I cant seem to find the correct answer to display 1 foreign key value:
it displays "house label" in the correct "table" it displays the value. but it does not give the perfect "column" name. i would love to display "house_name" in the table.. any idea's?
admin.py
from django.contrib import admin
from .models import UserProfile,House
# Register your models here.
class UserProfileAdmin(admin.ModelAdmin):
def house_label(self, obj):
return obj.house.house_name
list_display = ('user', 'api_key','house_label')
admin.site.register(UserProfile,UserProfileAdmin)
admin.site.register(House)
models.py
from django.db import models
from django.contrib.auth.models import User
# Create your models here.
class House(models.Model):
house_name = models.CharField(max_length=500,blank=False, null = False)
class UserProfile(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE, related_name ="profile")
api_key = models.CharField(max_length=500, blank=False, null = False)
house = models.ForeignKey(House, on_delete=models.CASCADE, related_name = "house")
If you just want it to say house and display the name, you need a __str__ method on your House model that looks like this:
class House(models.Model):
house_name = models.CharField(max_length=500,blank=False, null = False)
def __str__(self):
return f"{self.house_name}"
and your admin class would be:
class UserProfileAdmin(admin.ModelAdmin):
list_display = ('user', 'api_key', 'house')
If you truly want it to say house_name you just need to rename your admin function and refer to it by that name in your list_display.
class UserProfileAdmin(admin.ModelAdmin):
def house_name(self, obj):
return obj.house.house_name
list_display = ('user', 'api_key','house_name')
Related
i want to create a tag field like youtube give tage field while uploading a vedio this is what i tried in in my blog form
my models.py
from django.db import models
from django.contrib.auth.models import User
from django.utils import timezone
# Create your models here.
class Blog(models.Model):
author = models.OneToOneField(User, on_delete=models.CASCADE,)
title = models.CharField(max_length=200,blank=False,)
thumbnail = models.ImageField(upload_to='blogs_thumbnail',default='blogdefa.png')
tags = models.CharField(max_length=500, blank=False, default='Blog')
data = models.TextField(blank=False,)
published_date = models.DateTimeField(default=timezone.now,editable=False)
update_at = models.DateTimeField(auto_now=True,editable=False)
def __str__(self):
return self.title
any idea how to do it i don,t know how to do it
my forms.py
from django import forms
from django.forms import ModelForm, Textarea
from django.contrib.auth.models import User
from .models import Blog, comment, report
forms here
class BlogForm(forms.ModelForm):
class Meta:
model = Blog
fields = '__all__'
widgets = {'data': Textarea(attrs={'cols': 80, 'rows': 20, 'placeholder':'Write Here'}),
'title':forms.TextInput(attrs={'placeholder':'Your Blog Title Here'}),
'tags': forms.TextInput(attrs={'placeholder':'Please enter you content related tags'}),
}
exclude = ['author','published_date','update_at']
all i want is user can create his own tag for blogs like in youtube and not like stackoverflow where you have use to choose you tag
please help
currently it look like this
which is not cool
First thing is that tags work. So to get them working you should relate it to your post.
So you should create a Tag model and use a ManytoManyRelated field to relate tags because you need to get to the post/result at the end using tags.
from django.db import models
from django_extensions.db.fields import AutoSlugField
from django.db.models import CharField, TextField, DateField, EmailField, ManyToManyField
class Tag(models.Model):
name = CharField(max_length=31, unique=True, default="tag-django")
slug = AutoSlugField(max_length=31, unique=True, populate_from=["name"])
def __str__(self):
return self.name
class YourPost(models.Model):
name = CharField(max_length=31, db_index=True)
slug = AutoSlugField(max_length=31, unique=True, populate_from=["name"])
description = TextField()
date_founded = DateField(auto_now_add=True)
contact = EmailField()
tags = ManyToManyField(Tag, related_name="tags")
class Meta:
get_latest_by = ["date_founded"]
def __str__(self):
return self.name
Go on from here.
Create serializers, Viewsets. Relate your tags to your post.
I can't figure out how to add the User full_name in the list_filter.
