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Hello there can i have an hint about how should i write the regex code to search for the commas (,) in those values between the |'...'| pattern? i need to find the commas and replace with dots(.) , if there's a comma in there of course.
|'2,3'|;|'5,6'|;|'2,1'|;|'3'|;|'6,5'|;|'9'|;|'7'|;|'4,4'|;|'4'|;|'1,1'|
expected result:
|'2.3'|;|'5.6'|;|'2.1'|;|'3'|;|'6.5'|;|'9'|;|'7'|;|'4.4'|;|'4'|;|'1,1'|
the pattern can be also what i will write below depending on some input parameters that i am going to receive in my method:
|'2,3'|,|'5,6'|,|'2,1'|,|'3'|,|'6,5'|,|'9'|,|'7'|,|'4,4'|,|'4'|,|'1,1'|
expected result:
|'2.3'|,|'5.6'|,|'2.1'|,|'3'|,|'6.5'|,|'9'|,|'7'|,|'4.4'|,|'4'|,|'1.1'|
this why i need a pattern for this because i don't know if i will receive the string with (;) or (,) separating the values
thanks so much
Regex Pattern
Here is the pattern that you can use to search for the commas , between two numbers
(?<=[0-9]),(?=[0-9])
Regex Demo
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I tried to capture file extension: get .m3u8 if my filename is ABC.m3u8 for example.
The regular expression I use:
\w+(^\.[A-Za-z0-9]+)
I cannot get the result as my expected if I don't remove hat(^) character. Please tell me why, thanks.
There are two issues with \w+(^\.[A-Za-z0-9]+) :
^ would match the beginning of the string
not anchoring it at the end would give false captures, such as .foo for abc.foo.mp3
Here is the corrected regex:
^[\w+\.]+(\.[A-Za-z0-9]+)$
Or simply:
(\.[A-Za-z0-9]+)$
Learn more about regex: https://twiki.org/cgi-bin/view/Codev/TWikiPresentation2018x10x14Regex
^means match the beginning of a line, rather than beginning with ., so adding ^ will not match.
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I am having the following String
{'Sample': '#it{tq}', 'Yield': 0.011063753491221462, 'Error': 0}
and I would like to extract the value from 'Sample', that means '#it{tq}'. I tried that using a regular expression: 'Sample':(\s*.+?\s)
but its giving me: '#it{tq}', including that comma at the end. Does anyone know how to erase the comma at the end?
this regular expression should do the job.
regex: 'Sample':\s*('[^']*')
https://regex101.com/r/DL5Ltq/2
how about using this:
'Sample': '(.*?)',
beware that the regex in the accepted answer cannot process the case having single quote escape text inside the capture group like this: {'Sample': '#it'{tq}'}.
If you use (.*?), it greedily process any single character inside two single quote.
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The program contains text of this type:
A B Ccccc
A Ccccc
ACcccc
ABCcccc
I need only such text to remain:
Ccccc
I wrote a replacement function, but I just can’t pick up a pattern
How to make such a pattern?
No need for regex, nor VBA. It seems you simply are looking for the position of the last upper-case letter and then to extract from there:
Formula in B1 (with Excel O365):
=MID(A1,MAX(SEQUENCE(LEN(A1))*(EXACT(UPPER(MID(A1,SEQUENCE(LEN(A1)),1)),MID(A1,SEQUENCE(LEN(A1)),1)))),LEN(A1))
If you don't have Excel O365:
=MID(A1,MAX(ROW(A1:INDEX(A:A,LEN(A1)))*(EXACT(UPPER(MID(A1,ROW(A1:INDEX(A:A,LEN(A1))),1)),MID(A1,ROW(A1:INDEX(A:A,LEN(A1))),1)))),LEN(A1))
You probably need to enter as array through: CtrlShiftEnter
If you must go through VBA and regex then a pattern like:
[A-Z][^A-Z]*$
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I am trying to filter medical words from general english words.
but most of the drugs name contains hypen in it.
pls suggest how to check in python, that a string contains only alphabets and hypen.
for example : anti-allergic
Simplest way to check string is as below, remove '-' from string and check if remaining characters are all alphabets.
test_str = 'anti-allergic'
if test_str.replace('-','').isalpha():
print('Valid string')
This can be accomplished by using regular expressions (https://docs.python.org/3/library/re.html), where a (very quick and dirty) regex could ask for all letters, a to z (and A to Z), that has a hyphen in it.
([a-zA-Z]+[-].+)
Would match the following:
suoad
ADDADA
waeewrw
omaeqweSADADSwu
iraaief
anti-allergic
ANTI-ALLERGIC
testtesttest
You can test this out yourself using https://pythex.org/.
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I would use regex to select one changing number
For example in the following example I would select 12090343 that I could change
I use:
preg_match (/(?<=Dossier.N..)(.*)(?=-)/)
It works but it's not so clean I think because the number of spaces could change and so it will not detect the number any more
Dossier N° 11110144-001 Pvt du : 03/09/2013 à 7:16
It looks fine, but you could slightly clean it up by .not grouping the number and making it match digits:
(?<=Dossier.{0,3}N.{0,3})\d+(?=-)
Most regex engines can't handle look behinds of arbitrary length, so rather than using the simpler (but unbounded) expression \s*, you must use a limited length expression like \s{0,3} to allow "some" whitespace.
You can try the following expression:
/Dossier[^0-9]*\K([0-9]*)(?=-)/
Regex101 Demo