1 do " << iNumMax << "\n";
cin >> PlayerAns[i];
if (iNumSecret < PlayerAns[i] && PlayerAns[i] >= 0 && PlayerAns[i] <= 100)
{
cout << " - Secret number is lower ! "
<< "\n";
}
else if (iNumSecret > PlayerAns[i] && PlayerAns[i] >= 0 && PlayerAns[i] <= 100)
{
cout << " - Secret number is higher ! "
<< "\n";
}
else if (PlayerAns[i] < 0 || PlayerAns[i] > 100)
{
cout << " - Number is out of scope ! "
<< "\n";
iWrongAns++;
}
}
}
while (iNumSecret != PlayerAns[i]);
{
cout << "--- You get it !!!"
<< "\n";
cout << PlayerAns << "\n";
cout << "You guess number out of scope that many times: " << iWrongAns << "\n";
}
return 0;
}

Answer 1

The variable i is defined only inside the for loop in that case.
If you wanted to, you can define i before the do while loop, and then use it in the for loop like so:
for(i = 0; i < 100; i++) {
...
}
Suggestion:
You can try not using the for loop and make the PlayerAns an integer instead of an array.