My Blog model is as follows:
from django.db import models
from django.contrib.auth.models import AbstractUser
from django.utils import timezone
class User(AbstractUser):
pass
class Post(models.Model):
POST_STATUS = (('borrador', 'Borrador'), ('publicado', 'Publicado'))
title = models.CharField('titulo', max_length=100)
body = models.TextField('cuerpo')
author = models.ForeignKey(User, on_delete=models.CASCADE, related_name='blog_posts', verbose_name='autor')
created = models.DateTimeField('creado', auto_now_add=True)
published = models.DateTimeField('publicado', auto_now=True)
updated = models.DateTimeField('actualizado', auto_now=True)
slug = models.SlugField(max_length=100, unique_for_date='published')
status = models.CharField(max_length=10, choices=POST_STATUS, default='borrador')
class Meta:
ordering = ('-published',)
def __str__(self):
return self.title
As you can see, I have created a custom user model just in case I have to change it in the future.
In the Blog model, there is a 'author' field which uses the User as FK.
I want to add the posibility to filter by 'author' in the Blog's admin site. To do this I tried the following:
from django.contrib import admin
from django.contrib.auth.admin import UserAdmin
from .models import User, Post
admin.site.register(User, UserAdmin)
#admin.register(Post)
class PostAdmin(admin.ModelAdmin):
list_display = ('title', 'author', 'status', 'published')
list_filter = ('author' , 'status', 'published')
search_fields = [('title',), ('body',)]
prepopulated_fields = {'slug': ('title',)}
raw_id_fields = ('author',) # Reemplaza el drop-down para que parezca una lupa (para FKs)
date_hierarchy = 'published'
ordering = ('status', 'published')
The problem is that the filter by 'author' doesn't appear in the admin site:
If I do this: list_filter = ('author__last_name' , 'status', 'published') the filter shows up, but it looks like this ('appellido' means last_name in Spanish:
I would like the filter's text to be 'por autor (by author)' and be able to filter by the author's full name.
Is that possible?
Thanks in advance!!
Probably you can do that with django.contrib.admin.SimpleListFilter:
from datetime import date
from django.contrib import admin
from django.utils.translation import gettext_lazy as _
class PerAuthorListFilter(admin.SimpleListFilter):
title = _('Per Author')
parameter_name = 'per_author'
def lookups(self, request, model_admin):
authors = []
for u in User.objects.all():
authors.append((u.pk, '{} {}'.format(u.first_name, u.last_name)))
return authors
def queryset(self, request, queryset):
queryset = super().queryset(request, queryset)
return queryset.filter(author=self.value())
#admin.register(Post)
class PostAdmin(admin.ModelAdmin):
list_filter = [PerAuthorListFilter, ...]
Hi I need really very very simple example. First my models:
#This my student models
from django.db import models
SEX_CHOICES= (
('M', 'Male'),
('F', 'Female'),
)
class Students(models.Model):
student_name = models.CharField(max_length=50)
student_sex = models.CharField(max_length=8, choices=SEX_CHOICES)
student_city = models.Charfield(max_length=50)
student_bio = models.TextField()
def __unicode__(self):
return self.student_name
O.K. Let see my ClassRooms Model.
#This my ClassRooms models
from django.db import models
from myproject.students.models import *
class ClassRooms(models.Model):
class_number= models.CharField(max_length=50)
class_student_cities = models.ForeignKey(Students)
class_year = models.DateField()
def __unicode__(self):
return self.class_number
How can i show in the class_student_cities area the Students.student_city datas? I guess that about django-admin area. When i do it withclass_student_cities = models.ForeignKey(Students) i just see in that area the Students.student_name data (ex: John Smith). I want to see JUST Students.student_cities data (ex: NewYork). Can you give me a little example?
Should i use something like that:
class_student_cities = models.ForeignKey(Students.student_cities)
Many Thanks!
Try redifinition unicode method.
def __unicode__(self):
return self.student_city
So you'll see in the field student city.
Well, I tried to remake your application to set data with forms class. Something like this in admin.py in your application:
from django.contrib import admin
from django import forms
from myapp.models import *
class ClassRoomsAdminForm(forms.ModelForm):
class Meta:
model = ClassRoom
def __init__(self, *arg, **kwargs):
super(ClassRoomsAdminForm, self).__init__(*arg, **kwargs)
self.fields[' class_student_cities'].choices = [(csc.id,csc.student_city) for csc in Students.objects.all()
class ClassRoomsAdmin(admin.ModelAdmin):
form = ClassRoomsAdminForm
admin.site.register(ClassRooms,ClassRoomsAdmin)
Maybe you'll need to fix something, but I hope it will work. You will set init function to your forms, so in admin panel you set all choices to everything you keep in your Students model. csc.id you'll need to make this object iterable (cities aren't unique) and then you can choose everything from Students model to set in the field.
Hi I need really very very simple example. First my models:
#This my student models
from django.db import models
SEX_CHOICES= (
('M', 'Male'),
('F', 'Female'),
)
class Students(models.Model):
student_name = models.CharField(max_length=50)
student_sex = models.CharField(max_length=8, choices=SEX_CHOICES)
student_city = models.Charfield(max_length=50)
student_bio = models.TextField()
def __unicode__(self):
return self.student_name
O.K. Let see my Classes Model.
#This my Classes models
from django.db import models
from myproject.students.models import *
class Classes(models.Model):
class_number= models.CharField(max_length=50)
class_student_cities = models.ForeignKey(Students)
class_year = models.DateField()
def __unicode__(self):
return self.class_number
My classes/admin.py file looks like that:
from myproject.classes.models import *
from myproject.students.models import *
from django.contrib import admin
class ClassesChoiceField(Students):
class_student_cities = Classes.objects.get(id=1).class_student_cities.student_city
admin.site.register(Classes)
I get this error:
DoesNotExist at /admin/classes/classes/add/
Classes matching query does not exist.
How can i show in the class_student_cities area the Students.student_city datas? I guess that about django-admin area.
When i do it with ForeignKey(Students) i just see in that area the Students.student_name data :S. I'm really wondering how can I do it? Can you give me a little example?
Many Thanks!
See the documentation.
To get student_city from queryset, you can use:
Classes.objects.get(id=1).class_student_cities.student_city
And if you want to relate your foreignkey field not to primary key, you should use to_field argument
https://docs.djangoproject.com/en/dev/ref/models/fields/#django.db.models.ForeignKey.to_field
It will be like:
class_student_cities = models.ForeignKey(Students, to_field='student_city')
There are a few problems -- basically things are 'not quite right', which is why you keep being referred to the docs.
Here is an example of what an admin.py should look like:
from django.contrib import admin
from articles.models import Article
def show_articletype_thumbnail(self):
return self.image.admin_thumbnail()
show_articletype_thumbnail.allow_tags=True
show_articletype_thumbnail.short_description = 'Image'
class ArticleAdmin(admin.ModelAdmin):
save_on_top = True
list_display = ['status', 'articletype', 'issue', 'penname', 'issue', show_articletype_thumbnail]
list_display_links = ['articletype']
list_filter = ['articletype', 'allow_comments', 'template', 'issue']
admin.site.register(Article, ArticleAdmin)
My purpose is to see at the admin site only user name, email and phone number.
I've create UserProfile by extending User model:
model.py
from django.db import models
from django.contrib.auth.models import User
class UserProfile(models.Model):
user = models.ForeignKey(User, unique=True)
name = models.CharField(max_length=50, null=True,blank=True)
address = models.CharField(max_length=50, null=True,blank=True)
phone = models.CharField(max_length=20, null=True,blank=True)
country = models.CharField(max_length=20, null=True,blank=True)
state = models.CharField(max_length=20, null=True,blank=True)
zip = models.CharField(max_length=10, null=True,blank=True)
code = models.CharField(max_length=40, null=True)
def user_email(self):
return self.user.email
admin.py
from myApp.models import UserProfile
from django.contrib import admin
class UserProfileAdmin(admin.ModelAdmin):
fields = ('name','phone',)
list_display = ('name','user_email',)
admin.site.register(UserProfile, UserProfileAdmin)
so on the list_display it works, I can see only the columns I've chosen, but when I add 'user_email' ( fields = ('name','user_email', 'phone',) )to fields I get when I try to go to admin site:
'UserProfileAdmin.fields' refers to field 'user_email' that is missing from the form.
Fields on a related model use two underscores. Dunno if it'll work in the admin though.
list_display = ('name','user__email',)
Just because I recently used it and you maybe want this, too: If you wan't to add an inline admin to the "User" admin page in Django you can do this (at least in Django 1.3) by doing:
from django.contrib import admin
from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User
from models import UserProfile
class UserProfileInlineAdmin(admin.StackedInline):
model = UserProfile
class MyUserAdmin(UserAdmin):
inlines = [ UserProfileInlineAdmin ]
admin.site.unregister(User)
admin.site.register(User, MyUserAdmin)
You can't put editable fields from a related model into an admin form, without using inlines. You can show the field as a readonly value: just add it to readonly_fields.